98971 + Interview Questions in Primary School in Math

1.	ABCD is a parallelo-gram. Point E is on the ray AB suchthat BE = AB then prove that line EDbisects seg BC at point F.
Answer» Then i am a CHICKEN!

Discussion

2.	2. Use the given digits without repetition and make the greatest and smallest4-digit numbers(a) 2. 8. 7. 4 (b) 9.7. 4.1(c) 4.7.5.0(d) 1. 7. 6. 2 (e) 5. 4.0.3
Answer» ANSWER: hi Step-by-step EXPLANATION:

2.

2. Use the given digits without repetition and make the greatest and smallest4-digit numbers(a) 2. 8. 7. 4 (b) 9.7. 4.1(c) 4.7.5.0(d) 1. 7. 6. 2 (e) 5. 4.0.3

Answer»

ANSWER: hi

Step-by-step EXPLANATION:

Discussion

3.	The sum of two numbers is 7/8 . If one of them is 3/4. Find the otherDon't Spam.. ❌❌Spam=Reported
Answer» ANSWER= 1/8 I HOPE this HELP you

3.

The sum of two numbers is 7/8 . If one of them is 3/4. Find the otherDon't Spam.. ❌❌Spam=Reported

Answer»

ANSWER= 1/8

I HOPE this HELP you

Discussion

4.	A shopkeeper suffers a loss of 15% by selling a table for ` 680. The cost price of thetable is ________________ .
Answer» Step-by-step EXPLANATION: PLEASE MARK it as BRANLIEST

4.

A shopkeeper suffers a loss of 15% by selling a table for ` 680. The cost price of thetable is ________________ .

Answer»

Step-by-step EXPLANATION:

PLEASE MARK it as BRANLIEST

Discussion

5.	5^6 × 11^3----------------------121 × 11^4 × 625please show the working as well thank you
Answer» ANSWER: 1,572,763,671,875 I HOPE you are HAPPY

5.

5^6 × 11^3----------------------121 × 11^4 × 625please show the working as well thank you

Answer»

ANSWER:

1,572,763,671,875 I HOPE you are HAPPY

Discussion

6.	30. The length and breadth of an auditorium are 30 m and 24 mmrespectively. The rate of ulingis? 75 per sq metre and the Labourcharges are 25 per sq metre. Find the total expense of thing theauditorium(1) 33600012) 772000(3) 35400014) 7 96000
Answer» Answer: LENGTH of auditorium = 20m Breadth of auditorium = 15m Height of auditorium = 10m Rate of painting walls = Cost of painting the FOUR walls We need to paint the four walls of the auditorium.Hence, we need to find the lateral surface area of the auditorium. Lateral Surface Area of Auditorium = 2h(l+b) = 2(10)(20 + 15) = 20(35) = Cost of painting four walls = Rate × Area = 750 × 700 = Rs.525000 Therefore, the cost of painting four walls of the auditorium is Rs.525000 only. ___________________________ @ItsMysteriousGirl o2z1qpv and 14 more users found this answer helpful THANKS 8 5.0 (6 votes) Log in to add comment Answer 5.0/5 3 avni1433 Ambitious 19 answers 905 people helped Answer: the answer is 525000 Step-by-step explanation: 2h (l+b) 2(10)(20+15) 20(35)= 20 ×35 = 700 m cube cost =Rate × area = 750 ×700 =525000 Niccherip5 and 4 more users found this answer helpful THANKS 3 5.0 (1 vote) Log in to add comment Still have questions? FIND MORE ANSWERS ASK YOUR QUESTION New questions in Math Represent√9.3 on the number line In the given figure,arc AB = arc BC and angle BOC = 50°.Find: (i) angle AOB(ii) angle OAC f(x)3x-5 find the(4) please answer with solution and you will be marked as BRAINLIEST... dont spam please.. Find the square of 3 root 5 by 5.<br /> $3 \sqrt{5} \div 5$ <br /> Give me answer please find the unit digit of ${124}^{128}$ wis-egnv-tat only ho-rny girl 5. The following data shows the number of students participated in statelevel competitions in different sports of a secondary school. Draw apercentage … The incomes of RUCHI and Rajan are in the RATIO 4: 7. If Ruchi earns 16800 per month,how much does Rajan earn per month? Previous Next Ask your

6.

30. The length and breadth of an auditorium are 30 m and 24 mmrespectively. The rate of ulingis? 75 per sq metre and the Labourcharges are 25 per sq metre. Find the total expense of thing theauditorium(1) 33600012) 772000(3) 35400014) 7 96000

Answer»

Answer:

LENGTH of auditorium = 20m

Breadth of auditorium = 15m

Height of auditorium = 10m

Rate of painting walls =

Cost of painting the FOUR walls

We need to paint the four walls of the auditorium.Hence, we need to find the lateral surface area of the auditorium.

Lateral Surface Area of Auditorium

= 2h(l+b)

= 2(10)(20 + 15)

= 20(35)

=

Cost of painting four walls

= Rate × Area

= 750 × 700

= Rs.525000

Therefore, the cost of painting four walls of the auditorium is Rs.525000 only.

___________________________

@ItsMysteriousGirl

o2z1qpv and 14 more users found this answer helpful

THANKS

8

5.0

(6 votes)

Log in to add comment

Answer

5.0/5

3

avni1433

Ambitious

19 answers

905 people helped

Answer:

the answer is 525000

Step-by-step explanation:

2h (l+b)

2(10)(20+15)

20(35)= 20 ×35 = 700 m cube

cost =Rate × area

= 750 ×700

=525000

Niccherip5 and 4 more users found this answer helpful

THANKS

3

5.0

(1 vote)

Log in to add comment

Still have questions?

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ASK YOUR QUESTION

New questions in Math

Represent√9.3 on the number line

In the given figure,arc AB = arc BC and angle BOC = 50°.Find: (i) angle AOB(ii) angle OAC

f(x)3x-5 find the(4)

please answer with solution and you will be marked as BRAINLIEST... dont spam please..

Find the square of 3 root 5 by 5.<br /> $3 \sqrt{5} \div 5$ <br />

Give me answer please

find the unit digit of ${124}^{128}$

wis-egnv-tat only ho-rny girl

5. The following data shows the number of students participated in statelevel competitions in different sports of a secondary school. Draw apercentage …

The incomes of RUCHI and Rajan are in the RATIO 4: 7. If Ruchi earns 16800 per month,how much does Rajan earn per month?

Ask your

Discussion

7.	The lower limit and the upper limit of the first class of the given classinterval 0-50 50-100
Answer» Blablablablablablabla

Discussion

8.	What least number should be subtracted from 1365 to get a number exactly divisible by 25?Guys please answer with step by step explanation.
Answer» Answer: 1350 Step-by-step EXPLANATION: so the rule that can be divide by 25 is to SEE whether the LAST two digits can divide 25 or not. EXAMPLES: the last two digits of 150 is 50 and 50 can divide 25, so 150 can divide 25 we know that 25×3=75 and the last two digits of 1365 is 65 so its impossible to get 1375 so we can only do 25×2=50 and the ans is 1350

8.

What least number should be subtracted from 1365 to get a number exactly divisible by 25?Guys please answer with step by step explanation.

Answer»

Answer:

1350

Step-by-step EXPLANATION:

so the rule that can be divide by 25 is to SEE whether the LAST two digits can divide 25 or not. EXAMPLES: the last two digits of 150 is 50 and 50 can divide 25, so 150 can divide 25

we know that 25×3=75 and the last two digits of 1365 is 65 so its impossible to get 1375 so we can only do 25×2=50 and the ans is 1350

Discussion

9.	Evaluate the following algebraic expression using suitable laws of exponents:-(9lm2/3l-3m7)-3I'll mark as brainliest if your answer is correct and reasonable
Answer» Answer: Is n÷5 an expression or an equation? If you missed this PROBLEM, review Example 2.1.4. Simplify 45 . If you missed this problem, review Example 2.1.6. Simplify 1+8∙9 . If you missed this problem, review Example 2.1.8 Step-by-step explanation: HOPE IT HELPS . GOOD MORNING

9.

