\sin ^{2} \frac{\pi}{6}+\cos ^{2} \frac{\pi}{3}-\tan ^{2} \frac{\pi}{4

1.	\sin ^{2} \frac{\pi}{6}+\cos ^{2} \frac{\pi}{3}-\tan ^{2} \frac{\pi}{4}=-\frac{1}{2} 2 \cdot 2 \sin ^{2} \frac{\pi}{6}+\csc ^{2} \frac{7 \pi}{6} \cos ^{2} \frac{\pi}{3}=\frac{3}{2}
Answer» 1)sinπ/6=1/2 cosπ/3=1/2 tanπ/4=1hence(1/2)^2+(1/2)^2-1^2=1/4+1/4-1=-1/2 2)sinπ/6=1/2cosec7π/6=coSsec(π+π/6)=-cosecπ/6=-2cosπ/3=1/2put in the values21/2^2+(-2)^21/2^2=1/2+4*1/4=3/2

\sin ^{2} \frac{\pi}{6}+\cos ^{2} \frac{\pi}{3}-\tan ^{2} \frac{\pi}{4}=-\frac{1}{2} 2 \cdot 2 \sin ^{2} \frac{\pi}{6}+\csc ^{2} \frac{7 \pi}{6} \cos ^{2} \frac{\pi}{3}=\frac{3}{2}

Answer»

1)sinπ/6=1/2 cosπ/3=1/2 tanπ/4=1hence(1/2)^2+(1/2)^2-1^2=1/4+1/4-1=-1/2

2)sinπ/6=1/2cosec7π/6=coSsec(π+π/6)=-cosecπ/6=-2cosπ/3=1/2put in the values2*1/2^2+(-2)^2*1/2^2=1/2+4*1/4=3/2