52639 + Interview Questions in Secondary School in Chemistry

1.	Iv.In crystal lattice formed by bcc unitcell the void volume isa. 68 %b. 74 %c.32 %d. 26%
Answer» ANSWER: C] 32% Explanation: PLS MARKS as brianllianst answer

1.

Iv.In crystal lattice formed by bcc unitcell the void volume isa. 68 %b. 74 %c.32 %d. 26%

Answer»

ANSWER:

C] 32%

Explanation:

PLS MARKS as brianllianst answer

Discussion

2.	Who proposed Plum pudding model? *2 pointsChadwickJ J ThomsonBohr
Answer» ANSWER: JOSEPH JOHN THOMSON..............

2.

Who proposed Plum pudding model? *2 pointsChadwickJ J ThomsonBohr

Answer»

ANSWER:

JOSEPH JOHN THOMSON..............

Discussion

3.	A gas is collected at a pressure of 95 cm of Hg and a temperature of 50°C. To what temperatureshould it be cooled so that is occupies a volume which is 80% of its original volume when thepressureof thegasis 90 cm of Hg.
Answer» Answer: As per GAS laws begin mathsize 12px style FRACTION numerator p subscript 1 v subscript 1 over denominator T subscript 1 end fraction space equals space fraction numerator p subscript 2 v subscript 2 over denominator T subscript 2 end fraction fraction numerator 95 cross times v 1 over denominator 323 end fraction space equals space fraction numerator 90 cross times 0.8 cross times v 1 over denominator T subscript 2 end fraction H E n c e space T subscript 2 equals space fraction numerator 90 cross times 0.8 cross times 323 over denominator 95 end fraction space equals space 244.8 space K end style Explanation:

3.

A gas is collected at a pressure of 95 cm of Hg and a temperature of 50°C. To what temperatureshould it be cooled so that is occupies a volume which is 80% of its original volume when thepressureof thegasis 90 cm of Hg.

Answer»

Answer:

As per GAS laws

begin mathsize 12px style FRACTION numerator p subscript 1 v subscript 1 over denominator T subscript 1 end fraction space equals space fraction numerator p subscript 2 v subscript 2 over denominator T subscript 2 end fraction

fraction numerator 95 cross times v 1 over denominator 323 end fraction space equals space fraction numerator 90 cross times 0.8 cross times v 1 over denominator T subscript 2 end fraction

H E n c e space T subscript 2 equals space fraction numerator 90 cross times 0.8 cross times 323 over denominator 95 end fraction space equals space 244.8 space K

end style

Explanation:

Discussion

4.	The idea of the smallest unit of matter was first given by, *2 pointsMaharshi kanadaDemocritusDalton
Answer» Answer: DALTON GAVE the IDEA of smallest UNIT of matter

4.

The idea of the smallest unit of matter was first given by, *2 pointsMaharshi kanadaDemocritusDalton

Answer»

Answer:

DALTON GAVE the IDEA of smallest UNIT of matter

Discussion

5.	The elementwith atomic number 118, will bea.Alkali b. Noble gas c. lanthanided.transition element
Answer» Answer: $lanthanide$ OPTION ( c ) ✔ ⭐ HOPE it helps uH ⭐

5.

The elementwith atomic number 118, will bea.Alkali b. Noble gas c. lanthanided.transition element

Answer»

Answer:

$lanthanide$

OPTION ( c ) ✔

⭐ HOPE it helps uH ⭐

Discussion

6.	Use of this solution?Is the distilled water acidic/basic/neutral? How would you verify it?Describe the process of neutralisation with the help of an example.
Answer» Q 4. Is the distilled water acidic/basic/neutral? How would you verify it? SOLUTION: Distilled water is neutral in nature. To verify it, take a SMALL amount of distilled water in two test tubes. Add blue litmus paper to one test tube and red litmus paper to the other test tube. It is observed that there is no change in colour of either blue or red litmus paper which shows distilled water is neither acidic nor basic, HENCE neutral. Q 5. Describe the process of NEUTRALISATION with the help of an example. SOLUTION: Neutralisation is a process in which an acid reacts with a BASE to produce salt and water. Take some dilute HYDROCHLORIC acid in a test tube and add 2-3 drops of phenolphthalein. The solution will remain colourless. Add to this acidic solution, sodium hydroxide solution with the help of a dropper and shake the test tube after adding each drop. The pink colour which appears keeps disappearing on shaking. Stop adding sodium hydroxide drop when the pink colour does not disappear. This is the point where neutralisation reaction has taken place. After this, if you keep on adding sodium hydroxide the solution will remain pink since it is basic in nature. BTS LIVE FOREVER AND EVER

6.

Use of this solution?Is the distilled water acidic/basic/neutral? How would you verify it?Describe the process of neutralisation with the help of an example.

Answer»

Q 4. Is the distilled water acidic/basic/neutral? How would you verify it?

SOLUTION:

Distilled water is neutral in nature. To verify it, take a SMALL amount of distilled water in two test tubes. Add blue litmus paper to one test tube and red litmus paper to the other test tube. It is observed that there is no change in colour of either blue or red litmus paper which shows distilled water is neither acidic nor basic, HENCE neutral.

Q 5. Describe the process of NEUTRALISATION with the help of an example.

SOLUTION:

Neutralisation is a process in which an acid reacts with a BASE to produce salt and water. Take some dilute HYDROCHLORIC acid in a test tube and add 2-3 drops of phenolphthalein. The solution will remain colourless. Add to this acidic solution, sodium hydroxide solution with the help of a dropper and shake the test tube after adding each drop. The pink colour which appears keeps disappearing on shaking. Stop adding sodium hydroxide drop when the pink colour does not disappear. This is the point where neutralisation reaction has taken place. After this, if you keep on adding sodium hydroxide the solution will remain pink since it is basic in nature.

BTS LIVE FOREVER AND EVER

Discussion

7.	1- Preparation collection and study of some important physical and chemicalproperties of at least three gases, one each from the following groups:(i) Hydrogen and oxygenCarbon dioxide and hydrogen sulphide(iii) Chlorine , hydrogen, and sulphur dioxidePracticl
Answer» ANSWER: HYDROGEN, SULPHUR DIOXIDE PRACTICL

7.

1- Preparation collection and study of some important physical and chemicalproperties of at least three gases, one each from the following groups:(i) Hydrogen and oxygenCarbon dioxide and hydrogen sulphide(iii) Chlorine , hydrogen, and sulphur dioxidePracticl

Answer»

ANSWER:

HYDROGEN, SULPHUR DIOXIDE PRACTICL

Discussion

8.	12. The boiling point of benzene is 353.23 K. When1.80 g of a non-volatile solute was dissolved in90 g of benzene, the boiling point is raised to354.11 K. Calculate the molar mass of the solute.(K for benzene is 2.53 K kg mol-').33
Answer» Explanation: FIND the value of m so that the quadratic equation px^2 + (p – 1) x +(p – 1) = 0 has EQUAL roots.

8.

12. The boiling point of benzene is 353.23 K. When1.80 g of a non-volatile solute was dissolved in90 g of benzene, the boiling point is raised to354.11 K. Calculate the molar mass of the solute.(K for benzene is 2.53 K kg mol-').33

Answer»

Explanation:

FIND the value of m so that the quadratic equation px^2 + (p – 1) x +(p – 1) = 0 has EQUAL roots.

