This section includes 7 InterviewSolutions, each offering curated multiple-choice questions to sharpen your Current Affairs knowledge and support exam preparation. Choose a topic below to get started.
| 1. |
V 500 = ÂĽ (800 TVaRzovas oov el |
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| 2. |
augthesWhatishisscore?171 per kg and sent it to an orphanage. Findkg rice at the rate ofthe amount spent by Barkha. What value is being promoted?ght 2 |
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Answer» 1 kg = 17.520 3/8 can be written as 163/8163/8 of rice is purchased at a value of 356.56 |
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| 3. |
Using appropriate properties find. |
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| 4. |
I.Using appropriate properties find |
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| 5. |
EXERCISEUsing appropriate properties find |
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| 6. |
Using appropriate properties find.35 |
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| 7. |
1. Using appropriate properties find |
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| 8. |
(6)Write the lower and the uppper class limit of 35 to 40 |
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Answer» Lower limit is 35 and upper limit is 40 1 metre cube is equal to how many centimeter cube |
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| 9. |
1. Using appropriate properties find.+ |
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Answer» this is the NCERT book class 7 this is question very easy in fraction The right answer is 2 The right answer is 2 |
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| 10. |
32.M cosecB = 2, d θ =.(A) 00○ (B) 30°O (C) 45°○ (D) 60。 |
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| 11. |
3x+5y=7 if 3 time absicca = 4 time ordinate then find the value of y |
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Answer» etna hi ha answer |
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| 12. |
11. If a line is drawnparallel to the base of an isosceles triangle to intersect its equal sidesprovethat the quadrilateral so formed is cyclic |
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| 13. |
988-988 |
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Answer» 988-988= 0 is the answer |
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| 14. |
iil, a number divislble by 3.SECTION-Drax4-32 M]23 During a man drill exercises 6250 students of differentsehools are arrangoutuetionne numbor of students In each row is equal to the number of rows. In doing so, the instructionfinds out that 9 children arthee left out .Find the number of childran in each row of the square.24. Factories: |
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Answer» Let's assume the number of children in each row of the square is x Since, the number of students in each row is equal to the number of rows so, the number of children in each column of the square is x 6250 students of different schools But 9 children are left out so, total number of student in rows and columns =6250-9=6241 total number of student in rows and columns=(the number of children in each row of the square)*(the number of children in each column of the square) now, we can plug values 6421=x × xx^2=6421 now, we can solve for xx=√6421 =79 So, the number of children in each row of the square is 79...........Answer hit like if you find it useful |
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| 15. |
। ॥॥॥१॥ न १ प म ७ ५९ पन्हाकत ! | कजए।| 1, १ 988 की राशि पर 18% वार्षिक दर से 5 वर्ष के अन्त में कितना साधारण ब्याज अर्जित होगा।1771 16 |
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Answer» 1097.78 ayega option m h kya this answer is 888.2 ok this answer is true |
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| 16. |
Find the value of $\log \left(\frac{225}{32}\right)-\log \left(\frac{25}{81}\right)+\log \left(\frac{64}{729}\right)$ |
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| 17. |
26. Which one of the following numbers will occupyblank space?988+848. 2093. 15616972-1873= 15116=1246(A) 22WB) 18(C) 16 |
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Answer» 18 16 is the correct answer eighteen is the right answer 18 is the right answer.sum both c1 and c2 then again add c2. |
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| 18. |
A = \left[ \begin{array} { c c c } { 1 } & { - 1 } & { 0 } \\ { 2 } & { 3 } & { 4 } \\ { 0 } & { 1 } & { 2 } \end{array} \right] , B = \left[ \begin{array} { c c c } { 2 } & { 2 } & { - 4 } \\ { - 4 } & { 2 } & { - 4 } \\ { 2 } & { - 1 } & { 5 } \end{array} \right] |
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| 19. |
4sin-cosB+1& 30 ९ - ८०४४०...If4 tvm 0 = 3, evaluate 4sin®+cos0-1 ) |
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Answer» Let theta = A4tanA=3tanA = 3/4 = P/B In a ∆ ABC right angled at B.Base (AB) = 4 , Perpendicular( BC) = 3 AC² = AB² + BC²[By Pythagoras theorem]AC² = 4² + 3²AC² = 16 + 9 = 25AC= √25 = 5 The trigonometric ratios sin A = P/H = 3/5Cos A = B/H = 4/54sinA-cosA+1)/4sinA+cosA-1= (4×3/5 -4/5 +1) /(4×3/5 + 4/5 -1)= 12/5 - (4+5)/5 / 12/5 + (4 -5/5)= (12/5 +1/5) / (12/5 -1/5)= 13/5 / 11/5= 13/5 × 5/11 = 13/11 (4sinA-cosA+1)/(4sinA+cosA-1) = 13/11. |
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| 20. |
हर =5odY 16वy) €0 I १८ |
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| 21. |
(v If4 x 5 500, then the value of x* is |
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| 22. |