Evaluate the following algebraic expression using suitable laws of exponents:-(9lm2/3l-3m7)-3I'll mark as brainliest if your answer is correct and reasonable

Answer»

Answer:

Is n÷5 an expression or an equation? If you missed this PROBLEM, review Example 2.1.4.

Simplify 45 . If you missed this problem, review Example 2.1.6.

Simplify 1+8∙9 . If you missed this problem, review Example 2.1.8

Step-by-step explanation:

HOPE IT HELPS .

GOOD MORNING

Discussion

10.	Bob want to cover the floor of a room 3 metre with and 4 metre long by square tiles of side 0.5 metre how many tiles required to cover?Don't Spam.. ❌❌Spam=reported
Answer» ANSWER: BOB wants to cover the FLOOR of a room 3 m wide and 4 m longby squared tiles. If each square tile is of side 0.5 m, then find the number of tiles required to cover the floor of the room. =12/0.25= 48 tiles.

10.

Bob want to cover the floor of a room 3 metre with and 4 metre long by square tiles of side 0.5 metre how many tiles required to cover?Don't Spam.. ❌❌Spam=reported

Answer»

ANSWER:

BOB wants to cover the FLOOR of a room 3 m wide and 4 m longby squared tiles. If each square tile is of side 0.5 m, then find the number of tiles required to cover the floor of the room. =12/0.25= 48 tiles.

Discussion

11.	In a triangle , the length of the first side is 5 cm less than the length of the second side . The length of the third side is 7 cm more than the length of the first side if the first side is of length is 18 cm , then what is the semiperimeter of the triangle₦Ø₸E:•Don't spam ❌• Quality answer needed✔
Answer» Given : The length of the first side is 5 cm less than the length of the SECOND side . The length of the third side is 7 cm more than the length of the first side . Length of first side is 18 cm . To Find : Semi Perimeter of Triangle . Solution : $\longmapsto\tt{Let\:second\:side\:be=x}$ Length of the first side is 5 cm less than the length of the second side . So , $\longmapsto\tt{First\:side=x-5}$ Also , The length of the third side is 7 cm more than the length of the first side . So , $\longmapsto\tt{Length\:of\:third\:side=x-5+7}$ Length of first side is 18 cm : $\longmapsto\tt{x-5=18}$ $\longmapsto\tt{x=18+5}$ $\longmapsto\tt\bf{x=23}$ Therefore : $\longmapsto\tt{Length\:of\:first\:side=18\:cm}$ $\longmapsto\tt{Length\:of\:second\:side=x}$ $\longmapsto\tt\bf{23\:cm}$ $\longmapsto\tt{Length\:of\:third\:side=23-5+7}$ $\longmapsto\tt\bf{25\:cm}$ For Semi Perimeter : a = 18 cm b = 23 cm c = 25 cm Using Formula : $\longmapsto\tt\boxed{Semi\:Perimeter=\dfrac{a+b+c}{2}}$ Putting Values : $\longmapsto\tt{\dfrac{18+23+25}{2}}$ $\longmapsto\tt{\cancel\dfrac{66}{2}}$ $\longmapsto\tt\bf{<klux>33</klux>\:cm}$ So , The Semi Perimeter of Triangle is 33 cm .

11.

In a triangle , the length of the first side is 5 cm less than the length of the second side . The length of the third side is 7 cm more than the length of the first side if the first side is of length is 18 cm , then what is the semiperimeter of the triangle₦Ø₸E:•Don't spam ❌• Quality answer needed✔

Answer»

Given :

The length of the first side is 5 cm less than the length of the SECOND side .
The length of the third side is 7 cm more than the length of the first side .
Length of first side is 18 cm .

To Find :

Semi Perimeter of Triangle .

Solution :

$\longmapsto\tt{Let\:second\:side\:be=x}$

Length of the first side is 5 cm less than the length of the second side . So ,

$\longmapsto\tt{First\:side=x-5}$

Also ,

The length of the third side is 7 cm more than the length of the first side . So ,

$\longmapsto\tt{Length\:of\:third\:side=x-5+7}$

Length of first side is 18 cm :

$\longmapsto\tt{x-5=18}$

$\longmapsto\tt{x=18+5}$

$\longmapsto\tt\bf{x=23}$

Therefore :

$\longmapsto\tt{Length\:of\:first\:side=18\:cm}$

$\longmapsto\tt{Length\:of\:second\:side=x}$

$\longmapsto\tt\bf{23\:cm}$

$\longmapsto\tt{Length\:of\:third\:side=23-5+7}$

$\longmapsto\tt\bf{25\:cm}$

For Semi Perimeter :

a = 18 cm
b = 23 cm
c = 25 cm

Using Formula :

$\longmapsto\tt\boxed{Semi\:Perimeter=\dfrac{a+b+c}{2}}$

Putting Values :

$\longmapsto\tt{\dfrac{18+23+25}{2}}$

$\longmapsto\tt{\cancel\dfrac{66}{2}}$

$\longmapsto\tt\bf{<klux>33</klux>\:cm}$

So , The Semi Perimeter of Triangle is 33 cm .

Discussion

12.	3. Find the measure of the angle ABC in each of the following using the property of thegiven figures.
Answer» ANSWER: it so answer Step-by-step EXPLANATION: because i had did this by PROPERTY of LINEAR PAIR

12.

3. Find the measure of the angle ABC in each of the following using the property of thegiven figures.

Answer»

ANSWER:

it so answer

Step-by-step EXPLANATION:

because i had did this by PROPERTY of LINEAR PAIR

Discussion

13.	Find the accumulated value of the deposit $2500 made in simple interest for 3.5 years at 5% rate of interest per year.!! NO SPAMMING !!
Answer» <P> ${\huge{\underline{\bf{Solution:}}}}$ $\begin{gathered} \\ \end{gathered}$ Given: Principal = $2500 Time in years = 3.5 RATE of interest = 5% $\begin{gathered} \\ \end{gathered}$ To find: $\begin{gathered} \\ \end{gathered}$ Accumulated Value $\begin{gathered} \\ \end{gathered}$ Solution: $\begin{gathered} \\ \end{gathered}$ To find the SIMPLE interest, we use the formula: $\multimap \: \boxed{ \sf Simple\:Interest = \dfrac{PRT}{100}}$ Where, P = Principle R = Rate of Interest T = Time (years) $\begin{gathered} \\ \end{gathered}$ $\begin{gathered} \colon \longrightarrow \sf \: Simple\:Interest = \dfrac{PRT}{100} \\ \\ \end{gathered}$ $\begin{gathered} \colon \longrightarrow \sf \: Simple\:Interest = \dfrac{2500 \times 5 \times 3.5}{100} \\ \\ \end{gathered}$ $\begin{gathered} \colon \longrightarrow \sf \: Simple\:Interest = \dfrac{25 \cancel{00} \times 5 \times 3.5}{1 \cancel{00}} \\ \\ \end{gathered}$ $\begin{gathered} \colon \longrightarrow \sf \: Simple\:Interest = 25 \times 5 \times 3.5 \\ \\ \end{gathered}$ $\colon \implies\underline{ \boxed{ \bf{ \red{Simple\:Interest = 437.50}}}} \: \bigstar$ $\begin{gathered} \\ \end{gathered}$ Accumulated value is nothing but Amount. Hence, to find Amount, we use the formula: $\begin{gathered} \\ \end{gathered}$ $\multimap \: \boxed{ \sf Amount = P+I}$ Where, P = Principal I = Simple Interest $\begin{gathered} \\ \end{gathered}$ $\begin{gathered} \colon \longrightarrow \sf \: Amount = P+I \\ \\ \end{gathered}$ $\begin{gathered} \colon \longrightarrow \sf \: Amount = 2500+437.50 \\ \\ \end{gathered}$ $\colon \implies\underline{ \boxed{ \bf{ \green{Amount= 2937.50}}}} \: \bigstar$ Hence, the accumulated value is 2937.50

13.

