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This section includes 7 InterviewSolutions, each offering curated multiple-choice questions to sharpen your Current Affairs knowledge and support exam preparation. Choose a topic below to get started.
| 1. |
\cot ^ 2 A ( \frac \sec A - 1 1 %2B \sin A ) %2B \sec ^ 2 A ( \frac \sin A - 1 1 %2B \sec A ) |
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Answer» Like if you find it useful |
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| 2. |
\operatorname { cos } 18 ^ { \circ } - \operatorname { sin } 18 ^ { \circ } = \sqrt { 2 } \operatorname { sin } 27 ^ { \circ } |
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| 3. |
- \operatorname { sin } 18 ^ { \circ } = \sqrt { 2 } \operatorname { sin } 27 ^ { \circ } |
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Answer» To prove that, cos 18 - sin 18 = root 2 sin 27, we can prove that (cos 18 - sin 18)/ root2 = sin27.=1/root 2*cos 18 - 1/root2 * sin 18=sin 45*cos18 - cos 45*sin18=sin(45-18)= sin27 |
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| 4. |
1/(-tan(theta) %2B sec(theta))=tan(theta) %2B sec(theta) |
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| 5. |
(tan(theta) %2B sec(theta))/(-tan(theta) %2B sec(theta))=((sin(theta) %2B 1)/cos(theta))^2 |
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| 6. |
-1/cos(A) %2B 1/(tan(A) %2B sec(A))=1/cos(A) - 1/(-tan(A) %2B sec(A)) |
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Answer» LHS: Consider 1/secA-tanA - 1/cosA Multiplying by secA + tanA in the numerator and denominator of first term, we get, secA + tanA/(secA +tanA)(secA - tanA) - 1/cosA = secA + tanA - secA (Since sec²A - tan²A = 1) = tanA Adding and subtracting secA, we get secA + tanA - secA = 1/cosA - (secA - tanA) Now multiplying and dividing (secA - tanA) by (secA + tanA), we get 1/cosA - (sec²A - tan²A)/(secA + tanA) = 1/ cosA - 1/secA + tanA = R.H.S Hence Proved |
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| 7. |
\frac { \operatorname { sin } ^ { 2 } 63 ^ { \circ } + \operatorname { sin } ^ { 2 } 27 ^ { \circ } } { \operatorname { cos } ^ { 2 } 17 ^ { \circ } + \operatorname { cos } ^ { 2 } 73 ^ { \circ } } |
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| 8. |
ten thousand. |
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Answer» 1lakh=10 ten thousand 1lakh = 10 ten thousand 1 lakh = 10 ten thousand Thankxx 1 lakh = 10 ten thousand |
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| 9. |
quation in Two VariablesLinear Equation In Tuvion Bank ('-1sides of a rectangle are given. The lengvi)in the figure, the sides of ainom. Find the length and breadth of the rectangle24 253x - y + 32x+y+22x+3y + 4di) The forewheel of a tractor makes 120 revolution |
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Answer» it will became a quadratic equation with highest power 2, solve it either by elimination, or substitution or factorising or Cramer's rule or by synthetic division or by any method u are confidential in |
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| 10. |
pitu(c) As a harmless(d) As a means of generating friendship(a) 25(c) 45(b) 3092-1-25 |
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| 11. |
2.Simplify each of the following expressions:\begin{array}{ll}{(3+\sqrt{3})(2+\sqrt{2})} & {\text { (in) }(3+\sqrt{3})(3-\sqrt{3})} \\ {(\sqrt{5}+\sqrt{2})^{2}} & {\text { (iv) }(\sqrt{5}-\sqrt{2})(\sqrt{5}+\sqrt{2})}\end{array} |
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| 12. |
N = \frac { \sqrt { \sqrt { 5 } + 2 } + \sqrt { \sqrt { 5 } - 2 } } { \sqrt { \sqrt { 5 } + 1 } } - \sqrt { 3 - 2 \sqrt { 2 } } |
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| 13. |
how 1 lakh = 10 ten thousand |
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Answer» ♧♧HERE IS YOUR ANSWER♧♧ 1 lakh = 100000 Now, 100000 ÷ 10000 = 10 So, 10 ten thousands make 1 lakh. ♧♧HOPE THIS HELPS YOU♧♧plz likethanks. 110000 right answer |
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| 14. |
[ \frac \operatorname sin ^ 2 22 ^ \circ %2B \operatorname sin ^ 2 68 ^ \circ \operatorname cos ^ 2 22 ^ \circ %2B \operatorname cos ^ 2 68 ^ \circ %2B \operatorname sin ^ 2 63 ^ \circ %2B \operatorname cos 63 ^ \circ \operatorname sin 27 ^ \circ ] |
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Answer» Like if you find it useful |
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| 15. |
68^circ %2B sec(68^circ) |
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| 16. |
(c) prove that cosec 220 cot 68sin2220 + sin 680+ cot 68 |
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| 17. |
Q. 1. [A] Choose the correct option:1. If 2x + 5 = 17, then value of x will be :(a) 6 (b) 12 () 16 (d) 22. |
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Answer» 2x+5=17 2x=17-5 2x=12 x=12÷2 x=6 2x + 5 = 172x = 17 – 5x = 12/2x = 6 Ans. Given:2x+5=172x=17-52x=12x=12/2=6 |