(6) For the class 21 to 30, write lower and upper class limit. |
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Answer» Lower limit will be 21and upper limit = 30 |
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| 23. |
In a continuous frequency distribution, classmark of a class is 85 and lower limit is 83,then find its upper limit. |
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Answer» upper limit + lower limit/2=class mark upper limit=2*classmark-lower limit ul=2*85-83 upper limit =87 |
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| 24. |
For class interval 20-25 write the lower class limit and the upper classli |
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Answer» The lower class is the smallest no. in the class which is 20 here and the upper class limit is 25 |
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| 25. |
what is the upper limit andthelower iimit of class interval 17 to 34 |
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Answer» class is from 17 to 24so lower limit is 17 and upper limit is 24. |
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| 26. |
Q31. In a frequency distribution, the mid value of a class is 10 and the width of theclass is 6. Find the lower and upper limit of the class. |
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| 27. |
2. Look at the table given below0-10 |20-3030-40MarksNo. of students87The true upper limit of the class 10-20 is |
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Answer» what is question about it |
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| 28. |
012.In ABCD, cyclic Quad diagonal intersect at Q. <DBC-70 and <CAB 30, so find -BCD) |
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Answer» In quadrilateral In aΔCDB andΔBAC, ∠ CDB = ∠ BAC = 30° ...(1) [ Angles in the same segment of a circle are equal ]∠ DBC = 70° ...(2) In Δ BCD, ∠ BCD + ∠ DBC + ∠ CDB = 180° [Sum of all the angles of a triangle is 180°]⇒ ∠ BCD + 70° + 30° = 180° [ from (1) and (2) ] ⇒ ∠ BCD +100° =180° ⇒ ∠ BCD =180° - 100° ⇒ ∠ BCD = 80° |
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| 29. |
A father's age is 4 times that of his elder son and 5 times that of his younger son. When the age of the elder son well exceed that of his younger son 4 years, find their present ages. |
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Answer» suppose the fathers age=xage of elder son is=(1/4)xage of younger is =(1/5)xaccording to questionthe age difference btwn younger and father is 32so x-(1/5)x=32x=40yearsso father is 40 yrs old |
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| 30. |
11, A mangave 25% ofthe amount of money with him to his eldest son, 20% to his880 to his wifeyounger son and 20% of the remainder to his daughter and the restind theamount of money he had with him and also find the ratio of the moneyreceived by his eldest son to his younger son and to his daughter. |
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Answer» Let the amount of money he had be Rs. x. Amount of money he gave to his eldest son=25% of Rs. x=Rs. (x/4) Amount of money he gave to his younger son=20% of Rs. x=Rs. (x/5) Amount of money left=Rs.{x-(x/4)-(x/5)}=Rs.(11/20)xAmount of money he gave to his daughter =20% of Rs. (11/20)x=Rs. (11x/100) Amount of money left=Rs.(11x/20)-Rs. (11x/100)=Rs. (11x/25) Amount of money left was given by him to his wife=Rs. 880 =>11x/25=880=>x=2000 :. He originally had Rs.2000. Now, amount of money received by his eldest son=Rs(x/4) =Rs. 500 amount of money received by his younger son=Rs(x/5) =Rs. 400 Amount of money he gave to his daughter =Rs. (11x/100)=Rs. 220 :. Ratio of the money received by his eldest son, younger son and daughter=500:400:220=25:20:11 |
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| 31. |
A man gave 25% of the amount of money with him to his eldest son, 20% to hisyounger son and 20% of the remainder to his daughter and the rest 880 to his wFind the amount of money he had with him and also find the ratio of the moneyreceived by his eldest son to his younger son and to his daughter. |
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Answer» Let the amount of money he had be Rs. x. Amount of money he gave to his eldest son=25% of Rs. x=Rs. (x/4) Amount of money he gave to his younger son=20% of Rs. x=Rs. (x/5) Amount of money left=Rs.{x-(x/4)-(x/5)}=Rs.(11/20)xAmount of money he gave to his daughter =20% of Rs. (11/20)x=Rs. (11x/100) Amount of money left=Rs.(11x/20)-Rs. (11x/100)=Rs. (11x/25) Amount of money left was given by him to his wife=Rs. 880 =>11x/25=880=>x=2000 :. He originally had Rs.2000. Now, amount of money received by his eldest son=Rs(x/4) =Rs. 500 amount of money received by his younger son=Rs(x/5) =Rs. 400 Amount of money he gave to his daughter =Rs. (11x/100)=Rs. 220 :. Ratio of the money received by his eldest son, younger son and daughter=500:400:220=25:20:11 |
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| 32. |
A man left 3200 of his property to his wife, 3000to his elder son, 28% to his younger son andthe rest to his daughter. If the daughter's share is5000, find |
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Answer» Let, Man's property be xthen he's wife property will be,32x / 100elder son property will be,30x / 100younger son property will be,28x / 100Now, If remaing property (say y) will be,32% + 30% + 28% + y = 100%90% + y = 100%y = 10%so, He's daughter's property will be,10% of x = 75,000x = 7,50,000so, The value of man's property will be, 7,50,000 |
