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This section includes 7 InterviewSolutions, each offering curated multiple-choice questions to sharpen your Current Affairs knowledge and support exam preparation. Choose a topic below to get started.
| 1. |
In hoffman bromamide reaction an amide is converted to what?? |
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Answer» Answer: Explanation: |
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| 2. |
फेरस अमोनियम सल्फेट का निर्माण कर जाँच के लिए प्रस्तुत करें। |
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Answer» The layer of soil which is just below the top-soil is CALLED B-horizon. It is also known as sub-soil. The sub-soil is made up of SLIGHTLY bigger rock particles than that of top-soil. ... The sub-soil has very LITTLE humus (decayed organic MATTER). |
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| 3. |
The densely packed core in an atom |
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Answer» The nucleus is the TINY, dense, central core of the atom and is COMPOSED of protons and neutrons. Rutherford's atomic model became KNOWN as the nuclear model. In the nuclear atom, the protons and neutrons, which comprise nearly all of the mass of the atom, are located in the nucleus at the center of the atom. |
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| 4. |
Name the two metals that can be reduced by hydrogen. |
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Answer» Explanation: It has found commercial application for the synthesis of platinum group metals, some rare metals such as GERMANIUM and rhenium, and for the production of SPECIAL grades of metals (e.g., fine nickel and cobalt powders) HOWEVER, hydrogen is primarily APPLIED for the synthesis of TUNGSTEN and molyb- denum |
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| 6. |
Given that X,Y,Z are triads.Atomic masses of x and z 32125 respectively then what is the atomic mass of y |
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Answer» PLZ ........... |
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| 7. |
Q7. Which of the following is largest in size? *(a) Cl⁻(b) S²⁻(c) Na⁺(d) F⁻ |
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Answer»
SULPHUR S²- S²->Cl¹->F¹->NA+ |
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| 8. |
B) what happens when a hot salurated solution is casted ? |
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Answer» When a hot saturated solution is COOLED, then some of its dissolved SOLUTES will SEPARATE out in the FORM of solid CRYSTALS. |
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| 9. |
A compound on analysis was found to contain C= 54. 24% H= 9.05% and O= 36.7 81% calculate empirical formula and Molecular formulas molecular formulas mass =88 u |
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Answer» Answer: Find the empirical formula. Get the mass of each element by ASSUMING a certain overall mass for the sample (100 G is a GOOD mass to assume when working with percentages). ... Convert the mass of each element to moles. ... Find the ratio of the moles of each element. ... |
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| 10. |
Please help please please please please |
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Answer» oh L KNOW but pls MARK me BRAINLIEST first |
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| 11. |
Define the term atomic number/mass number |
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Answer» Answer:
Explanation: hope helps you.. |
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| 12. |
What is the state flower of Haryana?A. LotusB. RhododendronC. Golden ShowerD. Not declared |
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Answer» What is the STATE FLOWER of HARYANA? A. Lotus✅B. Rhododendron C. GOLDEN Shower D. Not DECLARED |
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| 13. |
C5H10 ka galnank aur kwathnank C4H8 se adhik kyu hota hai ? |