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| 18. |
डर और अर्धगोले का पृष्ठ क्षेत्रफल बराबर है। उनकेतनों का अनुपात है-A P LY |
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Answer» please like my answer if you find it useful option me nahi hai |
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| 19. |
A pair of equal angle of a rhombus has a measure of 30" less tharythe supplementary angle. Find the otherpair of equal angles of the rhombus? |
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Answer» When you know any 1 angle’s measure in a rhombus, you know all 4 angles’ measures. Opposite angles are congruent. And adjacent angles are supplementary - in other words any two adjacent angles sum to 180°. So if we have an angle that measures 60°, the other angles measure 120°, 60°, and 120°. Now, since the diagonals of a rhombus bisect the pairs of opposite angles, each 120° angle is cut into two 60° angles by the shorter diagonal, forming 2 equilateral triangles within the rhombus, each sharing that shorter diagonal as one of its sides. So the shared side/ diagonal of the rhombus must be the same length as the 4 sides of the rhombus. And since we know the length of the rhombus’s sides is 10 cm, we know that the shorter diagonal is 10 cm as well. |
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| 20. |
R ‘fl‘llया क्रमागत प्राकृत संख्याओं के वर्गों का योग 421 है । संख्यP . O 9 LY |
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| 21. |
Q. 4. Find the slope of the straight line3x-5y+1 7 = 0 and intercept cut on the Y-axis. |
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Answer» 3x-5y+17=0 Slope=5/3 Intercept on Y axis(x=0) -5y=-17y=17/5 thx but worng |
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| 22. |
65[44®) Lz )() s ge- थिसुई कहा कलह 5 - bfB howbl g ४ पथ 5 |
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Answer» In AP - 3, - 1/2, 2,......a = - 3 and d = - 1/2 + 3 = 5/2 nth term of an AP is given byan = a + (n-1)d Then,a13 = - 3 + 12*5/2 = - 3 + 6*5 = 27 (c) is correct option |
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| 23. |
evaluate:_ ( 17 power 0 + 18 power 0) (19 power 0 - 22 power 0) ( 22 power 0 plus(24)) |
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Answer» why answer is 0. middle term is (1-1) = 0 so total expression become zero why not 1 beause when power is 0 then 1 power |
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| 24. |
In the adjoining figure, I. mand n are parallel lines intersectedand 23.by a transversal p at X, Y and Z respectively. Find Z1, 22X60In the given figure, ABCD is a quadrilateral in whichZA= B = 2C = ZD = 90° |
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Answer» 1. 1202. 1203. 120 |
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| 25. |
5. In the adjoining figure, line p | line 7 || line q.Find 2 x with the help of the measures givenin the figure.30 |
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| 26. |
LyStepsp5*. In the adjoining figure, line p || line / || line q.Find Zr with the help of the measures given 1in the figure. |
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Answer» line p parallel to line i is not a make an angel 40 degree and line i paralle to line x is a stand on a angel 40 degree so line q parallel to i answer of x is 40degree because tsunami making alternate interior angles on parallel lines X=40 because they are alternate angles |
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| 27. |
3. Draw an angle equal to LAOB, given in the adjoining figure. |
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| 28. |
3. Draw an angle equal to AOB, given in the adjoining figure. |
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| 29. |
3. Draw an angle equal to <AOB, given in the adjoining figure. |
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| 30. |
Draw an angle equal to ZAOB, given in the adjoining figure.8 |
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| 31. |
\frac 5 44 \times \frac 33 35 \times \frac 2 3 |
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| 32. |
21. In Mathematies test given to 15 students, the following marks were obtained44, 38. s0. 48, 02 34. 43, 96,Find the mean and the median.5A. 98, 42, AS. S4, 62 |
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Answer» Marks in the ascending order 38 42 43 44 45 48 50 54 54 54 60 62 62 96 98 Mean = (38+42+43+44+45+48+50+54+54+54+60+62+62+96+98)/15 = 850/15 = 56.67 Madian = Middle element = 8th element = 54 |
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| 33. |
i-cost1-cost) -2 cosec2 θ |
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Answer» 1-costheta+1+costheta/1-cos^2theta2/sin^2theta2cosec^2theta |
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| 34. |
arenotedasgivenbelowa. A dice is thrown 100 times and the outcomes3186523Outcomie1491521Frequencynt random what is the probability of getting a (1) 3, (i) 6. fitl) 4. iv) 1? |
