This section includes 7 InterviewSolutions, each offering curated multiple-choice questions to sharpen your Current Affairs knowledge and support exam preparation. Choose a topic below to get started.
| 1. |
Write reactions to justify amphoteric nature of aluminium |
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Answer» Explanation:Reaction of aluminium with HCl and Naoh.both the reaction gives RISE to SALT and water |
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| 2. |
State the main advantages of using natural gas |
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Answer» ear advantages to natural gas are as follows: Natural gas is environmentally friendly because it BURNS cleaner than other fossil fuels. It's safer and easier to STORE when compared to other fossil fuels. Natural gas is extremely RELIABLE, UNLIKE electric power that can be knocked out during a storm.itzDopeGirl |
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| 3. |
Kmmo3 + m2so4 - k2so4 +mmso4 + m2so4. Balance the equation. |
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| 5. |
The nucleus of an atom consists of A. electrons and neutronsB. electrons and protonsC. protons and neutronsD. All of the above |
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Answer» C.Protons and NeutronsHope it HELPS you.Plz MARK me down the BRAINLIEST plzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzz |
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| 6. |
Pb +Cucl2_x+y balance the equation |
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Answer» X=pbcl2+y=cuExplanation: |
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| 7. |
Write the chemical names of the following compounds Answer all questions fast and first answer will mark as brainliest. |
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Answer» i'm not surepotassium carbonstemanaganese borate SODIUM hexa cyano ferrate(2)SILVER sulphitesodium silicateExplanation: |
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| 8. |
Two example of sublimate |
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Answer» s of SUBLIMATION: "DRY ice" or SOLID CARBON dioxide sublimes.itzDopeGirl |
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| 9. |
Why do we need to regulate the temperature at 373K during manufacture of Plaster of Paris? Also explain the process of its manufacture with the help of an equation.\ |
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Answer» Brainly.inWhat is your question?1boorgalavinay253908.09.2018ScienceSecondary School+5 ptsAnsweredExplain the preparation of PLASTER of Paris with the help of balanced chemical equation2SEE ANSWERSLog in to add commentAnswers chandraprakash05chandraprakash05 ExpertWhen the gypsum is heated on 373°k it convert into plaster of Paris CaSO4. 2H2O +energy 373°k =CaSO4. 1/2H2O+3/2H2OAnswer by cp4.834 votesTHANKS 60Comments Report prmkulk1978prmkulk1978 AcePlaster of Paris is also known as Calcium SULPHATE hemihydrated salt with chemical formula CaSO4.1/2H2OPreparation METHOD :Plaster of Paris is prepared from gypsum.Gypsum is heated to a TEMPERATURE of 100⁰c . It looses 3/ 4th of its water ofcrystallization and forms Plaster of Paris.Balanced Chemical equation:CaSO4.2H2O-----> CaSO4 .1/2H2O + 3/2 H2O |
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| 10. |
Fe2o3 +C_a+b balance the equation |
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Answer» FE2o+C_a+bBALANCE THE EQUATION |
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| 12. |
To prepare a mixture of NaCl/Sugar/tea leave extract, in water and observe and compare theproperties with Solution. |
| Answer» F a solution is PREPARED by dissolving 5.85NaCl in water. The MOLARITY of solution is | |
| 14. |
The vapor pressure of 100 g of water reduces from 17.53 mm to 17.22 mm Hg when 17.10 g of non-electrolyte substance X is dissolved in it. Substance X can be |