Find the accumulated value of the deposit $2500 made in simple interest for 3.5 years at 5% rate of interest per year.!! NO SPAMMING !!

Answer»

<P> ${\huge{\underline{\bf{Solution:}}}}$

$\begin{gathered} \\ \end{gathered}$

Given:

Principal = $2500
Time in years = 3.5
RATE of interest = 5%

$\begin{gathered} \\ \end{gathered}$

To find:

$\begin{gathered} \\ \end{gathered}$

Accumulated Value

$\begin{gathered} \\ \end{gathered}$

Solution:

$\begin{gathered} \\ \end{gathered}$

To find the SIMPLE interest, we use the formula:

$\multimap \: \boxed{ \sf Simple\:Interest = \dfrac{PRT}{100}}$

Where,

P = Principle
R = Rate of Interest
T = Time (years)

$\begin{gathered} \\ \end{gathered}$

$\begin{gathered} \colon \longrightarrow \sf \: Simple\:Interest = \dfrac{PRT}{100} \\ \\ \end{gathered}$

$\begin{gathered} \colon \longrightarrow \sf \: Simple\:Interest = \dfrac{2500 \times 5 \times 3.5}{100} \\ \\ \end{gathered}$

$\begin{gathered} \colon \longrightarrow \sf \: Simple\:Interest = \dfrac{25 \cancel{00} \times 5 \times 3.5}{1 \cancel{00}} \\ \\ \end{gathered}$

$\begin{gathered} \colon \longrightarrow \sf \: Simple\:Interest = 25 \times 5 \times 3.5 \\ \\ \end{gathered}$

$\colon \implies\underline{ \boxed{ \bf{ \red{Simple\:Interest = 437.50}}}} \: \bigstar$

$\begin{gathered} \\ \end{gathered}$

Accumulated value is nothing but Amount. Hence, to find Amount, we use the formula:

$\begin{gathered} \\ \end{gathered}$

$\multimap \: \boxed{ \sf Amount = P+I}$

Where,

P = Principal
I = Simple Interest

$\begin{gathered} \\ \end{gathered}$

$\begin{gathered} \colon \longrightarrow \sf \: Amount = P+I \\ \\ \end{gathered}$

$\begin{gathered} \colon \longrightarrow \sf \: Amount = 2500+437.50 \\ \\ \end{gathered}$

$\colon \implies\underline{ \boxed{ \bf{ \green{Amount= 2937.50}}}} \: \bigstar$

Hence, the accumulated value is 2937.50

Discussion

14.	II.Match the following:ItemsRiceSugarMustard SeedsWheatDalTeaPepperSaltCoriander seedGround nutsWeightKg/g52103500250251750200
Answer» not UNDERSTAND QUESTION

Discussion

15.	A fruit vendor packed 6 oranges, 5 apples,and 3 mangoes in each gift packet to be soldduring the festive season. If he managed to sell 300 oranges in these packets, how many apples andmangoes did he sell in these packets?
Answer» apples:250 and mangoes:150 hope it HELPS.

15.

A fruit vendor packed 6 oranges, 5 apples,and 3 mangoes in each gift packet to be soldduring the festive season. If he managed to sell 300 oranges in these packets, how many apples andmangoes did he sell in these packets?

Answer»

apples:250 and

mangoes:150

hope it HELPS.

Discussion

16.	1. Two buildings 13 and 15 metre high, stand upright on a ground. If they are 36 metre apart, find the distancebetween their top
Answer» ANSWER: √1300 Step-by-step EXPLANATION: So imagine that the BUILDING with 13 metre high on the left and 15 metre on the right and the distance between them is 36 metre. So now join all of them together and u will FOUND out this is a trapezium. Draw a straight horizontal line from the 13 metre high building to the other one and there will be 2 metre left. Use pythagorean triple, 2² + 36² = X², 4 + 1296 = √1300

16.

1. Two buildings 13 and 15 metre high, stand upright on a ground. If they are 36 metre apart, find the distancebetween their top

Answer»

ANSWER:

√1300

Step-by-step EXPLANATION:

So imagine that the BUILDING with 13 metre high on the left and 15 metre on the right and the distance between them is 36 metre. So now join all of them together and u will FOUND out this is a trapezium. Draw a straight horizontal line from the 13 metre high building to the other one and there will be 2 metre left. Use pythagorean triple, 2² + 36² = X², 4 + 1296 = √1300

Discussion

17.	A circular path of radius 7cm a rectangular sheet of dimension to centimetre into 1cm is removed find the area of the remaining cardpls answer the 32 second sum in the following pic
Answer» Answer: 152 cm² Step-by-step EXPLANATION: radius of circle is 7cm AREA of circular card = πr² = 22/7* (7)² = 22/7 * 77 = 227 = 154 cm² area of rectangular sheet is 2*1 = 2 cm² area of remaining part of circle = area of circular card - area of rectangular sheet 154 - 2 = 152 cm²

17.

A circular path of radius 7cm a rectangular sheet of dimension to centimetre into 1cm is removed find the area of the remaining cardpls answer the 32 second sum in the following pic

Answer»

Answer:

152 cm²

Step-by-step EXPLANATION:

radius of circle is 7cm

AREA of circular card = πr²

= 22/7* (7)²

= 22/7 * 7*7

= 22*7 = 154 cm²

area of rectangular sheet is 2*1 = 2 cm²

area of remaining part of circle = area of circular card - area of rectangular sheet

154 - 2 = 152 cm²

Discussion

18.	In a quiz, team A scored – 40, 10, 20 andteam B scored 10,0,–30 in three successiverounds. Which team scored more?
Answer» Step-by-step explanation: TEAM A score= – 40, 10, 20 -40+10+20=-40+30=-10 team B score= 10,0,–30 10+0+-30=10-30=20 Therefore-10is greater than-20 so team A SCORED more

18.

In a quiz, team A scored – 40, 10, 20 andteam B scored 10,0,–30 in three successiverounds. Which team scored more?

Answer»

Step-by-step explanation:

TEAM A score= – 40, 10, 20

-40+10+20=-40+30=-10

team B score= 10,0,–30

10+0+-30=10-30=20

Therefore-10is greater than-20 so team A SCORED more

Discussion

19.	A triangle has each of its base angles equal to 30° . What kind of triangle will it be , basedon angles ?
Answer» Answer: A isosceles triangle with each base ANGLE EQUAL to 30∘ is INSCRIBED in the ellipsex2a2+y2b2=1.

19.

A triangle has each of its base angles equal to 30° . What kind of triangle will it be , basedon angles ?

Answer»

Answer:

A isosceles triangle with each base ANGLE EQUAL to 30∘ is INSCRIBED in the ellipsex2a2+y2b2=1.

Discussion

20.	Long answer type question:raghav made a model using a square and a triangle as shown:- He want to decorate the model by putting decorative tape along the model. How much tape, in cm, is required to decorate the model.
Answer» ANSWER: GIVE the diagram Step-by-step EXPLANATION: PLEASE

20.

Long answer type question:raghav made a model using a square and a triangle as shown:- He want to decorate the model by putting decorative tape along the model. How much tape, in cm, is required to decorate the model.

Answer»

ANSWER:

GIVE the diagram

Step-by-step EXPLANATION:

PLEASE

Discussion

21.	Which is the smallest number by which 1400 should be divided to obtain a perfect cube? 17510014
Answer» ANSWER: 100 is UR answer KEEP SMILING

21.

