This section includes 7 InterviewSolutions, each offering curated multiple-choice questions to sharpen your Current Affairs knowledge and support exam preparation. Choose a topic below to get started.
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Example 4 : From a point P on the ground the angle of elevation of the top of a 10 mtall building is 30°. A flag is hoisted at the top of the building and the angle of elevationof the top of the flagstaff from P is 459. Find the length of the flagstaff and thedistance of the building from the point P. (You may take 3 1.732) |
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| 2. |
) Find the radian measures corresponding to the followidegree measures:i) 250i) 2400°iii) 5200°iv) 250°.4' |
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| 3. |
2. The total area of a page is 150 cm2. The combined width of the margin at the top and bottom is 3cm and the side 2 cm. What must be the dimensions of the page in orcer that the area of the printedmatter may be maximum? |
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| 4. |
DATEPAGEan bay(a) 29 |
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Answer» CP= 245SP= 200₹45 का लाभ होगाthanks cost price =245selling price=200loss=cp- sp =₹245-200 = ₹45 |
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| 5. |
what is conjunction |
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Answer» Those words who joined two sentences is called conjunction conjunction is a joining word which join the two or more word or sentences a word that is used for joining other words, phrases or sentences |
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| 6. |
what is a conjunction |
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Answer» Conjunction is a word used to connect clauses or sentences or to coordinate words in the same clause (e.g.and,but,if). tqq |
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| 7. |
Ive any2Prove that ;+1+cosĂ 1-cos |
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| 8. |
ive tIlC(i)5x+2=3x + 12 |
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Answer» 5x+2=3x+12 =5x-3x=12-2=2x=10=x=10/2=5 hence, answer is (x=5) |
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| 9. |
63°+ sin” 27°17° + cos® 73° |
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| 10. |
:- 470 30 =72the following radian measures lesson 7Find the degreFind the degree measures corresponding to the followingIllustration 7(ii) - 4=19 |
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Answer» (ii) -4 is the answer of first 1) 180/π×11/16 = 45×11×7/88 = 39°22'30'' (i). 11/16 is the answer |
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| 11. |
27. In Figure 17, determine the valuc of x.138°Fig. 17 |
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Answer» x+x=138 (vertically opposite angle)2x=138x=138/2x=69 |
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| 12. |
How many numbers of seven figures can be formed with the digits 1,2, 3, 4, 3, 2, 1, so that the odd digits always occupy the odd places ? |
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| 13. |
12) How many different numbers can be formedwith digits 1, 2. 3, 4. 3. 2. I, so that odd digitsalways occupy the odd places? |
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| 14. |
How many numbers of 8 digits can be formed with the digits4, 2, 2, 2, 3, 3, 5, 5 so that odd digits are always in oddplaces? |
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| 15. |
In how many ways can the letters of the word STRANGEbe arranged so that the vowels may appear in the odd places? |
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Answer» why you had multiple 4×3 in 3rd section for finding odd position |
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| 16. |
6. How many different words can be formed of the letters of the word MALENKOV so tu(i) no two vowels are together,/(ii) the vowels may occupy odd places? |
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| 17. |
In an A.P. of 99 terms, the sum of all theodd-numbered terms is 2550. Then find the sum of all the 99ILLUSTRATION 4.12terms of the A.P. |
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| 18. |
Find the roots of the followicompleting the square:2x^2 -7x+3 =0 |
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| 19. |
mplirty8+ 48 45-2717 Find the value of [1 +2+3+81 $218 Find the value ofx ifx (36)19.) Find the value ofx if (V3) 3'21-5/20.5 |
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Answer» Post questions one by one |
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| 20. |
EXAMPLE 28 If there are (2n +1) terms in A.P, then prove that the ratio of the sum of odd terms andthe sum of even terms is (n +1):n. |
