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In the the EQUATION you said that Zn and goes zn + 2 its MEAN Zn and releasing the ELECTRON so electron goes from Zn to AG

In case of sodium metal ETHANOL and ethanoic acid both will SHOW changes but in case of SOAP there would be no change as it SELF it is a sodium salt.
And for litmus test ethanoic acid will turn blue litmus RED , ethanol will be neutral and for soap solution it will be basic or i should say it will turn red litmus blue

The primary difference between diamond and graphite is the way their carbon atoms are arranged to form their physical crystal structures. The arrangement of carbon atoms in diamonds makes them bond together strongly, while graphite atoms are HELD together with a weaker bond, creating a soft physical substance.

Diamond molecules are shaped like perfect tetrahedra and are held together by SINGLE atoms forming strong bonds to four other atoms. Their shape makes diamond EXTRA hard and durable to resist compression and broken bonds.

Graphite molecules consist of a single carbon atom attached to three others and gather together with others to form SHEETS of molecules. Though individual graphite molecules are strongly bonded, the sheets they form are weak and EASILY broken apart.





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SYMMETRY POINT GROUPS of H3BO3

HEY!

Here is your ANSWER

Answer:- work = -2496 J

Solution:- The balanced equation for the reaction of zinc with HCl is:

GIVEN grams of Zn are CONVERTED to moles. Moles of hydrogen gas formed will ALSO be equal as there is 1:1 mol ratio between zinc and hydrogen.

=

From FIRST law of thermodynamics,  .....(1)

From an ideal gas law equation, PV = nRT    

So,    ---------(2)

From equation 1 and 2:

From above calculation, is 1 mol.

T = 300 K

R =

Let's plug in the values in the equation:

w = -24.63 atm.L

Since, 1 atm.L = 101.325 J

So,  

w = -2495.63 J or it is almost -2496 J

The negative sign indicates the work done by the system which is also clear as the gas is formed means there is expansion in volume.

So, the work done is -2496 J.

When TEMPERATURE changes the KINETIC energy of the molecules changes due to this molecular cross-section AL area of GASES changes.

✔✔ Hello mate ✔✔

here's your answer  

Molality is CONSIDERED BETTER for expressing the concentration as COMPARED to molarity because the molarity changes with temperature because of expansion or contraction of the LIQUID with temperature.But molality does not changes with temperature because the mass of the SOLVENT does not change with change in temperature.

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Hope it helps you

The halogen atoms have 3 PAIRS of electrons

so they donate it to benzene ring nd the donating group is ORTHO nd PARA directing .....

Because its MOLECULES are in HIGH MOTION

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Here is u r Ans ➡

✔The air REFRIGERATION SYSTEM WORKS on Bell-Coleman cycle. Assumptions:

1) The compression and expansion processes are reversible adiabatic processes.

2) There is a perfect inter-cooling in the heat exchanger.

3) There are no pressure LOSSES in the system.

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The answer is 3 option bcoz after some time there is an equilibrium between these two processes
and hence the conc. of I2 GAS appears to be CONSTANT

The HYDROGEN STORAGE in composite tanks not in metal hydrides because the high DENSITY hydrogen storage in metal hydride composites with the AIR.

= h/√2 X m x K.E.

= 6.626 x 1-34Js / √ 2 x 9.1 x 10-31kg x 150 x 1.6 x 10-19 J   = 6.626 x 10-34 / √4368 x 10-50 = 10–10 m = 1 Å  

Temperature is never INDEPENDENT of axial position UNLIKE the velocity profile situation.  For thermally fully DEVELOPED flow, the temperature profile continues to change continuously even variation in this DIRECTION has been assumed.

Chemical fibres are fibres PRODUCED in the laboratory that mimic the FUNCTION of daily use natural fibres. They are generally made from several long chain esters and are usually hydrocarbons in composition.

The main economic aspects of USING chemical fibres are as follows:

1. Easy to produce and so are cheaper.

2. REPLACE labour required for picking natural fibres.

3. Increase EXPORT capabilities of the country.

K.E=Ze22r

P.E=−Ze2r

∴P.E=−2K.E

∴K.EP.E=−1/2

Explanation:

Addition reactions are defined as the reactions in which one MOLECULE combines with another molecule to PRODUCE one larger molecule with no other products.

