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Yes the statement is true because complex number are in form of a+bi, where i² = -1 and a, b belongs to set of real numbers .To get real numbers set b = 0 there form will be only a i.e. the set of real numbers

Tan(75°) = tan(45° + 30°) = [tan(45°) + tan(30°)]/[1 - tan(45°)tan(30°)]

= [1 + 1/√(3)]/(1 - 1/√(3)]. tan(75°) = (√(3) + 1)/(√(3) - 1).

LCM*HCF=product of two numbers760*HCF=6080HCF=6080/760=8HCF=8

Let age of Manisha be xThen Manisha mother's age = 3x

After 4 yearsManisha age = x + 4Manisha mother's = 3x + 4

As per given condition3x + 4 = 2.5(x + 5)3x + 4 = 2.5x + 12.53x - 2.5x = 12.5 - 4.5x = 8.5x = 85/5 = 17

Manisha present age = 17 yearsMothers age = 3*17 = 51 years

Tan10 tan15 tan(90-75) tan (90-80)= tan10 tan15 cot 15 cot10as we know tan theta * cot theta = 1sotan10 cot10 tan15 cot 15= 1

we know tan (A+B) = (tan A +tan B)/(1- tan A tan B)

put A = 10° and B = 35°

to get tan 45° = ( tan 10 ° + tan 35°)/(1- tan 10° tan 35°)

or 1 = ( tan 10 ° + tan 35°)/(1- tan 10° tan 35°)

or (1- tan 10° tan 35°) = ( tan 10 ° + tan 35°)

or Tan35°+tan10°+tan35°tan10°= 1

(tan20/cosec70)2+(cot20/sec70)^2+2tan15tan45tan75={tan(90-20)/cosec70}^2+{cot90-20)/sec70}^2+2(tan90-15)tan45 tan 75=(cot70/cosec70)^2 + (tan70/sec70) ^2+ 2(cot75 tan 45 tan75 )=(cos 70/sin70/1/sin70)^2 +(sin70/cos70/1/cos70) ^2+2(1×1)=(cos70+sin70)^2 +2=1+2=3...

13915

We will use the division method as shown below:

51391511278311253232315139151127831125323231∴ 13915 = 5 × 11 × 11 × 23 = 3 × 112× 23

20+3×5=? solve this question

x+ 65+60 = 180( sum of three angles in triangle is 180)sox = 180 -125 = 55

Area of square is in ratio of side squarehence side ratio will be √225/256=15/16as perimeter is also in side ratio hence it will be 15/16

1 six are there in 36

1six are there in 36

6 is the correct answer

only one six are in36

Sin²25° + Sin²65° + √3 ( Tan5° × Tan15° × Tan30° × Tan75° × Tan85° ) .

Sin²(90-65° ) + Sin²65° + √3 ( Tan5° × Tan85° × Tan15° × Tan75° × Tan30° ).

Cos² 65° + Sin²65° + √3 ( Tan5° × Tan(90-5°) * Tan15° × Tan(90-15°) * Tan 30° ).

Sin²65° + Cos²65° + √3 ( Tan 5° × Cot5° * Tan15° × Cot15° * 1/√3 ).

Sin²65° + Cos²65° + √3 ( Tan5° × 1/Tan5° * Tan15° × 1/Tan15° × 1/√3 ).

1 + √3 ( 1 * 1 * 1/√3 )

1 + √3 ( 1/√3 )

1 + √3 × 1/√3

1 + 1

2

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let nuri' age =x and song age=y five years ago x=3(y) x-3y=0......... (1) and after ten year x=2(y) x-2y=0..........(2) from equal 1 and 2 by elimination

Let the age of nuri be x

and the age of sonu be yaccording to question,

Five years ago:

Nuri's age = X-5

Sonu's age = Y-5

so,by condition

== (X-5) = 3(Y-5)

== X=3Y-15 + 5

== X= 3Y- 10 ...(1)

Ten years after:

Nuri's age = X+10

Sonu's age = Y+10(X+10) = 2(Y+10)