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Answer» Let us consider n=1then we get (2n+1)= 2*1+1=3let us consider those 3 terms be 1,2,3sum of the odd terms 1+3=4sum of the even terrms =2Now the ratio of odd terms to even terms is 4:2=2:1which satisfy the condition (n+1):1=(1+1):1=2:1Hence proved |
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| 21. |
FINO THE VALUE OFX |
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Answer» sum of two interior angle =opposite exterior angle x + 60° = 130°x = 130°- 60° = 70° 130+c= 180c=50in abca+b+c=18060+x+50=180x=70 60+x=130(because sum of two interior angle =opposite exterior angle )60+x=130x=130-60x=70 x + 60 = 130x=130 - 60=70 60+x=130. angle sun propert. x=130 - 60 =70 70 ° is the correct answer of the given question the correct answer is 70° x=70 degree is the answer of this question |
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| 22. |
Find the value ofx in the given figure. |
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| 23. |
nd the value ofx |
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| 24. |
log Ď2)If =2 find the value ofx |
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Answer» logx/√7 = 2 log x = 2√7 x = e power (2√7) |
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| 25. |
Find the value ofx from the given figure. |
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Answer» as it is linear anglehencex-1+X+X+1=1803x=180X=60 thankyou |
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| 26. |
If| x-1-81, find the value ofx" +2 |
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| 27. |
ResonanceDAILY PRAGTICEPEducating for better tomorrowSESSION-2018-19Subject: MathematicsDPP No.1Class : vlWeek -3 (16-04-18 to 21-04-18)Instructions:Single choice objective (Q.1 to a.5)Subjective questions (Q.8 to Q.10)Which parts contain the fractions in ascending order ?Multiple choice objective (Q.6 & Q.7)1.19 11 16(C) 21'116 19 11(O) 15'21 1411 16 19(A) 14'19' 21fi and 7 he distinct integers, that are odd and positive. Which one of the following statement cannot be16 11 19(e)19 14 212 |
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Answer» To arrange fraction in ascending order thier denominator should be sameFor fractions 11/14,16/19,19/21Take LCM of 14, 19, 21 is 798Then 11x3x19/798, 16x6/799, 19x2x19/798627/798, 96/798, 722/798 Fraction ascending order16/19, 11/14, 19/21B is correct option integers how to arrange |
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| 28. |
Figure 15.20 B26. The adjoining figure 15.21 is made of the union of 4 triangles ACACI), ADE and AEF. How many right angles is the sum ofLABC+Figure 16.21 |
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| 29. |
iv)a*-(x-z)Factorise the followi0 p + 6p + 8 |
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Answer» Given: p^2+6p+8=0Sum=6 ; product=8numbers are: 4, 2p^2+4p+2p+8=0p(p+4) + 2(p+4)=0(p+4)(p+2)=0p=-4, -2 |
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| 30. |
17. If ι, β are the zeroes of the polynomial fli-ar' +bx+ c, then artb2+2acb2-2ac(Bb2 +acacDa |
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Answer» Option b is correct. |
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| 31. |
What makes different seasons occur? |
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Answer» The seasonsare caused bythetilt oftheEarth's rotational axis away or towardthesun as it travels through its year-long path aroundthesun. The Earth has a tilt of 23.5 degrees relative tothe"ecliptic plane" (theimaginary surface formed by it's almost-cicular path aroundthesun) |
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| 32. |
In the adjoining figure, find the value of x. |
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Answer» in triangle ABD 13²= 5²+ AD²( Pythagoras theorem)AD²169-25144= AD²AD = 12so in triangle ADC15² = 12²+ x²( Pythagoras theorem)225-144= x²81= x²x= 9cm |
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| 33. |
9. In the adjoining figure, ABCD is a quadrilateraland AC is one of its diagonals. Prove that:(i) AB BC+ CD+ DA>2AC(ii) AB BC+CD>DA(ii) AB+ BC+ CD + DA> AC+ BD |
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| 34. |
explain the area of irregular figures |
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Answer» To find thearea of irregular shapes, the first thing to do is to divide theirregular shapeinto regularshapesthat you can recognize such as triangles, rectangles, circles, squares and so forth... Then, find theareaof these individualshapesand add them up |
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| 35. |
