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This section includes 7 InterviewSolutions, each offering curated multiple-choice questions to sharpen your Current Affairs knowledge and support exam preparation. Choose a topic below to get started.
| 1. |
The factors of x² - 6x + 9 are |
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Answer» Step-by-step explanation: PLEASE GIVE me some thanks please MARK as brain list good morning |
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| 2. |
Find three rational numbers between 4/9and 5/7 by using the mean methodsplease tell me fast |
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Answer» Answer: 28/63,29/63,3063,31/63,45/63 Step-by-step explanation: 4/9 and 5/9 4*7/9*7 = 28/63 5*9/7*9=45/63 28/63 , 29/63 , 30/63, 31/63 , 45/63 please LIKE it |
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| 3. |
Find three rational numbers between 4/9and 5/7 by using the mean methods |
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Answer» 29/63 , 30/63 ,31/63 ,32/63, 33/63 , 34/63, 35/63 ,36/63 ,37/63 ,38/63 , 39/63 ,40/63 ,41/63 , 42/63 ,43/63 ,44/ 63 |
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| 4. |
Fibre to Fabric question answer from which parts of the plant cotton and jute ar obtained answer |
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Answer» Step-by-step explanation: (a) Cotton is obtained from the FRUIT of the cotton plants. The cottonseed which is a fruit which on ripening splits open to release white FIBERS of cotton. (b) Jute is obtained from the STEM of the jute plant. I think it is HELPFUL for you |
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| 5. |
Find the area of the rectangle whose length is 23.7cm and breath is 5.2 cm explain clearly |
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Answer» AREA = 123.24 cm² Step-by-step EXPLANATION: RECTANGLE area = Length×breadth = 23.7×5.2 = 123.24 cm² |
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| 6. |
Find the value of the following: (-2³) ×(-10³) |
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Answer» Step-by-step EXPLANATION: if the POWERS are same we will multiply the BASES on multiplying based we GET 20³ |
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| 7. |
AltsItlum, tind the value of 'x) |
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Answer» Answer: Here l∥m and p is TRANSVERSAL Therefore (3x+20) o +(5x−8) o =180 o (SUM of the interior angles on the same side of a transversal) 3x+20 o +5x−8 o =180 o
8x+12 o =180 o
8x=180 o −12 o
8x=168 o
X= 8 168 o
=21 o Step-by-step explanation: follow now |
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| 8. |
Let's see how much finds ans to this blue region |
| Answer» | |
| 9. |
IF X/V4 =V16, THEN FIND THE VALUE OF X(a) 4(b) 16(c) 8(d) 12 |
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Answer» Answer: 12 and the SOLUTION is below Step-by-step EXPLANATION: X/V4=V16 ->X=V16*V-4 ->X=V16-4 ->X=V12 |
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| 10. |
Roman Numeral class 6show that each of the following is meaningless. Give reason in each case.1. VC2. IL3. VVII4. IXX==================Math================== Roman Numeral===========assignment |
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Answer» Answer: 1. 56 2=15888855885 5555525 58888 |
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| 11. |
Graham carves a block of wood shaped like a cube with a square pyramid on top. What is the surface area of the toy?Type your answer and show your work in the space provided. You can take a picture and upload the image of your work. |
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Answer» FOLLOW now Step-by-step EXPLANATION: |
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| 12. |
The weight of 1000 children average 50 kg and the standard deviation is 5 kg. what is the z-score corresponds to 55?Solution: |
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Answer» Step-by-step EXPLANATION: ASSUME a normal distribution.Convert the upper and lower weight limits to ‘Z’ scores using the given average (or mean) and STANDARD deviation.Now use those scores in a table or online calculator (SAY Normal distribution calculator ) to find the fraction of the children between the the scores.Finally obtain the fraction of 1,000 using that fraction. |
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| 13. |
1) Pramod travelled 95km 659m on Saturday, 109km 253m on Sunday.Find the total distance travelled by Pramod? |
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Answer» Given |
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| 14. |
If a =3+√5/2 find a^2+1/a^2 |
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Answer» Step-by-step explanation: a= 2 3+
∴ a
= 3+ 5
2
On rationaliging the denominator , we get , a 1
= (3+ 5
)(3− 5
) 2(3− 5
)
= 9−5 6−2 5
= 4 6−2 5
= 2 3− 5
Also, (a+ a 1
) 2 =a 2 + a 2
1
+2 Substituting the values of a = a 1
, We get , `( 2 3+ 5
+ 2 3− 5
) 2 =(a 2 + a 2
1
+2) ∴a 2 + a 2
1
+2=( 2 3+ 5
+3− 5
) 2
=(3) 2 =9 ∴a 2 + a 2
1
=9−2=7. |