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Answer» Answer: 2n-2 Explanation: C5H10-Alkene C4H8-Alkyne |
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| 14. |
Design an experiment ti demonstarte hydrotropism |
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Answer» •Take two BEAKERS 1 and 2. •In beaker 1 add moist soil and sow the seeds. •In beaker 2 add dry soil in one part and moist soil in another part and sow the seeds. Also, PLACE a small beaker of water just adjacent to it. •Keep it for some time so that the plants can grow. please MARK as BRAINLIEST ❤️❤️❤️❤️...nd follow me |
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| 15. |
How many different IUPAC names can be assigned to compound with molecular formula C7H8O with a phenyl ring along its compounds. |
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Answer» phenylhydroxymethane benzylalcohol |
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| 16. |
Sweetiepie07 are u active?? |
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Answer» sssssss but noooooooo |
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| 17. |
O2)3d63d5.ঘ. উদ্দীপকের ২য় দ্রবণে বিকারক যােগ করে প্রাপ্ত।অধঃক্ষেপটির দ্রাব্যতা নির্ণয়ের পদ্ধতি বিশ্লেষণ।করাে। [25°C তাপমাত্রায় K০ = 4.5 x 10®2]NHOHআয়ন:দ্ররণবিকারক১ম দ্রবণক. হুণ্ডের নিয়ম লেখাে।সম আয়ন প্রভাবের ফলে দ্রাব্যতা হ্রাস পায় কেন?গ. উদ্দীপকের বিকারক ব্যবহার করে ১ম ও ২য় দ্রবণেথাকা আয়নদ্বয় কীরূপে সনাক্ত করবে, তা সংশ্লিষ্টসমীকরণসহ লেখাে।২য় দ্রবণখ.2000তবের দাব্যতা |
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Answer» দ্রাব্যতা পদার্থের একটি ভৌত ধর্ম। কোন নির্দিষ্ট তাপমাত্রায় নির্দিষ্ট পরিমাণ দ্রাবককে সম্পৃক্ত দ্রবণে পরিণত করতে যে পরিমান দ্রব দ্রবীভূত করতে হয় তাকেই ঐ তাপমাত্রায় ঐ দ্রবের দ্রাব্যতা বলে। কোন পদার্থের দ্রাব্যতা প্রকৃতপক্ষে ব্যবহৃত দ্রাবক, তাপমাত্রা ও চাপের উপর নির্ভর করে। তাপমাত্রার মত চাপও দ্রবণকে প্রভাবিত করে, সেটা তরল হোক বা বায়বীয়ই হোক। তাই দ্রাব্যতার সংজ্ঞা দেওয়ার সময় একটি নির্দিষ্ট তাপমাত্রা ও চাপ উল্লেখ করা হয়। দ্রাব্যতা প্রকাশ করা হয় ঘনমাত্রা প্রকাশের বিভিন্ন একক (মোলারিটি, মোলালিটি, নরমালিটি ইত্যাদি) দ্বারা। কারণ দ্রাব্যতা মূলত কোন দ্রবণে দ্রবের সর্বোচ্চ ঘনমাত্রাকেই প্রকাশ করে । দ্রাব্যতা একটি আনুপাতিক রাশি । এর কোন একক নেই। যেমনঃ ৩৫ ডিগ্রি তাপমাত্রায় KNO3 এর দ্রাব্যতা হল 60 তাহলে বোঝা যাবে যে ঐ তাপমাত্রায় 100G পানিতে সর্বাধিক 60G KNO3 দ্রবীভূত হয়ে দ্রবণ উৎপন্ন করবে । |
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| 18. |
Na requires how much energy to form its cation |
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Answer» Answer: The energy needed to remove one or more electrons from a neutral atom to FORM a positively charged ion is a physical property that influences the chemical behavior of the atom. By definition, the first ionization energy of an element is the energy needed to remove the OUTERMOST, or highest energy, electron from a neutral atom in the gas phase. Explanation: The magnitude of the first ionization energy of hydrogen can be BROUGHT into perspective by comparing it with the energy given off in a chemical reaction. When we burn natural gas, about 800 kJ of energy is released per mole of METHANE consumed. CH4(g) + 2 O2(g) -----> CO2(g) + 2 H2O(g) deltaHo = -802.4 kJ/mol The thermite reaction, which is used to weld iron rails, gives off about 850 kJ of energy per mole of iron oxide consumed. Fe2O3(s) + 2 Al(s) -----> Al2O3(s) + 2 Fe(l) deltaHo = -851.5 kJ/mol The first ionization energy of hydrogen is half again as large as the energy given off in either of these reactions. |
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| 19. |
The valency shell electronic configuration of an element in its first excited state is 3s1 3p3 3d1. To which block the element belongs |
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Answer» PJ xsphvqx qsvxuqsxpj hbce, s, , sqbp, sqsxjlevqu |
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| 20. |
Why should magnesium ribbon be cleaned before burning ? |