Which is the smallest number by which 1400 should be divided to obtain a perfect cube? 17510014

Answer»

ANSWER:

100 is UR answer KEEP SMILING

Discussion

22.	A ____ have all the properties of a rectangle and a rhombusa) Parallelogram b) Rhombus c) Square d) Trapezium
Answer» Step-by-step EXPLANATION: a PARALLELOGRAM have all the PROPERTIES of a RECTANGLE and a RHOMBUS

22.

A ____ have all the properties of a rectangle and a rhombusa) Parallelogram b) Rhombus c) Square d) Trapezium

Answer»

Step-by-step EXPLANATION:

a PARALLELOGRAM have all the PROPERTIES of a RECTANGLE and a RHOMBUS

Discussion

23.	There are 3 students in the class and 27 apples. If the apples are divided equally among the students, howdoes each student get?many
Answer» 27/3=9 Each STUDENT GET 9 APPLES

23.

There are 3 students in the class and 27 apples. If the apples are divided equally among the students, howdoes each student get?many

Answer»

27/3=9

Each STUDENT GET 9 APPLES

Discussion

24.	Area of square is equal to perimeter of a rectangle if the side of a square is 20 cm and breadth of rectangle is 40 cm find the length and area of the rectangleplease ans fast the ans will be marked as brainliest
Answer» ANSWER: LENGTH = 160 Area = 6400 Step-by-step EXPLANATION: I THINK this is the answer

24.

Area of square is equal to perimeter of a rectangle if the side of a square is 20 cm and breadth of rectangle is 40 cm find the length and area of the rectangleplease ans fast the ans will be marked as brainliest

Answer»

ANSWER:

LENGTH = 160

Area = 6400

Step-by-step EXPLANATION:

I THINK this is the answer

Discussion

25.	Covert the following1)2.45km into m2)4.63m into cm3)97cm into m4)12.5cm into mm5)234.5g into kg6)5.6kg into g7)6250ml to l8)0.5l into ml
Answer» 1)2450M 2)463Cm 3)0.97 4) 5)0.2345G 6)5600G 7)6.250 L 8)510 ml Hope its help You 4 ka nhi pta

25.

Covert the following1)2.45km into m2)4.63m into cm3)97cm into m4)12.5cm into mm5)234.5g into kg6)5.6kg into g7)6250ml to l8)0.5l into ml

Answer»

1)2450M

2)463Cm

3)0.97

4)

5)0.2345G

6)5600G

7)6.250 L

8)510 ml

Hope its help You 4 ka nhi pta

Discussion

26.	(a) यदि A(0, 9) र B(a, 0) बीचको दुरी 15 एकाइ भए a कोमान पत्ता लगाऊ।If the distance between A(0, 9) and B(a, 9) is 15units then find the value of a.Answer is 12.how to find out plz help me tomorrow is my maths exam
Answer» ANSWER: sq.root(a-0)2+(9-9)2 = 15 sq.root(a)2 = 15 a = 15

26.

(a) यदि A(0, 9) र B(a, 0) बीचको दुरी 15 एकाइ भए a कोमान पत्ता लगाऊ।If the distance between A(0, 9) and B(a, 9) is 15units then find the value of a.Answer is 12.how to find out plz help me tomorrow is my maths exam

Answer»

ANSWER:

sq.root(a-0)2+(9-9)2 = 15

sq.root(a)2 = 15

a = 15

Discussion

27.	A blind beggar had a brother who died. Whatrelation was the blind beggar to the brother whodied? "Brother" is not the answer. What is theanswer?
Answer» ANSWER: BEGGAR can be the CORRECT it is very TRICKY...!!

27.

A blind beggar had a brother who died. Whatrelation was the blind beggar to the brother whodied? "Brother" is not the answer. What is theanswer?

Answer»

ANSWER:

BEGGAR can be the CORRECT it is very TRICKY...!!

Discussion

28.	Septagoncirclesquaretriangle
Answer» ANSWER: jjsjsjsjsjkwwlkwkwowppwiaaoaoisjsisis

28.

Septagoncirclesquaretriangle

Answer»

ANSWER:

jjsjsjsjsjkwwlkwkwowppwiaaoaoisjsisis

Discussion

29.	In each figure below , tell what point of concurrency is shown and whatconstructions form that point:
Answer» $\huge{\underline{\underline{\underline{\sf{\pink{ﾑɳรᏇɛƦ࿐}}}}}}$ An ATMOSPHERE is a layer or a set of layers of gases surrounding a planet or other material BODY, that is held in place by the GRAVITY of that body. An atmosphere is more LIKELY to be retained if the gravity it is subject to is high and the temperature of the atmosphere is low.

29.

In each figure below , tell what point of concurrency is shown and whatconstructions form that point:

Answer»

$\huge{\underline{\underline{\underline{\sf{\pink{ﾑɳรᏇɛƦ࿐}}}}}}$

An ATMOSPHERE is a layer or a set of layers of gases surrounding a planet or other material BODY, that is held in place by the GRAVITY of that body. An atmosphere is more LIKELY to be retained if the gravity it is subject to is high and the temperature of the atmosphere is low.

Discussion

30.	14. A newspaper reports the given changes (in) inthe price of a stock over five days-2-3, 6, 8, 2Find the mean daily change.
Answer» ANSWER: SORRY but I don't KNOW your answer

30.

14. A newspaper reports the given changes (in) inthe price of a stock over five days-2-3, 6, 8, 2Find the mean daily change.

Answer»

ANSWER:

SORRY but I don't KNOW your answer

Discussion

31.	A doctor in Paris has a brother in Toronto who is alawyer. The lawyer does not have a brother who isa doctor in Paris. How is this possible?
Answer» Answer: The DOCTOR in PARIS is a girl his sister Step-by-step EXPLANATION: Please mark as the BRAINLIEST

31.

A doctor in Paris has a brother in Toronto who is alawyer. The lawyer does not have a brother who isa doctor in Paris. How is this possible?

Answer»

Answer:

The DOCTOR in PARIS is a girl

his sister

Step-by-step EXPLANATION:

Please mark as the BRAINLIEST

Discussion

32.	When 4(0.5x + 2.5y - 0.7x - 1.3y + 4) is simplified, what is the resulting expression?-0.8+4.8y+160.8x-4.8y+16-0.8x-4.8y +40.8x+4.8y+4
Answer» Answer: - 0.8x + 4.8y + 16 Step-by-step EXPLANATION: Let us SIMPLIFY the expression. 4 ( 0.5x + 2.5y - 0.7x - 1.3y + 4 ) = 4(0.5x - 0.7x + 2.5y - 1.3y + 4) = 4(- 0.2x + 1.2y + 4) = 4(- 0.2x) + 4(1.2y) + 4(4) = {4×(- 0.2x)} + (4×1.2y) + (4×4) = - 0.8x + 4.8y + 16 Hence the resulting expression will be -0.8x + 4.8y + 16 hope it helps.

32.

When 4(0.5x + 2.5y - 0.7x - 1.3y + 4) is simplified, what is the resulting expression?-0.8+4.8y+160.8x-4.8y+16-0.8x-4.8y +40.8x+4.8y+4

Answer»

Answer:

- 0.8x + 4.8y + 16

Step-by-step EXPLANATION:

Let us SIMPLIFY the expression.

4 ( 0.5x + 2.5y - 0.7x - 1.3y + 4 )

= 4(0.5x - 0.7x + 2.5y - 1.3y + 4)

= 4(- 0.2x + 1.2y + 4)

= 4(- 0.2x) + 4(1.2y) + 4(4)

= {4×(- 0.2x)} + (4×1.2y) + (4×4)

= - 0.8x + 4.8y + 16

Hence the resulting expression will be -0.8x + 4.8y + 16

hope it helps.

Discussion

33.	The diagonal of a quadrilateral is 16cm.The perpendiculars from thevertices to the diagonal measure 12cm and 15cm. Find the area of the quadrilateral.
Answer» Answer: 15 Step-by-step EXPLANATION:

33.

