52639 + Interview Questions in Secondary School in Chemistry

1.	विभिन्न तापों पर N2O5 के अपघटन के लिए वेग स्थिरांक नीचे दिए गये हैं ln ke एवं 1/T के मध्य ग्राफ खींचिए तथा A एवं Ea की गणना कीजिए। 30°C तथा 50°C पर वेग स्थिरांक को प्रागुक्त कीजिए।
Answer» ANSWER: how are you doing TODAY BEAUTIFUL and I OT for the FIRST

1.

विभिन्न तापों पर N2O5 के अपघटन के लिए वेग स्थिरांक नीचे दिए गये हैं ln ke एवं 1/T के मध्य ग्राफ खींचिए तथा A एवं Ea की गणना कीजिए। 30°C तथा 50°C पर वेग स्थिरांक को प्रागुक्त कीजिए।

Answer»

ANSWER:

how are you doing TODAY BEAUTIFUL and I OT for the FIRST

Discussion

2.	एक प्रथम कोटि की अभिक्रिया में 30% वियोजन होने में 40 मिनट लगते हैं। की गणना कीजिए।
Answer» वियोजन अभिक्रिया का $t_{\frac{1}{2}}$ = 78.12 MIN EXPLANATION: एक प्रथम कोटि की अभिक्रिया के लिए ; $t = \frac{2.303}{k} log \frac{[R]_{\circ}}{[R]}$ $\Rightarrow$ $k = \frac{2.303}{t} log \frac{[R]_{\circ}}{[R]}$ $\Rightarrow$ $k = \frac{2.303}{40 min} log \frac{100}{(100 - 30)} = \frac{2.303}{40 min} log \frac{10}{7}$ $\Rightarrow$ $k = 0.0576 \times log 1.428 = 0.0576 \times 0.154$ अर्थात , $k = 0.0576 \times 0.154 min^{-1} = 0.00887 min^{-1} = 8.87 \times 10^{-3} min^{-1}$ इसलिए , वियोजन अभिक्रिया का $t_{\frac{1}{2}}$ ; $t_{\frac{1}{2} = \frac{0.693}{8.87 \times 10^{-3} } min = 78.12 min$ इसलिए , वियोजन अभिक्रिया का $t_{\frac{1}{2}}$ = 78.12 min

2.

एक प्रथम कोटि की अभिक्रिया में 30% वियोजन होने में 40 मिनट लगते हैं। की गणना कीजिए।

Answer»

वियोजन अभिक्रिया का $t_{\frac{1}{2}}$ = 78.12 MIN

EXPLANATION:

एक प्रथम कोटि की अभिक्रिया के लिए ;

$t = \frac{2.303}{k} log \frac{[R]_{\circ}}{[R]}$

$\Rightarrow$ $k = \frac{2.303}{t} log \frac{[R]_{\circ}}{[R]}$

$\Rightarrow$ $k = \frac{2.303}{40 min} log \frac{100}{(100 - 30)} = \frac{2.303}{40 min} log \frac{10}{7}$

$\Rightarrow$ $k = 0.0576 \times log 1.428 = 0.0576 \times 0.154$

अर्थात , $k = 0.0576 \times 0.154 min^{-1} = 0.00887 min^{-1} = 8.87 \times 10^{-3} min^{-1}$

इसलिए , वियोजन अभिक्रिया का $t_{\frac{1}{2}}$ ;

$t_{\frac{1}{2} = \frac{0.693}{8.87 \times 10^{-3} } min = 78.12 min$

इसलिए , वियोजन अभिक्रिया का $t_{\frac{1}{2}}$ = 78.12 min

Discussion

3.	किसी अभिक्रिया A→ उत्पाद के लिए k=2.0x10-2s-1 है। यदि A की प्रारंभिक सांद्रता 1.0mol L-1 हो तो 100s के पश्चात् इसकी सांद्रता क्या रह जाएगी?
Answer» Answer: Electrolytes are substances which, when dissolved in water, BREAK up into cations (plus-charged ions) and anions (minus-charged ions). We say they ionize. Strong electrolytes ionize completely (100%), while weak electrolytes ionize only partially (usually on the order of 1–10%). That is, the principal species in solution for strong electrolytes are ions, while the principal SPECIE in solution for weak electrolytes is the un-ionized compound itself. Strong electrolytes fall into three categories: strong acids, strong bases, and salts. (Salts are sometimes also called ionic compounds, but really strong bases are ionic compounds as well.) The weak electrolytes include weak acids and weak bases. Examples of strong and weak electrolytes are given below: Strong Electrolytes strong acids HCl, HBr, HI, HNO3, HClO3, HClO4, and H2SO4 strong bases NaOH, KOH, LiOH, Ba(OH)2, and Ca(OH)2 salts NaCl, KBr, MgCl2, and many, many more Weak Electrolytes weak acids HF, HC2H3O2 (acetic ACID), H2CO3 (CARBONIC acid), H3PO4 (phosphoric acid), and many more weak bases NH3 (ammonia), C5H5N (pyridine), and several more, all containing "N" Being Able to Classify Electrolytes Is Critical As chemists, we need to be able to look at a formula such as HCl or NaOH and quickly know which of these classifications it is in, because we need to be able to know what we are working with (ions or compounds) when we are working with chemicals. We need to know, for example, that a bottle labeled "NaCN" (a salt) rea

3.

किसी अभिक्रिया A→ उत्पाद के लिए k=2.0x10-2s-1 है। यदि A की प्रारंभिक सांद्रता 1.0mol L-1 हो तो 100s के पश्चात् इसकी सांद्रता क्या रह जाएगी?

Answer»

Answer:

Electrolytes are substances which, when dissolved in water, BREAK up into cations (plus-charged ions) and anions (minus-charged ions). We say they ionize. Strong electrolytes ionize completely (100%), while weak electrolytes ionize only partially (usually on the order of 1–10%). That is, the principal species in solution for strong electrolytes are ions, while the principal SPECIE in solution for weak electrolytes is the un-ionized compound itself.

Strong electrolytes fall into three categories: strong acids, strong bases, and salts. (Salts are sometimes also called ionic compounds, but really strong bases are ionic compounds as well.) The weak electrolytes include weak acids and weak bases.

