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(i) p(0)= 1p(1)=1p(2)=3(ii)p(0)=2p(1)=4p(2)=6and so on

i)p(0)=1p(1)=1p(2)=3and so on

(i)p(0)=1p(1)=1p(2)=3is the right answer...

I p0=1p(1). 1p2=3is the wright answer

what is your question

volume of cylindrical vessel = 22/7× ( r)²×h= 22/7 × 4.5×4.5×4.5=286.39cmvolume of cylindrical iron piece =22/7×(r)²×h=22/7×3×3×4.5=127.28cmvolume of volume raised= volume of cylindrical vessel - volume of cylindrical iron piece=286.39-127.28=131.39cm²

i dont know.fhkhhiojb

diameter of hemisphere -9 cmradius-4.5cmvolume of hemisphere -2/3πr cube=190.9radius of cylinder -1.5cmheight of cylinder -3cmvolume of the cylinder -π rsq h

=

(1)GIVEN,f(x)=|x|g(x)=|5x-2|

gof(x)= g(f(x))gof(x)=g(|x|)gof(x)=|5|x|-2|

fog(x)=f(g(x))fog(x)=f(5|x|-2)fog(x)=|5|x|-2|.

(2)GIVEN f(x)=8x^3g(x)=x^1/3

gof(x)=g(f(x))gof(x)=g(8x^3)gof(x)=(8x^3)^1/3gof(x)=(2^3×x^3)^1/3gof(x)=2x

fog(x)=f(g(x))fog(x)=f(x^1/3)fog(x)=8(x^1/3)^3fog(x)=8x

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Thanks

Diameter of wheel=1.40mradius of wheel=0.7mdistance covered by wheel in one rotation =circumference of wheelcircumference of wheel=2*22/7*0.7=4.4m

distance covered by wheel in one rotation =4.4distance covered by wheel in 500 rotation =4.4^5002200m

number of rotation*circumference of wheel =77000mn=7700m/4.4mn=1750

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80 answer this ques.

(a+b)(a-b)=a^2-b^2(3+√3)(3-√3) =3^2 -(√3)^2=9-3 =6

Maya covered 7.5km distance from her home to city library.

Maya covered 30km distance from her home to the city library

7.5 is the correct answer

maya covered 7.5km distance from her home to city library

35 is the correct answer me to

7.5 is answer for this question

7.5 is correct answer

7.5 km is the correct answer ok

please like me please

30 km. is correct answer.

7.5 km. is correct answer.

bc(q - r) + ca(r - p) + ab(p - q)= bcq - bcr + acr - acp + abp - abq= p(ab - ac) + q(bc - ab) + r(ac - bc)

LetUnshaded regions be I, II, III and IVArea of I + Area of III= Area of ABCD – Areas of two semicircles = ( 10X10 - 2X1/2 X 3.14 X 5 X5) = (100 - 3.14 * 25) =21.5 cm²

similarly Area of II and IV is equal to 21.5cm²

So,Area of shaded region= 100 - (21.5 + 21.5) = 57cm²

ye right he ya wrong

plzzzz reply

The three broad categories of natural vegetation are—forests, grasslands and shrubs.

When a dice is thrown total possibilities are 6

i)A be event to get prime numberA = { 2, 3, 5 }

P(A) = 3/6 = 1/2

ii)

E be event or getting number lying between 2 and 6

E = { 3, 4, 5 }

P(E) = 3/6 = 1/2

at 3rd step instead of 6>5 write 4>3

Volume of cubiod = L × B × H

Area of base = L × B = 21.6 m²

So, given volume is 129.6 m³

Equating gives

129.6 = 21.6 × H

H = 129.6/21.6 = 6 m

So, height is 6 m

Here's the solution:

AC = CB (as C is the mid-point of line segment AB)

Add AC to both sides, we get

AC + AC = AC + CB ( Axiom 2: If equals are added to equals, then the wholes are equal)

So, 2 AC = AB (as AC+CB = AB)

AC = AB/2 ........ (1)

Next, AD = DC (as D is the mid-point of AC)

Add AD to both sides, we get

AD + AD = AD + DC (Axiom 2; same as above)

2 AD = AC (as AD + DC = AC)

Therefore, AD = AC/2 ......... (2)

Substituting value of AC from (1) in (2), we get

AD = AB/2÷ 2

AD = AB/2 x 1/2

AD = 1/4 AB

Given:-Volume of the cuboid is 275 cm cube and the base area is 25 square cm.

As we know that, base area× height=Volume=>Height=Volume/base area=275 cm³/25 cm=11 cm

Given, Cylinder radius r1 = 35/2 cm, height h1 = 32 cm

Cone radius r2 = 4/2 = 2 cm, height h2 = 7 cm

Volume of cylinder V1= pi*r1^2*h1= pi*35/2*35/2*32

Volume of cone V2= 1/3*pi*r2^2*h2= 1/3*pi*2*2*7

Let number of cones can be filled = n

Then,n*V2 = V1n = pi*35/2*35/2*32 / 1/3*pi*2*2*7 = 3*5*35*2 = 30*35 = 1050

Therefore, Number of cones can be filled = 1050

Number of cones = 126

what does n mean

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Rational numbers= √2+√3/2

if d/dx=0 then value of x is minimumso 2/3 x^2-4x+5=02x^2-12x+15=0so x=(12+root(144-120)/4 or (12-root(144-120)/4

so for x=3+root(6)/2 or x=3-root(6)/2 average cost is minimum.

IF U WANT THE LEAST U WILL TAKE HCF ,

hcf of the numbers

42 , 49 , 63 will be = 7

one plank will be = 7m

plank a = 42m/7m = 6

plank b = 49m/7m = 7

plank c = 63m/7m = 9

total number of planks will be 6 + 7 + 9 = 22

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