4,. The taxi fare in a city is as foflows: For the first kilometre, th

1.	4,. The taxi fare in a city is as foflows: For the first kilometre, the fare is 8subsequent distance it is, 5 per km. Taking the distance covered as xkmfare as Rs y, write a linear equation for this information, and drâw its graph
Answer» Given,Total distance covered= xkm=1+(x-1)km Fare For first kilometre= ₹8 Fare for subsequent distance= ₹5 per km Fare for next(x-1)km= 5(x-1) A.T.Q Total fare= y 8+5(x-1)=y 8+5x-5=y 5x-y+3=0 Which is the required linear equation. It can also be written as y= 5x+3 When X = 0 ,then Y = 3,When x=1, then y=5+3=8 When x= 2, then y= 10+3=13 [Table & graph are on the attachment] Now plot the points A(0,3), B(1,8), C(2,13) on the graph paper and join them to form a line BC, which represents therequired graph of linear equation. Like my answer if you find it useful!

4,. The taxi fare in a city is as foflows: For the first kilometre, the fare is 8subsequent distance it is, 5 per km. Taking the distance covered as xkmfare as Rs y, write a linear equation for this information, and drâw its graph

Answer»

Given,Total distance covered= xkm=1+(x-1)km

Fare For first kilometre= ₹8

Fare for subsequent distance= ₹5 per km

Fare for next(x-1)km= 5(x-1)

A.T.Q

Total fare= y

8+5(x-1)=y

8+5x-5=y

5x-y+3=0

Which is the required linear equation.

It can also be written as y= 5x+3

When X = 0 ,then Y = 3,When x=1, then y=5+3=8

When x= 2, then y= 10+3=13

[Table & graph are on the attachment]

Now plot the points A(0,3), B(1,8), C(2,13) on the graph paper and join them to form a line BC, which represents therequired graph of linear equation.

Like my answer if you find it useful!

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