Explore topic-wise InterviewSolutions in Current Affairs.

This section includes 7 InterviewSolutions, each offering curated multiple-choice questions to sharpen your Current Affairs knowledge and support exam preparation. Choose a topic below to get started.

1.

Find the complement of the following angles 58 degree

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Sum of complementary angles = 180=> X + 58 = 180=> X = 180-58 = 122 degrees.

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2.

Find the complement of the following angles 45 degree

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Compliment of 45° will be (90-45°) = 45°please like the solution 👍 ✔️👍

3.

Find the supplement of the following angles 120 degree

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Supplementary Angle will be(180-120)= 60°

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4.

Who is the founder of Vijayanagar KingdomName the

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The founder of vijayanagar kingdom is Buk rayai

The founder of Vijayanagar Kingdom --Harihara and Bukka Raya

the Vijaynagar kingdom founder is bukka raya

harihara 1 and the bukkaraya were the founders of vijayanagar empire bro

the founder of vijaynagar kingdom is harihara and bukkaraya

5.

Write the complement of each of the following angles34 degree25°ii. 89°iv. one-third of a right

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34 -> 90-34=5689 -> 90-89=125 -> 90-25=6590/3=30 -> 90-30=60

6.

27. From a rectangular sheet of paper ABCD with AB 40 cm andAD - 28 cm, a semicircular portion with BC as diameter is cut off. FindCBSE 2012the area of the remaining paper.

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thankx

7.

Find the supplement of the following angles a. 90 degree

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Sum of supplementary angles is 180.=> X + 90 = 180.=> X = 180-90 = 90.

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8.

Asotainge the pollgusuną tradi&313 lt

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9.

\frac{12}{313}-\frac{13}{12}

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10.

Simplify tan 3aSimplify tan-ax

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11.

Simplify: Cos (e)Simplify : sin (904 0)

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as we know sin(90+x) = cos x

and cos (-x) = cos xhence equation becomescosx/cosx=1

12.

As given in the figure, in the rectangular paper ABCD ,AB=30 cm and BC=20 cm. a semicircle with diameter BC is cut off from the paper. then the area of the remaining paper shown as ruled is ...... cm square ( pie =3.14) A.543B.443C.286D.246

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Since BC is the diameter, so radius = d/2 = 20/2 = 10 cmRadius = 10 cmArea of the semicircular portion = 1/2πr²= 1/2*3.14*100Area of the semicircular portion = 157 sq cmArea of the rectangle ABCD = L*B= 20*30Area of the rectangle ABCD = 600 sq cmNow area of the remaining part of the paper = Area of the rectangle ABCD - Area of the semicircular portion= 600 - 157= 443 sq cm

13.

find the complementary of the following angles 35 degree

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90 - 35 = 55 55 degrees is the complementary angle of 35 degree

55 is the right answer..

55 is the right answer.....

55 isthe right answer...

55 is ths right answer

55 is the correct answer

14.

245A tent is in the shape of a cylinder surmounted by a conical top. If the height anddiameter of the cylindrical part are 2.1 m and 4 m respectively, and the slant height of thetop is 2.8 m, find the area of the canvas used for making the tent. Also, find the cost ofthe canvas of the tent at the rate of Rs 500 per m2. (Note that the base of the tent will notbe covered with canvas.)

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15.

XEXERCISE 1.11. Using appropriate properties find.2 3 5 3 13 5.2 5 62. Write the additive inverse of each of the follo(1)--X-+----O3. Verify that - (-x) = x for.13

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16.

WILproblems of climate change on agriculture,16. Mahe a ppt on benefits of organic farming,MathsThe sum of two rational no. is w/9. If one of the number is -5/7. Find the other one,2. What should be subtracted from A/9. So as to get 5/1273. Divide the sum ofand 1/5 by their difference?4. Product of two rational no. is 15/22. If one of the nois 5/6, find the other one5. Find the value of Xif3/5(x-2/5)- 3/56/7-3/5*2/3.6. Write ten rational no between 3/5 and 17%7. Use appropriate property to solve the following23-1/541/63/24-1/5)*-5/3.

Answer»

x+y=-8/9 , first number =-5/7, -5/7+y=-8/9; y=8/9+5/7=8(7)+5(9)/63=56+45/63=100/63=10/9

17.

write additive inverse of -3/4

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+3/4 is adittive inverse

3/4 is the right answer

3/4 is the right answer

18.

write additive inverse ( negative ) of x

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-x

19.

256 at 500 per mº. Find its vA solid cubical block of fine wood costslength of each side.

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20.

Write the additive inverse of ea2

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additive inverse ofi) 2/8 is -2/8ii) -5/9 is 5/9

21.

Nall1) Write the additive inverse of

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-5/9 is the additive inverse

-5/9 is the additive inverse of 5/9

-5/9 is the correct answer of the given question

-5/9 is the additive inverse of 5/9

-5/9 is the answer and it is very simple to answer it

22.

write the additive inverse ( negative ) of question -x

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Negative inverse will be x of -xasx-x= 0

x-x=0 write this answer

23.

3: Write the additive inverse of the following:21112

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ii) The additive inverse is the negative of a given no.Therefore, the additive inverse for the given no is -21/112

additive inverse of 21/112=-21/112

-21/112 is the answer because additive inverse is the neg. of the given fraction

24.