Discussion

9.	Kclo3 on heating to give kcl and o2. what is the volume of o2 at Ntp liberate by 0.1 mole of kclo3 ?
Answer» ANSWER: U can CHOOSE nceart for SOLVING

9.

Kclo3 on heating to give kcl and o2. what is the volume of o2 at Ntp liberate by 0.1 mole of kclo3 ?

Answer»

ANSWER:

U can CHOOSE nceart for SOLVING

Discussion

10.	The compressibility factor for gas obeying van der Waals’ equation of state is given by ( where Vm is molar volume)A) Vm / Vm-b =a / RTVmB) a / RTVm = Vm / Vm-bC) RTVm / a = Vm-b / VmPlzz give me answer
Answer» OPTION c is the right answer. Plss pls pls pls pls pls thank maximum 200answers or MINIMUM 100 answers of mine as i want to reach my target 5thoisand THANKS whoever is watching pls pls pls thank in return u will GET a FOLLOW for sure

10.

The compressibility factor for gas obeying van der Waals’ equation of state is given by ( where Vm is molar volume)A) Vm / Vm-b =a / RTVmB) a / RTVm = Vm / Vm-bC) RTVm / a = Vm-b / VmPlzz give me answer

Answer»

OPTION c is the right answer.

Plss pls pls pls pls pls thank maximum 200answers or MINIMUM 100 answers of mine as i want to reach my target 5thoisand THANKS whoever is watching pls pls pls thank in return u will GET a FOLLOW for sure

Discussion

11.	Cos(cos^-1(x)+2*phi)/3)i need solve it
Answer» ANSWER: ................................

11.

Cos(cos^-1(x)+2*phi)/3)i need solve it

Answer»

ANSWER:

................................

Discussion

12.	Good morning friends . Jo friends iss time uthe hua h unn ka liya .or jo abhi soa nahi unm k liya good night
Answer» ANSWER: same to youuuuuuu

12.

Good morning friends . Jo friends iss time uthe hua h unn ka liya .or jo abhi soa nahi unm k liya good night

Answer»

ANSWER:

same to youuuuuuu

Discussion

13.	What is the threshold frequency of a metal whose workfunction is 13.26 x 10-25 J?(h=6.63 * 10-34 Js)• 910-8 Hz1x1010 Hz2 x 100 Hz5 100 Hz
Answer» Answer:- $\red{\bigstar}$ Threshold FREQUENCY $\large\leadsto\boxed{\sf \green{2 \times 10^{-9}Hz}}$ • Given:- WORK FUNCTION = $\bf{13.26 \times 10^{-25}J}$ • To Find:- Threshold frequency = ? • Solution:- $\pink{\bigstar}$ $\boxed{\sf{Work \: function [W_{0}] = Planck's \: Constant [h] \times Threshold \: frequency [v_{0}]}}$ here, h [Planck's constant] = 6.63 × 10 -³⁴ Js Hence, → $\sf{13.26 \times 10^{-25} J = 6.63 \times 10^{-34} Js \times v_{0}}$ → $\sf{v_{0} = \dfrac{13.26 \times 10^{-25}J}{6.63 \times 10^{-34}Js}}$ → $\sf \green{v_{0} = 2 \times 10^{-9}sec^{-1}}$ THEREFORE, the threshold frequency of the metal is $\bf{2 \times 10^{-9}Hz}$

13.

What is the threshold frequency of a metal whose workfunction is 13.26 x 10-25 J?(h=6.63 * 10-34 Js)• 910-8 Hz1x1010 Hz2 x 100 Hz5 100 Hz

Answer»

Answer:-

$\red{\bigstar}$ Threshold FREQUENCY

$\large\leadsto\boxed{\sf \green{2 \times 10^{-9}Hz}}$

• Given:-

WORK FUNCTION = $\bf{13.26 \times 10^{-25}J}$

• To Find:-

Threshold frequency = ?

• Solution:-

$\pink{\bigstar}$ $\boxed{\sf{Work \: function [W_{0}] = Planck's \: Constant [h] \times Threshold \: frequency [v_{0}]}}$

here,

h [Planck's constant] = 6.63 × 10 -³⁴ Js

Hence,

→ $\sf{13.26 \times 10^{-25} J = 6.63 \times 10^{-34} Js \times v_{0}}$

→ $\sf{v_{0} = \dfrac{13.26 \times 10^{-25}J}{6.63 \times 10^{-34}Js}}$

→ $\sf \green{v_{0} = 2 \times 10^{-9}sec^{-1}}$

THEREFORE, the threshold frequency of the metal is $\bf{2 \times 10^{-9}Hz}$

Discussion

14.	IN the laboratory an alkane may be prepared by:a) 3 methodsb) 4 methodsc) 5 methodsd) 6 methods
Answer» HEY mate! there are many METHODS of ALKANE to be prepared so I THINK the ANS could be (D) hope it helps❤❤

14.

IN the laboratory an alkane may be prepared by:a) 3 methodsb) 4 methodsc) 5 methodsd) 6 methods

Answer»

HEY mate!

there are many METHODS of ALKANE to be prepared so I THINK the ANS could be (D)

hope it helps❤❤

Discussion

15.	Calculate the amount of each present in solution 2litres of N/10 HCl
Answer» Answer: Therefore add 8.3 ML of 37% HCL to 1 LITER of D5W or NS to CREATE a 0.1N HCL SOLUTION. 12M (37% HCL) = 12 moles/L = 12 x 36.5 = 438 g/L = 438 mg/m Explanation:

15.

Calculate the amount of each present in solution 2litres of N/10 HCl

Answer»

Answer:

Therefore add 8.3 ML of 37% HCL to 1 LITER of D5W or NS to CREATE a 0.1N HCL SOLUTION. 12M (37% HCL) = 12 moles/L = 12 x 36.5 = 438 g/L = 438 mg/m

Explanation:

Discussion

16.	Please answer this it's urgent....What happens when crystal of sodium carbonate us added into dilute HCl ?? give reaction .....!!
Answer» ANSWER: Na2CO3 + HCL to GIVE NaCl + H2O + CO2

16.

Please answer this it's urgent....What happens when crystal of sodium carbonate us added into dilute HCl ?? give reaction .....!!

Answer»

ANSWER:

Na2CO3 + HCL to GIVE NaCl + H2O + CO2

Discussion

17.	3.Copper metal rects with conctrated HNO, asCu + 4HNO, 4 Cu(NO3)2 + 2NO, + 2H,0 .The number of moles of the HNO, reducedby one mole of the Cu will be1) 4 2) 2 3) 0.5 4) 0.25
Answer» ANSWER: answer is OPTION 2 for your QUESTION

17.

3.Copper metal rects with conctrated HNO, asCu + 4HNO, 4 Cu(NO3)2 + 2NO, + 2H,0 .The number of moles of the HNO, reducedby one mole of the Cu will be1) 4 2) 2 3) 0.5 4) 0.25

Answer»

ANSWER:

answer is OPTION 2 for your QUESTION

Discussion

18.	1. On what basis a thing iscalled "matter' ?Space andm2. (a) Define matter. Pg -(b) What is matter composed of ? důny particals(c) Which of the following are not regarded as matter andwhy? Electricity, smell, mercury, oxygen, taste, milk.3. What are the characteristics of :(a) matter (b) particles
Answer» Answer: Explanation: Anything that occupies space and has mass is called matter. Matter can exist in three physical states—SOLID, liquid, and gaseous. Chair and almond are forms of matter in the solid state. Cold drink is a liquid state of matter. Air is a gaseous state of matter. Note: The sense of smell is not matter. However, the smell or odour of a SUBSTANCE is CLASSIFIED as matter. The smell of any substance (say, perfume) can be classified as matter. This is because, perfume is in liquid state inside the bottle. It comes out in the FORM of tiny droplets. These droplets of perfume are matter and SPREAD out in the atmosphere to create a sense of smell. This smell can be detected by our olfactory system.