The diagonal of a quadrilateral is 16cm.The perpendiculars from thevertices to the diagonal measure 12cm and 15cm. Find the area of the quadrilateral.

Answer»

Answer:

15

Step-by-step EXPLANATION:

Discussion

34.	69. 56 तथा 84 दोनों के लिए निम्न में से कौन-सा सत्य है?(1) दोनों अभाज्य संख्याएँ हैं(2) दोनों सहअभाज्य संख्याएँ हैं(3) दोनों 14 के गुणज हैं(4) दोनों विषम संख्याएँ हैं.
Answer» ANSWER: c Step-by-step EXPLANATION: as 144=56 and 146=84

34.

69. 56 तथा 84 दोनों के लिए निम्न में से कौन-सा सत्य है?(1) दोनों अभाज्य संख्याएँ हैं(2) दोनों सहअभाज्य संख्याएँ हैं(3) दोनों 14 के गुणज हैं(4) दोनों विषम संख्याएँ हैं.

Answer»

ANSWER:

c

Step-by-step EXPLANATION:

as 14*4=56

and 14*6=84

Discussion

35.	Simplify the following expressions 3 upon 2 x 7 upon 9 minus 2 upon 3 + 1 upon 3 plus 2 upon 3 minus 4 upon 9A) 1 upon 3B) 2 upon 3C) 1D) 1 1 upon 3
Answer» Step-by-step EXPLANATION: C:- 2574030731 p:- HELLO Z●●M COME gir_ls

35.

Simplify the following expressions 3 upon 2 x 7 upon 9 minus 2 upon 3 + 1 upon 3 plus 2 upon 3 minus 4 upon 9A) 1 upon 3B) 2 upon 3C) 1D) 1 1 upon 3

Answer»

Step-by-step EXPLANATION:

C:- 2574030731

p:- HELLO

Z●●M

COME gir_ls

Discussion

36.	Form a 7-digit number using the following clues.a) Digit 4 is in the ten lakhs place.b) Digit 1 is in the ten thousands place.c) Digit 2 is in the tens place.d). Digit 6 is in ones place.e) The digits in the remaining place values are zero.
Answer» Answer: 4010026 Step-by-step EXPLANATION:

36.

Form a 7-digit number using the following clues.a) Digit 4 is in the ten lakhs place.b) Digit 1 is in the ten thousands place.c) Digit 2 is in the tens place.d). Digit 6 is in ones place.e) The digits in the remaining place values are zero.

Answer»

Answer:

4010026

Step-by-step EXPLANATION:

Discussion

37.	The postulate "the sum of angles of any triangles equal to two right angles" given bya) Play Fairb) Legendrec) Proclusd) Posido minus
Answer» ANSWER: C)Proclus i THINK it is WRITE but I am not SURE

37.

The postulate "the sum of angles of any triangles equal to two right angles" given bya) Play Fairb) Legendrec) Proclusd) Posido minus

Answer»

ANSWER:

C)Proclus

i THINK it is WRITE but I am not SURE

Discussion

38.	Ineachfigurebelow,tellwhatpointofconcurrencyisshownandwhatconstructionsformthatpoint:
Answer» ANSWER: brkodksnqnskaknq sjxjsvwvvwhqjwjannaja

38.

Ineachfigurebelow,tellwhatpointofconcurrencyisshownandwhatconstructionsformthatpoint:

Answer»

ANSWER:

brkodksnqnskaknq sjxjsvwvvwhqjwjannaja

Discussion

39.	Covert the following1)2.45km into m2)4.63m into cm3)97cm into m4)12.5cm into mm5)234.5g into kg6)5.6kg into g7)6250ml to l8)0.5l into ml{With Explanation}
Answer» Step-by-step explanation: तुमचा शोध - Covert the FOLLOWING 1)2.45km into m 2)4.63m into cm 3)97cm into m 4)12.5cm into mm 5 ... – कोणत्याही दस्तऐवजांशी जुळला नाही. सूचना: सर्व शब्दांचे शब्दलेखन योग्य असल्याची खात्री करा. भिन्न कीवर्ड्‍सचा प्रयत्न करा. अधिक सामान्य कीवर्ड्‍सचा प्रयत्न करा. कमी कीवर्ड्‍सचा प्रयत्न करा.

39.

Covert the following1)2.45km into m2)4.63m into cm3)97cm into m4)12.5cm into mm5)234.5g into kg6)5.6kg into g7)6250ml to l8)0.5l into ml{With Explanation}

Answer»

Step-by-step explanation:

तुमचा शोध - Covert the FOLLOWING 1)2.45km into m 2)4.63m into cm 3)97cm into m 4)12.5cm into mm 5 ... – कोणत्याही दस्तऐवजांशी जुळला नाही.

सूचना:

सर्व शब्दांचे शब्दलेखन योग्य असल्याची खात्री करा.

भिन्न कीवर्ड्‍सचा प्रयत्न करा.

अधिक सामान्य कीवर्ड्‍सचा प्रयत्न करा.

कमी कीवर्ड्‍सचा प्रयत्न करा.

Discussion

40.	If 39 = 3 X + 3 Y + 3 Z therefore X + Y + Z =?Options1. 52. 73. 44. 6PLZ ANSWER FAST... ITS URGENT
Answer» Answer: 13 OPTIONS may be WRONG 3 comes common so x PLUS y plus z is 13 . 39 divided by 3

40.

If 39 = 3 X + 3 Y + 3 Z therefore X + Y + Z =?Options1. 52. 73. 44. 6PLZ ANSWER FAST... ITS URGENT

Answer»

Answer:

13 OPTIONS may be WRONG 3 comes common so x PLUS y plus z is 13 . 39 divided by 3

Discussion

41.	Find the sum of three angles, in an inscribed hexagon .See the attachment for more details !
Answer» If you do this for a hexagon, you will FIND that you can create 4 triangles. You should know that the SUM of the INTERIOR angles in a triangle is 180 DEGREES. So 4 x 180 = 720 degree. Now divide this by the number of sides in a hexagon: 720/6 = 120 degrees (the interior ANGLE). This works for all regular polygons with 4 sides or more.

41.

Find the sum of three angles, in an inscribed hexagon .See the attachment for more details !

Answer»

If you do this for a hexagon, you will FIND that you can create 4 triangles. You should know that the SUM of the INTERIOR angles in a triangle is 180 DEGREES.

So 4 x 180 = 720 degree.

Now divide this by the number of sides in a hexagon:

720/6 = 120 degrees (the interior ANGLE).

This works for all regular polygons with 4 sides or more.

Discussion

42.	For which group of data does the mean equal the mode?a4, 4, 6, 6b4, 5, 6, 6c4, 5, 5, 6d4, 5, 5, 8
Answer» 4,5,5,5,6 When you add 4+5+5+5+6 is =25. You then DIVIDE it by the amount of NUMBERS which is 5. which=5. And 5 is the number you SEE the most. So that is your answer. *Thanks. Please* *mark* me as brain lest answer.