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| 15. |
Sorry i asked this question on accident :\ |
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Answer» its ok Step-by-step EXPLANATION: |
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| 16. |
In the pascal's triangle, all the elements of _____ Slanting row are triangular number |
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| 17. |
The radius of a circle is 3 feet. What is the circle's area?r=3 ft |
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Answer» Step-by-step EXPLANATION: so as we KNOW A= πr2 A=22/7×3² A=28.27 FT |
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| 18. |
Question =“Determine the total surface area of the prism” What is the answer please help |
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Answer» Answer: 392cm^2 Step-by-step EXPLANATION: We need to find the AREAS of each face The front and back share the same area That MEANS 6+6+32 for one face Multiply by 2 u get 88cm^2 for the front and back The Top face has an area of 64cm^2 The left and right faces have an area of 100cm^2 Now for the BOTTOM face We have 140cm^2 Add them all up You have 392cm^2 |
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| 19. |
Write 40/323240 start fraction, 40, divided by, 32, end fraction in simplest form. |
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Answer» Fabzara/customer/care/number/❾❽❽❸❸❺❾❾❸❽//❾❽❽❸❸❺❾❾❸❽ Fabzara/customer/care/number/❾❽❽❸❸❺❾❾❸❽//❾❽❽❸❸❺❾❾❸❽ Fabzara/customer/care/number/❾❽❽❸❸❺❾❾❸❽//❾❽❽❸❸❺❾❾❸❽ |
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| 20. |
Construct triangle ABC with BC=7.5cm,AC=5cm and MLC=60° |
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Answer» Step-by-step EXPLANATION: |
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| 21. |
Division following rational number. |
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Answer» Step-by-step explanation: 1. DIVIDE 14/5 by 21/15 by MULTIPLYING by the reciprocal of 21/15
14/5×15/21 2. CANCEL out 3×5×7 in both the numerator and denominator. answer = 2 thank you |
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| 22. |
Heather invested $8,000 in a 4-year Certificate of Deposit (CD) that pays 4.1% interest compounded annually. What is the value of the CD at the end of the 4 years? * |
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Answer» Step-by-step EXPLANATION: equation: A=P(1+i)^n p=AMOUNT- 8000 i=interest in %- 4.1/100 n= no. of years- 4 A= 8000(1+0.041)^4 A= 8000×1.17436450976 A= 9394.916 Interest = 1394.916 TOTAL AMOUNT RECEIVABLE = 9394.916 |
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| 23. |
Nadal invests $5,678 at an annual interest rate of 4.5 percent for 6 years. For which variable can Nadal substitute the value 5,678 in the simple interest formula?I = p r t |
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Answer» Answer: DESCRIBE the structure and function |
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| 24. |
6. Reduce the following fractions to their simplest form:115fractions into equivalent like fractions |
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Answer» Find the GCD (or HCF) of NUMERATOR and denominator GCD of 115 and 100 is 5 Divide both the numerator and denominator by the GCD 115 ÷ 5 100 ÷ 5 Reduced fraction: 23 20 Therefore, 115/100 SIMPLIFIED to LOWEST terms is 23/20. |
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| 25. |
The area of a square is 529 cm2. Find the length of one side. |
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Answer» length of square = length=23 cm |
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| 26. |
here is a rectangle ABCD the length of the rectangle is increased by 10% the width of the rectangle is increased by 5% find the percentage increase in the perimeter of the rectangle |
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Answer» Answer: 15% Step-by-step EXPLANATION: |
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| 27. |
Express the first quantity as a percentage of the second. 225mm,20cm |
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Answer» Answer: 20cm is 90% of 225mm |
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| 28. |
Exercise 4: Identify the kind of the underlined nouns in the following sentences:1. Radhakrishnan was the President of India2. Health is a great blessing,3. Kalidasa was the Shakespeare of India,4. Our team defeated the Korean team5. He spent his last years in peace.6. The love of money is the root of all evil.7. This chain is made of gold.8. I value his judgement.9. A crowd collected in the street.10. You should be careful about his safety. |
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Answer» Answer: 1.Radhakrishnan was the PRESIDENT of India 2. Health is a great blessing, 3. Kalidasa was the SHAKESPEARE of India, 4. Our team DEFEATED the Korean team 5. He spent his last year in peace. 6. The love of money is the root of all evil. 7. This chain is made of gold. 8. I VALUE his judgement. 9. A crowd collected in the street. 10. You should be CAREFUL about his safety.