30. A solid cubical block of fine wood costs 7 256 at 500 per mº. Find Its volume and thelength of each side.

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25.

o. A solid cubical block of fine wood costs? 256 at500 per rna. Find its volume and thelength of each side.

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26.

256 at? 500 per m2. Find its volume and the length ofA solid cubical block of fine wood costseach side.24,

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27.

A solid cubical block of fine wood costs rs 256 at 500 per m^2. Find its volume and the length of each side.

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28.

7.In the following figure, I l| m l| n and t is a transversal. Find the value of x and y.70°

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29.

30? A solid cublcal block of fine wood costs t 256 at t 500 per m2 Find its volume and tuelength of each side.Te

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30.

Integerswrite 'T, for true and ‘F' for false in each of the following:(i) 0 is neither positive nor negative.(ii) -(-36)-1 =-37.(i) On the number line -10 lies to the right of-6(iv) 0 is an integer(v) +15)=-15.(vi) |-40| + 40 = 0.

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31.

1521 trees are planted in a garden in such a way that there are as many trees inrow as there are rows in the garden. Find the number ofrows and number of trees ineatseachrow

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let the no of rows be xso the no of trees in each row will also be equal to xso total trees =x*x=x²atq,x²=1521⇒x=39..so there are 39 rows and 39 trees in each row.

32.

How many umes does9ufs. A solid cubical block of fine wood costs t 256 at t 500 per m. Find Its volume and dlength of each side

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33.

Fig. 3665°11. In Fig.37 show that EFI CD50°Fig.37143

Answer»

As FEB = 65°EBA = 35° + 30 ° = 65°so angle FEB = angle EBA, So, Alternate angle are equal

34.

5 A solid cubical block of fine wood costs256 at500/m3. Find its volume and thelength of each side.

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35.

Integers8Write "T" for true and 'F' for false in each of the following:(i) O is neither positive nor negative.(ii) -(-36) -1 = -37.(iii) On the number line - 10 lies to the right of -6.(iv) O is an integer.(v) +-15 = -15.(vi) |-40[ + 40 = 0.

Answer»
36.

2 How many bricks will be required to construct a wall 135 mlong, 6 m high and 22.5 cm thick? It is being given that enck brick

Answer»

Vol.of wall=(13500*600*22.50)cm^3

Vol.of brick=(27*12.5*9)cm^3

Thus,no.of bricks req.:

Vol.of wall/ vol.of brick

=(13500*600*22.5)/(27*12.5*9)

=60000

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It's so short process

37.

xsquare-4x=0,x=0,-2,4

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Please post a complete picture!

38.

4x²+4x=0

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39.

37 \frac { 1 } { 2 } \% \text { of } 36 kg

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The answer is 13.5 kg

40.

cleThe tangent lines to the circle x2 + y2-6x + 4y = 12 which are parallel to the line 4x + 3y + 5-0 aregiven by(A) 4x+3y-7 0, 4x 3y+ 15 0(C) 4x +3y-17 0, 4x +3y 13 0(B) 4x + 3y-31:0, 4x + 3y + 19:0(D) 4x + 3y-31 0, 4x+3y-19 0

Answer»

Let Equation of line parallel to 4x + 3y +5 =0 will be 4x + 3y + λ= 0.So, the distance of the line from the centre of the circle(3,-2) should be equal to radius 5.So, |4*3 + 3*(-2) + λ| / (4²+3²) = 5hence, 6+λ= 25 or -25λ = 25-6 or -25-6λ= 19 or -31So, equation will be 4x + 3y +19=0 or 4x + 3y -31=0.

41.

Circle6. The tangent lines to the circle x2+y? 6x + 4y 12 which are parallel to the line 4x +3y+5 0 aregiven by:(B)4x + 3y-31-0, 4x + 3y + 19:0

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42.

In a park, the number of plants increased by 9%over the previous year. If the number of plants nowis 62,130, how many plants were there in theprevious year?

Answer»

Let plants in prev. year be x Plants this year=109% ofx=62130 Thus, 109x/100=62130 x=57000

43.

5) In a park, the number of plants increased by9% over the previous year. If the number ofplants now is 62,130, how many plants werethere in the previous year?

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44.

3. A gardener wished to plant 97 plants in the form of asquare. He found that there were 3 plants less. Howmany plants did he want to put in each row?

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45.

In each row Aditi planted 5 plants. Thereare 15 such rows. How many plants didshe plant in all?

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since there are 15 such rows so total planted trees = 15*5 =75

46.

There are 2025 plants to be planted in a garden in such a way throw contains as many plants as therows aat eachnumber of rows. Find the number ofnd the number of plants in each row

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47.

ANSWER THE FOLLOWING:2x5=101.2025 plants are to be planted in a garden in such a way that each row containsas many plants as the number of rows. Find the number of rows and the numberof plants in each row.l following Cundrilateral

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48.

SQUARESANDSQUAREF8. 2025 plants are to be planted in a garden in such a way that each row contains asmany plants as the number of rows. Find the number of rows and the number ofplants in each row.

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49.

2. 14. In a garden bed, there are 23 rose plants in thefirst row, 21 are in the 2nd, 19 in 3rd row and soon. There are 5 plants in the last row. How manyrows are there of rose plants ? Also find the totalnumber of rose plants in the garden.

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50.

8. Find the area of the shaded portion.(a) _ 14mom8m4m10mom2m4m16m20m

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=200-(12+56+48+4) =200-120=80 Answer