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This section includes 7 InterviewSolutions, each offering curated multiple-choice questions to sharpen your Current Affairs knowledge and support exam preparation. Choose a topic below to get started.
| 1. |
A vessel is in the form of a hollow hemisphere mounted by a holloweylinder The diameter of the hemisphere is 14 cm and the totalheight of the vessel is 13 cm.Find the inner surface area of the vessel.1. |
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| 2. |
duyhówmuch?ouse (herbarium) is made entirely of glass paneside and 25 cm high.uA small indoor greenhouseId together with tape. It s0 em long5(includingbase) heldWhat is the area of the glass?es0 How much of tape is needed for all the 12 edges? |
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| 3. |
Find the area of a circle whose diameter is(1) 28 cm. (1) 1.4 m. |
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Answer» find the area of the dining table whose diameter is 105cm |
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| 4. |
dxQ. 13. (A) Evaluate-1- cos x |
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Answer» Explanation: ∫1/1+cosxdx=∫1−cosx(1+cosx)(1−cosx)dx =∫1−cosx1−cos2xdx =∫1−cosxsin2xdx =∫1sin2xdx−∫cosxsin2xdx =∫csc2xdx−∫cotxcscxdx =−cotx+cscx+C |
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| 5. |
CIUIL.39.The perimeter of a rectangle is 28 cm whose area is 48 sq.cm. then find its measures. |
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Answer» Let length of Reactangle = lLet breadth of Reactangle = b Perimeter of Reactangle= 2(length + breadth) 28 = 2(l + b)l + b = 14........ (1) Area of Reactangle= length * breadth l*b = 48b = 48/l...........(2) Put value of B from eq(2) in eq(1)l + 48/l = 14l^2 + 48 = 14ll^2 - 14l + 48 = 0l^2 - 8l - 6l + 48 = 0l(l - 8) - 6(l - 8) = 0(l - 6)(l - 8) = 0l = 6, 8 Therefore, If length = 6 cm, breadth = 8 cmIf length = 8 cm, breadth = 6 cm |
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| 6. |
Find the volume, area of the curved surface andthe total surface area of a cylinderwhose height and radius of base are 20 cm and 28 cm respectively |
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Answer» thank you |
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| 7. |
( 11 )52-15° के कोण की रचना कीजिए।Construct the angle of 15°. |
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Answer» first make 60 degree, then bisect the angle of 60 degree that is 30 degree and then again bisect the angle of 30 degree, thenit would be 15 degree. Steps to construct a 15° angle:-1. Draw a straight line.2. Draw an arc.3. Construct 60° angle.4. Bisect 60° to get 30° angle.5. Bisect 30° to get 15° angle. |
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| 8. |
c-H. Find the area of a rhombus, the lengths of whose diagonals are(0) 16 cm and 28 cm.(1l) 8 dm 5 cm and 5 dm 6 em |
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| 9. |
dydx+Py-Q, where P and Q are functions of r only. |
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| 10. |
Q. Find dy, ifdxy tan (x+ y) |
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| 11. |
ने लिखा जाता है।49. 10 से० मी० भुजा वाले दो ठोस घनों को साथ-साथरखने पर प्राप्त घनाभ का आयतन क्या है?(A) 500 घन से० मी०(B) 2000 घन से० मी०(C) 1000 घन से० मी०(D) 10000 घन से० मी० |
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Answer» 500 ghan yes the answers is 500 cm |
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| 12. |
1000 +2000 |
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Answer» 1000+2000= 3000 |
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| 13. |
दावा ७७ £* ४9 _ (ट+ फ6 (1. “टी 118 8§ STe DY wo T = S ५y wsisem फोर कप FEOrMN NWHFEFOISY FFywe (q(०७0७ %) |
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| 14. |
Q.4Ify = log (secx + tan x) then finddy= |
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| 15. |
t x'y(ty prove that dyx.y(x +y), prove thatp+qdx x |
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Answer» taking log of both sides plogx +qlogy = (p+q) log(x+y) differentiating w.r.t "x" p/x + (q/y)(dy/dx) = ((p +q)/(x+y)) (1 + dy/dx ) p/x - (p + q)/(x + y) = ((p+q)/(x + y) - q/y )dy/dx (py- qx)/x = ((py- qx)/y) dy/dx hence, dy/dx = y/x |
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| 16. |
Wer in each of gl to Q.1. A cuboid has(a) length onlylength, breadth and heightdice is an example of ab lengh and tradthdy thickness only |
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Answer» length,breadth and height |
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| 17. |
A -digit number a 72y is exactly divisible by 9, then least value of (x + y) is |
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| 18. |
.lfd is the HCF of 56 and 72, find x, y satisfying d = 56x + 72y. Also, show that x andy are1Snot unique. |