Discussion

43.	A cuboidal container of dimension 10 cm by 8cm and by 6cm filled with water and this water is poured into a cylindrical container of radius 7 cm . find the height of water in cylinder.Don't Answer if uh don't know :)
Answer» ★ Concept :- Here the concept of Volume of Cylinder and Volume of Cuboid has been used. We are given that the cuboidal container contains water. Since we are give it's full dimensions, then easily we can find the volume of container. Since water occupies the space of container in which it is kept, then the volume of water will be same as that of container. Now this same water is TRANSFERRED into a cylindrical container. So the volume of water will remain equal in that too. Then we will have an equation where we need to find the height of water in cylindrical container and from which we can find the values. Let's do it !! ______________________________________ ★ Formulas Used :- $\;\;\boxed{\sf{\pink{Volume\;of\;Cuboid\;=\;Length\:\times\:Breadth\:\times\:Height}}}$ $\;\;\boxed{\sf{\pink{Volume\;of\;Cylinder\;=\;\pi\:\times\:r^{2}\:\times\:h}}}$ ______________________________________ ★ Solution :- Given, » Length of Cuboidal container = L = 10 cm » Breadth of Cuboidal container = B = 8 cm » Height of Cuboidal container = H = 6 cm » Radius of the Cylindrical container = r = 7 cm Let the height of the Cylindrical Container be h cm . • For the volume of water :: We know that, >> Volume of Cuboidal container = Volume of water in Cuboidal container (Since container is filled) Let's now find the Volume of Container. This is given as, $\;\;\tt{\rightarrow\;\;Volume\;of\;Cuboid\;=\;Length\:\times\:Breadth\:\times\:Height}$ By applying values, we get $\;\;\tt{\rightarrow\;\;Volume\;of\;Cuboid\;=\;L\:\times\:B\:\times\:H}$ $\;\;\tt{\rightarrow\;\;Volume\;of\;Cuboid\;=\;<klux>10</klux>\:\times\:8\:\times\:6}$ $\;\;\tt{\rightarrow\;\;Volume\;of\;Cuboidal\;=\;10\:\times\:48}$ $\;\;\bf{\rightarrow\;\;Volume\;of\;Cuboidal\:Container\;=\;480\;\:cm^{3}}$ This GIVES us the volume of water in Cuboidal container as 480 cm³. • For the Height of water in Cylindrical container :: Since the volume of water will remain same. So, we can equate it easily in the formula . $\;\;\tt{\Longrightarrow\;\;Volume\;of\;Cylinder\;=\;\pi\:\times\:r^{2}\:\times\:h}$ Since water takes the shape of cylinder. This means that we can apply values in this formula. $\;\;\tt{\Longrightarrow\;\;\pi\:\times\:r^{2}\:\times\:h\;=\;Volume\;of\;Water}$ By applying values, we get $\;\;\tt{\Longrightarrow\;\;\dfrac{22}{7}\:\times\:(7)^{2}\:\times\:h\;=\;480}$ $\;\;\tt{\Longrightarrow\;\;\dfrac{22}{7}\:\times\:49\:\times\:h\;=\;480}$ By cancelling 49 with 7, we get $\;\;\tt{\Longrightarrow\;\;22\:\times\:7\:\times\:h\;=\;480}$ $\;\;\tt{\Longrightarrow\;\;154\:\times\:h\;=\;480}$ $\;\;\tt{\Longrightarrow\;\;h\;=\;\dfrac{480}{154}}$ $\;\;\tt{\Longrightarrow\;\;h\;=\;3.12\;\:cm}$ Here we have rounded off the ANSWER to two decimal points. This is the required answer. $\;\underline{\boxed{\tt{Height\;of\;water\;in\;Cylinder\;=\;\bf{\purple{3.12\;\:cm^{2}}}}}}$ ________________________________ ★ More to know :- $\;\sf{\leadsto\;\:L.S.A.\;of\;Cuboid\;=\;2(L\:+\:B)\:times\:H}$ $\;\sf{\leadsto\;\:T.S.A.\;of\;Cuboid\;=\;2(LB\:+\:BH\:+\:LH)}$ $\;\sf{\leadsto\;\:Diagonal\;of\;Cuboid\;=\;\sqrt{(L^{2}\:+\:B^{2}\:+\:H^{2})}}$ $\;\sf{\leadsto\;\;C.S.A.\;of\;Cylinder\;=\;2\pi rh}$ $\;\sf{\leadsto\;\;T.S.A.\;of\;Cylinder\;=\;2\pi rh\:+\;2\pi r^{2}}$ L = Length of Cuboid B = Breadth of Cuboid H = Height of Cuboid r = Radius of Cylinder h = Height of Cylinder

43.

A cuboidal container of dimension 10 cm by 8cm and by 6cm filled with water and this water is poured into a cylindrical container of radius 7 cm . find the height of water in cylinder.Don't Answer if uh don't know :)

Answer»

★ Concept :-

Here the concept of Volume of Cylinder and Volume of Cuboid has been used. We are given that the cuboidal container contains water. Since we are give it's full dimensions, then easily we can find the volume of container. Since water occupies the space of container in which it is kept, then the volume of water will be same as that of container. Now this same water is TRANSFERRED into a cylindrical container. So the volume of water will remain equal in that too. Then we will have an equation where we need to find the height of water in cylindrical container and from which we can find the values.

Let's do it !!

______________________________________

★ Formulas Used :-

$\;\;\boxed{\sf{\pink{Volume\;of\;Cuboid\;=\;Length\:\times\:Breadth\:\times\:Height}}}$

$\;\;\boxed{\sf{\pink{Volume\;of\;Cylinder\;=\;\pi\:\times\:r^{2}\:\times\:h}}}$

______________________________________

★ Solution :-

Given,

» Length of Cuboidal container = L = 10 cm

» Breadth of Cuboidal container = B = 8 cm

» Height of Cuboidal container = H = 6 cm

» Radius of the Cylindrical container = r = 7 cm

Let the height of the Cylindrical Container be h cm .

• For the volume of water ::

We know that,

>> Volume of Cuboidal container = Volume of water in Cuboidal container

(Since container is filled)

Let's now find the Volume of Container.

This is given as,

$\;\;\tt{\rightarrow\;\;Volume\;of\;Cuboid\;=\;Length\:\times\:Breadth\:\times\:Height}$

By applying values, we get

$\;\;\tt{\rightarrow\;\;Volume\;of\;Cuboid\;=\;L\:\times\:B\:\times\:H}$

$\;\;\tt{\rightarrow\;\;Volume\;of\;Cuboid\;=\;<klux>10</klux>\:\times\:8\:\times\:6}$

$\;\;\tt{\rightarrow\;\;Volume\;of\;Cuboidal\;=\;10\:\times\:48}$

$\;\;\bf{\rightarrow\;\;Volume\;of\;Cuboidal\:Container\;=\;480\;\:cm^{3}}$

This GIVES us the volume of water in Cuboidal container as 480 cm³.

• For the Height of water in Cylindrical container ::

Since the volume of water will remain same.

So, we can equate it easily in the formula .

$\;\;\tt{\Longrightarrow\;\;Volume\;of\;Cylinder\;=\;\pi\:\times\:r^{2}\:\times\:h}$

Since water takes the shape of cylinder. This means that we can apply values in this formula.

$\;\;\tt{\Longrightarrow\;\;\pi\:\times\:r^{2}\:\times\:h\;=\;Volume\;of\;Water}$

By applying values, we get

$\;\;\tt{\Longrightarrow\;\;\dfrac{22}{7}\:\times\:(7)^{2}\:\times\:h\;=\;480}$

$\;\;\tt{\Longrightarrow\;\;\dfrac{22}{7}\:\times\:49\:\times\:h\;=\;480}$

By cancelling 49 with 7, we get

$\;\;\tt{\Longrightarrow\;\;22\:\times\:7\:\times\:h\;=\;480}$

$\;\;\tt{\Longrightarrow\;\;154\:\times\:h\;=\;480}$

$\;\;\tt{\Longrightarrow\;\;h\;=\;\dfrac{480}{154}}$

$\;\;\tt{\Longrightarrow\;\;h\;=\;3.12\;\:cm}$

Here we have rounded off the ANSWER to two decimal points.

This is the required answer.