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| 29. |
Find the value of 'a' and 'b' Please Answer⚠️Don't Spam⚠️ |
Answer» (5+√3)/(√5-√3) = a/2 + 3b√15Rationalising the LHS (5+√3)(√5+√3) / (√5-√3)(√5+√3) = a/2 + 3b√15 5(√5+√3) + √3(√5+√3) / (√5)²-(√3)² = a/2 + 3b√15 5√5+5√3 + √15+3/ 5-3 = a/2 + 3b√15 5√5+5√3+3 + √15/ 2 = a/2 + 3b√15 (5√5+5√3+3)/2 + √15/ 2 = a/2 + 3b√15 a = 5√5+5√3+3 3b = 1/2 b = 1/6 |
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| 31. |
A pan has an original price of $32 but is marked down by 15 percent. Which equation shows the new price of the pan? |
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Answer» okkkkkkkkkkkkkkkkkkkkkkkkkkkk |
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| 32. |
Simplify the following.a) 15 + {24-48÷(7+16×2-27)} |
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Answer» Step-by-step EXPLANATION: |
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| 33. |
⚠️No Spam⚠️Please Solve |
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Answer» a=11, B= -6√3 Step-by-step EXPLANATION:
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| 34. |
7. Convert the speed of 15 m/s into km/h |
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Answer» Answer: 54 km/h Step-by-step explanation: 1 km/h = 1000m/60*60S = 1000m/3600s = (5/18) m/s So, 1 m/s = (18/5) km/h 15 m/s = 15* (18/5) km/h = 3*18 km/h = 54 km/h |
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| 35. |
In the hardware store there are five skeins of copper wire 120, 108, 84, 72, 60 m long. You have to divide them equally.What will be the maximum length of each part? |
Answer» ☆ SolutionRadius of the steel CABLE, r=1.5 cm = 0.015 m MAXIMUM allowable stress = 108 N/m2 Maximum stress =Areaofcross−sectionMaximumforce Maximum force = Maximum stress × Area of cross-section = 108×π×(0.015)2 = 7.065×104 N Hence, the cable can support the maximum . |
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| 36. |
In 18 by 3 = 6 , 6 is called |
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Answer» Answer: 6 called DIVISOR of 18 Step-by-step explanation: |
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| 37. |
12. Find the HCF and LCM of each of the following sets of numbers.(a) 84 and 189(b) 315 and 720C 392 and 616(d) 1008 and 1764e 140, 224 and 560(f) 315, 525 and 1400(g) 252, 378 and 567(h) 330, 792 and 1188Pls help me in this math hwww |
Answer» A) 84 and 189HCF = 21 , LCM = 756 B) 315 and 720HCF = 45 , LCM = 5040 C) 392 and 616HCF = 56 , LCM = 4312 D) 1008 and 1764HCF = 252 , LCM = 7065 E) 140, 224 and 560HCF = 28 , LCM = 1120 F) 315, 525 and 1400HCF = 35 , LCM = 12600 G) 252, 378 and 567HCF = 63 , LCM = 2268 H) 330, 792 and 1188HCF = 66 , LCM = 11880 ♡HOPE IT HELPS YOU♡ |
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| 38. |
A wholesaler has three bags of sugar weighing 54, 45 and 63 kg. He wants to make as many bags of equal weight as large as possible without mixing the contents of the bags. > How many bags can he fill?I want minimum comen multiple |
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Answer» Radius of the steel CABLE, r=1.5 cm = 0.015 m Radius of the steel cable, r=1.5 cm = 0.015 mMaximum ALLOWABLE stress = 10 Radius of the steel cable, r=1.5 cm = 0.015 mMaximum allowable stress = 10 8 Radius of the steel cable, r=1.5 cm = 0.015 mMaximum allowable stress = 10 8 N/m Radius of the steel cable, r=1.5 cm = 0.015 mMaximum allowable stress = 10 8 N/m 2 Radius of the steel cable, r=1.5 cm = 0.015 mMaximum allowable stress = 10 8 N/m 2 Radius of the steel cable, r=1.5 cm = 0.015 mMaximum allowable stress = 10 8 N/m 2 Maximum stress = Radius of the steel cable, r=1.5 