1.

( \operatorname { sin } \frac { \pi } { 6 } + \operatorname { cos } \frac { \pi } { 6 } ) ( \operatorname { sin } \frac { \pi } { 3 } - \operatorname { cos } \frac { \pi } { 3 } ) = \frac { 1 } { 2 }

Answer»

Pura taknic ke sath ek ek line please

thanks Bhaiya Ji



Discussion

No Comment Found