1.

ind two consecutive multiple of 3 whose sum is 415.

Answer»

Let the consecutive multiples of 3 be x and x+3respectively.then,x+(x+3)=4152x+3=4152x=415-32x=412x=412/2=206

so, the numbers are 206 and 209 respectively.

Let the consecutive multiples of 3 be x and x+3respectively.then,x+(x+3)=4152x+3=4152x=415-32x=412x=412/2=206

so, the numbers are 206 and 209 respectively



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