18.

1. On what basis a thing iscalled "matter' ?Space andm2. (a) Define matter. Pg -(b) What is matter composed of ? důny particals(c) Which of the following are not regarded as matter andwhy? Electricity, smell, mercury, oxygen, taste, milk.3. What are the characteristics of :(a) matter (b) particles

Answer»

Answer:

Explanation:

Anything that occupies space and has mass is called matter. Matter can exist in three physical states—SOLID, liquid, and gaseous.

Chair and almond are forms of matter in the solid state.

Cold drink is a liquid state of matter.

Air is a gaseous state of matter.

Note: The sense of smell is not matter. However, the smell or odour of a SUBSTANCE is CLASSIFIED as matter. The smell of any substance (say, perfume) can be classified as matter. This is because, perfume is in liquid state inside the bottle. It comes out in the FORM of tiny droplets. These droplets of perfume are matter and SPREAD out in the atmosphere to create a sense of smell. This smell can be detected by our olfactory system.

Discussion

19.	The ratio of number of non-metal atoms to The ratio of number of non-metal atoms to the metal atom on Anglesite ismetal atom on Anglesite is
Answer» Answer: *The RATIO of NUMBER of non-metal atoms to The ratio of number of non-metal atoms to the metal ATOM on ANGLESITE is metal atom on Anglesite is.*

19.

The ratio of number of non-metal atoms to The ratio of number of non-metal atoms to the metal atom on Anglesite ismetal atom on Anglesite is

Answer»

Answer:

The RATIO of NUMBER of non-metal atoms to The ratio of number of non-metal atoms to the metal ATOM on ANGLESITE is metal atom on Anglesite is.

Discussion

20.	The loops in Ptolemy's ____model, and those shown on the video, are called _____ motion.This phenomenon is caused by Earth's____ orbit than those of other planets. Options:A) Heliocentric B) GeocentricC) Retrograde Where do they go?
Answer» ANSWER: answer is a- HELIOCENTRIC

20.

The loops in Ptolemy's __model, and those shown on the video, are called _ motion.This phenomenon is caused by Earth's__ orbit than those of other planets. Options:A) Heliocentric B) GeocentricC) Retrograde Where do they go?

Answer»

ANSWER:

answer is

a- HELIOCENTRIC

Discussion

21.	In which of the following experiment, residue left behind is reddish brown.a) Heating of copper powder in airb) Heating of ferrous sulphate crystalsc) Heating of magnesium in aird) Heating of solid calcium carbonate
Answer» ANSWER: HEATING of COPPER POWDER in AIR

21.

In which of the following experiment, residue left behind is reddish brown.a) Heating of copper powder in airb) Heating of ferrous sulphate crystalsc) Heating of magnesium in aird) Heating of solid calcium carbonate

Answer»

ANSWER:

HEATING of COPPER POWDER in AIR

Discussion

22.	5.Consider the followingAH= u kJ/molsolAB(S)→ A(aq) + B (aq)AHLE = w kJ/mol= v kJ/molhydrationΔΗA(g) + B(g)The correct relation between u, v & w is[NCERT Pg. 180](1) w = y + u(2) u = W + V(3) v = 2(u + W) (4) v = w + u
Answer» ANSWER: a LOT more to the f and the QUESTION 2that is a more IMPORTANT issue to LR in this

22.

5.Consider the followingAH= u kJ/molsolAB(S)→ A(aq) + B (aq)AHLE = w kJ/mol= v kJ/molhydrationΔΗA(g) + B(g)The correct relation between u, v & w is[NCERT Pg. 180](1) w = y + u(2) u = W + V(3) v = 2(u + W) (4) v = w + u

Answer»

ANSWER:

a LOT more to the f and the QUESTION 2that is a more IMPORTANT issue to LR in this

Discussion

23.	At 100°C Vapour Pressure of aqueoussolution (havingnon-volatilesolute) is 750 mm of Hg. Whatis molality of solution?
Answer» Answer: The vapour PRESSURE of an aqueous solution of glucose is 750 mm of Hg at 373 k . Calculate the molality and mole fraction of SOLUTE. shivanshyadav48035 is WAITING for your help.

23.

At 100°C Vapour Pressure of aqueoussolution (havingnon-volatilesolute) is 750 mm of Hg. Whatis molality of solution?

Answer»

Answer:

The vapour PRESSURE of an aqueous solution of glucose is 750 mm of Hg at 373 k . Calculate the molality and mole fraction of SOLUTE. shivanshyadav48035 is WAITING for your help.

Discussion

24.	312. Correct expression of enthalpy of combustion is[NCERT Pg. 176](1) C2H6(g) + O2(g) → 2CO(g) + 3H20(1)(2) C(s) +-02 (9) --CO(9)2(diamond)4(3) C(s) +-02 (9)--CO (9)graphite2(4) S(s) + O2(g) →S02 (9)rhombic
Answer» Explanation: C 2 H 6 (g)+ 2 7 O 2 (g)→2CO 2 (g)+3H 2 O(L) Here heat of combustion for two mole of C 2 H 6 =3120 kj , So for ONE mole of C 2 H 6 =1560 kj Now we KNOW that ΔH reaction 0 =ΣΔH f 0 Product−ΣΔH f 0 Reactant Now using this formula -1560 = (−2×395−3×285)−X So X = -85 KJ / mol -X = 85

24.

312. Correct expression of enthalpy of combustion is[NCERT Pg. 176](1) C2H6(g) + O2(g) → 2CO(g) + 3H20(1)(2) C(s) +-02 (9) --CO(9)2(diamond)4(3) C(s) +-02 (9)--CO (9)graphite2(4) S(s) + O2(g) →S02 (9)rhombic

Answer»

Explanation:

C

2

H

6

(g)+

2

7

O

2

(g)→2CO

2

(g)+3H

2

O(L)

Here heat of combustion for two mole of C

2

H

6

=3120 kj , So for ONE mole of C

2

H

6

=1560 kj

Now we KNOW that ΔH

reaction

0

=ΣΔH

f

0

Product−ΣΔH

f

0

Reactant Now using this formula

-1560 = (−2×395−3×285)−X

So X = -85 KJ / mol

-X = 85

Discussion

25.	Is the set of quantum number permitted or not permitted =i] n=3 , l=2 , m=0 , s= -1/2ii] n=4 , l=2 , m=3 , s= +1/2
Answer» ANSWER: answer 1 n=4,l=2,m=3,s=+1/2 Mark as BRILLIANT ANT

25.

