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If one root of the quadratic equation 2x +Kx-6-0 is 2, find the value of K. Also find the other |
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Answer» if 2 is the root then it will satisfy the equation.substitute x=2(2)(2^2)+K*(2)-6=0=>8+2K-6=0=>2K=2=>K=-1( answer)for other root,2x^2-4x+3x-6=0=>2x(x-2)+3(x-2)=0=>x=2, x=3/2 |
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