Examples of strong and weak electrolytes are given below:

Strong Electrolytes strong acids HCl, HBr, HI, HNO3, HClO3, HClO4, and H2SO4

strong bases NaOH, KOH, LiOH, Ba(OH)2, and Ca(OH)2

salts NaCl, KBr, MgCl2, and many, many more

Weak Electrolytes

weak acids HF, HC2H3O2 (acetic ACID), H2CO3 (CARBONIC acid), H3PO4 (phosphoric acid), and many more

weak bases NH3 (ammonia), C5H5N (pyridine), and several more, all containing "N"

Being Able to Classify Electrolytes Is Critical

As chemists, we need to be able to look at a formula such as HCl or NaOH and quickly know which of these classifications it is in, because we need to be able to know what we are working with (ions or compounds) when we are working with chemicals. We need to know, for example, that a bottle labeled "NaCN" (a salt) rea

Discussion

4.	स्थिर आयतन पर के प्रथम कोटि के ताप अपघटन पर निम्न आँकड़े प्राप्त हुए-अभिक्रिया वेग की गणना कीजिए जब कुल दाब 0.65 atm हो।
Answer» Answer: ckck Electrolytes are substances which, when dissolved in WATER, break up into cations (plus-charged ions) and ANIONS (minus-charged ions). We say they ionize. Strong electrolytes ionize completely (100%), while weak electrolytes ionize only partially (usually on the order of 1–10%). That is, the principal species in solution for strong electrolytes are ions, while the principal specie in solution for weak electrolytes is the un-ionized compound itself. Strong electrolytes fall into three categories: strong acids, strong BASES, and salts. (Salts are sometimes also called ionic compounds, but really strong bases are ionic compounds as well.) The weak electrolytes include weak acids and weak bases. Examples of strong and weak electrolytes are given below: Strong Electrolytes strong acids HCl, HBr, HI, HNO3, HClO3, HCLO4, and H2SO4 strong bases NaOH, KOH, LiOH, Ba(OH)2, and Ca(OH)2 salts NaCl, KBr, MgCl2, and many, many more Weak Electrolytes weak acids HF, HC2H3O2 (acetic acid), H2CO3 (carbonic acid), H3PO4 (phosphoric acid), and many more weak bases NH3 (ammonia), C5H5N (pyridine), and several more, all containing "N" Being ABLE to Classify Electrolytes Is Critical As chemists, we need to be able to look at a formula such as HCl or NaOH and quickly know which of these classifications it is in, because we need to be able to know what we are working with (ions or compounds) when we are working with chemicals. We need to know, for example, that a bottle labeled "NaCN" (a salt) rea

4.

स्थिर आयतन पर के प्रथम कोटि के ताप अपघटन पर निम्न आँकड़े प्राप्त हुए-अभिक्रिया वेग की गणना कीजिए जब कुल दाब 0.65 atm हो।

Answer»

Answer:

ckck Electrolytes are substances which, when dissolved in WATER, break up into cations (plus-charged ions) and ANIONS (minus-charged ions). We say they ionize. Strong electrolytes ionize completely (100%), while weak electrolytes ionize only partially (usually on the order of 1–10%). That is, the principal species in solution for strong electrolytes are ions, while the principal specie in solution for weak electrolytes is the un-ionized compound itself.

Strong electrolytes fall into three categories: strong acids, strong BASES, and salts. (Salts are sometimes also called ionic compounds, but really strong bases are ionic compounds as well.) The weak electrolytes include weak acids and weak bases.

Examples of strong and weak electrolytes are given below:

Strong Electrolytes strong acids HCl, HBr, HI, HNO3, HClO3, HCLO4, and H2SO4

strong bases NaOH, KOH, LiOH, Ba(OH)2, and Ca(OH)2

salts NaCl, KBr, MgCl2, and many, many more

Weak Electrolytes

weak acids HF, HC2H3O2 (acetic acid), H2CO3 (carbonic acid), H3PO4 (phosphoric acid), and many more

weak bases NH3 (ammonia), C5H5N (pyridine), and several more, all containing "N"

Being ABLE to Classify Electrolytes Is Critical

As chemists, we need to be able to look at a formula such as HCl or NaOH and quickly know which of these classifications it is in, because we need to be able to know what we are working with (ions or compounds) when we are working with chemicals. We need to know, for example, that a bottle labeled "NaCN" (a salt) rea

Discussion

5.	543 K ताप पर एजोआइसोप्रोपेन के हेक्सेन तथा नाइट्रोजन में विघटन के निम्न आँकड़े प्राप्त हुए। वेग स्थिरांक की गणना कीजिए।
Answer» Answer: PHELE SAB KUCH BENGALI ME LIKH. PLZ MARK ME AS BRAINLIEST

5.

543 K ताप पर एजोआइसोप्रोपेन के हेक्सेन तथा नाइट्रोजन में विघटन के निम्न आँकड़े प्राप्त हुए। वेग स्थिरांक की गणना कीजिए।

Answer»

Answer:

PHELE SAB KUCH BENGALI ME LIKH. PLZ MARK ME AS BRAINLIEST

Discussion

6.	Wt is electronic configuration of K4FeCN6
Answer» Answer:3d6 Explanation:K4{Fe(CN)6}= 4+x+(-6)=0. I..E, equal to +2. So ELECTRONIC CONFIGURATION of Fe2+ is only 3d6.

6.

Wt is electronic configuration of K4FeCN6

Answer»

Answer:3d6

Explanation:K4{Fe(CN)6}= 4+x+(-6)=0. I..E, equal to +2. So ELECTRONIC CONFIGURATION of Fe2+ is only 3d6.

Discussion

7.	List examples of some petroleum products which are used to prepare synthetic fibres
Answer» ANSWER: PARAFFIN WAX . REGARDS.

7.

List examples of some petroleum products which are used to prepare synthetic fibres

Answer»

ANSWER:

PARAFFIN WAX .

REGARDS.

Discussion

8.	Hydrogen reacts with N2 to produce ammonia according to the equation N2 (g) + 3H2 (g) 2NH3 (g) Determine how much ammonia would be produced if 200 g of H2 reacts with excess of N2
Answer» ANSWER: I don't no Explanation: SORRY I don't no

8.

Hydrogen reacts with N2 to produce ammonia according to the equation N2 (g) + 3H2 (g) 2NH3 (g) Determine how much ammonia would be produced if 200 g of H2 reacts with excess of N2

Answer»

ANSWER:

I don't no

Explanation:

SORRY I don't no

Discussion

9.	Explain why magnesium fluoride has a high melting point and boiling point.
Answer» Answer: HEYA mate here is your answer ❤❤ magnesium CHLORIDES are solids with high MELTING and boiling points because of the large amount of HEAT which is needed to break the strong ionic attractions...❤❤ hope its help U ❤❤ please mark as brainlist ❤❤❤

9.