Is the set of quantum number permitted or not permitted =i] n=3 , l=2 , m=0 , s= -1/2ii] n=4 , l=2 , m=3 , s= +1/2

Answer»

ANSWER:

answer 1 n=4,l=2,m=3,s=+1/2

Mark as BRILLIANT ANT

Discussion

26.	FAH = a= d.P12. AH = bAH = dAH = C(B.On the basis of Hess's law of constant heat summation, choose the correct relation:(1) b = a -d + c(2) c = a - b + d(3) d = a + b + c(4) a-c = b + d
Answer» ANSWER: MARK MY ANSWER AS BRAINIEST PLEASE Explanation: (4) a-c = B + d

26.

FAH = a= d.P12. AH = bAH = dAH = C(B.On the basis of Hess's law of constant heat summation, choose the correct relation:(1) b = a -d + c(2) c = a - b + d(3) d = a + b + c(4) a-c = b + d

Answer»

ANSWER:

MARK MY ANSWER AS BRAINIEST PLEASE

Explanation:

(4) a-c = B + d

Discussion

27.	UTC(4) a - c = b + d13. In which of the following AH = AU?(1) N. (9) + 3H2(g) → 2NH,(9)(3) PCI;(9) - PCI;(9) + Cl2(9)14. Heat of combustion of CH4, CH4 and C. Ha are 890,(2) C(s) + O2(9) -CO2(9)(4) CaCO3(s) - Cao(s) + CO2(g)
Answer» ANSWER: I don't now your answer

27.

UTC(4) a - c = b + d13. In which of the following AH = AU?(1) N. (9) + 3H2(g) → 2NH,(9)(3) PCI;(9) - PCI;(9) + Cl2(9)14. Heat of combustion of CH4, CH4 and C. Ha are 890,(2) C(s) + O2(9) -CO2(9)(4) CaCO3(s) - Cao(s) + CO2(g)

Answer»

ANSWER:

I don't now your answer

Discussion

28.	15. The heat of neutralisation of four acids P, Q, R, S are -13.7. -9.4.-11.2 and -12.4 kcal, respectively whenthey are neutralised by a common base. The acidic character obeys the order(1) P>Q > R > S(2) PSR>Q(3) S > R > Q > P(4) S >> RPfore
Answer» ANSWER: hsjsisidjdhxgsyauquwhdvhdususuw

28.

15. The heat of neutralisation of four acids P, Q, R, S are -13.7. -9.4.-11.2 and -12.4 kcal, respectively whenthey are neutralised by a common base. The acidic character obeys the order(1) P>Q > R > S(2) PSR>Q(3) S > R > Q > P(4) S >> RPfore

Answer»

ANSWER:

hsjsisidjdhxgsyauquwhdvhdususuw

Discussion

29.	2.1 WHAT IS UNDERSTANDING THE CHEMICAL PROPERTIES OFACIDS AND BASES ?2.1.1WHAT IS ACIDS AND BASES IN THE LABORATORY?2.1.2HOW DO ACIDS AND BASES REACT WITH METALS?
Answer» Answer: Chemical Properties of Bases Bases change the colour of litmus from red to blue. They are BITTER in taste. Bases LOSE their basicity when MIXED with acids. Bases react with acids to form salt and water. ... They can conduct electricity. Bases feel slippery or soapy. Some bases are great CONDUCTORS of electricity.

29.

2.1 WHAT IS UNDERSTANDING THE CHEMICAL PROPERTIES OFACIDS AND BASES ?2.1.1WHAT IS ACIDS AND BASES IN THE LABORATORY?2.1.2HOW DO ACIDS AND BASES REACT WITH METALS?

Answer»

Answer:

Chemical Properties of Bases

Bases change the colour of litmus from red to blue.

They are BITTER in taste.

Bases LOSE their basicity when MIXED with acids.

Bases react with acids to form salt and water. ...

They can conduct electricity.

Bases feel slippery or soapy.

Some bases are great CONDUCTORS of electricity.

Discussion

30.	Calcium carbo(e)5. Give the names of the elements present in the followingcompounds.(a) Quick lime(b) Hydrogen bromide(c) Baking powder(d) Potassium sulphate.
Answer» Answer: Compound Chemical Formula Elements present a)Quick lime CaO CALCIUM, Oxygen b)Hydrogen BROMIDE HBr Hydrogen, Bromine c)Baking powder NAHCO3 Sodium, Hydrogen, Carbon, Oxygen d)Potassium sulphate K2SO4 Potassium, Sulphur, Oxygen

30.

Calcium carbo(e)5. Give the names of the elements present in the followingcompounds.(a) Quick lime(b) Hydrogen bromide(c) Baking powder(d) Potassium sulphate.

Answer»

Answer:

Compound Chemical Formula

Elements present

a)Quick lime CaO CALCIUM, Oxygen

b)Hydrogen BROMIDE HBr Hydrogen, Bromine

c)Baking powder NAHCO3 Sodium, Hydrogen, Carbon, Oxygen

d)Potassium sulphate K2SO4 Potassium, Sulphur, Oxygen

Discussion

31.	Draw the path of light when emerging from (light source, beaker containing the sample, particles in the mixture)
Answer» Answer: (i) When a beam of LIGHT is PASSED through a COLLOIDAL sol, colloidal particles scatter light and we can see the path of light. Thus, Tyndall effect is observed. (ii) When an electrolyte, NaCl is added to hydrated ferric OXIDE sol. NaCl provides colloidal particles which coagulate oppositely charged ferric hydroxide colloidal particles bearing positive CHARGE. (iii) When electric current is passed through a colloidal sol, the colloidal particles move towards oppositely charged electrode, where they lose their charge and are coagulated. The process is known as electrophoresis. Explanation: Path of light is in the picture

31.

Draw the path of light when emerging from (light source, beaker containing the sample, particles in the mixture)

Answer»

Answer:

(i) When a beam of LIGHT is PASSED through a COLLOIDAL sol, colloidal particles scatter light and we can see the path of light. Thus, Tyndall effect is observed.

(ii) When an electrolyte, NaCl is added to hydrated ferric OXIDE sol.

NaCl provides colloidal particles which coagulate oppositely charged ferric hydroxide colloidal particles bearing positive CHARGE.

(iii) When electric current is passed through a colloidal sol, the colloidal particles move towards oppositely charged electrode, where they lose their charge and are coagulated. The process is known as electrophoresis.

Explanation:

Path of light is in the picture

Discussion

32.	ΔΗ =a1 =1.AP2. ΔΗ =bΔΗ =dΔΗ =-ΔΗ =cOn the basis of Hess's law of constant heat summation, choose the correct relat(1) b = a – d + ο(2) C = a – b + d(3) d = a +6 +οCTΠ
Answer» QUESTION NOT CLEAR FRIEND... POST IT AGAIN .....

32.

ΔΗ =a1 =1.AP2. ΔΗ =bΔΗ =dΔΗ =-ΔΗ =cOn the basis of Hess's law of constant heat summation, choose the correct relat(1) b = a – d + ο(2) C = a – b + d(3) d = a +6 +οCTΠ

Answer»

QUESTION NOT CLEAR FRIEND... POST IT AGAIN .....

Discussion

33.	Write the correct iupac name of the following-(a)pent-4-en-1-yne(b)1,6-Hexdiene(c)But-3-hydroxy-1-one(d)3-Amino-butan-2al
Answer» ANSWER: all are the CORRECT IUPAC NAME only they are not INCORRECT.

33.

Write the correct iupac name of the following-(a)pent-4-en-1-yne(b)1,6-Hexdiene(c)But-3-hydroxy-1-one(d)3-Amino-butan-2al

Answer»

ANSWER:

all are the CORRECT IUPAC NAME only they are not INCORRECT.