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Answer» Answer: Magnesium RIBBON should be cleaned with sandpaper before BURNING in the AIR. ... To remove the Magnesium oxide layer from the ribbon which MAY prevent or slow down the burning of magnesium ribbon. Unwanted IMPURITIES deposited on the magnesium ribbon can be removed and only pure magnesium can be used for the reaction. |
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| 22. |
State the radioactive decay law |
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Answer» Answer: The radioactive DECAY law states that the probability PER unit time that a nucleus will decay is a constant, independent of time. This constant is called the decay constant and is DENOTED by λ, “LAMBDA”. Explanation: |
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| 23. |
Create a comic strip on any topic from ch 5 coal and petroleum |
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| 24. |
এ্যাসাইনমেন্ট/নির্ধারিত কাজপ্রশ্ন ১: পৃথিবীতে অসংখ্য ভাইরাস, ব্যাক্টেরিয়া, ছত্রাক ও এন্টামিবা আছে। এদের সবারগঠন ও বৈশিষ্ট্য এক রকম নয়। এদের মধ্যে প্রকৃতিতে কিছু ভাইরাস ও ব্যাক্টেরিয়া মানুষের |
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Answer» Answer: jdjdjd the natural LANDSCAPE the natural the natural Landscape the FOLLOWING INFORMATION about our products are ADVERTISED and I will send it |
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| 25. |
निम्नलिखित में से कौन ढलवाँ लोहा (Pig Iron) में प्रमुख अशुद्धि के रूप में उपस्थित रहता है |
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Answer» ................. |
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| 26. |
The relationship between standard reduction potenial of a cell and equilibrium constant is shown by |
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Answer» where E* is standard reduction POTENTIAL |
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| 27. |
A fraction's value is 4/5. When its numeratoris increased by 9, the new fraction equalsthe reciprocal of the value of the originalfraction. Find the original fraction |
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Answer» If the NUMERATOR of a fraction is increased by 2 and the DENOMINATOR is increased by 3 the fraction becomes 79 |
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| 28. |
The correct IUPAC name of the compound CH3 – CH2 – CH2 – OHa) Propan – 1 – ol b) Propan – 1 – al c) Pentan – 1 – ol d) Pentan – 1 – al |
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| 29. |
Calculate the empirical and molecular formula of a compound containing carbon, 6.38%hydrogen and rest oxygen it's vapour density is 47. |
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Answer» Here is your answer: You MISSED the COMPOSITION of carbon I have did this question in 11th Carbon % = 76.5% Hydrogen% = 6.38% Oxygen% = 100 - (76.5 + 6.38)
= 100 - 82.88 = 17.12% Now DIVIDE the percentage composition by the atomic mass of the element For carbon: 76.5/12 = 6.38 For hydrogen: 6.38/1 = 6.38 For oxygen: 17.12/16 = 1.07 Now divide the answers you got to the least composition to a rough and nearest integer: For carbon: 6.38/1.07 = 6 For Hydrogen: 6.38/1.07 = 6 For Oxygen: 1.07/1.07 = 1 Empirical Formula is C₆H₆O. Empirical Formula Mass = 12 × 6 + 1 × 6 + 16 = 94 g Molecular Mass = 2 × Vapor Density ∴ Molecular Mass = 2 × 47 ∴ Molecular Mass = 94 g. ∴ n = Molecular Mass/Empirical Formula Mass = 94/94 = 1 ∴ Molecular Formula = 1 × C₆H₆O = C₆H₆O Please mark me BRAINLIEST |
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| 30. |
Please solve Thermodynamics q(24,25,26) |
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Answer» Answer: sorry Explanation: we can't draw anything in TEXT |
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| 31. |
A physical change is temporary and reverisble ... true / false |