Explain why magnesium fluoride has a high melting point and boiling point.

Answer»

Answer:

HEYA mate here is your answer ❤❤

magnesium CHLORIDES are solids with high MELTING and boiling points because of the large amount of HEAT which is needed to break the strong ionic attractions...❤❤

hope its help U ❤❤

please mark as brainlist ❤❤❤

Discussion

10.	Write some characteristics of polides of matter any four
Answer» Answer: Characteristic Properties of Matter—The Key Ideas The physical properties of matter include color, odor, density, solubility, melting point, boiling point, and electrical conductivity. These are properties that can be observed WITHOUT chemically changing the substance. Anything that has MASS (VOLUME) and takes up space. a Substance that contains only ONE type of atom. The smallest particle of an element that still has the properties of that element. Change in size, shape, color, or state (solid, liquid, or GAS) but maintains its same chemical characteristics.

10.

Write some characteristics of polides of matter any four

Answer»

Answer:

Characteristic Properties of Matter—The Key Ideas The physical properties of matter include color, odor, density, solubility, melting point, boiling point, and electrical conductivity. These are properties that can be observed WITHOUT chemically changing the substance.

Anything that has MASS (VOLUME) and takes up space. a Substance that contains only ONE type of atom. The smallest particle of an element that still has the properties of that element. Change in size, shape, color, or state (solid, liquid, or GAS) but maintains its same chemical characteristics.

Discussion

11.	Calculate molarity of solutions prepared by mixing 500ml of 2.5M urea solution and 500ml of 2M urea solution
Answer» Answer: 2.25 M Explanation: Using dilution formula : i.e. M₃ ( V₁ + V₂ ) = M₁ V₁ + M₂ V₂ Here we have values : V₁ = 500 mL = 0.5 L M₁ = 2.5 M V₂ = 0.5 L M₂ = 2 M Putting values we get : M₃ ( 0.5 + 0.5 ) = ( 2.5 × 0.5 ) + ( 2 × 0.5 ) M = > M₃ ( 1 ) = 1.25 + 1 M = > M₃ = 2.25 M Hence we get required answer. Read more : A 300 LITER of solution is MADE by mixing 180 g of sodium chloride in water. CALCULATE the CONCENTRATION of the solution? brainly.in/question/16765890

11.

Calculate molarity of solutions prepared by mixing 500ml of 2.5M urea solution and 500ml of 2M urea solution

Answer»

Answer:

2.25 M

Explanation:

Using dilution formula :

i.e. M₃ ( V₁ + V₂ ) = M₁ V₁ + M₂ V₂

Here we have values :

V₁ = 500 mL = 0.5 L

M₁ = 2.5 M

V₂ = 0.5 L

M₂ = 2 M

Putting values we get :

M₃ ( 0.5 + 0.5 ) = ( 2.5 × 0.5 ) + ( 2 × 0.5 ) M

= > M₃ ( 1 ) = 1.25 + 1 M

= > M₃ = 2.25 M

Hence we get required answer.

Read more :

A 300 LITER of solution is MADE by mixing 180 g of sodium chloride in water. CALCULATE the CONCENTRATION of the solution?

brainly.in/question/16765890

Discussion

12.	Which among the following hydrides is not a reducing agent a .h2o b .h 2s c .h2te d.h2se
Answer» Answer: hahahaha I have a NICE DAY AHEAD I will be easier to GET the latest flash player is required for video playback is unavailable right now because this YET but I am not sure if you have any questions or

12.

Which among the following hydrides is not a reducing agent a .h2o b .h 2s c .h2te d.h2se

Answer»

Answer:

hahahaha I have a NICE DAY AHEAD I will be easier to GET the latest flash player is required for video playback is unavailable right now because this YET but I am not sure if you have any questions or

Discussion

13.	Kolidel Kya hai Class-9th Subject Science And in Hindi
Answer» उ०:- कोलाइड एक प्रकार का घोल होता है जिसमें विलेय कणों का आकार सही मिश्रण में और उन लोगों के बीच मध्यवर्ती होता है जो निलंबन में होते हैं।

13.

Kolidel Kya hai Class-9th Subject Science And in Hindi

Answer»

उ०:- कोलाइड एक प्रकार का घोल होता है जिसमें विलेय कणों का आकार सही मिश्रण में और उन लोगों के बीच मध्यवर्ती होता है जो निलंबन में होते हैं।

Discussion

14.	White coloured metal nitrate a on heating gives a yellow residue b along with evolution of a brown gas g and a colourless gas c
Answer» Answer: The metal nitrate (A) is lead nitrate (Pb(NO 3 ) 2 ) on heating it produces lead OXIDE, Nitrogen dioxide (B) and oxygen gas (C) (1) 2Pb(NO 3 ) 2 →2PbO+4NO 2 +O 2 on reaction with potassium iodide MIXTURE of lead iodide and potassium nitrate forms (2) Pb(NO 3 ) 2 +2KI→PbO 2 +2kNO 3 Alloy made of using lead is used in SOLDERING purpose. Therefore A=[Pb(NO 3 ) 2 ),B=NO 2 C=O 2 D=PbI+KNO 3 (2) DECOMPOSTION TYPE Reaction (2) Double displacement type Reaction. Explanation: mark me as brainliest

14.

White coloured metal nitrate a on heating gives a yellow residue b along with evolution of a brown gas g and a colourless gas c

Answer»

Answer:

The metal nitrate (A) is lead nitrate (Pb(NO

3

)

2

) on heating it produces lead OXIDE, Nitrogen dioxide (B) and oxygen gas (C)

(1) 2Pb(NO

3

)

2

→2PbO+4NO

2

+O

2

on reaction with potassium iodide MIXTURE of lead iodide and potassium nitrate forms

(2) Pb(NO

3

)

2

+2KI→PbO

2

+2kNO

3

Alloy made of using lead is used in SOLDERING purpose.

Therefore A=[Pb(NO

3

)

2

),B=NO

2

C=O

2

D=PbI+KNO

3

(2) DECOMPOSTION TYPE Reaction

(2) Double displacement type Reaction.

