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87+24+17+28+14=111+17+28+14=128+28+14=170

both given fraction are equivalent 6/8 = 3/43/4 = 3/4

SP>CPso profit=SP-CP=450-400=50profit percentage=50/400*100=12.5%

4/5, 5/7by cross multiple4*7=285*5=254/5>5/7

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9 by 18 12 by 18 8 by 18 15 by 18

sir only 5 is a proper fraction or not

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The orthocenter is the intersecting point for all the altitudes of the triangle. The point where the altitudes of a triangle meet is known as the Orthocenter. In the below mentioned diagram orthocenter is denoted by the letter ‘O’. There is no direct formula to calculate the orthocenter of the triangle. It lies inside for an acute and outside for an obtuse triangle.

Altitudes are nothing but the perpendicular line ( AD, BE and CF ) from one side of the triangle ( either AB or BC or CA ) to the opposite vertex. Vertex is a point where two line segments meet ( A, B and C ).

ToCalculate the slope of the sides of the triangle. The formula to calculate the slope is given as,

SlopeofaLine=y2−y1x2−x1

To calculate the perpendicular slope of the sides of the triangle. It gives us the slope of the altitudes of the triangle. The formula to calculate the perpendicular slope is given as,

PerpendicularSlopeofaLine=−1SlopeofaLine

To calculate the equation for the altitudes with their respective coordinates. The point slope formula is given as,

y−y1=m(x−x1)

Finally by solving any two altitude equation, we can get the orthocenter of the triangle

thanks mam

well1. angle ADE = 55 (corresponding angles)2. angle AED=65 +55+x=180so Angle AED=603. in triangle ABC 55+65+X=180So angle C=60

Sum of first 6 terms of AP = 42S6 = 6/2(2a + 5d)...... (1)

nth term of an APTn = a + (n-1)dWhere, a = first termd = common difference

According to the given condition T10/T30 = 1/3(a + 9d)3 = a + 29d3a + 27d = a + 29d2a = 2da = d

Put value of d = a in eq(1)42 = 3(2a + 5a)7a = 14a = 14/7 = 2

Thus a = 2, d = 2

Therefore, First term = 213th term = a + 12d = 2 + 12*2 = 26

Since DE || BC, by Thales theorem AD/DB = AE/EC Therefore, both AD/DB and AE/EC = 1: 2 So AD:AB = 1:3 or AB:AD = 3:1

The triangles are similar by SAS axiom. Hence the areas of the triangles are in the ratio of squares of corresponding sides.

Therefore, the ratio of area of Δ ABC to the area of Δ ADE = 3^2:1^2 = 9:1

1)AD/DB = AE/EC 1.5/3 = 1/ECEC= 2 cm

2)AD/BD = AE/EC AD/7.2 = 1.8/5.4AD=2.4cm

thanks

Given,Total distance covered= xkm=1+(x-1)km

Fare For first kilometre= ₹8

Fare for subsequent distance= ₹5 per km

Fare for next(x-1)km= 5(x-1)

A.T.Q

Total fare= y

8+5(x-1)=y

8+5x-5=y

5x-y+3=0

Which is the required linear equation.

It can also be written as y= 5x+3

When X = 0 ,then Y = 3,When x=1, then y=5+3=8

When x= 2, then y= 10+3=13

[Table & graph are on the attachment]

Now plot the points A(0,3), B(1,8), C(2,13) on the graph paper and join them to form a line BC, which represents therequired graph of linear equation.

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86.813

13 rounds to 1086.81

how

thanks so much for your help and support

x^2 - 2x + 1 = 0x^2 - x - x + 1 = 0x(x - 1) - 1(x - 1) = 0(x - 1)^2 = 0x = 1

Thankyou

1+5=5 2+5=12 3+6=21 8+6

Red line is y = -3x + 1Blue line is 3x + y = -7So from given graph we see that both are parallel to each other, hence, there is no solution exists.

a. :. =b. :. <c. :. >d. :. <

x*x - 2x + 1 = 0 x*x - x - x + 1 = 0 (x-1)(x-1) = 0 x = 1 x + 1/x = 1 + 1/1 = 1 + 1 = 2

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D=b^2-4achenceD=3*3-4*-4*2D=9+32=41hence as it is positive hence roots are real and distinct

if 2 is the root then it will satisfy the equation.substitute x=2(2)(2^2)+K*(2)-6=0=>8+2K-6=0=>2K=2=>K=-1( answer)for other root,2x^2-4x+3x-6=0=>2x(x-2)+3(x-2)=0=>x=2, x=3/2

speed=60 km/h=60×(5/18) m/s=16.67 m/s:. Distance travelled=speed× time=16.67m/s×45 mins=16.67 m/s×45×60sec=45009 m= 45.009 km

6.4 km. may be the answer

6.32 km is the correct answer of the given question

6.32km is the correct answer

3km=3×1000=3000mA/cDistance covered in 45 min=3000m(or 3km)". ". ". 94.8 min=3000/45×948/10=6320 m.Hence distance covered in 94.8 min is 6320m.

the correct answer is 6.32km of the following

6.4km is the answer of the following

speed = Distance/time = 3/45 = 1/45 km/ hr so distance covers in 94.8 munitesDistance = speed × time =1/15 × 94.8 = 1×94.8/15 = 6.32 km

6.32km is the right answer of the following

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Speed of first aeroplane = 3300/3= 1100 km/hr.Speed of second aeroplane - 1100 - 100= 1000 km/hr.

Time taken by second aeroplane = Distance / Speed= 3300/1000= 3.3 hours.

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