$\;\underline{\boxed{\tt{Height\;of\;water\;in\;Cylinder\;=\;\bf{\purple{3.12\;\:cm^{2}}}}}}$

________________________________

★ More to know :-

$\;\sf{\leadsto\;\:L.S.A.\;of\;Cuboid\;=\;2(L\:+\:B)\:times\:H}$

$\;\sf{\leadsto\;\:T.S.A.\;of\;Cuboid\;=\;2(LB\:+\:BH\:+\:LH)}$

$\;\sf{\leadsto\;\:Diagonal\;of\;Cuboid\;=\;\sqrt{(L^{2}\:+\:B^{2}\:+\:H^{2})}}$

$\;\sf{\leadsto\;\;C.S.A.\;of\;Cylinder\;=\;2\pi rh}$

$\;\sf{\leadsto\;\;T.S.A.\;of\;Cylinder\;=\;2\pi rh\:+\;2\pi r^{2}}$

L = Length of Cuboid

B = Breadth of Cuboid

H = Height of Cuboid

r = Radius of Cylinder

h = Height of Cylinder

Discussion

44.	The ratio of ₹20 and ₹25 is(a) 4:5(b) 5:4(e) 5:6(d) 6:5answer me with method please
Answer» ANSWER: 4:5 20 : 25 will be the answer so we NEED to simplify. simplification is is attached so these are the STEPS

44.

The ratio of ₹20 and ₹25 is(a) 4:5(b) 5:4(e) 5:6(d) 6:5answer me with method please

Answer»

ANSWER:

4:5

20 : 25 will be the answer

so we NEED to simplify.

simplification is is attached

so these are the STEPS

Discussion

45.	The ratio of 20 and 7 25 is(a) 4:5(b) 5:4(e) 5:6(d) 6:5answer me with method please
Answer» 4:5 is ANSWER ___________________

45.

The ratio of 20 and 7 25 is(a) 4:5(b) 5:4(e) 5:6(d) 6:5answer me with method please

Answer»

4:5 is ANSWER

___________________

Discussion

46.	(2) For the point (3.4), the distance from the X axis is(a) 10(b) 3(c) 13units(d) 7Method please
Answer» Answer: 3 as the POINT (3,4) is 3 UNITS AWAY from the origin hope it HELPS :)

46.

(2) For the point (3.4), the distance from the X axis is(a) 10(b) 3(c) 13units(d) 7Method please

Answer»

Answer:

3

as the POINT (3,4) is 3 UNITS AWAY from the origin

hope it HELPS :)

Discussion

47.	ClassmateDatePageB What is the difference betwerph the smallenumber of five digit and the largestnumber of four digit
Answer» ANSWER: i didn't GET the QUESTION MEANS not understood••••♡♡♡

47.

ClassmateDatePageB What is the difference betwerph the smallenumber of five digit and the largestnumber of four digit

Answer»

ANSWER:

i didn't GET the QUESTION MEANS not understood••••♡♡♡

Discussion

48.	300 m long train crosses a pole in 24 sec. What is the speed of the train in km/hr ?1) 45 km/hr2) 60 km/hr 3) 36 km/hr 4) 42 km/hr.
Answer» The train covers 300M in 24 seconds. If we divide 300 by 24 300/24 = 12.5m/sec We have to CONVERT this to PER hour, We can do that by MULTIPLYING 12.5 by 18/5 12.5 x 18/5 12.5 x 3.6 45 km/hr The answer is (1) 45 km/hr

48.

300 m long train crosses a pole in 24 sec. What is the speed of the train in km/hr ?1) 45 km/hr2) 60 km/hr 3) 36 km/hr 4) 42 km/hr.

Answer»

The train covers 300M in 24 seconds.

If we divide 300 by 24

300/24 = 12.5m/sec

We have to CONVERT this to PER hour,

We can do that by MULTIPLYING 12.5 by 18/5

12.5 x 18/5

12.5 x 3.6

45 km/hr

The answer is (1) 45 km/hr

Discussion

49.	Simplify?options
Answer» $\large\textsf{ }$ $\LARGE\textsf{\underline\textcolor{aqua}{↭ SoLuTioN :-}}$ $\large\textsf{ }$ $\qquad\tt{:}\longrightarrow\large\textsf{$2\cfrac{\large\textsf{1}}{\large\textsf{4}} - \left(\cfrac{\large\textsf{1}}{\large\textsf{2}} - 3\cfrac{\large\textsf{1}}{\large\textsf{4}}\right)$}$ $\large\textsf{ }$ $\qquad\tt{:}\longrightarrow\large\textsf{$\cfrac{\large\textsf{2 × 4 + 1}}{\large\textsf{4}} - \left(\cfrac{\large\textsf{1}}{\large\textsf{2}} - \cfrac{\large\textsf{4 × 3 + 1}}{\large\textsf{4}}\right)$}$ $\large\textsf{ }$ $\qquad\tt{:}\longrightarrow\large\textsf{$\cfrac{\large\textsf{9}}{\large\textsf{4}} - \left(\cfrac{\large\textsf{1}}{\large\textsf{2}} - \cfrac{\large\textsf{13}}{\large\textsf{4}}\right)$}$ $\large\textsf{ }$ $\qquad\tt{:}\longrightarrow\large\textsf{$\cfrac{\large\textsf{9}}{\large\textsf{4}} - \left(\cfrac{\large\textsf{1 × 4}}{\large\textsf{2 × 4}} - \cfrac{\large\textsf{13 × 2}}{\large\textsf{4 × 2}}\right)$}$ $\large\textsf{ }$ $\qquad\tt{:}\longrightarrow\large\textsf{$\cfrac{\large\textsf{9}}{\large\textsf{4}} - \left(\cfrac{\large\textsf{4}}{\large\textsf{8}} - \cfrac{\large\textsf{26}}{\large\textsf{8}}\right)$}$ $\large\textsf{ }$ $\qquad\tt{:}\longrightarrow\large\textsf{$\cfrac{\large\textsf{9}}{\large\textsf{4}} - \left(\cfrac{\large\textsf{4 - 26}}{\large\textsf{8}}\right)$}$ $\large\textsf{ }$ $\qquad\tt{:}\longrightarrow\large\textsf{$\cfrac{\large\textsf{9}}{\large\textsf{4}} - \left(\cfrac{\large\textsf{- 22}}{\large\textsf{8}}\right)$}$ $\large\textsf{ }$ $\qquad\tt{:}\longrightarrow\large\textsf{$\cfrac{\large\textsf{9}}{\large\textsf{4}} - \left(\cfrac{\large\textsf{- 11}}{\large\textsf{4}}\right)$}$ $\large\textsf{ }$ $\qquad\tt{:}\longrightarrow\large\textsf{$\cfrac{\large\textsf{9}}{\large\textsf{4}} + \cfrac{\large\textsf{11}}{\large\textsf{4}}$}$ $\large\textsf{ }$ $\qquad\tt{:}\longrightarrow\large\textsf{$\cfrac{\large\textsf{9 + 11}}{\large\textsf{4}}$}$ $\large\textsf{ }$ $\qquad\tt{:}\longrightarrow\large\textsf{$\cfrac{\large\textsf{20}}{\large\textsf{4}}$}$ $\large\textsf{ }$ $\qquad\tt{:}\longrightarrow\boxed{\large\textsf\textcolor{red}{5}}$ $\large\textsf{ }$

49.