In this question, we need to write the chemical EQUATION which leads us to the formation of 3-methyl-3-hexanol.

The chemical reaction in which 3-methyl-3-hexene is combining with water molecule will GIVE us the product as asked in the question.

The STRUCTURES are drawn in the image attached.

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Let me give you a Summary of Electrolysis of Copper Sulfate

Here you go..✌

Whenever copper sulfate or CuSO4 is added to water, it gets dissolved in the water. As the CuSO4 is an electrolyte, it splits into Cu+ + (cation) and SO4 − − (anion) ions and move freely in the solution. electrolyte copper sulphate

Now we will immerse two copper electrodes in that solution. The Cu+ + ions (cation) will be attracted towards cathode i.e. the electrode connected to the negative terminal of the battery.

On reaching on the cathode, each Cu+ + ION will take electrons from it and becomes neutral copper atoms. Similarly the SO4 − − (anion) ions will be attracted by anode i.e. the electrode connected to the positive terminal of the battery.

So SO4 − − ions will move towards anode where they give up two electrons and BECOME SO4 RADICAL.

But SINCE SO4 radical can not exist in the electrical neutral state, it will attack copper anode and will FORM copper sulfate. In the above process, after taking electrons the neutral copper atoms get deposited on the cathode. At the same time, SO4 reacts with copper anode and becomes CuSO4 but in water it can not exist as single molecules instead of that CuSO4 will split into Cu+ +, SO4 − − and dissolve in water. So it can be concluded that, during electrolysis of copper sulfate with copper electrodes, copper is deposited on cathode and same amount of copper is removed from anode

➠Some Hints:  

★It's Cu+2 which is responsible for blue colour.

★Reduction always occur in Cathode...Oxidation will occur at Anode.

★Gaining of electron is called Reduction And Losing of electron is called Oxidation.

With these Hints and Summary Try to answer different questions.

IF ANY DOUBTS FEEL FREE TO ASK IN COMMENT BOX

Hope it Helpz

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THANK YOU

It SHOWS that ARHAR DAL have some REACTION

Water cannot be used as a solvent for ir spectroscopy because:
1- Water has two STRONG infrared absorption peaks.

2- Water is a strongly POLAR solvent that dissolves the ALKALI HALIDE DISKS commonly used for IR.

MARK BRAINLIEST...

Butter is a COLLOID of LIQUID and solid where solid is the dispersed phase and liquid is the dispersion medium...
HOPE THIS HELPS YOU FRIEND :)

1.Iron FE 2, 3

2.Tin SN 2, 4

3.Lead PB 2, 4

I 2

will be PRODUCE ...

1 mole of SO2 = 64g

1g of SO2 = -----mole?

= 1/64 mole

From the given data 1/64 MOLES SULPHUR dioxide CONTAIN x molecules

We know that equal moles of all gases will have equal NUMBER of molecules.

Hence 1/64 moles of Methane Contains x molecules of methane

Now we should find out  the number of moles in 1g of methane

1 mole of methane = 16g

1g of methane = ------Mole?

 = 1/16 mole

Since, 1/64 mole of methane = x molecules

1/16 mole of methane contains = -------molecules?

= x * 64/16 =  4x molecules

Method 1

3 molecules of acetylene when pass through red hot TUBE under 873 K

Method 2

Sodium benzoate HEATED with CaO

Benzene not act as ALKENES due to delocalisation of electrons.

This happens because of incomplete combustion of the saturated hydrocarbon in the AIR. ... The flame is sooty because the PERCENTAGE of carbon is comparatively HIGHER than that of ALKANES and so does not get COMPLETELY oxidized in air. However, when acetylene and pure oxygen burn, a non-sooty, blue flame is produced

It MAKE the lead CONTROL ,REMOVAL of iron and MAGNESIUM ,COLOUR removal and for tast

Malleability is ability of METALS to be beaten into sheets.

DUCTILITY is the ability of metals to be ABLE to drawn into wires.

Hey MATE SORRY i dont know this ANSWER.....

I HOPE that you will be UNDERSTAND

The simplest organic compounds are the HYDROCARBONS, which contain onlycarbon and hydrogen. ALKANES contain only carbon–hydrogen and carbon–carbon single bonds, ALKENES contain at least ONE carbon–carbon double BOND, and alkynes contain one or morecarbon–carbon triple bonds