Discussion

34.	Difference between oxidising agent and reducing agent??If you know the answer then reply otherwise I report your answer but give me answer as soon as possible... I hope you all get it.. Its a humble request
Answer» Some substances are capable of adding oxygen to others. These are known as OXIDIZING agents. The SUBSTANCE which loses ELECTRONS to the other substance and gets oxidized to the higher valency STATE is known as reducing agent.. MARK ME AS BRAINIEST..✌️

34.

Difference between oxidising agent and reducing agent??If you know the answer then reply otherwise I report your answer but give me answer as soon as possible... I hope you all get it.. Its a humble request

Answer»

Some substances are capable of adding oxygen to others. These are known as OXIDIZING agents. The SUBSTANCE which loses ELECTRONS to the other substance and gets oxidized to the higher valency STATE is known as reducing agent..

MARK ME AS BRAINIEST..✌️

Discussion

35.	When Cu is added to dil.HCl bubble formation is not seen and the temperature also remains unchanged. Give Reason.Class 10
Answer» Answer: No reaction occurs as H is more reactive than Cu. So Cu, being LESS reactive than H does not replace it. So no change occur. Plz MARK as BRAINLIEST

35.

When Cu is added to dil.HCl bubble formation is not seen and the temperature also remains unchanged. Give Reason.Class 10

Answer»

Answer:

No reaction occurs as H is more reactive than Cu. So Cu, being LESS reactive than H does not replace it. So no change occur.

Plz MARK as BRAINLIEST

Discussion

36.	“Reagents in Organic Chemistry”.1. Which is the suitable catalyst for bringing out the transformation given below?a) BF3. Et20b) NaOEtc) tungsten lampd) dibenzoyl peroxide
Answer» ANSWER: hiii MATE (d) is your correct answer i THINK its helps you

36.

“Reagents in Organic Chemistry”.1. Which is the suitable catalyst for bringing out the transformation given below?a) BF3. Et20b) NaOEtc) tungsten lampd) dibenzoyl peroxide

Answer»

ANSWER:

hiii MATE

(d) is your correct answer

i THINK its helps you

Discussion

37.	Q.4The product in the following sequence isO요NH HCNNH2NH2OHNH2OHNH2OCHSOHAB.сD.
Answer» Answer: The product 'C' in the following sequence of chemical reaction is Acetoxime. CH 3 COOH Ca(OH) 2 (A) (CH 3 COO) 2 Ca Δ (B) C H 3 COCH 3 NH 2 OH Acetoxime CH 3 C ∣ H 3 C =N−OH ACETIC acid reacts with calcium hydroxide to give calcium acetate. Calcium acetate on dry DISTILLATION gives acetone. Acetone undergoes condensation reaction with hydroxylamine to form acetoxime. Option D is CORRECT.

37.

Q.4The product in the following sequence isO요NH HCNNH2NH2OHNH2OHNH2OCHSOHAB.сD.

Answer»

Answer:

The product 'C' in the following sequence of chemical reaction is Acetoxime.

CH

3

COOH

Ca(OH)

2

(A)

(CH

3

COO)

2

Ca

Δ

(B)

C

H

3

COCH

3

NH

2

OH

Acetoxime

CH

3

C

∣

H

3

C

=N−OH

ACETIC acid reacts with calcium hydroxide to give calcium acetate.

Calcium acetate on dry DISTILLATION gives acetone.

Acetone undergoes condensation reaction with hydroxylamine to form acetoxime.

Option D is CORRECT.

Discussion

38.	The elementspresent inpure water can be separated byA) physical methodB)chemical methodC)both (A) and (B)D)they cannot be separated
Answer» OPTION C is the CORRECT ANSWER

Discussion

39.	Q.5The reaction given below is an example of which of the following reaction.0H Н+OH+\N-CNA. Ugi reactionB. BiginellireactionC. PasserinireactionD. Streckerreaction
Answer» ANSWER: Your QUESTION isn't CLEAR to me WRITE it CLEARLY

39.

Q.5The reaction given below is an example of which of the following reaction.0H Н+OH+\N-CNA. Ugi reactionB. BiginellireactionC. PasserinireactionD. Streckerreaction

Answer»

ANSWER:

Your QUESTION isn't CLEAR to me

WRITE it CLEARLY

Discussion

40.	_____ is the product formed when sulphur reacts with oxygen it dissolves in water to produce _____choose correct option for x and yX. Ya. So2. Acidb. So3. Neutral c. So2. Based. So3. Acid
Answer» ANSWER: It's. (a) SO2.Acid......

40.

_ is the product formed when sulphur reacts with oxygen it dissolves in water to produce _choose correct option for x and yX. Ya. So2. Acidb. So3. Neutral c. So2. Based. So3. Acid

Answer»

ANSWER:

It's. (a) SO2.Acid......

Discussion

41.	8.Homogenous mixtures areA) pure mixturesC)partially pure mixturesB)impure mixturesD)none of these
Answer» Answer: B) Impure Explanation: A mixture is an impure substance. It CONSISTS of different elements and substances combined together physically in an unknown ratio. ... Their constituents are not combined CHEMICALLY but only physically. The mixture STILL shows all the properties of its constituents.I guess!! PLS mark me as the brainliest!

41.

8.Homogenous mixtures areA) pure mixturesC)partially pure mixturesB)impure mixturesD)none of these

Answer»

Answer:

B) Impure

Explanation:

A mixture is an impure substance. It CONSISTS of different elements and substances combined together physically in an unknown ratio. ... Their constituents are not combined CHEMICALLY but only physically. The mixture STILL shows all the properties of its constituents.I guess!!

PLS mark me as the brainliest!

Discussion

42.	Q.12 Which of these must be avoided in any presentation?A. Proper grammarB. Complex wordsC. Short sentencesD. Clear voice
Answer» ANSWER: B) COMPLEX words PLEASE, MARK ME AS BRAINLIEST!

42.

Q.12 Which of these must be avoided in any presentation?A. Proper grammarB. Complex wordsC. Short sentencesD. Clear voice

Answer»

ANSWER:

B) COMPLEX words

PLEASE, MARK ME AS BRAINLIEST!

Discussion

43.	Magnitude of current ?c. State the relationship between Potential difference, Work Done and Charged moved.
Answer» Explanation: Potential DIFFERENCE = WORK DONE / Charge MOVED.

43.

Magnitude of current ?c. State the relationship between Potential difference, Work Done and Charged moved.

Answer»

Explanation:

Potential DIFFERENCE = WORK DONE / Charge MOVED.

Discussion

44.	Write balanced chemical equations for the following reactions.i. Naural gas burns in air to form carbon dioxide and water . ii. During Respiration , glucose combines with oxygen to form carbon dioxide and water along with the release of energy .
Answer» (i) C + O2 -----------> CO2 (ii) C6H12O6 + 6O2 ---------> 6CO2 + 6H20

44.

Write balanced chemical equations for the following reactions.i. Naural gas burns in air to form carbon dioxide and water . ii. During Respiration , glucose combines with oxygen to form carbon dioxide and water along with the release of energy .