Simplify?options

Answer»

$\large\textsf{ }$

$\LARGE\textsf{\underline\textcolor{aqua}{↭ SoLuTioN :-}}$

$\large\textsf{ }$

$\qquad\tt{:}\longrightarrow\large\textsf{$2\cfrac{\large\textsf{1}}{\large\textsf{4}} - \left(\cfrac{\large\textsf{1}}{\large\textsf{2}} - 3\cfrac{\large\textsf{1}}{\large\textsf{4}}\right)$}$

$\large\textsf{ }$

$\qquad\tt{:}\longrightarrow\large\textsf{$\cfrac{\large\textsf{2 × 4 + 1}}{\large\textsf{4}} - \left(\cfrac{\large\textsf{1}}{\large\textsf{2}} - \cfrac{\large\textsf{4 × 3 + 1}}{\large\textsf{4}}\right)$}$

$\large\textsf{ }$

$\qquad\tt{:}\longrightarrow\large\textsf{$\cfrac{\large\textsf{9}}{\large\textsf{4}} - \left(\cfrac{\large\textsf{1}}{\large\textsf{2}} - \cfrac{\large\textsf{13}}{\large\textsf{4}}\right)$}$

$\large\textsf{ }$

$\qquad\tt{:}\longrightarrow\large\textsf{$\cfrac{\large\textsf{9}}{\large\textsf{4}} - \left(\cfrac{\large\textsf{1 × 4}}{\large\textsf{2 × 4}} - \cfrac{\large\textsf{13 × 2}}{\large\textsf{4 × 2}}\right)$}$

$\large\textsf{ }$

$\qquad\tt{:}\longrightarrow\large\textsf{$\cfrac{\large\textsf{9}}{\large\textsf{4}} - \left(\cfrac{\large\textsf{4}}{\large\textsf{8}} - \cfrac{\large\textsf{26}}{\large\textsf{8}}\right)$}$

$\large\textsf{ }$

$\qquad\tt{:}\longrightarrow\large\textsf{$\cfrac{\large\textsf{9}}{\large\textsf{4}} - \left(\cfrac{\large\textsf{4 - 26}}{\large\textsf{8}}\right)$}$

$\large\textsf{ }$

$\qquad\tt{:}\longrightarrow\large\textsf{$\cfrac{\large\textsf{9}}{\large\textsf{4}} - \left(\cfrac{\large\textsf{- 22}}{\large\textsf{8}}\right)$}$

$\large\textsf{ }$

$\qquad\tt{:}\longrightarrow\large\textsf{$\cfrac{\large\textsf{9}}{\large\textsf{4}} - \left(\cfrac{\large\textsf{- 11}}{\large\textsf{4}}\right)$}$

$\large\textsf{ }$

$\qquad\tt{:}\longrightarrow\large\textsf{$\cfrac{\large\textsf{9}}{\large\textsf{4}} + \cfrac{\large\textsf{11}}{\large\textsf{4}}$}$

$\large\textsf{ }$

$\qquad\tt{:}\longrightarrow\large\textsf{$\cfrac{\large\textsf{9 + 11}}{\large\textsf{4}}$}$

$\large\textsf{ }$

$\qquad\tt{:}\longrightarrow\large\textsf{$\cfrac{\large\textsf{20}}{\large\textsf{4}}$}$

$\large\textsf{ }$

$\qquad\tt{:}\longrightarrow\boxed{\large\textsf\textcolor{red}{5}}$

$\large\textsf{ }$

Discussion

50.	Which of the following cannot be written as (-20) + 5 ?(a) (-5) + 20(b) - [20 + 5] (c) 20 - (-5)(d) - 4
Answer» Answer: Answer is (-5) +20 Step-by-step EXPLANATION: U HOPE this answer is you USEFUL.

50.

Which of the following cannot be written as (-20) + 5 ?(a) (-5) + 20(b) - [20 + 5] (c) 20 - (-5)(d) - 4

Answer»

Answer:

Answer is (-5) +20

Step-by-step EXPLANATION:

U HOPE this answer is you USEFUL.

Discussion

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5^6 × 11^3----------------------121 × 11^4 × 625please show the working as well thank you

30. The length and breadth of an auditorium are 30 m and 24 mmrespectively. The rate of ulingis? 75 per sq metre and the Labourcharges are 25 per sq metre. Find the total expense of thing theauditorium(1) 33600012) 772000(3) 35400014) 7 96000

The lower limit and the upper limit of the first class of the given classinterval 0-50 50-100

What least number should be subtracted from 1365 to get a number exactly divisible by 25?Guys please answer with step by step explanation.

Evaluate the following algebraic expression using suitable laws of exponents:-(9lm2/3l-3m7)-3I'll mark as brainliest if your answer is correct and reasonable

Bob want to cover the floor of a room 3 metre with and 4 metre long by square tiles of side 0.5 metre how many tiles required to cover?Don't Spam.. ❌❌Spam=reported

3. Find the measure of the angle ABC in each of the following using the property of thegiven figures.

II.Match the following:ItemsRiceSugarMustard SeedsWheatDalTeaPepperSaltCoriander seedGround nutsWeightKg/g52103500250251750200

1. Two buildings 13 and 15 metre high, stand upright on a ground. If they are 36 metre apart, find the distancebetween their top

In a quiz, team A scored – 40, 10, 20 andteam B scored 10,0,–30 in three successiverounds. Which team scored more?

Which is the smallest number by which 1400 should be divided to obtain a perfect cube? 17510014

A ____ have all the properties of a rectangle and a rhombusa) Parallelogram b) Rhombus c) Square d) Trapezium

There are 3 students in the class and 27 apples. If the apples are divided equally among the students, howdoes each student get?many

Area of square is equal to perimeter of a rectangle if the side of a square is 20 cm and breadth of rectangle is 40 cm find the length and area of the rectangleplease ans fast the ans will be marked as brainliest

Covert the following1)2.45km into m2)4.63m into cm3)97cm into m4)12.5cm into mm5)234.5g into kg6)5.6kg into g7)6250ml to l8)0.5l into ml

(a) यदि A(0, 9) र B(a, 0) बीचको दुरी 15 एकाइ भए a कोमान पत्ता लगाऊ।If the distance between A(0, 9) and B(a, 9) is 15units then find the value of a.Answer is 12.how to find out plz help me tomorrow is my maths exam

A blind beggar had a brother who died. Whatrelation was the blind beggar to the brother whodied? "Brother" is not the answer. What is theanswer?

14. A newspaper reports the given changes (in) inthe price of a stock over five days-2-3, 6, 8, 2Find the mean daily change.

A doctor in Paris has a brother in Toronto who is alawyer. The lawyer does not have a brother who isa doctor in Paris. How is this possible?

The diagonal of a quadrilateral is 16cm.The perpendiculars from thevertices to the diagonal measure 12cm and 15cm. Find the area of the quadrilateral.

Simplify the following expressions 3 upon 2 x 7 upon 9 minus 2 upon 3 + 1 upon 3 plus 2 upon 3 minus 4 upon 9A) 1 upon 3B) 2 upon 3C) 1D) 1 1 upon 3

Form a 7-digit number using the following clues.a) Digit 4 is in the ten lakhs place.b) Digit 1 is in the ten thousands place.c) Digit 2 is in the tens place.d). Digit 6 is in ones place.e) The digits in the remaining place values are zero.

The postulate "the sum of angles of any triangles equal to two right angles" given bya) Play Fairb) Legendrec) Proclusd) Posido minus

Covert the following1)2.45km into m2)4.63m into cm3)97cm into m4)12.5cm into mm5)234.5g into kg6)5.6kg into g7)6250ml to l8)0.5l into ml{With Explanation}

If 39 = 3 X + 3 Y + 3 Z therefore X + Y + Z =?Options1. 52. 73. 44. 6PLZ ANSWER FAST... ITS URGENT

Find the sum of three angles, in an inscribed hexagon .See the attachment for more details !

A cuboidal container of dimension 10 cm by 8cm and by 6cm filled with water and this water is poured into a cylindrical container of radius 7 cm . find the height of water in cylinder.Don't Answer if uh don't know :)

The ratio of ₹20 and ₹25 is(a) 4:5(b) 5:4(e) 5:6(d) 6:5answer me with method please

The ratio of 20 and 7 25 is(a) 4:5(b) 5:4(e) 5:6(d) 6:5answer me with method please

(2) For the point (3.4), the distance from the X axis is(a) 10(b) 3(c) 13units(d) 7Method please

ClassmateDatePageB What is the difference betwerph the smallenumber of five digit and the largestnumber of four digit

300 m long train crosses a pole in 24 sec. What is the speed of the train in km/hr ?1) 45 km/hr2) 60 km/hr 3) 36 km/hr 4) 42 km/hr.

Simplify?options

Which of the following cannot be written as (-20) + 5 ?(a) (-5) + 20(b) - [20 + 5] (c) 20 - (-5)(d) - 4