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| 35. |
A machine is sold for Rs 23000 at a loss ofFind the C.P. of the machine |
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| 36. |
A machine is marked at 5,000 and is sold at a discount of 10%. Find the sellingprice of the machine. |
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| 37. |
ремFANICY RIE Bl 19 i┬еig |
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Answer» Sin ( 31 x 180 / 3) = sin ( 31 x 60) = sin(1860) = sin(5x360 - 60) =sin60=√3/2 тнαикѕ |
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| 38. |
m Cosx-Cost2itm |
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Answer» after applying LH rule once |
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| 39. |
what is the menaning of helping |
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Answer» to give or provide what is necessary to accomplish a task or satisfy a need मदद करना |
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| 40. |
find the sum of the even number between 15 and 100 |
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Answer» an = a+(n-1)d98=52+(n-1)298-52=(n-1)2(n-1)=46÷2(n-1)=23n=24 Sn=n/2(a+l)s24=24/212(52+98)12(150)1800 |
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| 41. |
Find the value of Îť, if the mode of the following data is 20:15, 20, 25, 18, 13, 15, 25, 15, 18, 17, 20, 25, 20, Îť, 18.12. |
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Answer» Excluding Lambda, the frequency of 25, 15, 18 and 20 is 3. But the mode is 20. So, the frequency must be more than 3. Hence, Lambda must be 20. |
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| 42. |
6. A G.P. consists of an even number of terms. If the sum of all the terms is 3 times the sunof the odd terms, then find its common ratio. |
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Answer» 1 2 |
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| 43. |
i2 Find the value of Îť, if the mode of the following data is 2015, 20, 25, 18, 13, 15, 25, 15, 18, 17, 20, 25, 20, Îť, 18. |
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Answer» lambda has to be 20 for the mode to be 20. since 15, 25 also occur 3 times and 20 is also 3 times present so for mode 20 has to be present more number of times , lambda being 20 makes 20 occur 4 times thus. 20 is the answer |
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| 44. |
Find the value of Îť/ if the mode of the following data is 20 ;15, 20, 25, 18, 13, 15, 25, 15, 18, 17, 20, 25, 20, Îť, 18.12. |
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| 45. |
3.Collecting personalandinformationeffectively posing as another individual isknown as the crime of:(A) Spooling (B) Identity theft(C) Spoofing (D) Hacking |
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Answer» Hacking is right answer Spoiling is answer bddbd djsnnrjejfjxx. |
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| 46. |
the length and breadth of rectangular field are 40 m and 10 M effectively if the side of square is 20 m then find the ratio of their perimeter? |
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Answer» Perimeter of rectangle = 2(length + breadth) = 2(40+10) = 100m Perimeter of square = 4(one side) = 4*20m = 80m ratio = 100:80 = 5:4 If you find this answer helpful then like it. |
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| 47. |
105. Recommended value of effective length (!) of long R.C.C. column, ascompared to actual length (1), effectively held in position and restrainedagainst rotation in both ends is(A) 0.707(B) 0.801(C) 0.50 1(D) 0.657 |
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Answer» the answer is 0.65l..... 0.65 is the right answer.... 0.65 l is the right answer.... 0.65 is the right answer...... 0.65l is the right answer.... 0.65 is the right answer..... 0.65 l is the correct answer. ...... 0.65l is the chutiya answer...... the answer is 0.651.... |
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| 48. |
38, bay? qayfindtheH.C.F. |
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Answer» 3x^2 = 3*x*x6xy^2 = 2*3*x*y*y9xy = 3*3*x*y Therefore,HCF = 3*x = 3x |
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| 49. |
find the radian measures corresponding to following1. 25°2. -47°30'3. 240°4. 520° |
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| 50. |
xample 4 : From a point P on the ground the angle of elevation of the top of a 10mtall building is 30째. A flag is hoisted at the top of the building and the angle of elevationof the top of the flagstaff from P is 45째. Find the length of the flagstaff and thedistance of the building from the point P. (You may take 3 1.732) |
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Answer» Thanks dude |
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