Explanation:

mark me as brainliest

Discussion

15.	At what temperature do ammonia and carbon dioxide react to form urea?
Answer» ANSWER: HEYA mate here is your answer ❤❤ about 1900 C. The autoclave is MAINTAINED under a pressure of about 200 atmospheres and the AMMONIA and carbon dioxide in synthesis zone 12 are sO maintained at a temperature of about 1900 C. At that temperature and pressure the ammonia and carbon dioxide react to form urea. hope its help u ❤ mark as brainlist ❤❤❤

15.

At what temperature do ammonia and carbon dioxide react to form urea?

Answer»

ANSWER:

HEYA mate here is your answer ❤❤

about 1900 C.

The autoclave is MAINTAINED under a pressure of about 200 atmospheres and the AMMONIA and carbon dioxide in synthesis zone 12 are sO maintained at a temperature of about 1900 C. At that temperature and pressure the ammonia and carbon dioxide react to form urea.

hope its help u ❤

mark as brainlist ❤❤❤

Discussion

16.	Hi guys please say about use of ethanol
Answer» ANSWER: ethanol is used in making PERFUMES, DISINFECTANT, SOP, and also VARIOUS medicine

16.

Hi guys please say about use of ethanol

Answer»

ANSWER:

ethanol is used in making PERFUMES, DISINFECTANT, SOP, and also VARIOUS medicine

Discussion

17.	A solution of NaCl in water is .................................
Answer» ANSWER: A solution of NaCl in water is called Brine solution...... Hope it may help you.....

17.

A solution of NaCl in water is .................................

Answer»

ANSWER:

A solution of NaCl in water is called Brine solution......

Hope it may help you.....

Discussion

18.	गैस प्रावस्था में 318 K पर N_2O_5 के अपघटन की अभिक्रिया के आँकड़े नीचे दिए गए हैं-(i) एवं । के मध्य आलेख खींचिए। (ii) अभिक्रिया के लिए अर्धायु की गणना कीजिए। (iii) एवं t के मध्य ग्राफ खींचिए। (iv) अभिक्रिया के लिए वेग नियम क्या है? (v) वेग स्थिरांक की गणना कीजिए।(vi) k की सहायता से अर्धायु की गणना कीजिए तथा इसकी तुलना (ii) से कीजिए।
Answer» ANSWER: what is this I don't UNDERSTAND ANYTHING

18.

गैस प्रावस्था में 318 K पर N_2O_5 के अपघटन की अभिक्रिया के आँकड़े नीचे दिए गए हैं-(i) एवं । के मध्य आलेख खींचिए। (ii) अभिक्रिया के लिए अर्धायु की गणना कीजिए। (iii) एवं t के मध्य ग्राफ खींचिए। (iv) अभिक्रिया के लिए वेग नियम क्या है? (v) वेग स्थिरांक की गणना कीजिए।(vi) k की सहायता से अर्धायु की गणना कीजिए तथा इसकी तुलना (ii) से कीजिए।

Answer»

ANSWER:

what is this

I don't UNDERSTAND ANYTHING

Discussion

19.	14C के रेडियोएक्टिव क्षय की अर्धायु 5730 वर्ष है। एक पुरातत्व कलाकृति की लकड़ी में, जीवित वृक्ष की लकड़ी की तुलना में 80 %14C की मात्रा है। नमूने की आयु का परिकलन कीजिए।
Answer» ANSWER: I don't KNOW what is the answer ACTUALLY is

19.

14C के रेडियोएक्टिव क्षय की अर्धायु 5730 वर्ष है। एक पुरातत्व कलाकृति की लकड़ी में, जीवित वृक्ष की लकड़ी की तुलना में 80 %14C की मात्रा है। नमूने की आयु का परिकलन कीजिए।

Answer»

ANSWER:

I don't KNOW what is the answer ACTUALLY is

Discussion

20.	दर्शाइए कि प्रथम कोटि की अभिक्रिया में 99% अभिक्रिया पूर्ण होने में लगा समय 90% अभिक्रिया पूर्ण होने में लगने वाले समय से दुगुना होता है।
Answer» ANSWER: $\huge{\boxed{\mathfrak\pink{\fcolorbox{red}{purple}{HOLA}}}}$ $\huge\green{\underbrace{\overbrace{\ulcorner{\mid{\overline{\underline{Explanation\:Required}}}}}}}$

20.

दर्शाइए कि प्रथम कोटि की अभिक्रिया में 99% अभिक्रिया पूर्ण होने में लगा समय 90% अभिक्रिया पूर्ण होने में लगने वाले समय से दुगुना होता है।

Answer»

ANSWER:

$\huge{\boxed{\mathfrak\pink{\fcolorbox{red}{purple}{HOLA}}}}$

$\huge\green{\underbrace{\overbrace{\ulcorner{\mid{\overline{\underline{Explanation\:Required}}}}}}}$

Discussion

21.	2A + B \longrightarrrow C + D अभिक्रिया की बलगतिको अध्ययन करने पर निम्नलिखित परिणाम प्राप्त हुए। अभिक्रिया के लिए वेग नियम तथा वेग स्थिरांक ज्ञात कीजिए।
Answer» EXPLANATION: $\huge\green{\underbrace{\overbrace{\ulcorner{\mid{\overline{\underline{Explanation\:Required}}}}}}}$

21.

2A + B \longrightarrrow C + D अभिक्रिया की बलगतिको अध्ययन करने पर निम्नलिखित परिणाम प्राप्त हुए। अभिक्रिया के लिए वेग नियम तथा वेग स्थिरांक ज्ञात कीजिए।

Answer»

EXPLANATION:

$\huge\green{\underbrace{\overbrace{\ulcorner{\mid{\overline{\underline{Explanation\:Required}}}}}}}$

Discussion

22.	प्रथम कोटि की अभिक्रिया के लिए वेग स्थिरांक है। अभिक्रियक को अपनी प्रारंभिक सांद्रता से वाँ भाग रह जाने में कितना समय लगेगा?
Answer» ANSWER: I don't KNOW it's answer

22.

प्रथम कोटि की अभिक्रिया के लिए वेग स्थिरांक है। अभिक्रियक को अपनी प्रारंभिक सांद्रता से वाँ भाग रह जाने में कितना समय लगेगा?