Answer»

(i) C + O2 -----------> CO2

(ii) C6H12O6 + 6O2 ---------> 6CO2 + 6H20

Discussion

45.	On what bases are plants and animals put into different kingdoms? Differentiate betweenkingdom Plantae and the kingdom fungi on the basis of their nutrition and material of cellwalls.(2)
Answer» Answer: Kingdom Plantae Kingdom Animalia1. Have multicellular EUKARYOTE plants.Have multicellular eukaryote animals.2. Presence of cell WALL (MADE up of cellulose.)Absence of cell wall.3. Capable of producing their own FOOD (autotrophic mode of nutrition.)Depend on others for their food requirements (heterotrophic mode of nutrition.)4. Photosynthesis occurrence due to the presence of chloroplast.Since they are non-green in nature and do not produce chlorophyll, they do not undergo photosynthesis.5. Are immobile.Are mobile.6. Can grow throughout their life.Achieve a maximum size and then stop growing.7. Consume carbon dioxide and release oxygen.Consume oxygen and release carbon dioxide.8. Have two SETS of chromosomes (diploid.)Have only one set of the chromosome (haploid.)9. Have reserved food in the form of starch.Have reserved food in the form of glucose.

45.

On what bases are plants and animals put into different kingdoms? Differentiate betweenkingdom Plantae and the kingdom fungi on the basis of their nutrition and material of cellwalls.(2)

Answer»

Answer:

Kingdom Plantae Kingdom Animalia1. Have multicellular EUKARYOTE plants.Have multicellular eukaryote animals.2. Presence of cell WALL (MADE up of cellulose.)Absence of cell wall.3. Capable of producing their own FOOD (autotrophic mode of nutrition.)Depend on others for their food requirements (heterotrophic mode of nutrition.)4. Photosynthesis occurrence due to the presence of chloroplast.Since they are non-green in nature and do not produce chlorophyll, they do not undergo photosynthesis.5. Are immobile.Are mobile.6. Can grow throughout their life.Achieve a maximum size and then stop growing.7. Consume carbon dioxide and release oxygen.Consume oxygen and release carbon dioxide.8. Have two SETS of chromosomes (diploid.)Have only one set of the chromosome (haploid.)9. Have reserved food in the form of starch.Have reserved food in the form of glucose.

Discussion

46.	Hii guys!!!please meri hlp kro aap me se koi mujhe je bta skta hai ki answer me power kyu change ho gye hai plz
Answer» ANSWER: kyuki esme MOLECULES batane the toh answer BHI molecules me hi aayege plz MARK as brainlest

46.

Hii guys!!!please meri hlp kro aap me se koi mujhe je bta skta hai ki answer me power kyu change ho gye hai plz

Answer»

ANSWER:

kyuki esme MOLECULES batane the

toh answer BHI molecules me hi aayege

plz MARK as brainlest

Discussion

47.	. The temperature at which hydrogen moleculeshave the same kinetic energy as oxygen moleculeshave at 40°C is : give ans with full explanation plz
Answer» ANSWER: The TEMPERATURE at which hydrogen molecules have the same KINETIC energy as OXYGEN molecules have at. 40°C is : 3 28 T.

47.

. The temperature at which hydrogen moleculeshave the same kinetic energy as oxygen moleculeshave at 40°C is : give ans with full explanation plz

Answer»

ANSWER:

The TEMPERATURE at which hydrogen molecules have the same KINETIC energy as OXYGEN molecules have at. 40°C is : 3 28 T.

Discussion

48.	Which of the following relation holds true for anequilibrium reaction, if its reaction quotient(Q) = 1?(1) AG = 0(2) AG° = 0(3) AG > AG°(4) AG = AG°
Answer» ANSWER: hhhbhhhhhhhhhhu I NEED TOH

48.

Which of the following relation holds true for anequilibrium reaction, if its reaction quotient(Q) = 1?(1) AG = 0(2) AG° = 0(3) AG > AG°(4) AG = AG°

Answer»

ANSWER:

hhhbhhhhhhhhhhu I NEED TOH

Discussion

49.	Electrolysis of molten lead bromide is carried out.The bulb will not light until the lead bromide has melted. Why not?
Answer» EXPLANATION: The bulb won't glow when the electrodes are emebedded in solid lead BROMIDE. ... The bulb will glow when the material surrounding the electrodes is molten lead bromide. When an ionic compound is in the molten (liquid) form the positive and negative IONS are free to MOVE around.

49.

Electrolysis of molten lead bromide is carried out.The bulb will not light until the lead bromide has melted. Why not?

Answer»

EXPLANATION:

The bulb won't glow when the electrodes are emebedded in solid lead BROMIDE. ... The bulb will glow when the material surrounding the electrodes is molten lead bromide. When an ionic compound is in the molten (liquid) form the positive and negative IONS are free to MOVE around.

Discussion

50.	Orange A, Greento solid (A)residue(B) + Gas (C) + Gas (D)hotCaC₂NaOHAnhydrousCuSO4Evolvedgas (F)Product (H)Turns intois a good blue compoundYellowfro fertilizer(E)solution (G) SEHOPb(OAC),Yellow ppt. (1)Gas (F) + CaCO3TCCaso stommPassage 5: For Questions 13-16
Answer» ANSWER: where are the OPTIONS of these QUESTIONS

50.

Orange A, Greento solid (A)residue(B) + Gas (C) + Gas (D)hotCaC₂NaOHAnhydrousCuSO4Evolvedgas (F)Product (H)Turns intois a good blue compoundYellowfro fertilizer(E)solution (G) SEHOPb(OAC),Yellow ppt. (1)Gas (F) + CaCO3TCCaso stommPassage 5: For Questions 13-16

Answer»

ANSWER:

where are the OPTIONS of these QUESTIONS

Discussion

Explore topic-wise InterviewSolutions in Current Affairs.

Iv.In crystal lattice formed by bcc unitcell the void volume isa. 68 %b. 74 %c.32 %d. 26%​

Who proposed Plum pudding model? *2 pointsChadwickJ J ThomsonBohr​

A gas is collected at a pressure of 95 cm of Hg and a temperature of 50°C. To what temperatureshould it be cooled so that is occupies a volume which is 80% of its original volume when thepressureof thegasis 90 cm of Hg.​

The idea of the smallest unit of matter was first given by, *2 pointsMaharshi kanadaDemocritusDalton​

The elementwith atomic number 118, will bea.Alkali b. Noble gas c. lanthanided.transition element​

OPTION ( c ) ✔

Use of this solution?Is the distilled water acidic/basic/neutral? How would you verify it?Describe the process of neutralisation with the help of an example.​

Q 4. Is the distilled water acidic/basic/neutral? How would you verify it?

Q 5. Describe the process of NEUTRALISATION with the help of an example.

BTS LIVE FOREVER AND EVER

1- Preparation collection and study of some important physical and chemicalproperties of at least three gases, one each from the following groups:(i) Hydrogen and oxygenCarbon dioxide and hydrogen sulphide(iii) Chlorine , hydrogen, and sulphur dioxidePracticl

12. The boiling point of benzene is 353.23 K. When1.80 g of a non-volatile solute was dissolved in90 g of benzene, the boiling point is raised to354.11 K. Calculate the molar mass of the solute.(K for benzene is 2.53 K kg mol-').33​

Kclo3 on heating to give kcl and o2. what is the volume of o2 at Ntp liberate by 0.1 mole of kclo3 ?​

The compressibility factor for gas obeying van der Waals’ equation of state is given by ( where Vm is molar volume)A) Vm / Vm-b =a / RTVmB) a / RTVm = Vm / Vm-bC) RTVm / a = Vm-b / VmPlzz give me answer​

OPTION c is the right answer.