cm = 0.015 mMaximum allowable stress = 10 8 N/m 2 Maximum stress = Areaofcross−section Radius of the steel cable, r=1.5 cm = 0.015 mMaximum allowable stress = 10 8 N/m 2 Maximum stress = Areaofcross−sectionMaximumforce Radius of the steel cable, r=1.5 cm = 0.015 mMaximum allowable stress = 10 8 N/m 2 Maximum stress = Areaofcross−sectionMaximumforce Radius of the steel cable, r=1.5 cm = 0.015 mMaximum allowable stress = 10 8 N/m 2 Maximum stress = Areaofcross−sectionMaximumforce Radius of the steel cable, r=1.5 cm = 0.015 mMaximum allowable stress = 10 8 N/m 2 Maximum stress = Areaofcross−sectionMaximumforce Maximum force = Maximum stress × Area of cross-section Radius of the steel cable, r=1.5 cm = 0.015 mMaximum allowable stress = 10 8 N/m 2 Maximum stress = Areaofcross−sectionMaximumforce Maximum force = Maximum stress × Area of cross-section = 10 Radius of the steel cable, r=1.5 cm = 0.015 mMaximum allowable stress = 10 8 N/m 2 Maximum stress = Areaofcross−sectionMaximumforce Maximum force = Maximum stress × Area of cross-section = 10 8 Radius of the steel cable, r=1.5 cm = 0.015 mMaximum allowable stress = 10 8 N/m 2 Maximum stress = Areaofcross−sectionMaximumforce Maximum force = Maximum stress × Area of cross-section = 10 8 ×π×(0.015) Radius of the steel cable, r=1.5 cm = 0.015 mMaximum allowable stress = 10 8 N/m 2 Maximum stress = Areaofcross−sectionMaximumforce Maximum force = Maximum stress × Area of cross-section = 10 8 ×π×(0.015) 2 Radius of the steel cable, r=1.5 cm = 0.015 mMaximum allowable stress = 10 8 N/m 2 Maximum stress = Areaofcross−sectionMaximumforce Maximum force = Maximum stress × Area of cross-section = 10 8 ×π×(0.015) 2 Radius of the steel cable, r=1.5 cm = 0.015 mMaximum allowable stress = 10 8 N/m 2 Maximum stress = Areaofcross−sectionMaximumforce Maximum force = Maximum stress × Area of cross-section = 10 8 ×π×(0.015) 2 = 7.065×10 Radius of the steel cable, r=1.5 cm = 0.015 mMaximum allowable stress = 10 8 N/m 2 Maximum stress = Areaofcross−sectionMaximumforce Maximum force = Maximum stress × Area of cross-section = 10 8 ×π×(0.015) 2 = 7.065×10 4 Radius of the steel cable, r=1.5 cm = 0.015 mMaximum allowable stress = 10 8 N/m 2 Maximum stress = Areaofcross−sectionMaximumforce Maximum force = Maximum stress × Area of cross-section = 10 8 ×π×(0.015) 2 = 7.065×10 4 N Radius of the steel cable, r=1.5 cm = 0.015 mMaximum allowable stress = 10 8 N/m 2 Maximum stress = Areaofcross−sectionMaximumforce Maximum force = Maximum stress × Area of cross-section = 10 8 ×π×(0.015) 2 = 7.065×10 4 NHence, the cable can support the maximum load of 7.065×10 Radius of the steel cable, r=1.5 cm = 0.015 mMaximum allowable stress = 10 8 N/m 2 Maximum stress = Areaofcross−sectionMaximumforce Maximum force = Maximum stress × Area of cross-section = 10 8 ×π×(0.015) 2 = 7.065×10 4 NHence, the cable can support the maximum load of 7.065×10 4 Radius of the steel cable, r=1.5 cm = 0.015 mMaximum allowable stress = 10 8 N/m 2 Maximum stress = Areaofcross−sectionMaximumforce Maximum force = Maximum stress × Area of cross-section = 10 8 ×π×(0.015) 2 = 7.065×10 4 NHence, the cable can support the maximum load of 7.065×10 4 N. |
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| 39. |
Simplify the following 4√3-9√3 |
Answer» HEY dear your answer =5√3please Mark as Brainliest answer anymore QUESTION |
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| 40. |
A player in a board game rolls a six-sided number cube labeled 1 through 6 one time. Determine the theoretical probability of rolling a 1 or 2. |
