In a triangle , the length of the first side is 5 cm less than the len

1.	In a triangle , the length of the first side is 5 cm less than the length of the second side . The length of the third side is 7 cm more than the length of the first side if the first side is of length is 18 cm , then what is the semiperimeter of the triangle₦Ø₸E:•Don't spam ❌• Quality answer needed✔
Answer» Given : The length of the first side is 5 cm less than the length of the SECOND side . The length of the third side is 7 cm more than the length of the first side . Length of first side is 18 cm . To Find : Semi Perimeter of Triangle . Solution : $\longmapsto\tt{Let\:second\:side\:be=x}$ Length of the first side is 5 cm less than the length of the second side . So , $\longmapsto\tt{First\:side=x-5}$ Also , The length of the third side is 7 cm more than the length of the first side . So , $\longmapsto\tt{Length\:of\:third\:side=x-5+7}$ Length of first side is 18 cm : $\longmapsto\tt{x-5=18}$ $\longmapsto\tt{x=18+5}$ $\longmapsto\tt\bf{x=23}$ Therefore : $\longmapsto\tt{Length\:of\:first\:side=18\:cm}$ $\longmapsto\tt{Length\:of\:second\:side=x}$ $\longmapsto\tt\bf{23\:cm}$ $\longmapsto\tt{Length\:of\:third\:side=23-5+7}$ $\longmapsto\tt\bf{25\:cm}$ For Semi Perimeter : a = 18 cm b = 23 cm c = 25 cm Using Formula : $\longmapsto\tt\boxed{Semi\:Perimeter=\dfrac{a+b+c}{2}}$ Putting Values : $\longmapsto\tt{\dfrac{18+23+25}{2}}$ $\longmapsto\tt{\cancel\dfrac{66}{2}}$ $\longmapsto\tt\bf{<klux>33</klux>\:cm}$ So , The Semi Perimeter of Triangle is 33 cm .