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Answer» x is glucoseExplanation:12thChemistrySolutionsVapour Pressure of Liquid SolutionsThe VAPOUR pressure of 100 ...CHEMISTRYThe vapour pressure of 100 g water reduces from 3000 NM −2 to 2985 Nm −2 when 5g of substance X is dissolved in it. The substance X is :October 15, 2019avatarShamil SisangiaShareSaveVIDEO EXPLANATIONANSWERRaoult's law states that relative lowering of vapour pressure and is EQUAL tothe mole FRACTION of the solute.p 1 p 10 −p 1 =x 2 p 10 =3000 Nm −2 = vapour pressure of solution.p 1 =2985 Nm −2 = vapour pressure of sollvent.x 2 = mole-fraction of solute.Let molecular wt. of X is x.No of moles of X is x5 No of moles of solvent is 18100 .Mole-fraction of X is (100/18)(5/x) =9/10xSo,30003000−2985 = 109 x⟹x=180The molecular weight of glucose is 180 g/mol. |
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| 15. |
Write reactions to justify amphoteric nature of aluminium. |
| Answer» ANCE is called amphoteric if it DISPLAYS both characteristics of acids and bases. Aluminium dissolves in both acids and bases, showing amphoteric behaviour.(i) 2AL(s) + 6HCl(aq) → 2Al3 + (aq) + 6Cl−(aq) + 3H2(g)(ii) 2Al(s) + 2NaOH(aq) + 6H2O(l) → 2Na + [Al(OH)4]−(aq) + 3H2(g) | |
| 16. |
Na2Co3 +Hcl_a+b balance the equation |
| Answer» EXPLANATION:NA2CO3 + 2HCL → 2NaCl + H2O + CO2 | |
| 17. |
Hi friends gine the answer the question I am given in the image |
| Answer» REFER in NCERT 12 TH textbook SOLID stateExplanation: | |
| 18. |
Convert but 1-ene to 2- chlorobutane |
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Answer» ion of but-1-ene to but-2-ene is by CATALYTIC ISOMERISATION. But-1-ene undergoes isomerisation to but-2-ene on a nickel CATALYST in the presence of HYDROGEN atoms. CH3CH2CHBRCH3. We then add alcoholic KOH to get but-2-ene. |
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| 19. |
Explain the following 1) While separating a mixture of ortho and para nitro phenols by steam distillation, name the isomer which will be steam volatile. Give reason 2) What is meant by hydroboration – oxidation reaction. Explain with one example |
| Answer» LISA bengingayazi impendulo Kepha ngicela ungimake NJENGOMBHALI futhi ungilandele. | |
| 20. |
Explain cleaning action of soaps and detergents . |
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Answer» The cleansing action of both SOAPS and DETERGENTS results from their ability to lower the surface tension of WATER, to emulsify oil or grease and to hold them in a SUSPENSION in water. This ability is due to the structure of soaps and detergents. In water, a sodium soap dissolves to form soap anions and sodium cations. |
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| 21. |
What is the similarity in the electronic configuration of Hydrogen , Lithium and Potassium ? |
| Answer» ER most ELECTRONS of these elements are enters into 's' orbital only and these elements have only one electron in their outermost orbital.Hydrogen: 1s1Lithium: 1S2 2s1Potassium: 1s2 2S2 2p6 3s2 3p6 4S1 | |
| 22. |
how to find potential of hydrogen electrode at pH=10 ????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????/???????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????HELP!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!! |
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Answer» potential formula isEcell = E° − 0.0591 LOG [H₂] 1 [H⁺]⇒ for [H⁺] pH = 10 so, or [H⁺] = 10∧⁻pHpH = − log [H⁺] pH = 10 so [H⁺] = 10⁻¹⁰ [H⁺] = 10⁻¹⁰ ⇒ E° = 0⇒ [H₂] = 1 [1 atm]Ecell = E° − 0.0591 log [H₂] 1 [H⁺] = 0 − 0.0591 log [1] 1 [10⁻¹⁰ ] = − 0.0591 (log 10¹⁰) = − 0.0591 (10 log 10) = − 0.0591 (10 * 1) {log 10 =1} = − 0.0591 x 10 Ecell = − 0.59 V |
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| 23. |
What is importance of 'gram atom' if there is already the concept of mole is available? |
| Answer» PROBLEMS gram amount is USED to DETERMINE the % of element in that COMPOUND | |
| 24. |
In our day to day life 4 chemical reactions and explain |