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Answer» Answer: Cost of a smartphone = Rs. 24500 Cost of a FEATURE PHONE = Rs. 9750 Step-by-step explanation: To Find: The cost of a smartphone and a feature phone. Let us assume: The cost of a smartphone be x. The cost of a feature phone be y. The price of a smartphone is 5000 more than the cost of two feature phones. i.e., x = 2y + 5000 _____(i) The cost of 4 feature phones and two smartphone is 88000. i.e., 4y + 2x = 88000 _____(ii) Finding the cost of a smartphone and a feature phone: In equation (ii). ⟿ 4y + 2x = 88000 Substituting the value of x from eqⁿ(i). ⟿ 4y + 2(2y + 5000) = 88000 ⟿ 4y + 4y + 10000 = 88000 ⟿ 8Y = 88000 - 10000 ⟿ 8y = 78000 ⟿ y = 78000/8 ⟿ y = 9750 ∴ Cost of a feature phone = Rs. 9750 In equation (i). ⟿ x = 2y + 5000 ⟿ x = 2(9750) + 5000 ⟿ x = 19500 + 5000 ⟿ x = 24500 ∴ Cost of a smartphone = Rs. 24500 |
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| 41. |
Do this one please help |
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Answer» b) 2,4,5,6 Step-by-step EXPLANATION: prime NUMBERS= 2 and 5 composite number=4 and 6 |
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| 42. |
The measure of an angle is four times the measure of its complementary angle. What is the measure of each angle? |
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Answer» Step-by-step explanation: Therefore the second angle = 4x Two ANGLES are called complementary when their measures add to 90 degrees. Therefore, x + 4x = 90 = 5x = 90 = x = 90/5 = 18 Answers:- First angle = Second angle = 4 * 18 or 90 - 18 = Hope it HELPS! |
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| 43. |
1/(a+b+x) = 1/a + 1/b + 1/x |
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Answer» |
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| 45. |
True or false. I and x can reapted at the most three times |
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Answer» TRUE ,I and X and C can be REPEATED only up to THREE times.symbols V,D And L are not repeated |
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| 46. |
X - 5 + x^2/x+5 = 11 |
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Answer» Let's GO through this problem together! :D Objective: To FIND "x". Equation: x -5 + x² / x + 5 What it equals to: 11 First let's take all the constant numbers to the other equal side. ∴ x + x² / x + 5 = 11 + 5 = x + x² / x + 5 = 16. Now let's make the question more clear. = Let's now multiply. ∴ x² = x + 5 - 16 = x² = x - 11 = x² + x = - 11 = x × x + x = - 11 = 3X= - 11 = x = I THINK I'm wrong with the answer, but hopefully the STEPS are correct :) |
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| 47. |
Which of the following is 3d object A rectangle b circle c square d cylinder |
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| 48. |
Represent 8/5and √20 on a number line. |
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Answer» Answer: here is your answer Step-by-step EXPLANATION: have a GREAT DAY. HOPE you understand my HANDWRITING |
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| 49. |
Find square root of 76176 by using long division method |
Answer» ☆ SolutionDIVIDE the NUMBER (76176) by 2 to get the first guess for the square ROOT . First guess = 76176/2 = 38088. Step 2: Divide 76176 by the previous RESULT. |
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| 50. |
Assosative property pls explain |
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Answer» Answer: This property states that when three or more NUMBERS are added (or multiplied), the sum (or the product) is the same regardless of the grouping of the addends (or the MULTIPLICANDS). ASSOCIATIVE property INVOLVES 3 or more numbers. |
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