1.

esent ages of A and B are in the ratio 7:5. Ten years later, thewne ratio 9: 7. Find their present ages.

Answer»

let the common ratio be x7x+5x+10=9x+7x12x+10=16x12x-16x=-10-4x=-10x=-10/-4x=2.5the present age of A is 17x7x=2.5×77x=17.5 the age of A is 17 years and 6 months

and the age of B is 5x5x=2.5×55x=12.5the age of B is 12 years and 6 months

Let the present ages of A and B be denoted by x. So we have, 7x and 5x

After 10 years, their ages will be

A = 7x + 10 and B = 5x + 10

According to the question, the ratio was 9:7 (After 10 years)So, the equation will be

7x + 10/5x + 10

7:5ten years later 9:7 7:5×9:7 =9:5

Let the age of A be 7x

Let the age of B be 5x___________________

ATQ -----___________________

=> (7x + 10) : (5x + 10) = 9 : 7

=> (7x + 10) / (5x + 10) = 9 / 7

=> 7 (7x + 10) = 9 (5x + 10) [Cross multiplication)

=> 49x + 70 = 45x + 90

=> 49x - 45x = 90 - 70

=> 4x = 20

=> x = 20 / 4

=> x = 5__________________

• A's present age = 7x = (7×5) years = 35 years

• B's present age = 5x = (5×5) years = 25 years

Let the present age of A be 7x and the present age of B be 5x. ten years later,. the age of A be =7x+10. the age of B be=5x+10. now,. 7x+10/5x+10= 9/7. 7(7x+10)=9(5x+10). 49x+70=45x+90. 49x-45x=90-70. 4x=20. X=5. since,. A=7x=7×5=35. and, B=5×5=25. hence, the present age of A and B be 35 and 25 years

A is 35years B is 25 years

present age of a=35. and b=25

let the common ratio be7x+5x+10=9x+7x12x+10=16x12x-16x=-10-4x=-10x=-10/-4x=2.5the present age of A is 17x7x=2.5×77x=17.5the age of A is 17years and 6 Months

the age of A is 17 years and 6 months

DAV ka ho na hdhdhdjjdjdjd

a's present age=35 yearsb's present age =25 years



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