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This section includes InterviewSolutions, each offering curated multiple-choice questions to sharpen your knowledge and support exam preparation. Choose a topic below to get started.
| 6301. |
12. The inside perimeter of a running track (shown in Fig. 13.61) is 401length of each of the straight portion is 90 m and the ends are semi-cirtetrack is everywhere 14 m wide, find the area of the track. Also findlthebthe outer running track. |
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| 6302. |
o. The inside perimeter of a running track shown in the figure is 400 m.The length of each of the straight portions is 90m90 m,, and the ends are semicircles. If thetrack is 14 m wide everywhere, find the areaof the track. Also, find the length of the outer 14 ノ)boundary of the track. |
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Answer» thanks |
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| 6303. |
5. The inside perimeter of a running track (shown in Fig. 20.24) is 400 m. The leneach of the straight portion is 90 m and the ends are semi-circles. If trackeverywhere 14 m wide, find the area of the track. Also, find the length of the autemrunning track. |
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| 6304. |
inside perimeter of a running track (shown in Fig. 13.75) is 400each of the straight portion is 90 m and the ends are semi-circles. Ifteverywhere 14 m wide, find the area of the track. Also, find the length of theack11. Thethe track. Also, find the length ofackrunning trackouter |
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| 6305. |
60. The inside perimeter of a running track shown in the figure is 400 m.The length of each of the straight portions is 90 m90 m, and the ends are semicircles. If thetrack is 14 m wide everywhere, find the areaof the track. Also, find the length of the outer14 mboundary of the track. |
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| 6306. |
Mathematics for Class Vill5. The inside perimeter of a running track (shown in Fig. 20.24) is 400 m. The length ofeach of the straight portion is 90 m and the ends are semi-circles. If track iseverywhere 14 m wide, find the area of the track. Also, find the length of the outerrunning track. |
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| 6307. |
पल “रन अत '. 2 2 23% * 91%क/--ऊ-0 ० |
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Answer» Since it is a 0/0 formwe will use L'hopital rulewe will diffrentiate the numerator and denominatortill it's not a 0/0 formafter diffrentiationit will be 2[4.cos4xsinx+sin4x cosx]/3x^2now putting limits2/3[4+1]2/3*510/3 will be the answeras sinx/x = 1 cosX= 1 (when limit x tends to 0)10/3 is the answer |
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| 6308. |
2 \times 5 \times ( 10 x ^ { 2 } y - 100 x y ^ { 2 } ) |
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Answer» thank you so much |
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| 6309. |
whd aunter wil be inext it the given seriesa) tee tr(b) 7number is equal to the cube of second number. The numbe(c 63(d) 4, 2 |
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Answer» CORRECT OPTION : B) EXPLANATION: Let's see the options provided.a) 9^2 = 18.3^3 = 27.b) 8^2 = 644^3 = 63c) 6^2 = 363^3 = 27d) 4^2 = 162^3 = 8. WE CAN SEE THAT ONLY IN OPTION B, THE SQUARE OF THE FIRST NUMBER IS EQUAL TO THE CUBE OF THE SECOND NUMBER. PLEASE HIT THE LIKE BUTTON |
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| 6310. |
15. The sum of two numbers is2825of the firstnumber. The second number is what per cent ofthe first? |
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| 6311. |
numbers in the ratio 2:5 are such that the first number is 36 less than thesecond number. Find the second number.1. Two |
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Answer» Let the ratio be x So, numbers are 2x and 5x. According to question, 2x = 5x - 36 5x - 2x = 36 3x = 36 x = 12 So, second number is 5x = 60 |
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| 6312. |
write the decimal for each of following(1) 50+8+9/10+6/100(2) 20+1+0/10+9/100(3)60+1/10+3/100 |
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| 6313. |
Solve the following0 10p-100(1) 10x + 10 =100(v) 2x+3-13v) 15y + 4) - 2y- |
