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75/45=5/3 = The ratio of their Mark's are 5:3..

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ratio of the marks are 5/3is the best answer 🏆🏆🏆

ratio of the marks =5/3is the answer 🎯

ratio of marks =5/3is the correct answer 🏆🏆🏆

75/45=5/3=t8 ratio of their Mark,s are 5:3

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Ratio will be Madhavis marks / Radha's marks=75/45 =15×5/15×3=5/3. Therefore, the ratio is 5/3.

80% of X is 32080/100*X=320X=320*100/80=400marks

30 days = 30 × 24 = 720 hoursRatio = 720/36 = 20:1

50x + 25 (10-x) = 40 ( 10 )

50x + 250 - 25x = 400

50x-25x = 400 - 250

25x = 150

x = 150/6

x= 6

Use 6 litres of 50% acid and 4 litres of 25%

6 , because the no. on both extreme left and extreme right of table are same in others too.

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The ratio of length and width=5:2

And width =40m

Given

So 2 ratio=40m

1 ratio =40/2=20m

Then Length =20x5=100m

thanks bri

bro

Perimeter =2( length + breadth)

So length=(perimeter/2)-breadth

Length = 60/2-19 =11

Verandah area Av = 64 m^2Verandah width = 2 m

Let square room length = sThen, Area of room Ar= s*sArea of outer space including room Ao = (s + 4)*(s + 4)

Av = Ao - Av64 = (s + 4)*(s + 4) - s*s64 = 8s + 168s = 64 - 16s = 48/8s = 6

Area of room = 6*6 = 36 m^2

2 no because in integer every large in negative is less

-12 because number on right side is larger than number on left side

x(x+1)+8=(x+2)(x-2)x^2 + x + 8 = x^2 -4x+12=0

linear

x^3 + 8x^2 + 9x - 18

=x^3 - x^2 + 9x^2 - 9x + 18x - 18

=x^2(x - 1) + 9x(x - 1) + 18(x - 1)

= (x - 1)(x^2 + 9x + 18)

= (x - 1)(x^2 + 6x + 3x + 18)

= (x - 1)(x(x + 6) + 3(x + 6))

= (x - 1)(x + 3)(x + 6)

x²+8x+16x²+4x+4x+16x(x+4)+4(x+4)(x+4)(x+4)

X= -b +_ √ b^2 - 4ac ________________ 2aX= -8 +_√64-4(16) ______________ 2X= - 4(X+4)(X + 4)

(x+4)(x+4) is the best answer of the following

x×x+6×x+9 =×+×+×+9+6=×3+16

7xsq + 9 is the answer

X xX + 6X+9= X×X+3X + 3X +9. = X(X+3)+3(X+3) = (X+3)(X+3)

x^2+8x+3=0=(x)^2+2x×4+(4)^2-13=0(x+4)^2=13(x+4)=+-√13x= +√13-4x= -√13-4

x^2+8x+3=0; a=1 b=8, c=3; x=-b+-Vb^2-4ac/2a 8+-V64-4(1)(3)/2(1)= V64-12/2=V52/2=V26

correct answer isx = 9,-17

2x-y-4x+y=2-4-2x=-2so x=12-y=2 so y=0

we get graph intersect x axis at x = 1 and y = 0 which are solution of the equation

In mathematics, arational numberis anynumberthat can be expressed as the quotient or fraction p/q of two integers, a numerator p and a non-zero denominator q. Since q may be equal to 1, every integer is arational number

1/2 is a rational number (1 divided by 2, or the ratio of 1 to 2)• 0.75 is a rational number (3/4)• 1 is a rational number (1/1)• 2 is a rational number (2/1)• 2.12 is a rational number (212/100)• −6.6 is a rational number (−66/10)• etc

45.digari

2x + 3y = 11......(1)2x - 4y = - 24..... (2)

Subtract eq(2) from eq(1)7y = 35y = 35/7 = 5

Put value of y=5 in eq(1)2x + 3*5 = 112x = 11 - 152x = - 4x = - 4/2 = - 2

Value of x = - 2, y = 5

The pair of equation will have infinite number of solutions when they are coincident lines.

a-b=2a+b=-33a-b-2=7

2a=-1a=-1/2b=a-2=-1/2 -2=-5/2

X+2=13X=13-2X=11this is the correct answer.

X+2=13X=13-2 X=11This is the correct answer

x+2=13x=13-2x=11 is the correct answer

According to question, x+2=13So, x=11

X= 11 is the correct answer of the given question

x+2=13×=13-2.×=11.

x+2 =13 x=13-2 x=11

value of X will be 11

x+2=13 then x=13-2=11 is your answer

Given that:- x+12= 13 x= 13-12 x= 1

solution→ x + 12 = 13 x = 13 - 12 x = 1

given :- x+12 = 13 x. = 12 - 13 x. = 1 the answer is 1

perimeter of square= 4 × side perimeter of rectangle=2(l+b)area of parallelogram=h×barea of triangle=half×b×h

4× side is answer coming

first take out the LCM of20,48,7,24 and then add3+3+4+(-3)

100÷12+488.33+ 48=56.33 answer

100÷12=8.338.33+48=56.33

the answer of your question is 56.33

p^2-1/p is the correct answer

p^2-1/p is the correct answer

SP = CP + gain = CP + {(11/2)/100}*CP = (211/200)*CP = (211/200)*2500 =2637.5 Rs

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CosA-sinA+1/cosA+sinA-1

=(cosA-sinA+1)(cosA+sinA+1)/(cosA+sinA-1)(cosA+sinA+1)

=(cos²A-cosAsinA+cosA+cosAsinA-sin²A+sinA+cosA-sinA+1)/{(cosA+sinA)²-(1)²}

=(cos²A-sin²A+2cosA+1)/(cos²A+2cosAsinA+sin²A-1)

={cos²A+2cosA+(1-sin²A)}/(1+2cosAsinA-1) [∵, sin²A+cos²A=1]

=(cos²A+2cosA+cos²A)/2cosAsinA

=(2cos²A+2cosA)/2cosAsinA

=2cosA(cosA+1)/2cosAsinA

=(cosA+1)/sinA

=cosA/sinA+1/sinA

=cotA+cosecA

=cosecA+cotA (Proved)

Area of rectangle = L× B = 3×4 = 12 cm²

In ∆PAQ,tan30= 10/AP 1/√3 =10/ AP AP = 10√3 In ∆PBR,tan45=BP/8 BP=8 tan45 =8AB= AP+PB =10√3+8