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Answer» Answer: the answer is true mate... hope it helps..... A physical CHANGE is a change to a sample of matter in which some properties of the material change, but the IDENTITY of the matter does not. In a reversible physical change, the original form of the matter can be RESTORED. In an irreversible physical change, the original form cannot be restored. have a nice DAY~!! |
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| 32. |
Name one negative catalyst containing phosphorous |
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Answer» Answer: Example. Phosphoric acid acts as a negative CATALYST to DECREASE the rate of the decomposition of HYDROGEN peroxide. Alcohol too acts as a negative catalyst in CERTAIN chemical REACTIONS. |
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| 33. |
Which one of the following is correct order of atomic size |
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Answer» Hey Explanation: PLEASE follow only 2 followers please MARK as BRAINLIEST |
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| 34. |
State and explane law of conservation of mass |
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Answer» Explanation: The LAW of Conservation of Mass DATES from Antoine Lavoisier's 1789 discovery that mass is neither created nor destroyed in chemical REACTIONS. In other words, the mass of any ONE element at the beginning of a REACTION will equal the mass of that element at the end of the reaction. |
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| 35. |
(c) Cu, d, 2A metal M shows variable valencies 2 and 3.Calculate the ratio of oxygen atoms present in theircorresponding sulphates.(a) 1:3(6) 3:1(c) 3:4(d) 3:21.ide |
Answer» ANSWERExplanation: ANSWER IS A) 1:3 LET the m be x XSO4 and X2SO4it is 4:12 EVALUATE then it will COME 1:3 MARK AS BRAINLIEST ANSWER AND FOLLOW ME |
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| 36. |
The energy change in kilojoules per mole when lithium atoms lose an electron to bromine atoms to form isolated Li+ and Br- ions. [The Ei for Li(g) is +520 kJ/mol; the Eea for Br(g) is -325 kJ/mol.] |
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| 38. |
Q.Oxidation state of Pt in [Pt(NH3)2(bpy)(ox)]Cl2 is 1. +22. +33. +44. 0 |
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Answer» Explanation: |
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| 39. |
4. Explain the dot structure of Oxygen. |
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Answer» PLEASE FOLLOW me okkkkkkkkkkkkkkkkkkkkkkkkkkkkkkkkkkkkkkkkkkk |
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| 40. |
OSMAleDare to be DIFFERENTis UNIQUE.the vol ofCalentateconvertdir containing 210.he Sulphur biodide under the sameconditions)canbe obtained from logopotassium chlorate.of polas)) میH.W2of oxygen bey vol at STP required to9 s/what vol of oxygen at 18°c 4 450mm294 cms of so. (Sulphiese dionice |
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Answer» QUESTION is not UNDERSTOOD |
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| 41. |
The pH of an aqueous solution of H2 S o4 is 2. the molarity of the solution is(A)0.01M(B)0.005M(C)0.05M(D)0.1M |
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Answer» d. 0.1M ...............,............ |
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| 43. |
What hairstyle should I getI need options and pictures of hairstyles if you answer my question!I will give free points and I might mark you brainliest |
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Answer» I think that you need to one side CUT because it is a starting hairstyle and after four five times then two side on this side. in this hairstyle you need combination of black shirt, black TIE, black JEANS, and black shoes. thanks...... |
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| 44. |
Which equation is balanced?A). Mg + O2--> 2MgOB). 2Al + 3O2--> Al2O3C). 2Al + F2--> 2AlF3D). 2Na + F2--> 2NaFPlease answer correctly and I will give you brainliest. Please answer if you are from K12 |
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Answer» D is the balanced equation |