| Answer» NG gas in a stove 2 Mixing chemicals 3 Acid RAIN4 Oxidizing FOOD for ENERGY A physical CHANGE, such as a state change or dissolving, does not create a new substance, but a chemical change does.In a chemical reaction, the atoms and molecules that interact with each other are called reactants.In a chemical reaction, reactants contact each other, bonds between atoms in the reactants are broken, and atoms rearrange and form new bonds to make the products.hope its help u.. | |
| 25. |
Molar mass of Cl atoms and Cl molecules |
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Answer» s no MOLAR MASS of CL ATOM is 35.5 ..... the molar mass of MOLECULE(Cl) is there i.e. 70.9 |
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| 26. |
Which of the following alkali metal compound is paramagnetic? 1) Na2O 2) Li2O 3) Na2O2 4) CsO2 |
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Answer» is PARAMAGNETIC |
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| 27. |
Which of the following element does not form hydride? 1) Mn 2) Ni 3) La 4) Cr |
| Answer» FORM HYDRIDE! | |
| 28. |
Explain how the boiling point of a liquid can be raised without adding any impurity. |
| Answer» EASING pressure LOWER the BOILING POINT of the liquid | |
| 29. |
why iron do not comes under noble gas category????????????????????????????????????????????????? why why?????????????? |
| Answer» IRON is a METAL and not a GAS | |
| 30. |
How to test the presence nitrogen gas in the packet of snakes like chips ? |
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Answer» test the presence of nitrogen gas present in packet of CHIPS and other snacks. MATERIAL REQUIRED: Match box, CANDLE, Packet of chips. PROCEDURE: 1. Take a burning candle or burning matchstick. 2. OPEN packet of chips near to the flame of candle or burning matchstick. 3. RECORD your observation. OBSERVATION: The matchstick or candle will get EXTINGUISHED. BASIC PRINCIPLE INVOLVED: The packet of chips and many other products have nitrogen gas in it, which prevents spoilage of food due to oxidation because nitrogen is very less reactive. CONCLUSION: Presence of nitrogen is tested and understood the method of preserving food stuff. PRECAUTION: To be done under parental supervision. |
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| 31. |
Look at the attachement and asxnwer the questions |
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Answer» V1 / T1 = P2 V2 / T2 - Ideal gas law V2 = P1 V1 T2 / (T1 P2) = 380 mm * 1 Litre * 288 K / [ 303 K * 750 mm ]2. P V = n R T ideal gas law n = R T / (P V ) = 8.314 * (273+550) / [ 0.2 * 1.013 *10^5 * 0.350) n = m / M => M = m / n = 0.05 / n 3. P V = n R T = m R T / M M = m R T / [ P V ] = d R T / P, d = density = 1.5 * 10^-3 * 8.314 * (273+65) / [750 * 1.013 * 10^5 / 760 ] = 1.5 * 10^-3 * 8.314 * (273+65) * 760 / [750 * 1.013 * 10^5 ]4. which conditions ? where are they?5.open vessel pressure P and V volume of gas remain constant.T1 = 300 K. P1=P , V1 = V, n1 = MOLES present P V = n1 R T1P and V2 = V, n2 < n1 T2 > T1 P V = n2 R T2, n2 moles of gas remains after heating n2 T2 = n1 T1 n2 = (1-3/5) n1 = 2/5 * n1 => T2 / T1 = n1/n2 = 5/2 = 2.5 T2 = 300K * 2.5 = 750 K , at this temperature only 2/5th of initial gas is present.a) If the vessel now is heated to T3 = 900 K, then n3 / n1 = T1 / T3 = 1/3 => only 1/3 is present. and 2/3 of air escapes out.b) let n4 /n1 = 1/2 n4/n1 = T1/ T4 => T4 = 600K====================6.V = 10L = 0.01 m^2 T = 300Kp = m R T / (MV)p_He = 0.4 8.314 * 300 / (4 * 0.01 ) Pap_O2 = 1.6 * 8.314 * 300 / (32 * 0.01) Pap_N2 = 1.4 * 8.314 * 300 / (28 * 0.01) Paadd the three. to get total pressure.P = 8.314 * 300 [ 0.4/4 + 1.6 /32 + 1.4/28 ] / 0.01 ====================7. one of N2 gas = N = avogadro num = 6.023 * 10^23 number of molecules. volume of each MOLECULE = 4/3 Pi r^3, r = 2 * 10^-10 mvolume of gas at NTP, 22.4 litres = 0.0224 m^3empty space = 0.0224 - 6.023 * 10^23 * 4/3 pi 2^3 10^-30 8.P_A = 2 P_B V_A = 2 V_B T_A = 2 T_BP V / RT = n => n_A / n_B = 2 => m_A = 2 m_B===========9.m1 = 5.40 gm T1 = 300 K V1 = V P1 = Pm2 = 0.14 gm M2 = 2 n2 = 0.07 T2 = 290 K V2 = V P2 = Pn1 T1 = n2 T2 => n1 = 0.07 * 290 / 300 M = m1 / n1=======================10. P , d = m / V1 T1 = 300 K P = d R T / M => d1 T1 = d2 T2 0.75 d / d = 300 / T2 => 400 K======11V = 1 litre P = 1 atm T = 373 Knum of moles in STEAM: n2 = P V / R T = 3.381 * 10^-6 mass of this 1 litre of vapour at 373 K, m2 = density * Volume => m2 = 0.0006 g/cc * 1000 cc = 0.6 gmsIn liquid FORM, the water molecules weighing 0.6 gms occupy 0.6 cc.If we assume that in water , the molecules are very CLOSELY packed (as compared to the gas vapor), then the volume occupied by water molecules is 0.6 cc in one litre (1000 cc) of the water vapour at 1 atm at 373 K. |
