1.

tan30+tan10+tan35*tan10

Answer»

we know tan (A+B) = (tan A +tan B)/(1- tan A tan B)

put A = 10° and B = 35°

to get tan 45° = ( tan 10 ° + tan 35°)/(1- tan 10° tan 35°)

or 1 = ( tan 10 ° + tan 35°)/(1- tan 10° tan 35°)

or (1- tan 10° tan 35°) = ( tan 10 ° + tan 35°)

or Tan35°+tan10°+tan35°tan10°= 1


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