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As given in the figure, in the rectangular paper ABCD ,AB=30 cm and BC=20 cm. a semicircle with diameter BC is cut off from the paper. then the area of the remaining paper shown as ruled is ...... cm square ( pie =3.14) A.543B.443C.286D.246 |
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Answer» Since BC is the diameter, so radius = d/2 = 20/2 = 10 cmRadius = 10 cmArea of the semicircular portion = 1/2πr²= 1/2*3.14*100Area of the semicircular portion = 157 sq cmArea of the rectangle ABCD = L*B= 20*30Area of the rectangle ABCD = 600 sq cmNow area of the remaining part of the paper = Area of the rectangle ABCD - Area of the semicircular portion= 600 - 157= 443 sq cm |
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