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| 33. |
A man gave 35% of his money to his elder son and 40% of the remainder to his younger son. If heis left with23,400, find how much money did he haveoriginally. |
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| 34. |
he difference of ages between a girl and her younger sister is 4 years. The younger sister in turnars older than her brother. The sum of the ages of the younger sister and her brother is 16. Howe the three children? |
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| 35. |
6 Insert an irrational number between V5 and7 Insert two irrational numbers between 3 and V7 |
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Answer» Take the approximate values of root 5 and root 7 and find the irrational numbers between themRoot 5 = 2.23Root 7 = 2.642 values between them are2.333356282581......2.5815830267199..... tdgfxhdjhgfbhjhytffg ggyjjhdduj hffg |
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| 36. |
u ne liuiliel Ul each type ot coins.e difference of ages between a girl and her younger sister is 4 years. The younger sister in trs older than her brother. The sum of the ages of the younger sister and her brother is 16.Hethe three children ? |
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| 37. |
10 tex-coordinate of(CBSE 1992with the x-axis.)Find the points on the curve +=1 at which the tangents are]() parallel to x-axis (ii) parallel to y-axisINCERT)... dy 16 x dy -0.Hint: 10) = 0 = x=0, y = 14(CBSE 1992 |
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| 38. |
कोण का माप कितना है?(9) 31380. एक त्रिभुज के कोणों के माप 3 : 4:5 के अनुपात में हैं. इसमें सबसे बड़े कोण का माप(a) 50°(b) 75°(c) 90°(d) 120 |
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Answer» answer is a 50 b 75 c 90 d 120 =90° प्रश्न के अनुसार दिया गया है कि3x+4x+5x= 18012x= 180x= 180/12x= 15° सबसे बड़े कौन का माफ होगा= 15*5= 75°option- B the answer is the option is b option b is right 75° type Hindi mein Karke bhejen solution Hindi mein Karke bhejen एक ऋजु कोण का माप __ होता हैं |
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| 39. |
6045004002001989199019911992 1993a) do which you were few than 200 booksbald?1989 j) 1991 111).1993 U) 1992what will bedi terra el number of600 |
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Answer» ii &I've is the correct answer |
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| 40. |
CBSE 2005)-I71 (find)CBSE 1992)0 4 |
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| 41. |
11.8 Cyclic QuadrilateralsQ What Is meant by Cyclic Quadrilaterals? |
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Answer» A cyclic quadrilateral is any four-sided geometric figure whose vertices all lie on a circle. All rectangles are cyclic, but many other quadrilaterals are not. In a cyclic quadrilateral, the sum of each pair of opposite angles is 180 degrees. thanks sar |
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| 42. |
30180000/313 |
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Answer» 30180000/313=96421.725is the answer correct answer is 96,421.7252 please like and accept as best answer 30180000÷313÷96421.725 |
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| 43. |
1. Find the complement of each of the following angles:(1) 20°(ii) 45°(iii) 58°(v) 89°(vi) 5°(iv) 600 |
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Answer» subtract all from 90 to find its complement (1) 70(2) 45(3) 32(4) 30(5) 1(6) 85 1)70°2)45°3)32°4)30°5)1°6)95° we have subtract by 90 because it is complement a. 90-20= 70b. 90-45= 45c. 90-58= 32d. 90-60= 30e. 90-89= 1f. 90-5= 85 70°45°32°30°1°85° is the correct answer of the given question I) 70 degreesII) 45 degrees III) 32 degrees iv) 30 degrees v)1 degrees vi) 85 degrees subtract all angles by 90° one by one we get their solutions |
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| 44. |
SuumiConvert the following into Gradian oRadian1) 45 degreeGiven the angle is 45 degree |
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| 45. |
EXERCISE 1.11.Using appropriate properties find |
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| 46. |
EXERCISE 1.11. Using appropriate properties find.2 Write the additive veeofansh |
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| 47. |
Match the following:Column Aང་དུ་གསལ་བཀཀྱS2. Mahargjodhiraj3. PrashastisColumn B(a) Praising the kings(b) Subordinates(C) Kings of King |
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Answer» 1. Samantas - Subordinates 2. Maharajadhiraj - Kings of king 3. Prashastis - Praising the kings |
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| 48. |
Simplify \tan ^{-1}\left[\frac{a \cos x-b \sin x}{b \cos x+a \sin x}\right], \text { if } \frac{a}{b} \tan x>-1 |
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Answer» Awesome |
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| 49. |
- 6 )70 - 7.-9_ 16EXERCISE 1.11. Using appropriate properties find56Write the additive inverse of each of the |
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Answer» by associative property(-2/3*3/5)+5/2(3/5*1/6)-6/15+5/2-3/30-6/15-3/30+5/2-12-3/30+5/2-15/30+5/2-1/2+5/2=4/2 closure property |
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| 50. |
3535-6-1707-9EXERCISE 11. Using appropriate properties find.HW2 3 5 3 1352562. Write the additive inverse of each-53. Verify that - - x)=x for. |
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