1.

Rahul bought a car Rs. 4 lakhs in 2018. The rate ofdepreciation is 10% per year. Find the depreciationvalue of the car in the year 2020?Solution P=4,00,000 R= 10%, N=_years.A=P(_______) (Formula)On substituting the values of P, N, and R solving we getA=4,00,000 X _______ square = 4000 X (_______)= Rs.________Depreciation in price = Cost price - A= Rs.________​

Answer»

ANSWER :-

The DEPRECIATION VALUE of CAR 

= 400000 - 324000  \\ = Rs. 76000  \\  \\ ello \: jaan



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