This section includes 7 InterviewSolutions, each offering curated multiple-choice questions to sharpen your Current Affairs knowledge and support exam preparation. Choose a topic below to get started.
| 1. |
Evaluate the following:i) Ń35 ii) i888 iii) i93 iv) i116403vii) 888V1) 58Vilviii) i0ii5060 |
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| 2. |
Show that any ring can be embeddedinto a ring with unity |
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| 3. |
4. (i) 2xy-52 + 39 में से xy + 2-3 को घटाइए। |
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Answer» 2xy-5z+3y^2+xy+z-3=3xy-4z+3y^2-3 2xy-5z+3y^2+xy+z-3=3xy-4z+3y^2-3 |
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| 4. |
The L.C.M. of two numbers is 12 times theirH.C.F. The sum of H.C.F. and L.C.M. is 403.If one number is 93, then the other is |
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Answer» Tq |
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| 5. |
ttice .iar · 272ollog SD4240806 |01|-| -| -|-1。1 | οι los39 |
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Answer» tabular form of data. properly displayed |
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| 6. |
. Find0the lateral or curved surface area of a closed cylindrical petrol storage tank that is4.2 m in diameter and 4.5 m high.how much steel was actually used, if豆ofthe steel actually-ised was wasted inmaking the tank.(i)12 |
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| 7. |
Find(i)(ii)9.the lateral or curved surface area of a closed cylindrical petrol storage tank that is4.2 m in diameter and 4.5 m high.how much steel was actually used, ifmaking the tank.ofthe steel actually used was wasted in12 |
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| 8. |
. Find0 the lateral or curved surface area of a closed cylindrical petrol storage tank that is4.2 m in diameter and 4.5 m high.ø) how much steel was actually used, if 12 of the steel actually used was wasted inmaking the tank |
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| 9. |
The radii of circular ends oits curved surface.f a bucket of height 24 cm are 15 cm and 5 cm. Find the area |
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| 10. |
The radi of circular ends of a bucket of height 24 cm are 15 cm and 5 cm Find the area ofits curved surface |
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| 11. |
The radii of circular ends of a bucket of height 24 cm are 15 cm and 5 cm. Find the area of its curved surface. |
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| 12. |
The radii of circular ends of a bucket of height 24 cm are 15 cm and 5 cm. Find the area ofits curved surface. |
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Answer» Radius of top of the bucket ( R ) = 15 cm. Radius of bottom of the bucket ( r ) = 5 cm. And Height of the bucket ( H ) = 24 cm. Therefore, Slant Height ( L ) = √ ( H )² + ( R - r )² => ✓ ( 24)² + ( 15 - 5 )² => √576 + (10)² => √ 576 + 100 => √676 => 26 cm. • Curved Surface area of bucket = πL ( R + r ) cm². => 22/7 × 26 ( 15 + 5 ) cm². => ( 22 × 26 ) × 20 / 7 cm². => ( 22 × 26 × 20 ) / 7 cm². => 1634.28 cm². |
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| 13. |
The dimensions of a cuboid are 44 cm, 21 cm and 12 cm. It is melted and a cone ofheight 24 cm is made. Find the radius of its base. |
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| 14. |
29. The radi of circular ends of a bucket of height 24 cm are 15 cm and 5 cm. Find thearea of 4its curved surface. |
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Answer» Radius of top of the bucket ( R ) = 15 cm. Radius of bottom of the bucket ( r ) = 5 cm. And Height of the bucket ( H ) = 24 cm. Therefore, Slant Height ( L ) = √ ( H )² + ( R - r )² => ✓ ( 24)² + ( 15 - 5 )² => √576 + (10)² => √ 576 + 100 => √676 => 26 cm. • Curved Surface area of bucket = πL ( R + r ) cm². => 22/7 × 26 ( 15 + 5 ) cm². => ( 22 × 26 ) × 20 / 7 cm². => ( 22 × 26 × 20 ) / 7 cm². => 1634.28 cm². |
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| 15. |
(2) The dimensions of a cuboid are 44 cm, 21 cm and 12 cm. It is melted and a cone ofheight 24 cm is made. Find the radius of its base |
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Answer» We know, volume of a cuboid = l×b×hvolume = 44×21×12 = 11,088 cm³ Now, volume of cone = 1/3(πr²h) 11,088 = 1/3(π×r×r×24)11,088 = πr²×8πr²= 1386r² = (1386×7)/22r² = 441r = 21 cm Therefore, radius of its base is 21cm. |
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| 16. |
Between I and 1.60, natural mumbers divisible by 33,6, 9,...., 159t(n-1)× |
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Answer» a=3d=6-3=9-6=3Tn=a+(n-1)d159=3+(n-1)*3156=(n-1)*3n-1=52n=53 |
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| 17. |
Factorize 403 +855 C |
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| 18. |
22th 29 5201 39 + |
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| 19. |
Fatthe sum of the odd mumbers between 0 and 5a |
