29. The radi of circular ends of a bucket of height 24 cm are 15 cm an

1.	29. The radi of circular ends of a bucket of height 24 cm are 15 cm and 5 cm. Find thearea of 4its curved surface.
Answer» Radius of top of the bucket ( R ) = 15 cm. Radius of bottom of the bucket ( r ) = 5 cm. And Height of the bucket ( H ) = 24 cm. Therefore, Slant Height ( L ) = √ ( H )² + ( R - r )² => ✓ ( 24)² + ( 15 - 5 )² => √576 + (10)² => √ 576 + 100 => √676 => 26 cm. • Curved Surface area of bucket = πL ( R + r ) cm². => 22/7 × 26 ( 15 + 5 ) cm². => ( 22 × 26 ) × 20 / 7 cm². => ( 22 × 26 × 20 ) / 7 cm². => 1634.28 cm².

29. The radi of circular ends of a bucket of height 24 cm are 15 cm and 5 cm. Find thearea of 4its curved surface.

Answer»

Radius of top of the bucket ( R ) = 15 cm.

Radius of bottom of the bucket ( r ) = 5 cm.

And

Height of the bucket ( H ) = 24 cm.

Therefore,

Slant Height ( L ) = √ ( H )² + ( R - r )²

=> ✓ ( 24)² + ( 15 - 5 )²

=> √576 + (10)²

=> √ 576 + 100

=> √676

=> 26 cm.

• Curved Surface area of bucket = πL ( R + r ) cm².

=> 22/7 × 26 ( 15 + 5 ) cm².

=> ( 22 × 26 ) × 20 / 7 cm².

=> ( 22 × 26 × 20 ) / 7 cm².

=> 1634.28 cm².