What is the threshold frequency of a metal whose workfunction is 13.26

1.	What is the threshold frequency of a metal whose workfunction is 13.26 x 10-25 J?(h=6.63 * 10-34 Js)• 910-8 Hz1x1010 Hz2 x 100 Hz5 100 Hz
Answer» Answer:- $\red{\bigstar}$ Threshold FREQUENCY $\large\leadsto\boxed{\sf \green{2 \times 10^{-9}Hz}}$ • Given:- WORK FUNCTION = $\bf{13.26 \times 10^{-25}J}$ • To Find:- Threshold frequency = ? • Solution:- $\pink{\bigstar}$ $\boxed{\sf{Work \: function [W_{0}] = Planck's \: Constant [h] \times Threshold \: frequency [v_{0}]}}$ here, h [Planck's constant] = 6.63 × 10 -³⁴ Js Hence, → $\sf{13.26 \times 10^{-25} J = 6.63 \times 10^{-34} Js \times v_{0}}$ → $\sf{v_{0} = \dfrac{13.26 \times 10^{-25}J}{6.63 \times 10^{-34}Js}}$ → $\sf \green{v_{0} = 2 \times 10^{-9}sec^{-1}}$ THEREFORE, the threshold frequency of the metal is $\bf{2 \times 10^{-9}Hz}$