X= 2Y+ 20 -10X = 2Y+10

From eqution(i) X= 3Y- 10

→3Y- 10 = 2Y+10

→3Y- 2Y = 20

→Y = 20

putting value of y in (equation 1

→ X= 3(20)- 10

→ X= 50

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Let Nuri is x years and Sonu is y years

x-5=3(y-5)x-3y=-10

x+10=2(y+10)x+10=2y+20x-2y=10

Subtract equationsy=20x=10+40=50

let the common ratio be x7x+5x+10=9x+7x12x+10=16x12x-16x=-10-4x=-10x=-10/-4x=2.5the present age of A is 17x7x=2.5×77x=17.5 the age of A is 17 years and 6 months

and the age of B is 5x5x=2.5×55x=12.5the age of B is 12 years and 6 months

Let the present ages of A and B be denoted by x. So we have, 7x and 5x

After 10 years, their ages will be

A = 7x + 10 and B = 5x + 10

According to the question, the ratio was 9:7 (After 10 years)So, the equation will be

7x + 10/5x + 10

7:5ten years later 9:7 7:5×9:7 =9:5

Let the age of A be 7x

Let the age of B be 5x___________________

ATQ -----___________________

=> (7x + 10) : (5x + 10) = 9 : 7

=> (7x + 10) / (5x + 10) = 9 / 7

=> 7 (7x + 10) = 9 (5x + 10) [Cross multiplication)

=> 49x + 70 = 45x + 90

=> 49x - 45x = 90 - 70

=> 4x = 20

=> x = 20 / 4

=> x = 5__________________

• A's present age = 7x = (7×5) years = 35 years

• B's present age = 5x = (5×5) years = 25 years

Let the present age of A be 7x and the present age of B be 5x. ten years later,. the age of A be =7x+10. the age of B be=5x+10. now,. 7x+10/5x+10= 9/7. 7(7x+10)=9(5x+10). 49x+70=45x+90. 49x-45x=90-70. 4x=20. X=5. since,. A=7x=7×5=35. and, B=5×5=25. hence, the present age of A and B be 35 and 25 years

A is 35years B is 25 years

present age of a=35. and b=25

let the common ratio be7x+5x+10=9x+7x12x+10=16x12x-16x=-10-4x=-10x=-10/-4x=2.5the present age of A is 17x7x=2.5×77x=17.5the age of A is 17years and 6 Months

the age of A is 17 years and 6 months

DAV ka ho na hdhdhdjjdjdjd

a's present age=35 yearsb's present age =25 years

answer(b) 23% its is correct

option D 24.

4 cubes in first row2 in second, 4 in third row, again 4 in fourth row.,3 in fifth row, 4 in sixth row, 3 in seventh row.

by adding the numbers,4+2+4+4+3+4+3= 24 is the answer.

Thanks

(81)^{0.16} * (81)^{0.09}

we know :- [mⁿ * mˣ = m⁽ⁿ ⁺ ˣ⁾]

so, ⇒(81)^{0.16 + 0.09}

⇒(81)^{0.25}

⇒(3⁴)^{0.25}

⇒(3)^{4*0.25}

⇒(3)^{1}

⇒3

please write this on paper

I can understand

(81)^0.16 * (81)^0.09

= (81)^0.16+0.09

= (81)^0.25

= (81)^1/4

= (3*3*3*3)^1/4

= 3

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(81)^0.16 * (81)^0.09

= (81)^0.16+0.09

= (81)^0.25

= (81)^1/4

= (3*3*3*3)^1/4

= 3

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ans is 9h 60m or 10h.

9h 60m or 10h is the right answer

answer is 9h 60m means total time is 10h..

10hour is the right answer

9hours 60 mints is the right answer

10 hour is the right answer

answer is 9h 60m means total time is 10h.......

4+5 is equal to 9 and 20+40 is equal to 60.weknow that 1 hour is equal to 60 minutes so,9+1 is equal to 10 hours

red line is y = x-2 , blue line is y = 2x+1 and green line is y = 4

Q.3 Ans:- 4Q.4 Ans:-21

perimeter of a semicircle is equal to pi r +2rr=7cm

the perimeter of semicircle is 36CM. radius=36/4=3.5 cm

50 + x = 180° ..... ( linear pair)

so, x = 180-50 = 130°

and y = 130° ..... ( vertically opposite angles)

also, since x = y = 130 ° .. forms alternate interior angles.. so AB || CD

50+x= 180 linear pair anglesx=180-50x=130x= y alternate interior anglesx=y= 130

tysm

81^x * 3^x = 9

We know 81 = 3^4

So,

3^4x * 3^x = 3²

5x = 2

x = 2/5

Put y=x5x-2x=93x=9x=3hence y=3

as AB || CD,

50+x = 180°

x = 180-50 = 130°

and

as opposite angles are equal,

y = 130°

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y = 130° by vertically opposite angle

x+ 50 = 180 ( linear pair)x = 130°