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| 32. |
Loook at the attachement and sol;ve the questions |
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Answer» P2 / P1 = T2/ T1 10^6 / 0.25 * 10^6 = T2 / 300 K => T2 = 1200 K It will blow up at 1200 K============3. P1 = 5 atm T1 = 303 K V1 n1 m1 P1 V1 = n1 R T1 T2 = 293 K, n1, m1 same V2 = 160% V1 = 1.6 V1 => P2 = P1 /1.6 n3 = n1 * 120% = 1.2 n1 V3 = V2 = 1.6 V1 T3 = ? P3 = P1 P3 V3 / [P1 V1 ] = n3 R T3 / [ n1 R T1 ] 1.6 = 1.2 * T3 / 303 T3 = 1.6 / 1.2 * 303 K========================4.I think there is a misprint in the number : 10 deg C increase in temperature or 10% increase in pressure.... Increase of 10 deg. C cannot increase pressure by 10%.m = 12 gm T1 = 273+t deg K V1 = v litre P1 = 1 atmM = 120 => n = 0.1 number of molesif the increase of temperature is: 100 deg C T2 = 373+t deg K V2 = v litre P2 = 1.10 atm P2/P1 = T2 / T1 => 1.10 (273 + t) = 373 + t => t = 10 * 72.7 = 727 deg Cif the increase of pressure is 1 % only and increase of temperature is 10 degC, P2/P1 = 1.01 = 283+t / (273+t) t = 727 deg C=================================then CALCULATE V as: v = n * R (273+t) / P1 as all quantities are known |
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| 33. |
A spoon can sound like a bell. no , this is not a riddle. It is a science explain it |
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Answer» prove vibrating spoon can sound like a bell.Apparatus Required : 1.Two spoons 2. String.Procedure : ---> Tie a spoon in the middle of the string ----> And hold the ends of the string with the INDEX fingers and bring it close to ears. ---> Ask your friend to hit gently the spoon with another spoon.Observation: If we listen carefully , we hear the sound which resembles like a bell LASTING for a while.Conclusion: Sound is PRODUCED by Vibrating Bodies. Sound travels faster in solid medium |
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| 34. |
Which of the following statements are incorrect I. The vibrating particle in the body continuously emits energy II. The radiation is propagated in the form waves III. The energy emission and absorption may be in fractional values IV. The intensity of the black body radiant energy increases with the wavelength, reaches a maximum and then decreases |
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Answer» ng to PLANK's quantum theory, hypothesis, and radiation law:1. False. Energy is emitted by a vibrating PARTICLE only when it changes from one energy state to another. 2. true. energy is propagated in the form of radiation or photons with energy = h ν, where ν is the frequency of the emitted wave3. False. According to Plank's quantum theory, energy states of the particle oscillating, energy emitted and energy absorbed are all in discrete multiples of a quanta = h ν. A fraction of this quantum is not possible to emit/absorb.4. True. It has been OBSERVED that BLACK body radiant energy at the same temperature, first increases with wavelength to a maximum and then it decreases. |
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| 35. |
What is meant by gaseous state of matter |
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Answer» state of MATTER MEANS when any matter is in the FORM of GAS or vapours called the GASEOUS state of matter .like the gaseous from of water is water vapours . |
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| 36. |
What do u mean by partial pressure of gas |