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Answer» 1) p = 100/10=10; 3)10x + 10 =100; 10x=90; ; x = 90/10=9; 4) 2x + 3 =13; 2x=13-3=10; x= 10/2=5; |
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| 6314. |
a) 40b)AOd)05. "If we add 3 to twice of a number we cequation form isc) 2x +9a)2x-9The expanded form of 3.42 isd) 2x + 32+4+b) 30 + 4 + 100 , c) 3 +10 100+ikd) 3 + 4 x 10 + 2 x 10010 10 |
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| 6315. |
Raju scored 540 marks out of 600Write his score as a pecentage.1. |
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Answer» Score percentage = [(Marks obtained)/(Total marks)] × 100 = (540/600) × 100 = 90% |
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| 6316. |
the lateral surface of a cylinder is 94.2 cm2 and its height is 5 cm, then fi(ii) its volume. fUse Tt 3.14)4. If(i) radius of its base |
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| 6317. |
ECO-FRIENDLY PACKAGING |
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Answer» Eco-friendly packagingis usually made from biodegradable, recycled material which reduces the waste of natural resources for production. In addition, the manufacturing process tends to be more efficient, further reducing precious resources and minimizing the negative impact businesses have on the environment. |
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| 6318. |
19. A circular garden of radius 25 m has aconcentric circular fountain of radius 3 m.Find the area of the garden available forthe children to play in. (Ď = 3.14) |
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Answer» Area of circle = (22/7)*radius*radius. Area available for children = Area of bigger circle - Area of smaller circle= (22/7)*25*25 - (22/7)*3*3= 1936 sq m PLEASE HIT THE LIKE BUTTON are u sure this answer is correct |
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| 6319. |
7. A tin contains litres petrol, 14 litres petrol gets leaked. How much petrol is left in the tin?37. A tin contains litres petrol,g |
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| 6320. |
14. Find the mode of the following data:40-60hs20-406600-20Class181510 |
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| 6321. |
An archery target has three concentric circular regions. The diameters of the regions are in the ratio1:2:3. Find the ratio of their areas |
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Answer» Then the radii are d/2, d, 3d/2 The area of the central circle = pi.d^2/4 The area of the next region = pi (d^2 - d^2/4) = (3/4)pi.d^2 The area of the outermost region = pi (9d^2/4 - d^2) = (5/4)pi.d^2 Cancel out the 1/4ths So the ratios of their areas are: 1:3:5 |
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| 6322. |
E.URaju scored 540 marks out of 600.Write his score as a pecentage |
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Answer» (540/600) * 100 = 90% Total score=600Raju score=540Therefore, percent=540÷600×100 =90 |
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| 6323. |
1. True/False:a) A cube has 10 edges.b) A circular prism has no vertex. |
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Answer» a circular prism has no vertex 1. false 2. trueanswer of the given question jguguftfhdhfgxg v hugjfjh false, true is the correct answer of the given question a circular pism has no vertex 1. false 2. true is the correct answer |
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| 6324. |
14.The central angle and radius of a sector of a circular disc are 180° and 21 cmrespectively. If the edges of the sector are joined together to make a hollow cone,then find the radius of the cone. |
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Answer» The cone is being created by joining the radius. So the radius of the sector is going to be the slant height of the cone. Slant height (L) = 21 cm Arc length of the sector = Circumference of the base of the cone Length of arc = (θ/360)x2Π R Here R represents radius of the sector = (180/360)x2x(22/7)x(21) = (1/2)x2x22x3 = 66 cm So,circumference of the base of the cone =66 2 Π r = 66 2x(22/7)xr = 66 r = 66x(1/2)x(7/22) r = 10.5 cm Radius of the cone =10.5 cm |
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| 6325. |