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| 20. |
5. Find two rational mumbers between 3 and 4,6. If (2r-3) is a factor of 2r15x 15k, find the v |
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Answer» two rational numbers between 3 and 43.5,3.6 |
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| 21. |
1 2का डे ८८2 b 5 e foh - s |
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| 22. |
Gहु) 2o Y& e eQ “पक ष बता [AL N |
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Answer» 4 rupee= 400 paise= 80/400= 8/40= 1/51:5 |
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| 23. |
hoo parts |
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Answer» Length = 6.4 cmRatio is 5:3So length will be 4 and 2.4. |
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| 24. |
Hoo wexe the anisiams abtected by Hr Revt 185 |
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Answer» Industrial Revolution in England and the economic policy of the East India Company jointly closed the markets for Indian handicrafts. In England machines went for large scale productions and those machine products were cheap and colorful. Not only markets but also the British Government as well as manufacturers encouraged the supply of their machine products to European markets. As a result, the British machine-products entered into unfair competition with Indian products. Handicrafts of India could not sustain the pressure of the competition with cheaper machine goods. Thus, those were driven out of European markets. Further, the British trade policy proved extremely fatal for Indian handicrafts. In 1813, trade monopoly was abolished and one way free trade policy was imposed on India. By this policy the British machine products were imported to India freely and the export of Indian goods to England was discouraged by imposition of heavy duties on those products. The Industrial Revolution closed foreign markets for Indian goods and British trade policy closed domestic market for Indian products. Once the markets were closed demand for Indian products declined suddenly and production stopped. It resulted in making the artisans and craftsman jobless and handicraft industries were closed down. |
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| 25. |
2/ The cost et hoo rally and hou, choinuchaischai |
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| 26. |
\frac { 3 x + 3 } { 4 } + 3 = 3 |
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Answer» 3xane 3x no sarvalo kari nakh pachi 6 na ched ma 4 ched udadi |
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| 27. |
\frac{(3)^{-2} \times(3)^{4}}{(3)^{3}} |
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| 28. |
Arrange the following in descending order2/9, 2/3, 8/21 |
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Answer» 9)2(0.2 0 20 18 3)2(0.6 0 20 18 21)8(0.3 0 80 633|2, 21|8 ,9|2 2/9=0.222/3=0.678/21=0.38so in descending order 2/3,8/21,2/9 |
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| 29. |
DATE: 20PAGE Nothe Sum ol thed iothoo digh |
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| 30. |
How many uoo dioitmany Hoo dmumbers ae devisib le3 |
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| 31. |
EXERCISE 8.2しABCD is a quadrilateral in which P, Q, R and S aremid-points of the sides AB, BC, CD and DA(see Fig 8.29).AC is a diagonal. Show that:SR[AC and SR =_AC(i)m) PQRS is a parallelogram.PQ=SR |
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| 32. |
Arrange the following in descending order:54796203,4675238,63240613,5125648,589623 |
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Answer» 63240613>54796203>5125648>4675238>58962 I already solved ir |
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| 33. |
descending order.4 3 3,3' 7 9 |
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Answer» thanks |
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| 34. |
arrange the descending order 5032786, 23794206, 5032790, 23756819, 987876 |
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| 35. |
arrange in descending order3/4,11/8,9/16,33/16 |
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Answer» 3/4=0.75 11/8=1.37 9/16=0.5625 33/16=2.0625so in descending order33/16,11/8,3/4,9/16 |
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| 36. |
Q6. Arrange the following in descending order-4+-3 |
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| 37. |
UPSblem of sudifference in twThus, on the first daEXERCISE 6.2ind:17.5 +4.216.105 10.12nd:0.6 - 0.1412.35 - 2.52.147 - 1.0110.129 1.7nplify: |
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| 38. |
and find the area of the triangle tomed by these les au23. When the son will be as old as his father today, the sum of their ages then will be 126When the father was as old as his son today. sum of their ages was 38.Find their present ages. |
