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t x'y(ty prove that dyx.y(x +y), prove thatp+qdx x |
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Answer» taking log of both sides plogx +qlogy = (p+q) log(x+y) differentiating w.r.t "x" p/x + (q/y)(dy/dx) = ((p +q)/(x+y)) (1 + dy/dx ) p/x - (p + q)/(x + y) = ((p+q)/(x + y) - q/y )dy/dx (py- qx)/x = ((py- qx)/y) dy/dx hence, dy/dx = y/x |
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