1.

Find the accumulated value of the deposit $2500 made in simple interest for 3.5 years at 5% rate of interest per year.!! NO SPAMMING !!

Answer»

<P>{\huge{\underline{\bf{Solution:}}}}

\begin{gathered} \\ \end{gathered}

Given:

  • Principal = $2500
  • Time in years = 3.5
  • RATE of interest = 5%

\begin{gathered} \\ \end{gathered}

To find:

\begin{gathered} \\ \end{gathered}

  • Accumulated Value

\begin{gathered} \\ \end{gathered}

Solution:

\begin{gathered} \\ \end{gathered}

To find the SIMPLE interest, we use the formula:

\multimap \: \boxed{ \sf Simple\:Interest = \dfrac{PRT}{100}}

Where,

  • P = Principle
  • R = Rate of Interest
  • T = Time (years)

\begin{gathered} \\ \end{gathered}

\begin{gathered} \colon \longrightarrow \sf \: Simple\:Interest = \dfrac{PRT}{100} \\ \\ \end{gathered}

\begin{gathered} \colon \longrightarrow \sf \: Simple\:Interest = \dfrac{2500 \times 5 \times 3.5}{100} \\ \\ \end{gathered}

\begin{gathered} \colon \longrightarrow \sf \: Simple\:Interest = \dfrac{25 \cancel{00} \times 5 \times 3.5}{1 \cancel{00}} \\ \\ \end{gathered}

\begin{gathered} \colon \longrightarrow \sf \: Simple\:Interest = 25 \times 5 \times 3.5 \\ \\ \end{gathered}

\colon \implies\underline{ \boxed{ \bf{ \red{Simple\:Interest = 437.50}}}} \: \bigstar

\begin{gathered} \\ \end{gathered}

Accumulated value is nothing but Amount. Hence, to find Amount, we use the formula:

\begin{gathered} \\ \end{gathered}

\multimap \: \boxed{ \sf Amount = P+I}

Where,

  • P = Principal
  • I = Simple Interest

\begin{gathered} \\ \end{gathered}

\begin{gathered} \colon \longrightarrow \sf \: Amount = P+I \\ \\ \end{gathered}

\begin{gathered} \colon \longrightarrow \sf \: Amount = 2500+437.50 \\ \\ \end{gathered}

\colon \implies\underline{ \boxed{ \bf{ \green{Amount= 2937.50}}}} \: \bigstar

Hence, the accumulated value is 2937.50



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