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Avariableis any characteristics, number, or quantity that can be measured or counted. Avariablemay also be called a data item. Age, sex, business income and expenses, country of birth, capital expenditure, class grades, eye colour and vehicle typeare examplesofvariables

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We have, a= 5, d=3 and an=50

> a+(n-1)d= 50

> 5+(n-1)3=50

> 3(n-1)=50-5

> n-1 = 45/3

> n-1 = 15+1 = 16

Putting n = 16, a= 5 and l = an = 50 in Sn= n/2(a+l),We get

S16 = 16/2( 5 + 50) = 8 × 55 = 440

Hence, n= 16 and S16 = 440

a) 9-3= 66 cups remainingb)5-4=11 balloon remaining

1 packet has 52 balloons24 packets have (52*24) = 1248 balloons.

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Let the distance travelled be x km

speed downstream = 15+ 5 = 20km/h

speed upstream = 15-5 = 10 km/h

Total distance = 2x

Total time = x/20 + x/10 = 3x/20

Average speed = Total distance/Total time

= 2x / (3x/20)

= 40/3

The ratio of average speed to the speed in still water = 40/3 : 15

= 40 : 45

= 8 : 9

Let the speed of the stream be = u kmphlet the speed of the boat be = v kmph

speed upstream will be = v - u kmph speed downstream will be = v + u kmph

30 km upstream in time duration = 30 / (v - u) hrs44 km down stream in time duration = 44 / (v + u) hrs

44 / (v + u) + 30 / (v -u) = 10 hrs --- (1)

Similarly,

40 /(v - u) + 55 / (v +u) = 13 hrs Multiply with 3/4: 30/(v-u) + 165 / 4(v+u) = 39/4 --- (2)

Now (1) - (2) => [44 - 165/4] / (v+u) = 10 - 39/4 = 1/4 => v + u = 11 --- (3)Substitute this in (1) to get: 44/11 + 30/(v-u) = 10 => v - u = 30/6 = 5 --- (4)

Solving (3) and (4) , we get : v = 8 kmph and u = 3 kmph

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thinks

Let the speed of the stream be = u kmphlet the speed of the boat be = v kmph

speed upstream will be = v - u kmph speed downstream will be = v + u kmph

30 km upstream in time duration = 30 / (v - u) hrs44 km down stream in time duration = 44 / (v + u) hrs

44 / (v + u) + 30 / (v -u) = 10 hrs --- (1)

Similarly,

40 /(v - u) + 55 / (v +u) = 13 hrs Multiply with 3/4: 30/(v-u) + 165 / 4(v+u) = 39/4 --- (2)

Now (1) - (2) => [44 - 165/4] / (v+u) = 10 - 39/4 = 1/4 => v + u = 11 --- (3)Substitute this in (1) to get: 44/11 + 30/(v-u) = 10 => v - u = 30/6 = 5 --- (4)

Solving (3) and (4) , we get : v = 8 kmph and u = 3 kmph

a = 0 and common difference d = 4

so, T50 = a+(40-1)d = 0+(49)*4 = 196

the right answer will be 196mark me as best answer

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For 25 baskets she takes 35 days

for 1 baskets she will take3525=1.43525=1.4days

For 110 baskets she will take 1.4*110=154 days.

m(x)=5-4xm(3)=5-4(3)=5-12=7m(-3)=5-4(-3)=5+12=17m(2)=5-4(2)=5-8=-3m(3)+m(-3)-m(2)=7+17+3=27

thanks

256÷16÷2÷18÷9×2

256÷8÷2×2

42÷2×221×2=42

256÷16÷2÷18÷9×2answer = 0.0987654321

377 5ufvjrynkyttgbnjtti

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= Geetika weaves 20 baskets ----- in 30 days

= Number of days for 120 baskets = 120 * 30 / 20 = 180 days.

5x + 3y = 9..........(1)2x - 3y = 12.........(2)(1)+(2)7x = 21then x = 3then y = -2

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Let Work Done by A be aAnd work done by B be b

Thus According to question

60% of A = 1560/100 of A = 15A = 15/0.60A = 25

And Also

40% of (A + B) = 50.40 ( 25 + B) = 525 + B = 12.5Thus B = 12.5 days

Sweets left = 1 - 3/4

= 1/4

a) 5 3 3 + 4 7 5 8 0

the velocity of the river is 3 km /h

I have more questions can u help me ??

let the velocity of the river be x. the velocity of the river will be in the horizontal direction.

velocity of boat in still water is 5km/hr. As the width of the river is 1 km and time taken by the boat to cross the river along the shortest path is 15 min.

Therefore, the velocity of the boat is= 1*60/15= 4km/hr

according to the figure the velocity of the river is along AB . By applying triangle law of vector addition the value of AB comes to be 3km/hr

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24 hours= 1 daynow 36 hours= 1.5 daysnow ratio30/1.5= 20/1

distance = speed × time =45 × 36 =1620kma train covers in 36 hr is 1620km

In one hour distance covered by train = 36 3/4 = 147/4 km

In second hour distance covered by train = 40 2/5 = 202/5 km

In third hour distance covered by train = 38 km

Total distance covered by train in 3 hours= 147/4 + 202/5 + 38= (735 + 808 + 760)/20= 2303/20= 115.15 km

but ans is 2313/20

Area of zari = Area of outer rectangle (or sari) - Area of rectangle without zariClearly, area of sari = length × breadth = 5.5 m × 1.25 m = 6.875 m2For area of rectangle without zari, we have length = 5.5 m - 0.3 m [Using 100 cm = 1 m]= 5.2 Similarly, its breadth = 1.25 m - (2.5 cm + 2.5 cm) = 1.25 m - 5 cm= 1.25 - 0.05 m [Again, using 100 cm = 1 m]= 1.2 mTherefore, area of sari without zari = length × breadth= 5.2 m × 1.2 m = 6.24 m2So, the area of zari = Area of outer rectangle (or sari) - Area of rectangle without zari= 6.875 m2- 6.24 m2= 0.635 m2Hence, the area of zari is 0.635 m2.

Let the speed of the stream be = u kmphlet the speed of the boat be = v kmph

speed upstream will be = v - u kmph speed downstream will be = v + u kmph

30 km upstream in time duration = 30 / (v - u) hrs44 km down stream in time duration = 44 / (v + u) hrs

44 / (v + u) + 30 / (v -u) = 10 hrs --- (1)

Similarly,

40 /(v - u) + 55 / (v +u) = 13 hrs Multiply with 3/4: 30/(v-u) + 165 / 4(v+u) = 39/4 --- (2)

Now (1) - (2) => [44 - 165/4] / (v+u) = 10 - 39/4 = 1/4 => v + u = 11 --- (3)Substitute this in (1) to get: 44/11 + 30/(v-u) = 10 => v - u = 30/6 = 5 --- (4)

Solving (3) and (4) , we get : v = 8 kmph and u = 3 kmph