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how to find potential of hydrogen electrode at pH=10 ????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????/???????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????HELP!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!! |
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Answer» potential formula isEcell = E° − 0.0591 LOG [H₂] 1 [H⁺]⇒ for [H⁺] pH = 10 so, or [H⁺] = 10∧⁻pHpH = − log [H⁺] pH = 10 so [H⁺] = 10⁻¹⁰ [H⁺] = 10⁻¹⁰ ⇒ E° = 0⇒ [H₂] = 1 [1 atm]Ecell = E° − 0.0591 log [H₂] 1 [H⁺] = 0 − 0.0591 log [1] 1 [10⁻¹⁰ ] = − 0.0591 (log 10¹⁰) = − 0.0591 (10 log 10) = − 0.0591 (10 * 1) {log 10 =1} = − 0.0591 x 10 Ecell = − 0.59 V |
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