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Answer» Let son 's current age is x andfather 's current age is y. Where does the(y-x) term come from? Well, it says 'when the son will be as old as the father is today, which means that the son has to age a certain amount of years. How many years does he have to age? The difference between his current age and his father 's current age. For example, if the son was 10 and the father was 40, it would take the son 30 years (or y-x = 40-10) to reach his current age. In the meantime, the father would age the same amount (y - x = 40 - 10 = 30 years). [Father 's new age] + [Son 's new age] = 126 [y+(y-x)] + [(x + (y-x))] = 126 ⇒2y - x + y = 126 ∴3y - x = 126 ----------(1) [Father 's previous age] + [Son 's previous age] = 38 ⇒[y - (y-x)] + [x - (y-x)] = 38 ⇒x + x - y + x = 38 ⇒3x - y = 38 ∴y = 3x - 38 -----------(2) Now sub equ(2) into equation 1 ⇒3(3x-38) - x = 126 ⇒9x - 114 - x = 126 ⇒8x = 240 ∴x = 30 Nowy = 3x - 38 ⇒y = 3(30) - 38 ∴y = 52 The son is 30 years old, and the father is 52 years old. Letthepresentageofson=xandpresentageoffather=yNow,differenceintheirages=(y−x)yrsAccordingtofirstcondition,[x(y−x)]+[y(y−x)]=126⇒3y−x=126....(1)Accordingtosecondcondition,[y+(x−y)]+[x+(x−y)]=38⇒−y+3x=38....(2)multiply(2)by3,weget−3y+9x=114....(3)Adding(1)and(3),weget8x=240⇒x=30Now,from(1),wegety=52So,presentageoffather=52yrspresentageofson=30yrs |
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| 39. |
o hibers rbyJnd three consecutive positive integers such that the sum of the square of toduct of the other two is 154.um of their reciprocals is. Find the numl |
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| 40. |
Breedth of the rectangleLeagth of the rectangle- 12 m2 12-8-16mWrite the information given in the picture in the form of anfollowing figure.Also, findinthe15 cmWrite the information given infollowing figure. k13 cmfwe add 7 to twice a number, we get 49. Find the numberf we subtract 22 from three times a number, we get 68. Find the number.ind a number which when multiplied by 7 and then reduced by 3 is equal to 53.um of two numbers is 95. Ifone exceeds the other by 3, find the numbers.um of three consecutive integers is 24. Find the integers.nd the length and breadth of the rectangle given below if its perimeter is 72m.5x +4x-4gth of a rectangle exceeds its breadth by 4 m. If the perimeter of the rectar, find its length and breadth.SALE-2016 |
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Answer» 7 5 length of a rectangle exceeds its breadth by 5 cm if the perimeter of the rectangle is 90 metre find its length and breadth |
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| 41. |
nd. ry ind the voui of |
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Answer» (2x+3y)^2=644x^2+9y^2+12xy=644x^2+9y^2+24=64so 4x^2+9y^2=40 thnx |
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| 42. |
(g) 0.93×0.843. The cost of a pen is 25.35. Find the cost of 45 such pens.ヘ4. A car covers 40.5 km in one hour. How much distance will it cover5. 1 kg of rice costs75.50. What will be the cost of 4 kg of rice? |
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| 43. |
ind two consecutive multiple of 3 whose sum is 415. |
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Answer» Let the consecutive multiples of 3 be x and x+3respectively.then,x+(x+3)=4152x+3=4152x=415-32x=412x=412/2=206 so, the numbers are 206 and 209 respectively. Let the consecutive multiples of 3 be x and x+3respectively.then,x+(x+3)=4152x+3=4152x=415-32x=412x=412/2=206 so, the numbers are 206 and 209 respectively |
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| 44. |
Draw an angle of measure 70° with protractor. Bisect this angle using compasses and rul |
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| 45. |
ndind the middle term of the AP 6, 13, 20[CBSE 2015]216. |
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| 46. |
17. Fill in the blanks:(1) Two ltne segments are congruent if they have .(ii) Two angles are congruent if they have....lili) Two squares are congruent if they have....(iv) Two circles are congruent if they have.....(v) Two rectangles are congruent if they have.... .(vi) Two triangles are congruent if they have. |
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| 47. |
Draw a line segmentXY equal to 8 cm. Using compasses and ruler, constructperpendicular bisector. |
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| 48. |
Draw a line segment XY equal to 8 cm. Using compasses and ruler, construct perpendicular bisector. |
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| 49. |
raw aline parallel toJ. Draw a line, say AB, take a point Coutside it. Through C, draw a line paralletoline, say AB, take a point C outusng ruler and compasses only |
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| 50. |
(iv)jacenk fiquvemd the, macmiof Coch the4hree anies fot3Sumang les ata Pointoaline is 18o |
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Answer» as angles are in linear pair so sum of them is 180x+2x+3x= 1806x= 180x= 30therefore angles are, 30, 60, 90 |
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