In the hardware store there are five skeins of copper wire 120, 108, 8

1.	In the hardware store there are five skeins of copper wire 120, 108, 84, 72, 60 m long. You have to divide them equally.What will be the maximum length of each part?
Answer» ☆ Solution Radius of the steel CABLE, r=1.5 cm = 0.015 m MAXIMUM allowable stress = 108 N/m2 Maximum stress =Areaofcross−sectionMaximumforce Maximum force = Maximum stress × Area of cross-section = 108×π×(0.015)2 = 7.065×104 N Hence, the cable can support the maximum .

In the hardware store there are five skeins of copper wire 120, 108, 84, 72, 60 m long. You have to divide them equally.What will be the maximum length of each part?

Answer»

Radius of the steel CABLE, r=1.5 cm = 0.015 m

MAXIMUM allowable stress = 108 N/m2

Maximum stress =Areaofcross−sectionMaximumforce

Maximum force = Maximum stress × Area of cross-section

= 108×π×(0.015)2

= 7.065×104 N

Hence, the cable can support the maximum .