Cos(cos^-1(x)+2*phi)/3)i need solve it

Good morning friends . Jo friends iss time uthe hua h unn ka liya .or jo abhi soa nahi unm k liya good night​

What is the threshold frequency of a metal whose workfunction is 13.26 x 10-25 J?(h=6.63 * 10-34 Js)• 9*10-8 Hz1x1010 Hz2 x 100 Hz5* 100 Hz​

Answer:-

• Given:-

• To Find:-

• Solution:-

IN the laboratory an alkane may be prepared by:a) 3 methodsb) 4 methodsc) 5 methodsd) 6 methods​

HEY mate!

hope it helps❤❤

Calculate the amount of each present in solution 2litres of N/10 HCl

Please answer this it's urgent....What happens when crystal of sodium carbonate us added into dilute HCl ?? give reaction .....!!​

3.Copper metal rects with conctrated HNO, asCu + 4HNO, 4 Cu(NO3)2 + 2NO, + 2H,0 .The number of moles of the HNO, reducedby one mole of the Cu will be1) 4 2) 2 3) 0.5 4) 0.25​

The ratio of number of non-metal atoms to The ratio of number of non-metal atoms to the metal atom on Anglesite ismetal atom on Anglesite is

The loops in Ptolemy's ____model, and those shown on the video, are called _____ motion.This phenomenon is caused by Earth's____ orbit than those of other planets. Options:A) Heliocentric B) GeocentricC) Retrograde Where do they go?​

answer is

In which of the following experiment, residue left behind is reddish brown.a) Heating of copper powder in airb) Heating of ferrous sulphate crystalsc) Heating of magnesium in aird) Heating of solid calcium carbonate

5.Consider the followingAH= u kJ/molsolAB(S)→ A*(aq) + B (aq)AHLE = w kJ/mol= v kJ/molhydrationΔΗA*(g) + B(g)The correct relation between u, v & w is[NCERT Pg. 180](1) w = y + u(2) u = W + V(3) v = 2(u + W) (4) v = w + u​

At 100°C Vapour Pressure of aqueoussolution (havingnon-volatilesolute) is 750 mm of Hg. Whatis molality of solution?​

312. Correct expression of enthalpy of combustion is[NCERT Pg. 176](1) C2H6(g) + O2(g) → 2CO(g) + 3H20(1)(2) C(s) +-02 (9) --CO(9)2(diamond)4(3) C(s) +-02 (9)--CO (9)graphite2(4) S(s) + O2(g) →S02 (9)rhombic​

Is the set of quantum number permitted or not permitted =i] n=3 , l=2 , m=0 , s= -1/2ii] n=4 , l=2 , m=3 , s= +1/2​

FAH = a= d.P12. AH = bAH = dAH = C(B.On the basis of Hess's law of constant heat summation, choose the correct relation:(1) b = a -d + c(2) c = a - b + d(3) d = a + b + c(4) a-c = b + d​

UTC(4) a - c = b + d13. In which of the following AH = AU?(1) N. (9) + 3H2(g) → 2NH,(9)(3) PCI;(9) - PCI;(9) + Cl2(9)14. Heat of combustion of CH4, CH4 and C. Ha are 890,(2) C(s) + O2(9) -CO2(9)(4) CaCO3(s) - Cao(s) + CO2(g)​

15. The heat of neutralisation of four acids P, Q, R, S are -13.7. -9.4.-11.2 and -12.4 kcal, respectively whenthey are neutralised by a common base. The acidic character obeys the order(1) P>Q > R > S(2) PSR>Q(3) S > R > Q > P(4) S >> RPfore​

2.1 WHAT IS UNDERSTANDING THE CHEMICAL PROPERTIES OFACIDS AND BASES ?2.1.1WHAT IS ACIDS AND BASES IN THE LABORATORY?2.1.2HOW DO ACIDS AND BASES REACT WITH METALS? ​

Calcium carbo(e)5. Give the names of the elements present in the followingcompounds.(a) Quick lime(b) Hydrogen bromide(c) Baking powder(d) Potassium sulphate.​

Draw the path of light when emerging from (light source, beaker containing the sample, particles in the mixture)

ΔΗ =a1 =1.AP2. ΔΗ =bΔΗ =dΔΗ =-ΔΗ =cOn the basis of Hess's law of constant heat summation, choose the correct relat(1) b = a – d + ο(2) C = a – b + d(3) d = a +6 +οCTΠ​

Write the correct iupac name of the following-(a)pent-4-en-1-yne(b)1,6-Hexdiene(c)But-3-hydroxy-1-one(d)3-Amino-butan-2al

Difference between oxidising agent and reducing agent??If you know the answer then reply otherwise I report your answer but give me answer as soon as possible... I hope you all get it.. Its a humble request ​

When Cu is added to dil.HCl bubble formation is not seen and the temperature also remains unchanged. Give Reason.Class 10​

“Reagents in Organic Chemistry”.1. Which is the suitable catalyst for bringing out the transformation given below?a) BF3. Et20b) NaOEtc) tungsten lampd) dibenzoyl peroxide​

Q.4The product in the following sequence isO요NH HCNNH2NH2OHNH2OHNH2OCHSOHAB.сD.​

The elementspresent inpure water can be separated byA) physical methodB)chemical methodC)both (A) and (B)D)they cannot be separated​

Q.5The reaction given below is an example of which of the following reaction.0H Н+OH+\N-CNA. Ugi reactionB. BiginellireactionC. PasserinireactionD. Streckerreaction​

_____ is the product formed when sulphur reacts with oxygen it dissolves in water to produce _____choose correct option for x and yX. Ya. So2. Acidb. So3. Neutral c. So2. Based. So3. Acid

8.Homogenous mixtures areA) pure mixturesC)partially pure mixturesB)impure mixturesD)none of these​

Q.12 Which of these must be avoided in any presentation?A. Proper grammarB. Complex wordsC. Short sentencesD. Clear voice​

Magnitude of current ?c. State the relationship between Potential difference, Work Done and Charged moved.​

Write balanced chemical equations for the following reactions.i. Naural gas burns in air to form carbon dioxide and water . ii. During Respiration , glucose combines with oxygen to form carbon dioxide and water along with the release of energy .​

On what bases are plants and animals put into different kingdoms? Differentiate betweenkingdom Plantae and the kingdom fungi on the basis of their nutrition and material of cellwalls.(2)​

Hii guys!!!please meri hlp kro aap me se koi mujhe je bta skta hai ki answer me power kyu change ho gye hai plz ​

. The temperature at which hydrogen moleculeshave the same kinetic energy as oxygen moleculeshave at 40°C is : give ans with full explanation plz​

Which of the following relation holds true for anequilibrium reaction, if its reaction quotient(Q) = 1?(1) AG = 0(2) AG° = 0(3) AG > AG°(4) AG = AG°

Electrolysis of molten lead bromide is carried out.The bulb will not light until the lead bromide has melted. Why not?