6616 cm2 respectively, then fi16 cm2 respectiIf the areas of two concentric circles are 154 cm2 andteof the circular path between them |
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Answer» Let r = radius of inner circlearea of inner circle = 154 cm²⇒πr^2=154⇒r^2=154×722=49⇒r=7cm Let R = radius of outer circlearea of outer circle = 616 cm^2⇒πR^2=616⇒R^2=616×722=196⇒R=14cm width of ring = R - r = 14 - 7 = 7 cm |
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| 6326. |
की.” g e g bd |
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Answer» 12576>4052 by euclid division alogrinthm 12576=4052*3 +420 4052=420*9+272 420=272*1+148 272=148*1+124 148=124*1+24 124=24*5+4 24=4*6+0 as the process stops . so our HCF is 4 |
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| 6327. |
|| 1 2- g â - ' - e g -. 3 |
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Answer» 1/4 × 5 + 5 - 1/3 × 2/3 = 4/5 + 5 - 2/9 = (4+25)/5 - 2/9 = 29/5 - 2/9 = (29×9-5×2)/45 = 251/45 If you find this answer helpful then like it. |
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| 6328. |
he blood groups of 30 students of Class VIlI are recorded as follows:(A,B,O, O, AB, O, A, Q, B,A,O, B, A, Q,O;A, AB, O.A,A, O, O, AB. B,A.O, B,A, B, 9.Represent this data in the form of a frequency distribution table. Which is the mostcommon, and which is the rarest, blood group among these students? |
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| 6329. |
1300children took the NuMATS test and 65more than 25. How many are they?5.%ofthem scorede other percent |
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Answer» 1300*65/100=845 children scored more than 25 what does '*' means |
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| 6330. |
Two buildings 30 m and 15 m high are sepárated hy a distance of 36 m. Fini the distancebetween their tops. |
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Answer» Like if you find it useful |
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| 6331. |
200 + 200 |
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Answer» 200 (+)200 = 400 |
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| 6332. |
200+200 |
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Answer» 200 + 200=400 is the answer 200+ 200_________ 400 400 is the answer of the following 200 +200=400This is right and best answer. 400it is only adding1st class question |
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| 6333. |
2. The angle of elevation of the Sun is 609. Then findthe length of the shadow of a 15 m high tree. ) |
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| 6334. |
के, 600 + 300 + 200 600 + 300 + 200 |
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Answer» 1100. buklgvndcdgkkf vbngml |
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| 6335. |
200+200=?? |
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Answer» 300 is the correct answer me sorry 400 is the correct answer me 400 is the correct answer me 400 is the correct answer 400 is the answer sid bhai maine ek que dala hua hai tm answer de do jaldi or ise best accept kar lo 400 is correct answer me 400 is the right answer 200+200=400 is the correct answer. 400 is correct answer 200+200=400 answer.... 200+200= 400......... 400 is the right answer 400 is the right answer 400 answer of question 400 it is the final answer obvioiusly 400 200+200 = 400 400 is the right answer of the question |
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| 6336. |
19 sin20 =17 sinoo eg~ |
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| 6337. |
200+200+300=?? |
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Answer» 700 is the correct answer me 700 is the answer sid bro 200+200+300=700 this is answer for your question 200+200+300=700 is the correct answer. 700 is correct answer 200+200+300=700 ...... 200+200💕+300=700 700 is the right answer for the question |
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| 6338. |
Proved thot\begin{array}{r}{3 \cos \frac{\pi}{3} \sec \frac{\pi}{3}-4 \sin \frac{5 \pi}{8} \tan \frac{\pi}{4}} \\ {\cos 2 \pi=1}\end{array} |
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| 6339. |
\operatorname { cos } ( \frac { 3 \pi } { 2 } + x ) \operatorname { cos } ( 2 \pi + x ) [ \operatorname { cot } ( \frac { 3 \pi } { 2 } - x ) + \operatorname { cot } ( 2 \pi + x ) ] = 1 |
