नीचे दी गई प्रथम कोटि की अभ�

1.	नीचे दी गई प्रथम कोटि की अभिक्रियाओं के वेग स्थिरांक से अर्धायु की गणना कीजिए-
Answer» Answer: $\large\boxed{\sf{(i)\;3.465\times{10}^{-3}\:s}}$ $\large\boxed{\sf{(ii)\;0.3465\;min}}$ $\large\boxed{\sf{(<klux>III</klux>)\;0.17325\;yrs}}$ EXPLANATION: First of all, let's understand the meaning of question in english. प्रथम कोटि = First Order अभिक्रियाओं = Reactions वेग स्थिरांक = Rate constants (K) अर्धायु = Half life ( t½ ) Given that, different VALUES of rate constants (k) for a first order reaction. To find the values of half lives, t½. But, we know that, t½ = 0.693/k Therefore, we will GET, (i) k = 200 /s => t½ = 0.693/200 => t½ = $3.465\times{10}^{-3}\:s$ (ii) k = 2 / min => t½ = 0.693/2 => t½ = 0.3465 min (iii) k = 4 / yrs. => t½ = 0.693/4 => t½ = 0.17325 yrs.

नीचे दी गई प्रथम कोटि की अभिक्रियाओं के वेग स्थिरांक से अर्धायु की गणना कीजिए-

Answer»

Answer:

$\large\boxed{\sf{(i)\;3.465\times{10}^{-3}\:s}}$

$\large\boxed{\sf{(ii)\;0.3465\;min}}$

$\large\boxed{\sf{(<klux>III</klux>)\;0.17325\;yrs}}$

First of all, let's understand the meaning of question in english.

Given that, different VALUES of rate constants (k) for a first order reaction.

To find the values of half lives, t½.

But, we know that,

Therefore, we will GET,

(i) k = 200 /s

=> t½ = 0.693/200

=> t½ = $3.465\times{10}^{-3}\:s$

(ii) k = 2 / min

=> t½ = 0.693/2

=> t½ = 0.3465 min

(iii) k = 4 / yrs.

=> t½ = 0.693/4

=> t½ = 0.17325 yrs.