QuadrilateralsIn the adjoining figure, ABCD is a quadrilateral Dand AC is one of its diagonals. Prove that(G) AB+ BC+ CD+DA 2AC(ii) AB + BC+ CD > DAii)AB+ BC+ CD+ DA> AC+BD. |
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| 36. |
Quadrilateralsfigure, ABCD is a quadrilateral D3i3ne of its diagonals. Prove thatis one of its diagonBC+ CDaAB + BC + CD + DA > 2AC) AB + BC + CD > DAR+BC+CD+ DAAC+ BD |
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| 37. |
How can we measure the volume of an irregular small object? |
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Answer» You can find thevolume of an irregular objectby immersing it in water in a beaker or other container withvolumemarkings, and by seeing how much the level goes up. |
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| 38. |
Find rif(i)5P,-26P,-1(ii)"P,=6P,-1 |
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Answer» Explanation : nPr = n!/(n-r)! i) 5Pr = 2*6P(r-1) 5!/(5-r)! = 2*6!/(6-r+1)! 5!/(5-r)! = 2*6×5!/(7-r)! 1/(5-r)! = 12/((7-r)(6-r)(5-r)!) (7-r)(6-r) = 4×3 r = 3 ii) 5Pr = 6P(r-1) 5!/(5-r)! = 6!/(6-r+1)! 5!/(5-r)! = 6×5!/(7-r)! 1/(5-r)! = 6/((7-r)(6-r)(5-r)!) (7-r)(6-r) = 3×2 r = 4 Answer : i) r = 3 ii) r = 4 If you find this answer helpful then like it thnq |
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| 39. |
(Begin with: No season)Winter is the best season. |
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Answer» No season is better than winter. m - m -1 / 2 = 1 - m -2 / 3 |
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| 40. |
Shivani made a gud patti in a round shape. She divided it into 5 parts. She ate one piece from it. IfMukund eat another piece, then how much would be left?9 |
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Answer» Thank you very much |
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| 41. |
7. A cricket team won 26 matches in a season.If they won 65% of the matches, how manymatches did they play in that season? |
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Answer» Let the total number of Matches played be x. They won 65% So 65/100x=26x=26×100/65x=2×100/5x=2×20x=40So they played 40 matches. |
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| 42. |
7. A cricket team won 26 matches in a season.If they won 65% of the matches, how manymatches did they play in that season?th 3000 |
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Answer» Let the total number of Matches played be x. They won 65% So 65/100x=26x=26×100/65x=2×100/5x=2×20x=40So they played 40 matches. |
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would they make?A group of 360 people were asked to votefor their favourite season from the threeseasons rainy, winter and summer0 Which season got the most votes?(a) Find the central angle of each sector(i) Draw a pie chart to show thisinformation |
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| 44. |
asu uyXudo спилило2The sum of the present ages of Ram and Sham is 45. Three years hence Ram will beTwice the age of Sham then. Find their present ages |
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Answer» thanks for the answer..... |
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| 45. |
The present age of a woman is 3 years more than three times the ageof her daughter. Three years hence, the woman's age will be 10 yearsmore than twice the age of her daughter. Find their present ages45. |
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| 46. |
Find the cost of 15.1 lkg of rice if cost of 1 kg rice is₹24.25. |
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Answer» 1 kg is of 24.25 so 15.1 kg are of 15.1×24.25 = 366.175 |
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| 47. |
Lata bays 17.5 kg of rice for936.25. Find the price of 1 kg of rice. |
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Answer» For 17.5 Kg cost is ₹936.25For 1 kg cost is ₹936.25/17.5 = ₹53.5 |
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| 48. |
If the cost of 5 kg of rice is = 206., then find the cost of 8 kg of rice. |
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Answer» cost of 11/2kgs of rice=825/4; cost of 1kg of rice=825/4×2/11==75/2; cost of 33/4kg of rice=75/2×38/4=2850/8=309 3/8 , the cost of 8(1/4) kg of rice=309 (3/8) 2475/8 is the correct answer of the given question |
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| 49. |
1. If the equal sides of an isosceles triangle areproduced, prove that the exterior angles soformed are obtuse and equal. |
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| 50. |
The time taken to drill a hole through a25mm thick plate with the drill rotating at300rpm and moving at a feed rate of0.25mm/rev is(a) 10 sec(c) 60sec(b) 20sec(d) 100sec |
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