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- \operatorname { sin } 18 ^ { \circ } = \sqrt { 2 } \operatorname { sin } 27 ^ { \circ } |
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Answer» To prove that, cos 18 - sin 18 = root 2 sin 27, we can prove that (cos 18 - sin 18)/ root2 = sin27.=1/root 2*cos 18 - 1/root2 * sin 18=sin 45*cos18 - cos 45*sin18=sin(45-18)= sin27 |
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