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254FincenExample 6 : Find the area of the shaded design in Fig. 12.17, where ABCD is a 2squarediameter. (Use Ď 3.14)of side 10 cm and semicircles are drawn with each side of the square asIV10 cm |
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Answer» LetUnshaded regions be I, II, III and IVArea of I + Area of III= Area of ABCD – Areas of two semicircles = ( 10X10 - 2X1/2 X 3.14 X 5 X5) = (100 - 3.14 * 25) =21.5 cm² similarly Area of II and IV is equal to 21.5cm² So,Area of shaded region= 100 - (21.5 + 21.5) = 57cm² |
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