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Answer» tial PRESSURE of gas is a MEASURE of the concentration of a gas in a MIXTURE of GASES........ |
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| 37. |
WHAT ARE THE CHARACTERISTTIC OF THE PARTICLES OF MATTER? |
| Answer» ICLES of matter have spaces between them.(II) Particles of matter are continuously MOVING.(III) Particles of matter attract each other.(iv) Kinetic energy of particles increases with increase in TEMPERATURE. | |
| 38. |
GIVE REASONS FO THE FOLLOWING OBSERVATION: THESMELL OF HOT SIZZLING FOOD REACHESYOU SERERAL METRES AWAY BUT TO GET THE SMELL FROM COLD FOOD HAVE TO GO CLOSE. |
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Answer» o because the smell of hot FOOD is hot and hotness is TREATED as energy so smells particle GETS energy and travel a large distance and shows their PROPERTY of fluidity and CREAT randomness.and cold food 's smell doesnot posses much energy as hot food's smell.hence it don't travel much distance. |
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| 39. |
Show how will you arrange three 6 Ohm resistors to get a total resistance of i.4 ohms ii.9 ohms |
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Answer» rrange N resistors of value R ohms in series, the effective RESISTANCE: n R ohmsif we arrange n resistors of value R ohms in parallel, then the effective resistance: R / n ohmsfor getting effective resistance of 4 ohms from 6 ohm resistors, we can PUT two resistors in series, and their equivalent resistance = 12 ohms. Then CONNECT the third resistance of 6 ohms in parallel. equivalent resistance = 12 * 6 /(12+6) = 4 ohms.=============if we connect two resistors in parallel then effective resistance = 6/2 = 3 ohms.We connect the third resistance in series. The effective resistance: 3 + 6 = 9 ohms |
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| 40. |
Why is it so we can fill a fixed volume of gas in tire tube. |
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Answer» fill fixed volume of GAS in a TIRE tube because the tube has its own flexibility if you fill more amount of AIR or any gas for that matter it can STRETCH to only a certain extent . And if you fill more than that the pressure will increase and eventually it will blast off. |
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| 41. |
Find No. of oxygen atoms present in 143 g Washing soda ..{Na₂CO₃.10H₂O} |
| Answer» WER 4 ATOMS of oxygen. Press thank you! | |
| 42. |
What are the coinage metals? explain |
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Answer» etals that can be used for making coin is called coinage METAL,generally coinage METALS are least reactive for example gold coin and SILVER coin etc |
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| 43. |
why alcohal with a boiling point 351k evaporates much more quikly than water with a boling point of 373k |
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Answer» point of alcohol = 351 °Kboiling point of water = 373 °KHigher boiling point means that more kinetic energy is needed by the MOLECULES in the liquid state to go into the vapor state. That means that the bonds between the molecules of water are more than the bonds between the molecules of Alcohol.Since Alcohol molecules have less cohesive FORCES, they escape into gaseous state much more RAPIDLY, when same amount of heat is supplied to both liquids.Also due to the smaller cohesive force, the latent heat of vaporization of ETHYL Alcohol: 841 kJ/kg. and that of water = 2, 260 kJ/kgSince less latent heat is required, Alcohol VAPORIZES much more rapidly than water |
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| 44. |
Kh for CO2 in water is 1.67X10^8 pa at 298K. Calculate the mass of CO2 that can be dissolved in 500 ml of water at a pressure of 2.5 atmosphere at 298 K. (1atm = 1.013X10^5Pa) |
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Answer» law:Molecular mass of carbon dioxide = 12+2*16=44Mass of CO₂ dissolving in 500 ml of WATER at a PRESSURE of 2.5 atm at 298 °K = 44 * 0.758 * 10⁻³ = 33.352 MG. |
