The vapor pressure of 100 g of water reduces from 17.53 mm to 17.22 mm Hg when 17.10 g of non-electrolyte substance X is dissolved in it. Substance X can be

The vapor pressure of 100 g of water reduces from 17.53 mm to 17.22 mm

1.	The vapor pressure of 100 g of water reduces from 17.53 mm to 17.22 mm Hg when 17.10 g of non-electrolyte substance X is dissolved in it. Substance X can be
Answer» x is glucoseExplanation:12thChemistrySolutionsVapour Pressure of Liquid SolutionsThe VAPOUR pressure of 100 ...CHEMISTRYThe vapour pressure of 100 g water reduces from 3000 NM −2 to 2985 Nm −2 when 5g of substance X is dissolved in it. The substance X is :October 15, 2019avatarShamil SisangiaShareSaveVIDEO EXPLANATIONANSWERRaoult's law states that relative lowering of vapour pressure and is EQUAL tothe mole FRACTION of the solute.p 1 p 10 −p 1 =x 2 p 10 =3000 Nm −2 = vapour pressure of solution.p 1 =2985 Nm −2 = vapour pressure of sollvent.x 2 = mole-fraction of solute.Let molecular wt. of X is x.No of moles of X is x5 No of moles of solvent is 18100 .Mole-fraction of X is (100/18)(5/x) =9/10xSo,30003000−2985 = 109 x⟹x=180The molecular weight of glucose is 180 g/mol.