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Answer» BY APPLYING EUCLID's DIVISION LEMMA TO 56 AND 72 : 72 = 56 × 1 +16 ------------ (1) 56 = 16 × 3 + 8 ------------ (2) 16 = 8 × 2 + 0 -------------- (3) THEREFORE HCF OF 56 AND 72 = 8 FROM (2) -- 8 = 56 - 16 ×3 8 = 56 - (72-56×1) ×3 (from 1)8 = 56 - 3 × 72 + 56 × 3 8 = 56 × 4 + (-3) × 72 therefore , x = 4 and y = -3 Now, 8 = 56 × 4 + (-3) × 72 8 = 56 × 4 + (-3) × 72 - 56 × 72 + 56 × 72 8 = 56 × 4 -56 × 72 + (-3) × 72 + 56 ×72 8 = 56 × (4-72) + {(-3) + 56} × 72 8 = 56 × (-68) + (53) × 72 therefore x = -68 and y = 53 |
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| 19. |
17. If d is the HCF of 56 and 72, find x, y satisfying d= 56x + 72y. Also, show that x and y are notunique |
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| 20. |
e-Techno Text Book17, The equation of the line where x-intercept is -5/7 and which is parallel to3x+4y-7-01) 28x+21y+15-031 21x-28y+15-0Ji 21x+28y+15-o4) 28x-21y+15-0 |
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Answer» Given equation, 3x+4y-7=0Slope =-3/4 For parallel line, slope must be -3/4 of that line. Let equation is y=mx+cm=-3/4x intercept=-5/7Therefore, when y=0mx=-c(-3/4)(-5/7)=-c-15/28=c Equation is y=(-3/4)x-15/2828y=-3*7x-1521x+28y+15=0 Option b is correct |
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| 21. |
A line cutting off intercept -3 from the y-axis and the tengent aaxis is , its equation is(A) 5y 3x +15 0angle to the3(B) 3y-5x + 15-0(D) of these(C) Sy 3x - 15 0 |
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Answer» equation of line in slope form Y = mx + c here m = slope = tan∅ = 3/5 , and intercept is c = -3 so equation is y = 3x/5 -3 => 5y-3x+15 = 0 option A. |
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| 22. |
6The graph shows the payment of a car loan.-900-700-500 300 299 100 500 500 7009001400100160020002400200032001Which equation shows the relationship between x, the number of months and y, theamount still owed on the loan? (7.7A, RS, RC2)F y = 400x + 1,200G y = 400x - 1,200Hy = -400x + 1,200J y = -400x - 1,200Not For Duplication©2017 GF Educators7th Grade Math Power Review |
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| 23. |
62. 2x_ky +7-06x-12y +15=0 |
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| 24. |
50010001000200050010002000100010001000 |
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Answer» 5000 will be it's answer |
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| 25. |
4.AすB砌丏マ arH 2000五言1 A 95%で(a) 750歹.(c) 1 500(b) 1250.(d) 1600 |
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| 26. |
18. 500 men took dip in a tank which is 80 m long, 50 m broad. What is the rise in water level if the averagedisplacement of water by a man is 4 m3?[Hint. Volume of water displaced by 500 men (4 x 500) 2000 m3Area of the tank = 80 Ă 50 = 4000 m2. Let the rise in the level of water = h metres. Then 4000 x h-20001 |
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Answer» Volume of water displaced by 500 men = 4*500 = 2000 cubic metres. Area of the tank = 80*50 = 4000 sq metres. Let the rise in water level be h metres. Then, 4000*h = 2000=> h = 2000/4000=> h= 0.5 metres. |
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| 27. |
4. Find the angle which is equalind the angle which is erusal tovits suppfement6. In the given figure. /1 and △angles.If 41in 42 so that both the angles stiltsupplementary.ld take placeremainis decreased, what changes shoustillaTeIrmentary if botth of them |
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Answer» 5)let angle be xthen its supplement =180-xx=180-x2x=180x=180/2=90 |
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| 28. |
Q13. The following data relates to the expenditure of the families A and B per monthItem of ExpenditureFamily AFamily BFood40004536Rent500532Clothing800868Education200023801260504Miscellaneous1260Saving500Represent the expenditure of the families A and B by Pie Chart. |
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Answer» this is the pie chart question not answered by text... yes it is geometey quetion.... |
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| 29. |
All inear pairs of angles are supplementaryangles but all supplementary angles are notlinear pair of angles. Give reasons |
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| 30. |
Among how many CleThere are 91 buttons in a box. If 1 shirt requires 7 buttons, howmany shirts can be fixed with the buttons from the box? Howmany buttons will still remain in the box? |
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| 31. |
Chalk contains calcium, carbon and oxygen in the ratio 10:3:12. Find the pof carbon in chalk |
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Answer» Percentage of carbon = 3/10+3+12×100%=3/25×100%=12%(ans) ohhyrufydjfdxjo if iffy 8o |