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| 45. |
Carbon can not form C⁴⁺ and C⁴⁻ . give reason. |
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Answer» Answer: Carbon is UNABLE to form C4- anion as its nucleus with six protons will not be able to hold ten electrons. Thus carbon achieves noble GAS electronic configuration by sharing its four electrons with other elements, i.e. it FORMS covalent COMPOUNDS. |
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| 46. |
describe an activity to show the water of crystallization with aim,material required,procedure,observation,conclusion. |
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Answer» Answer: C6H8O7 + 3NaHCO3 →Na3C6H5O7 + 3H2CO3H2CO3 → CO2 + H2O Explanation: Aim : To prepare beet root indicator and test for acidity/basicity of the compounds Material REQUIRED: Beet root, vinegar, baking soda Procedure : A) Preparation of beet root indicator i) Take beet root and crush it in a mortar. ii) Add water to the crushed beet root to OBTAIN an extract and filter off the extract to get the filtrate. The filtrate obtained is the beet root indicator. This is red in colour and is acidic in nature. B) Test for the acid or basic nature of the compounds ( vinegar , baking soda) i) Vinegar and baking soda were added in test tubes A and B respectively. ii) To each of the test tube few drops of beet root indicator was added and colour change was observed. Observations : Test tube A containing vinegar - No colour change Test tube B containing baking soda - Colour changed to yellow Conclusion : Since the colour of the test tube A did not changed , vinegar is acidic in nature. While , the colour of the test tube B changed from red to yellow , baking soda is basic in nature. 2) Aim : Neutralisation of lemon juice with baking powder Materials Required : Lemon juice , baking powder Note : Lemon juice is acidic in nature because it contains citric acid (C6H8O7) and is acidic, while baking powder is basic in nature because it contains sodium bicarbonate (NaHCO3) Procedure: i) Take lemon juice in a beaker. ii) To it slowly add baking soda. iii) Neutralisation REACTION starts with formation of bubbles. iv) Add baking powder slowly till no more formation of bubbles happen. Observation : Effervescence produced due to the formation of CO2. Conclusion: Formation of bubbles is due to formation of carbonic acid which is unstable and dissociates into carbon dioxide and water which is the cause of bubble formation.The neutralisation reaction is taking PLACE which is as follows: C6H8O7 + 3NaHCO3 →Na3C6H5O7 + 3H2CO3H2CO3 → CO2 + H2O |
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| 47. |
৯ পরিস্থিতিতে ২০২০ শিক্ষাবর্ষে পুর্নবিন্যাসকৃত পাঠ্যসূচির ভিত্তিতে এ্যাসাইনমেন্ট। নির্ধারিত কাজ ও মূল্যায়ন নির্দেশশ্রেণি: নবমবিষয়: রসায়নএ্যাসাইনমেন্ট/নির্ধারিত কাজনির্ধারিতকাজ-১। অ্যাসাইনমেন্ট-১; হাতে কলমে কাজের মাধ্যমে খাদ্য লবণ ও বালুর মিশ্রণ থেকেউপাদানসমূহ পৃথক কর এবং নিমের প্রশ্নগুলাের উত্তর দাও1:১। এ পরীক্ষণে কোন কোন পদ্ধতি ব্যবহার করা হয়েছে?২। কাজের ধারাবাহিক বর্ণনা কর।৩। পরীক্ষণের উপর তােমার পর্যবেক্ষণ ও সিদ্ধান্ত ব্যাখ্যা কর।৪। এ পরীক্ষণে তুমি কী কী সাবধানতা অবলম্বন করেছ? |
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Answer»
pls follow me and MARK me as BRANLIEST pls And GIVE me thanks |
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| 48. |
How many electron can be filt in the orbital for which n=3,R=1 |
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| 49. |
Why is NH₄Cl Ionic bond even when there is no transfer of electrons between NH₄⁺ and Cl⁻ |
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| 50. |
Which pair of elements described by the proton number will react together exothermicallya) 2 and 8b) 12 and 16c) 3 and 10d) 19 and 9 |
Answer» ANSWER:b)12 and 16EXPLANATION:Explanation: since proton number 10 is for an UNREACTIVE noble gas because both are 2+&2- ,so the overall CHARGE is greater than the rest |
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