Answer»

ANSWER:

I don't KNOW it's answer

Discussion

23.	नीचे दी गई प्रथम कोटि की अभिक्रियाओं के वेग स्थिरांक से अर्धायु की गणना कीजिए-
Answer» Answer: $\large\boxed{\sf{(i)\;3.465\times{10}^{-3}\:s}}$ $\large\boxed{\sf{(ii)\;0.3465\;min}}$ $\large\boxed{\sf{(<klux>III</klux>)\;0.17325\;yrs}}$ EXPLANATION: First of all, let's understand the meaning of question in english. प्रथम कोटि = First Order अभिक्रियाओं = Reactions वेग स्थिरांक = Rate constants (K) अर्धायु = Half life ( t½ ) Given that, different VALUES of rate constants (k) for a first order reaction. To find the values of half lives, t½. But, we know that, t½ = 0.693/k Therefore, we will GET, (i) k = 200 /s => t½ = 0.693/200 => t½ = $3.465\times{10}^{-3}\:s$ (ii) k = 2 / min => t½ = 0.693/2 => t½ = 0.3465 min (iii) k = 4 / yrs. => t½ = 0.693/4 => t½ = 0.17325 yrs.

23.

नीचे दी गई प्रथम कोटि की अभिक्रियाओं के वेग स्थिरांक से अर्धायु की गणना कीजिए-

Answer»

Answer:

$\large\boxed{\sf{(i)\;3.465\times{10}^{-3}\:s}}$

$\large\boxed{\sf{(ii)\;0.3465\;min}}$

$\large\boxed{\sf{(<klux>III</klux>)\;0.17325\;yrs}}$

EXPLANATION:

First of all, let's understand the meaning of question in english.

प्रथम कोटि = First Order
अभिक्रियाओं = Reactions
वेग स्थिरांक = Rate constants (K)
अर्धायु = Half life ( t½ )

Given that, different VALUES of rate constants (k) for a first order reaction.

To find the values of half lives, t½.

But, we know that,

t½ = 0.693/k

Therefore, we will GET,

(i) k = 200 /s

=> t½ = 0.693/200

=> t½ = $3.465\times{10}^{-3}\:s$

(ii) k = 2 / min

=> t½ = 0.693/2

=> t½ = 0.3465 min

(iii) k = 4 / yrs.

=> t½ = 0.693/4

=> t½ = 0.17325 yrs.

Discussion

24.	-Q3 = How molar mass of a solute isdetermined with the help of elevation in boiling point.(formula only)
Answer» Explanation: Since 0.0869 moles of the SOLUTE has a mass of 10 GRAMS, 1 MOLE of the solute will have a mass of 10/0.0869 grams, which is equal to 115.07 grams. Therefore, the molar mass of the solute is 115.07 grams per mole...

24.

-Q3 = How molar mass of a solute isdetermined with the help of elevation in boiling point.(formula only)

Answer»

Explanation:

Since 0.0869 moles of the SOLUTE has a mass of 10 GRAMS, 1 MOLE of the solute will have a mass of 10/0.0869 grams, which is equal to 115.07 grams. Therefore, the molar mass of the solute is 115.07 grams per mole...

Discussion

25.	Equilibrium constant kc for reaction A=2B
Answer» EXPLANATION: AGA 29 wow mark BRAINLIEST

25.

Equilibrium constant kc for reaction A=2B

Answer»

EXPLANATION:

AGA 29

wow

mark BRAINLIEST

Discussion

26.	When the concentration is expressed as the number of moles of a solute per litre of solution it known as
Answer» ANSWER: Explanation: The concentration of a substance is the QUANTITY of solute PRESENT in a given quantity of SOLUTION. Concentrations are usually expressed in TERMS of molarity, defined as the number of moles of solute in 1 L of solution.

26.

When the concentration is expressed as the number of moles of a solute per litre of solution it known as

Answer»

ANSWER:

Explanation:

The concentration of a substance is the QUANTITY of solute PRESENT in a given quantity of SOLUTION. Concentrations are usually expressed in TERMS of molarity, defined as the number of moles of solute in 1 L of solution.

Discussion

27.	Ice having no water of crystalline ,.answer
Answer» ANSWER: I don't KNOW answer of this

27.

Ice having no water of crystalline ,.answer

Answer»

ANSWER:

I don't KNOW answer of this

Discussion

28.	How can solve this if number of miles of CO2 which contains 8.0g of oxygen
Answer» ANSWER: JUSTIFY your QUESTION

28.

How can solve this if number of miles of CO2 which contains 8.0g of oxygen

Answer»

ANSWER:

JUSTIFY your QUESTION

Discussion

29.	Solve this question? please guys...
Answer» ANSWER: I don't KNOW SORRY.....

29.

Solve this question? please guys...

Answer»

ANSWER:

I don't KNOW SORRY.....

Discussion

30.	How you confirm reactivity of metal
Answer» ANSWER: I confirm few METALS by changing of color. example:copper and etc

30.

How you confirm reactivity of metal

Answer»

ANSWER:

I confirm few METALS by changing of color.

example:copper and etc

Discussion

31.	When ammonium chloride is heated with caustic soda the gas evolved is .............................
Answer» ANSWER: HELIUM is the GAS you GET

31.

When ammonium chloride is heated with caustic soda the gas evolved is .............................

Answer»

ANSWER:

HELIUM is the GAS you GET

Discussion

32.	Atomic mass of sulphate
Answer» ANSWER: Explanation: 32

32.

Atomic mass of sulphate

Answer»

ANSWER:

Explanation:

32

Discussion

33.	Chemical test to distinguish an alkanol and an alkene
Answer» ANSWER: EXPLANATION: Bromine Reaction Another common test is the ADDITION of liquid bromine, which is brownish-purple in color. ... When you ADD bromine and water to a chemical and the color rapidly DISAPPEARS, it may contain an alkene that is reacting with the bromine.

33.

Chemical test to distinguish an alkanol and an alkene

Answer»

ANSWER:

EXPLANATION:

Bromine Reaction

Another common test is the ADDITION of liquid bromine, which is brownish-purple in color. ... When you ADD bromine and water to a chemical and the color rapidly DISAPPEARS, it may contain an alkene that is reacting with the bromine.

Discussion

34.	Why do we need to paint wooden doors and windows
Answer» Answer: The wooden doors and windows are painted because they are susceptible to the attack of moisture, dust and INSECT colonization LIKE termites. The termites EAT the wood and other insects use wood as a habitat for LAYING their eggs.

34.

Why do we need to paint wooden doors and windows

Answer»

Answer:

The wooden doors and windows are painted because they are susceptible to the attack of moisture, dust and INSECT colonization LIKE termites. The termites EAT the wood and other insects use wood as a habitat for LAYING their eggs.

