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Fig. 9.325. In Fig.9.33, ABC and BDE are two equilateraltriangles such that D is the mid-point of BC. IfAEintersects BC at F, show that0 ar(BDE)ar (ABC)4(i) ar(BDE)--ar(BAE)(ii) ar (ABC)-2 ar (BEC)(iv) ar (BFE)- ar (AFD)(v) ar (BFE)-2 ar (FED)Fig. 9.33(v)ar(FED)- ar(AFC: Join EC and AD. Show that BE |IAC and DE AB, ete] |
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