Orange A, Greento solid (A)residue(B) + Gas (C) + Gas (D)hotCaC₂NaOHAnhydrousCuSO4Evolvedgas (F)Product (H)Turns intois a good blue compoundYellowfro fertilizer(E)solution (G) SEHOPb(OAC),Yellow ppt. (1)Gas (F) + CaCO3TCCaso stommPassage 5: For Questions 13-16​

Iv.In crystal lattice formed by bcc unitcell the void volume isa. 68 %b. 74 %c.32 %d. 26%

Who proposed Plum pudding model? *2 pointsChadwickJ J ThomsonBohr

A gas is collected at a pressure of 95 cm of Hg and a temperature of 50°C. To what temperatureshould it be cooled so that is occupies a volume which is 80% of its original volume when thepressureof thegasis 90 cm of Hg.

The idea of the smallest unit of matter was first given by, *2 pointsMaharshi kanadaDemocritusDalton

The elementwith atomic number 118, will bea.Alkali b. Noble gas c. lanthanided.transition element

Use of this solution?Is the distilled water acidic/basic/neutral? How would you verify it?Describe the process of neutralisation with the help of an example.

12. The boiling point of benzene is 353.23 K. When1.80 g of a non-volatile solute was dissolved in90 g of benzene, the boiling point is raised to354.11 K. Calculate the molar mass of the solute.(K for benzene is 2.53 K kg mol-').33

Kclo3 on heating to give kcl and o2. what is the volume of o2 at Ntp liberate by 0.1 mole of kclo3 ?

The compressibility factor for gas obeying van der Waals’ equation of state is given by ( where Vm is molar volume)A) Vm / Vm-b =a / RTVmB) a / RTVm = Vm / Vm-bC) RTVm / a = Vm-b / VmPlzz give me answer

Good morning friends . Jo friends iss time uthe hua h unn ka liya .or jo abhi soa nahi unm k liya good night

What is the threshold frequency of a metal whose workfunction is 13.26 x 10-25 J?(h=6.63 * 10-34 Js)• 910-8 Hz1x1010 Hz2 x 100 Hz5 100 Hz

IN the laboratory an alkane may be prepared by:a) 3 methodsb) 4 methodsc) 5 methodsd) 6 methods

Please answer this it's urgent....What happens when crystal of sodium carbonate us added into dilute HCl ?? give reaction .....!!

3.Copper metal rects with conctrated HNO, asCu + 4HNO, 4 Cu(NO3)2 + 2NO, + 2H,0 .The number of moles of the HNO, reducedby one mole of the Cu will be1) 4 2) 2 3) 0.5 4) 0.25

The loops in Ptolemy's __model, and those shown on the video, are called _ motion.This phenomenon is caused by Earth's__ orbit than those of other planets. Options:A) Heliocentric B) GeocentricC) Retrograde Where do they go?

5.Consider the followingAH= u kJ/molsolAB(S)→ A(aq) + B (aq)AHLE = w kJ/mol= v kJ/molhydrationΔΗA(g) + B(g)The correct relation between u, v & w is[NCERT Pg. 180](1) w = y + u(2) u = W + V(3) v = 2(u + W) (4) v = w + u

At 100°C Vapour Pressure of aqueoussolution (havingnon-volatilesolute) is 750 mm of Hg. Whatis molality of solution?

312. Correct expression of enthalpy of combustion is[NCERT Pg. 176](1) C2H6(g) + O2(g) → 2CO(g) + 3H20(1)(2) C(s) +-02 (9) --CO(9)2(diamond)4(3) C(s) +-02 (9)--CO (9)graphite2(4) S(s) + O2(g) →S02 (9)rhombic

Is the set of quantum number permitted or not permitted =i] n=3 , l=2 , m=0 , s= -1/2ii] n=4 , l=2 , m=3 , s= +1/2

FAH = a= d.P12. AH = bAH = dAH = C(B.On the basis of Hess's law of constant heat summation, choose the correct relation:(1) b = a -d + c(2) c = a - b + d(3) d = a + b + c(4) a-c = b + d

UTC(4) a - c = b + d13. In which of the following AH = AU?(1) N. (9) + 3H2(g) → 2NH,(9)(3) PCI;(9) - PCI;(9) + Cl2(9)14. Heat of combustion of CH4, CH4 and C. Ha are 890,(2) C(s) + O2(9) -CO2(9)(4) CaCO3(s) - Cao(s) + CO2(g)

15. The heat of neutralisation of four acids P, Q, R, S are -13.7. -9.4.-11.2 and -12.4 kcal, respectively whenthey are neutralised by a common base. The acidic character obeys the order(1) P>Q > R > S(2) PSR>Q(3) S > R > Q > P(4) S >> RPfore

2.1 WHAT IS UNDERSTANDING THE CHEMICAL PROPERTIES OFACIDS AND BASES ?2.1.1WHAT IS ACIDS AND BASES IN THE LABORATORY?2.1.2HOW DO ACIDS AND BASES REACT WITH METALS?

Calcium carbo(e)5. Give the names of the elements present in the followingcompounds.(a) Quick lime(b) Hydrogen bromide(c) Baking powder(d) Potassium sulphate.

ΔΗ =a1 =1.AP2. ΔΗ =bΔΗ =dΔΗ =-ΔΗ =cOn the basis of Hess's law of constant heat summation, choose the correct relat(1) b = a – d + ο(2) C = a – b + d(3) d = a +6 +οCTΠ

Difference between oxidising agent and reducing agent??If you know the answer then reply otherwise I report your answer but give me answer as soon as possible... I hope you all get it.. Its a humble request

When Cu is added to dil.HCl bubble formation is not seen and the temperature also remains unchanged. Give Reason.Class 10

“Reagents in Organic Chemistry”.1. Which is the suitable catalyst for bringing out the transformation given below?a) BF3. Et20b) NaOEtc) tungsten lampd) dibenzoyl peroxide

Q.4The product in the following sequence isO요NH HCNNH2NH2OHNH2OHNH2OCHSOHAB.сD.

The elementspresent inpure water can be separated byA) physical methodB)chemical methodC)both (A) and (B)D)they cannot be separated

Q.5The reaction given below is an example of which of the following reaction.0H Н+OH+\N-CNA. Ugi reactionB. BiginellireactionC. PasserinireactionD. Streckerreaction

_ is the product formed when sulphur reacts with oxygen it dissolves in water to produce _choose correct option for x and yX. Ya. So2. Acidb. So3. Neutral c. So2. Based. So3. Acid

8.Homogenous mixtures areA) pure mixturesC)partially pure mixturesB)impure mixturesD)none of these

Q.12 Which of these must be avoided in any presentation?A. Proper grammarB. Complex wordsC. Short sentencesD. Clear voice

Magnitude of current ?c. State the relationship between Potential difference, Work Done and Charged moved.

Write balanced chemical equations for the following reactions.i. Naural gas burns in air to form carbon dioxide and water . ii. During Respiration , glucose combines with oxygen to form carbon dioxide and water along with the release of energy .

On what bases are plants and animals put into different kingdoms? Differentiate betweenkingdom Plantae and the kingdom fungi on the basis of their nutrition and material of cellwalls.(2)

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. The temperature at which hydrogen moleculeshave the same kinetic energy as oxygen moleculeshave at 40°C is : give ans with full explanation plz

Orange A, Greento solid (A)residue(B) + Gas (C) + Gas (D)hotCaC₂NaOHAnhydrousCuSO4Evolvedgas (F)Product (H)Turns intois a good blue compoundYellowfro fertilizer(E)solution (G) SEHOPb(OAC),Yellow ppt. (1)Gas (F) + CaCO3TCCaso stommPassage 5: For Questions 13-16