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| 6340. |
\sin ^{2} \frac{\pi}{6}+\cos ^{2} \frac{\pi}{3}-\tan ^{2} \frac{\pi}{4}=-\frac{1}{2} 2 \cdot 2 \sin ^{2} \frac{\pi}{6}+\csc ^{2} \frac{7 \pi}{6} \cos ^{2} \frac{\pi}{3}=\frac{3}{2} |
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Answer» 1)sinπ/6=1/2 cosπ/3=1/2 tanπ/4=1hence(1/2)^2+(1/2)^2-1^2=1/4+1/4-1=-1/2 2)sinπ/6=1/2cosec7π/6=coSsec(π+π/6)=-cosecπ/6=-2cosπ/3=1/2put in the values2*1/2^2+(-2)^2*1/2^2=1/2+4*1/4=3/2 |
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| 6341. |
In 'an aeroplane, there are 120 passengers. If 20 are children , find howmany percent are children? |
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Answer» among 120, 20 are children so percent of children are 20/120 * 100 = 16.67% |
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| 6342. |
In an aeroplane, there are 120 passengers. If 20 are children,find howmany percent are children? |
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Answer» among 120, 20 are children so percent of children are 20/120 * 100 = 16.67% |
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| 6343. |
In an aeroplane there are 120 passengers. If 20 are children, then how many percent are children? |
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Answer» among 120, 20 are children so percent of children are 20/120 * 100 = 16.67% |
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| 6344. |
S रीनेम्नलिखित में से कौन-सी संख्याएं पुर्ण घन नहीं1000 6५ 100G 216 128 छा) N e उरात्ताओं |
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Answer» sorry thanks |
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| 6345. |
( \operatorname { sin } \frac { \pi } { 6 } + \operatorname { cos } \frac { \pi } { 6 } ) ( \operatorname { sin } \frac { \pi } { 3 } - \operatorname { cos } \frac { \pi } { 3 } ) = \frac { 1 } { 2 } |
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Answer» Pura taknic ke sath ek ek line please thanks Bhaiya Ji |
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| 6346. |
k. 80,000 - 80,000-. 9,7901-19,7901 1n. 4.32,700-1000n. 6,95,550 -1010,00,000-1p. 5,00,000-5,00,000 =r. 5,37,600- 10002,55,500-100 =7,77,700-09,38,600-10 =bination of addition and subtraction |
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Answer» k 80,000 - 80,000 = 0m 4,32,700 - 1000 = 431700o 10,00,000 - 1 = 999999q 2,55,500 - 100 = 2,55,400s 7,77,700 - 0 = 7,77,700l 9,7901 - 1 = 9,7900n 6,95,550 - 10 = 6,95,540p 5,00,00 - 5,00,000 = 0r 5,37,600 - 1000 = 5,36,600t 9,38,600 - 10 = 9,38,690 lwhat is names and where you live |
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| 6347. |
(iii) 2.48 = 4(vii) 3.96 : 4(iv) 65.4 = 6(viii) 0.80 = 5(iv) 33.1 + 10(iii) 0.7 - 10(vii) 3.97 +101. Find:0.4+2 ( 0.35 - 5(v) 651.2 + 4 (vi) 14.49 : 72. Find:4.8 -1052.5 : 10(v) 272.23 - 10 (vi) 0.56 - 103. Find:2.7 = 100 N 0.3 + 100(iv) 432.6 + 100 (v) 23.6 -1004. Find:w 7.9: 1000 26.3 + 1000(iv) 128.9 - 1000 (v) 0.5 : 10005. Find:(1) 7+3.5 W 36:0.2(v) 0.5 0.25 (vi) 7.75 -0.25fix) 2.73 : 1.3(m) 0.78 + 100(vi) 98.53 - 100(ii) 38.531000(ii) 3.25 -0.5(vii) 76.5 +0.15(iv) 30.94 +0.7(vin) 37.8 + 1.4 |
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Answer» 1-0.2 0.72-0.48 5.253-0.027 0.0034-0.0079 0.0263 1)0.2 0.7 2)0.48 5.25 3)_0.027 0.003 4)0.0079 _0.0263 5)7÷35=5, (ii)36÷0.2=180, (iii)3.25÷0.5=6.5, (iv)3.25÷0.5=6.5 (v)30.94÷0.7=44.2, (vi)0.5÷0.25=2, (vii)7.75÷0.25=31, (viii)76.5÷0.15=306, (ix)37.8÷1.4=27, ( x)2.73÷1.3=2.1 8)7.9÷1000=0.0079 (ii) 26.3÷1000=0.00263.(3(iii))27÷100=0.27, (iv)0.3÷100=0.003 |
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| 6348. |
Prove that (1-sin20)sec29-1 |
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Answer» we know that1-sin^2= cos^2nowcos^2*(1/cos^2)= 1thanks |
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| 6349. |
Write the value of cot20-sin20 |
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| 6350. |
(1) In how many ways can 4 boys and 3 girlsbeseated in a row of 7 chairs if boys and girls alternate ?(ii) In how many ways can 4 boys and 3 girls be seated in a row so that no two girls are together?(ii) In how many ways can 5 girls and 3 boys be seated in a row so that no two boys are together ?(N.C.E.R.Т.; H.PB. 2011) |
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