Calculate the amount of each present in solution 2litres of N/10 HCl

1.	Calculate the amount of each present in solution 2litres of N/10 HCl
Answer» Answer: Therefore add 8.3 ML of 37% HCL to 1 LITER of D5W or NS to CREATE a 0.1N HCL SOLUTION. 12M (37% HCL) = 12 moles/L = 12 x 36.5 = 438 g/L = 438 mg/m Explanation:

Answer»

Answer:

Therefore add 8.3 ML of 37% HCL to 1 LITER of D5W or NS to CREATE a 0.1N HCL SOLUTION. 12M (37% HCL) = 12 moles/L = 12 x 36.5 = 438 g/L = 438 mg/m

Explanation:

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