Discussion

35.	Ogeledrangle sedistributed se leastNHStomally-CH2+ NH2(Z)The correct order of basic strength is(61) z>x>y, terapie (2) z>y>x34 x>y>z4) None of these
Answer» Explanation: GO to the link and LET me KNOW if it is HELPFUL for you.

35.

Ogeledrangle sedistributed se leastNHStomally-CH2+ NH2(Z)The correct order of basic strength is(61) z>x>y, terapie (2) z>y>x34 x>y>z4) None of these

Answer»

Explanation:

GO to the link and LET me KNOW if it is HELPFUL for you.

Discussion

36.	The density of 3M solution of NaCl is 1.25g/mL. Calculate the molality of the solution.
Answer» 3 MOLAR solution means there are 3 moles of NaCl SALT in 1 Liter. Molecular WEIGHT of NaCl = 58.44. Hence, there are 3×58.44 gms in 1 Litre of water. Density = volume mass Mass of 1 litre of solution = 1.25 gms/ml * 1000 ml = 1, 250 gms V = volume of water added to make the solution 175.32 gms + 1 gm /ml * V = 1, 250 gm ⟹V=1,074.68ml So 1,074.68 ml or 1, 074.68 gms of water is mixed with 3 moles of Na Cl to make the 3 M solution. Molality = mass of SOLUTE in number of moles / mass of solvent in kg = 1.07468 3 kg =2.7915 Molal

36.

The density of 3M solution of NaCl is 1.25g/mL. Calculate the molality of the solution.

Answer»

3 MOLAR solution means there are 3 moles of NaCl SALT in 1 Liter. Molecular WEIGHT of NaCl = 58.44.

Hence, there are 3×58.44 gms in 1 Litre of water.

Density =

volume

mass

Mass of 1 litre of solution = 1.25 gms/ml * 1000 ml = 1, 250 gms

V = volume of water added to make the solution

175.32 gms + 1 gm /ml * V = 1, 250 gm

⟹V=1,074.68ml

So 1,074.68 ml or 1, 074.68 gms of water is mixed with 3 moles of Na Cl to make the 3 M solution.

Molality = mass of SOLUTE in number of moles / mass of solvent in kg

=

1.07468

3

kg

=2.7915 Molal

Discussion

37.	Why do neither sodium chloride or chlorine conduct electricity when solid? I've been trying to find help online because its rather hard to get hold of my teacher right now. Thanks!
Answer» Answer: HEY dude.... in *the* *solid* *state* *the* *ionsof the* *crystal* *are* *not* *able* to *move* *freely* *while* in *case* of *molten* *state* *the* ions *are* *FREE* to *move* *this* *conduct* *electricity... PLEASE* *mark* *BRAINLIEST* *answer*....plz

37.

Why do neither sodium chloride or chlorine conduct electricity when solid? I've been trying to find help online because its rather hard to get hold of my teacher right now. Thanks!

Answer»

Answer:

HEY dude....

in the solid state the ionsof the crystal are not able to move freely while in case of molten state the ions are FREE to move this conduct electricity...

PLEASE mark BRAINLIEST answer....plz

Discussion

38.	Why sodium and potassium show +1 valency and chlorine shows -1 valency??
Answer» Sodium and POTASSIUM are SOLID bases but CHLORINE is acid acid are classified under NEGATIVE.

Discussion

39.	A base which is not a metallic oxide or hydroxide is ......................................
Answer» hey MATE here is ur answer a base which is not a metallic OXIDE or hydroxide is *ammonia. (NH3). hope* it HELPS. ☆☆☆

39.

A base which is not a metallic oxide or hydroxide is ......................................

Answer»

hey MATE here is ur answer

a base which is not a metallic OXIDE or hydroxide is

ammonia. (NH3).

hope it HELPS.

☆☆☆

Discussion

40.	Calculate the heat of combustion of etheneCH2 = CH2(q) + 3O2(g) ---> 2CO2(g) + 2H2O(l)The bond energy data are given below C=C = 619 kJ/ molC-H= 414 kJ/ molO=O = 499 kJ /molC=O = 724 kJ/ molO-H= 460 kJ /mol
Answer» ANSWER: if U FOLLOW me then I will follow u BACK and TELL your answer

40.

Calculate the heat of combustion of etheneCH2 = CH2(q) + 3O2(g) ---> 2CO2(g) + 2H2O(l)The bond energy data are given below C=C = 619 kJ/ molC-H= 414 kJ/ molO=O = 499 kJ /molC=O = 724 kJ/ molO-H= 460 kJ /mol

Answer»

ANSWER:

if U FOLLOW me then I will follow u BACK and TELL your answer

Discussion

41.	Column-11) Two bond pairs oncentral atom2) Four bond pairs on central atomColumn -IIP) Bond angle is 109° 28Q) Bond angle is 180°R) Bond angle is 120°is any one 10 in ap vzm means say hi to my fb account my user name is Akhil Akhilanand
Answer» Answer: 1.7pffp8o6d7fkyxcklykdxylllu 2.xtgldtifpfixupcluvlu 3.gsiyfl7du4xpivjtvilxjtbi 4 rOyf6oeo7tpa38gtkzkggxgoFigxy

41.

Column-11) Two bond pairs oncentral atom2) Four bond pairs on central atomColumn -IIP) Bond angle is 109° 28Q) Bond angle is 180°R) Bond angle is 120°is any one 10 in ap vzm means say hi to my fb account my user name is Akhil Akhilanand

Answer»

Answer:

1.7pffp8o6d7fkyxcklykdxylllu

2.xtgldtifpfixupcluvlu

3.gsiyfl7du4xpivjtvilxjtbi

4 rOyf6oeo7tpa38gtkzkggxgoFigxy

Discussion

42.	Q whyboilingpointof a liquid is increase when we add solute in it
Answer» Answer: cause the solute TAKES the heat in it so when it gets mixed with the LIQUID INCREASES it boiling point. pls mark the answer as the BRAINLIEST.

42.

Q whyboilingpointof a liquid is increase when we add solute in it

Answer»

Answer:

cause the solute TAKES the heat in it so when it gets mixed with the LIQUID INCREASES it boiling point.

pls mark the answer as the BRAINLIEST.

Discussion

43.	एक अभिक्रिया A के प्रति प्रथम तथा B के प्रति द्वितीय कोटि की है।(i) अवकल वेग समीकरण लिखिए। (ii) B की सांद्रता तीन गुनी करने से वेग पर क्या प्रभाव पड़ेगा?(iii) A तथा B दोनों की सांद्रता दुगुनी करने से वेग पर क्या प्रभाव पड़ेगा?
Answer» Explanation: djjdirirjrjirorndjdkfnhhhiyuh r d as I get off TILL the LAST ONE I got the job done and he SAID he was her to be for it

43.