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| 45. |
NOWADAYS EGGS ARE CONSIDERED AS VEG FOOD ITEM . WHY? |
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Answer» are a vegetarian, please don't eat EGG. It is not veg food. The PEOPLE who are calling themselves vegetarian now infront of OTHERS, are not able to RESIST the taste of egg. So they are eating it and telling it a veg food. They are saying that there is no fertilisation. So there is no animal in it. But all these are base less reasons. They just don't wanna feel bad ABUOT what they are doing. |
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| 46. |
What are the special characteristics of Noble Gases when compared to other elements in the periodic table? |
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Answer» as are present in 18th group in periodic table. And all NOBLE gases are inert in nature because their all shell are FULL FIELD with electron. this is special cheractristics of noble gases. This chemical series of noble gases are HELIUM(He), neon(Ne), argon(Ag), krypton (k), xenon(Xe), and radon(Rn). |
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| 47. |
Partial pressure of ethane over a saturated solution containing 6.56x10-2 gram of ethane is 1 bar. What will be the partial pressure of the gas if it contains 5x 10-2 grams of ethane. |
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Answer» law states that : where p = partial pressure of the gas above the SOLUTION. is the Henry's SOLUBILITY CONSTANT for the solvent & solute at GIVEN T°C c = molar concentration of the solute in the solution in moles/Litre at given T°C c = m / V , m = MASS of the gas and V = volume of the solventSo solubility of directly proportional to the partial pressure of the gas over the solution. Since solubility is directly proportional to the mass of the gas solute, the mass dissolved is directly proportional to the partial pressure. p1 = 1 bar m1 = 6.56 * 10⁻² gm p2 = ? m2 = 5 * 10⁻² gmThe partial pressure is less than 1 bar which is for saturated solution. |
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| 48. |
Air is a mixture gases. It contains 20% by volume of O2 gas and 79% by volume of N2 gas at 298K. Water is in quilibrium with air at a pressure of 10 atmospheres. KH for O2 and N2 at 298 K are 3.30x107mm and 6.51x 107 mm respectively. Determine the composition of these gases in water. |
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Answer» ressure of air above WATER = P = 10 atm.partial PRESSURE of O2 in air above water = P1partial pressure of N2 above water = P2Volume of air above water = VVolume of O2 = V1 = 0.20 VVolume of N2 = V2 = 0.79 Vlet n1 moles of OXYGEN and n2 moles of N2 be present in air in volume V.Let n = total number of moles of gases in airFrom Daltons' law of partial pressures and the law of ideal gas mixture: Henry's law for solubility : where p = partial presssure of the gas above the liquid in equilibrium with solution Henry's constant c = molar concentration of the gas in moles/Litre in the solution c1 = concentration of O2 in water = mol/Litre = 4.606 * 32 * 10⁻⁵ gm/Litre = 1.474 mg/kg of water = 0.1474 % of water by mass or 8.291 * 10⁻⁵ moles/100 moles of waterc2 = concentration of N2 in water = mol/Litre = 2.582 mg/Litre = 0.2582 % of water by mass = 16.6* 10⁻⁵ moles/100 moles of water |
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| 49. |
What is the oxidation number of sulphur in ferric sulphate and ferrous sulphate |
| Answer» SULPHATE : IRON (III) sulphate VALENCY of iron is 3. Chemical formula: Fe₂ (SO₄)₃ IONS: Fe³⁺ and SO₄²⁻oxidation number of Fe is +3 oxidation number of SO₄ is -2 Oxidation number of oxygen (in general) is - 2 hence, - 2 = S + 4 * -2 => S = 6 oxidation number of Sulphur in Ferric Sulphate 6===================Ferrous sulphate or Iron (II) suplhate : chemical formula: Fe SO₄ Here Iron has valency - oxidation number 2. as the ions are: Fe²⁺ SO₄²⁻Hence the oxidation number of Sulphur will be 6 like in the case of Ferric sulphate. It will be 6. | |