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| 32. |
8. Calculate the area of the designed region in figure, commenbetween the two quadrants of the circles of radius 10 om eah(use π 3.14)in figure,0m. |
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| 33. |
How many angles measures can be seen in the picture ?(1) 4(2) 6(3) 8(4) 10 |
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| 34. |
4. A conical tent with base radius 7 m and height 24 m is made from 5 m wide canvas. Find thelength of the canvas used.| Ď7 |
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Answer» l2=242+72 l2=576+49 l2=625 l=25 22/7*7*25=length*width 22*25=length*5 550/5=length 110m=length |
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| 35. |
Find the area of canvas required for a conical tent of height 24 m andbase radius 7 m. |
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| 36. |
lfas-az-as,a1 +a2ヶa3 +……ー+a23 +a24-6are in AP, such that ai + as + a10 + as + a20 + a2.-225, thena) 909b) 75c) 750d) 900 |
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| 37. |
5. A field is in the form of a trapezium. Its area is 1586 m2 and the distance between itsparallel sides is 26 m. If one of the parallel sides is tm f |
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| 38. |
Solve eah For Aoces 2 A = 1. |
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| 39. |
Find the ares of the iron sheet required to prepare a cone 24 em high with base radius 7 em |
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| 40. |
A joker's cap is in the form of a right circular cone of base radius 7 cm and height24 cm. Find the area of the sheet required to make 10 such caps7. |
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| 41. |
7. A joker's cap is in the form of a right circular cone of base radius 7 cm and heigh24 om. Find the area of the sheet required to make 10 such caps |
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| 42. |
5. In Fig.9.33, ABC and BDE are two equilateraltriangles such that D is the mid-point of BC. IfAEintersects BC at F, show that(i)ar(BDE)--ar(ABC)4Gi) ar (BDE)-ar(BAE)(Gii) ar (ABC)-2 ar (BEC)(iv) ar (BFE)- ar (AFD)(v) ar (BFE)-2 ar (FED)Fig. 9.33(vi) ar (FEDar (AFC |
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| 43. |
Fig. 9.325. In Fig.9.33, ABC and BDE are two equilateraltriangles such that D is the mid-point of BC. IfAEintersects BC at F, show that0 ar(BDE)ar (ABC)4(i) ar(BDE)--ar(BAE)(ii) ar (ABC)-2 ar (BEC)(iv) ar (BFE)- ar (AFD)(v) ar (BFE)-2 ar (FED)Fig. 9.33(v)ar(FED)- ar(AFC: Join EC and AD. Show that BE |IAC and DE AB, ete] |
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| 44. |
A.o) ar (APB)+ ar (PCD)ar (ABCD)2lug 9.16(ii)ar (APD)tar (PBC)-ar (APB) + ar (PCD) |
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Answer» draw linesupport parallel to AD and AB. |
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| 45. |
20 tmHOTS kABC 0Çsatra ezi nim whiBCAB12on Find the area ofDC 20 cm, AD-15 cm and BC s l 2 cm. Find the area ofrapezium.,15c1S cm29 en 4LEARNWELLTMATHEMATCS-Mi278 |
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| 46. |
り17/L mean «r 13.cbservutisns is ly tif.thea of firstt observations s 12 and thatct last tien et sex varionsshservarien isis16, tanTH212 ) 13)1y)15 |
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Answer» mean of 13 elements is 14so addition of 13 elements =14*13=182mean of first 7 elements is 12so addition of first 7 elements =12*7=84mean of last 7 elements is 16so addition of last 7 elements =16*7=112now if we add first and last 7 elements 7th element is repeatedso by subtracting addition of 13 elements from first and last 7 elements addition we will get 7th elememt84+112-182=14 |
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| 47. |
Fig. 9.31. In Fig.9.33, ABC and BDE are two equilateralFig. 9.32triangles such that D is the mid-point of BC. If AEintersects BC at F, show thato(BDE)^ ar (ABC)1) ar4avi)ar (BDE)ar (BAE)F/Drectr(ii) ar (ABC) 2 ar (BEC)(iv) ar (BFE) ar (AFD)(v) ar (BFE) 2 ar (FED)Fig. 9.33(vi) ar (FED)ar (AFC)int: Join EC andAD. Show that BEII AC and DE IAB, etc.] |
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| 48. |
Express coch number inthe tmeah nuf) 15-ti 9 |
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| 49. |
17. In the figure, h I| l2 and ai || a2. Find the value ofx.'1itct4- 15 |
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Answer» Please hit the like button if this helped you |
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| 50. |
203ark. One of its side walls has been painted in some colour wtha sirdeapark. One of its side walls ha"KEEP15 m, 11 m and 6 m, find the area painted in colourTHEPARK GREENANDCLEAN (see Fig, 12.10) If the sides of theTm:KEEP THE PARKGREENAND CLEAN15 m |
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