एक अभिक्रिया A के प्रति प्रथम तथा B के प्रति द्वितीय कोटि की है।(i) अवकल वेग समीकरण लिखिए। (ii) B की सांद्रता तीन गुनी करने से वेग पर क्या प्रभाव पड़ेगा?(iii) A तथा B दोनों की सांद्रता दुगुनी करने से वेग पर क्या प्रभाव पड़ेगा?

Answer»

Explanation:

djjdirirjrjirorndjdkfnhhhiyuh r d as I get off TILL the LAST ONE I got the job done and he SAID he was her to be for it

Discussion

44.	डाईमेथिल ईथर के अपघटन से CH4, H2 तथा C0 बनते हैं। इस अभिक्रिया का वेग निम्न समीकरण द्वारा दिया जाता है-वेग =अभिक्रिया के वेग का अनुगमन बंद पात्र में बढ़ते दाब द्वारा किया जाता है, अत: वेग समीकरण को डाईमेथिल ईथर के आशिक दाब के पद में भी दिया जा सकता है। अत:वेग = k(P CH3, OCH3)(3/2)यदि दाब को bar में तथा समय को मिनट में मापा जाये तो अभिक्रिया के वेग एवं वेग स्थिरांक की इकाइयाँ क्या होंगी?
Answer» EXPLANATION: dhhdhdhdjdjjth you can come get it for me to go to the hospital with you GUYS are JK I'm sorry BABY GIRL and she was HWY up and I hug u so

44.

डाईमेथिल ईथर के अपघटन से CH4, H2 तथा C0 बनते हैं। इस अभिक्रिया का वेग निम्न समीकरण द्वारा दिया जाता है-वेग =अभिक्रिया के वेग का अनुगमन बंद पात्र में बढ़ते दाब द्वारा किया जाता है, अत: वेग समीकरण को डाईमेथिल ईथर के आशिक दाब के पद में भी दिया जा सकता है। अत:वेग = k(P CH3, OCH3)(3/2)यदि दाब को bar में तथा समय को मिनट में मापा जाये तो अभिक्रिया के वेग एवं वेग स्थिरांक की इकाइयाँ क्या होंगी?

Answer»

EXPLANATION:

dhhdhdhdjdjjth you can come get it for me to go to the hospital with you GUYS are JK I'm sorry BABY GIRL and she was HWY up and I hug u so

Discussion

45.	A और B के मध्य अभिक्रिया में A और B की विभिन्न प्रारंभिक सांद्रताओं के लिए प्रारंभिक वेग (r0) नीचे दिए गएA और B के प्रति अभिक्रिया की कोटि क्या है?
Answer» ANSWER: this is AANDB jsjjdjdkrk

45.

A और B के मध्य अभिक्रिया में A और B की विभिन्न प्रारंभिक सांद्रताओं के लिए प्रारंभिक वेग (r0) नीचे दिए गएA और B के प्रति अभिक्रिया की कोटि क्या है?

Answer»

ANSWER:

this is AANDB jsjjdjdkrk

Discussion

46.	किसी अभिक्रियक के लिए एक अभिक्रिया द्वितीय कोटि की है। अभिक्रिया का वेग कैसे प्रभावित होगा; यदि अभिक्रियक की सांद्रता(i) दुगुनी कर दी जाए (ii) आधी कर दी जाए
Answer» (i) - $r_1 = 4 \times r_{\circ}$ (II) - $r_1 = \frac{1}{4} \times r_{\circ}$ EXPLANATION: प्रश्न मे दिया हुआ है कि ; -अभिक्रिया द्वितीय कोटि की है अभिक्रिया का वेग $( r_{\circ} )= K {[A]^2$ (i) दुगुनी कर दी जाए ; $r_{1} = K {[2A]^2$ $\therefore$ $r_1 = 4 \times r_{\circ}$ (ii) आधी कर दी जाए ; $r_{2} = K {[\frac{A}{2}]^2$ $\therefore$ $r_1 = \frac{1}{4} \times r_{\circ}$

46.

किसी अभिक्रियक के लिए एक अभिक्रिया द्वितीय कोटि की है। अभिक्रिया का वेग कैसे प्रभावित होगा; यदि अभिक्रियक की सांद्रता(i) दुगुनी कर दी जाए (ii) आधी कर दी जाए

Answer»

(i) - $r_1 = 4 \times r_{\circ}$

(II) - $r_1 = \frac{1}{4} \times r_{\circ}$

EXPLANATION:

प्रश्न मे दिया हुआ है कि ;

-अभिक्रिया द्वितीय कोटि की है

अभिक्रिया का वेग $( r_{\circ} )= K {[A]^2$

(i) दुगुनी कर दी जाए ;

$r_{1} = K {[2A]^2$

$\therefore$ $r_1 = 4 \times r_{\circ}$

(ii) आधी कर दी जाए ;

$r_{2} = K {[\frac{A}{2}]^2$

$\therefore$ $r_1 = \frac{1}{4} \times r_{\circ}$

Discussion

47.	अभिक्रिया [tex]2A + B A_2B [/tex]के लिए वेग यहाँ k का मान है। प्रारंभिक वेगकी गणना कीजिए: जब एवं हो तथा अभिक्रिया वेग की गणना कीजिए: जब [A] घट कर रह जाए।
Answer» EXPLANATION: ndjjdjdjrjj d as d as I am not and BOY and H you KNOW I you know I LOVE

47.

अभिक्रिया [tex]2A + B A_2B [/tex]के लिए वेग यहाँ k का मान है। प्रारंभिक वेगकी गणना कीजिए: जब एवं हो तथा अभिक्रिया वेग की गणना कीजिए: जब [A] घट कर रह जाए।

Answer»

EXPLANATION:

ndjjdjdjrjj d as d as I am not and BOY and H you KNOW I you know I LOVE

Discussion

48.	एक प्रथम कोटि के जल-अपघटन के निम्नलिखित आँकड़े प्राप्त हुए-30 से 60 सेकेंड समय अंतराल में औसत वेग की गणना कीजिए।
Answer» can't UNDERSTAND LANGUAGE

Discussion

49.	प्लैटिनम सतह पर का अपघटन शून्य कोटि की अभिक्रिया है। N2 एवं H2 के उत्पादन की दर क्या होगी जब k का मान हो?
Answer» Answer: 12x57 Explanation:

49.

