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1/3x^3-2x^2 +5x Find the output at which average variable cost is minimum. |
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Answer» if d/dx=0 then value of x is minimumso 2/3 x^2-4x+5=02x^2-12x+15=0so x=(12+root(144-120)/4 or (12-root(144-120)/4 so for x=3+root(6)/2 or x=3-root(6)/2 average cost is minimum. |
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