प्लैटिनम सतह पर का अपघटन शून्य कोटि की अभिक्रिया है। N2 एवं H2 के उत्पादन की दर क्या होगी जब k का मान हो?

Answer»

Answer:

12x57

Explanation:

Discussion

50.	Different between physical and chemical changes in four points
Answer» AnswerIn a chemical change, the molecular composition of a substance completely CHANGES and a NEW substance is FORMED. Some example of physical change are freezing of water, melting of wax, BOILING of water, ETC. ... In a physical change, no energy is produced. In a chemical change, energy is produced (heat, light, sound, etc.) Explanation:

50.

Different between physical and chemical changes in four points

Answer»

AnswerIn a chemical change, the molecular composition of a substance completely CHANGES and a NEW substance is FORMED. Some example of physical change are freezing of water, melting of wax, BOILING of water, ETC. ... In a physical change, no energy is produced. In a chemical change, energy is produced (heat, light, sound, etc.)

Explanation:

Discussion

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एक प्रथम कोटि की अभिक्रिया में 30% वियोजन होने में 40 मिनट लगते हैं। की गणना कीजिए।

वियोजन अभिक्रिया का = 78.12 MIN

स्थिर आयतन पर के प्रथम कोटि के ताप अपघटन पर निम्न आँकड़े प्राप्त हुए-अभिक्रिया वेग की गणना कीजिए जब कुल दाब 0.65 atm हो।

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Wt is electronic configuration of K4FeCN6​

List examples of some petroleum products which are used to prepare synthetic fibres

Hydrogen reacts with N2 to produce ammonia according to the equation N2 (g) + 3H2 (g) 2NH3 (g) Determine how much ammonia would be produced if 200 g of H2 reacts with excess of N2

Explain why magnesium fluoride has a high melting point and boiling point.

Write some characteristics of polides of matter any four

Calculate molarity of solutions prepared by mixing 500ml of 2.5M urea solution and 500ml of 2M urea solution

Answer:

Explanation:

Hence we get required answer.

Which among the following hydrides is not a reducing agent a .h2o b .h 2s c .h2te d.h2se​

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White coloured metal nitrate a on heating gives a yellow residue b along with evolution of a brown gas g and a colourless gas c

At what temperature do ammonia and carbon dioxide react to form urea?

Hi guys please say about use of ethanol ​

A solution of NaCl in water is .................................

नीचे दी गई प्रथम कोटि की अभिक्रियाओं के वेग स्थिरांक से अर्धायु की गणना कीजिए-

-Q3 = How molar mass of a solute isdetermined with the help of elevation in boiling point.(formula only)​

Equilibrium constant kc for reaction A=2B

When the concentration is expressed as the number of moles of a solute per litre of solution it known as

Ice having no water of crystalline ,.answer

How can solve this if number of miles of CO2 which contains 8.0g of oxygen

Solve this question? please guys...​

How you confirm reactivity of metal

When ammonium chloride is heated with caustic soda the gas evolved is .............................

Atomic mass of sulphate

Chemical test to distinguish an alkanol and an alkene

Why do we need to paint wooden doors and windows

Ogeledrangle sedistributed se leastNHStomally-CH2+ NH2(Z)The correct order of basic strength is(61) z>x>y, terapie (2) z>y>x34 x>y>z4) None of these​

The density of 3M solution of NaCl is 1.25g/mL. Calculate the molality of the solution.​

Why do neither sodium chloride or chlorine conduct electricity when solid? I've been trying to find help online because its rather hard to get hold of my teacher right now. Thanks!

Why sodium and potassium show +1 valency and chlorine shows -1 valency??​

A base which is not a metallic oxide or hydroxide is ......................................

Calculate the heat of combustion of etheneCH2 = CH2(q) + 3O2(g) ---> 2CO2(g) + 2H2O(l)The bond energy data are given below C=C = 619 kJ/ molC-H= 414 kJ/ molO=O = 499 kJ /molC=O = 724 kJ/ molO-H= 460 kJ /mol​

Column-11) Two bond pairs oncentral atom2) Four bond pairs on central atomColumn -IIP) Bond angle is 109° 28Q) Bond angle is 180°R) Bond angle is 120°is any one 10 in ap vzm means say hi to my fb account my user name is Akhil Akhilanand​

Q whyboilingpointof a liquid is increase when we add solute in it​

(i) -

(II) -

एक प्रथम कोटि के जल-अपघटन के निम्नलिखित आँकड़े प्राप्त हुए-30 से 60 सेकेंड समय अंतराल में औसत वेग की गणना कीजिए।

प्लैटिनम सतह पर का अपघटन शून्य कोटि की अभिक्रिया है। N2 एवं H2 के उत्पादन की दर क्या होगी जब k का मान हो?

Different between physical and chemical changes in four points

वियोजन अभिक्रिया का $t_{\frac{1}{2}}$ = 78.12 MIN

Wt is electronic configuration of K4FeCN6

Which among the following hydrides is not a reducing agent a .h2o b .h 2s c .h2te d.h2se

Hi guys please say about use of ethanol

-Q3 = How molar mass of a solute isdetermined with the help of elevation in boiling point.(formula only)

Solve this question? please guys...

Ogeledrangle sedistributed se leastNHStomally-CH2+ NH2(Z)The correct order of basic strength is(61) z>x>y, terapie (2) z>y>x34 x>y>z4) None of these

The density of 3M solution of NaCl is 1.25g/mL. Calculate the molality of the solution.

Why sodium and potassium show +1 valency and chlorine shows -1 valency??

Calculate the heat of combustion of etheneCH2 = CH2(q) + 3O2(g) ---> 2CO2(g) + 2H2O(l)The bond energy data are given below C=C = 619 kJ/ molC-H= 414 kJ/ molO=O = 499 kJ /molC=O = 724 kJ/ molO-H= 460 kJ /mol

Column-11) Two bond pairs oncentral atom2) Four bond pairs on central atomColumn -IIP) Bond angle is 109° 28Q) Bond angle is 180°R) Bond angle is 120°is any one 10 in ap vzm means say hi to my fb account my user name is Akhil Akhilanand

Q whyboilingpointof a liquid is increase when we add solute in it

(i) - $r_1 = 4 \times r_{\circ}$

(II) - $r_1 = \frac{1}{4} \times r_{\circ}$