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This section includes 7 InterviewSolutions, each offering curated multiple-choice questions to sharpen your Current Affairs knowledge and support exam preparation. Choose a topic below to get started.
| 1. |
]+SinA'V1-SinA |
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Answer» on rationalizing it with √1+sinA = √(1+sinA)*√(1+sinA)/√(1-sinA)(1+sinA)= √(1+sinA)²/√cos²A= (1+sinA)/cosA= 1/cosA +sinA/cosA= secA + tanA |
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| 2. |
(vi)V13.5cm |
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Answer» thank you |
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| 3. |
- 29. V1 + V343 = ? |
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Answer» 12 |
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| 4. |
EXERCISE 7.2しtín an isosceles triangle ABC. with AB = AC, the bisectors of L B and L C intersecteach other at O. Join A to O. Show that:AV(i)OB=OC(ii) AO bisectsA |
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Answer» thanks |
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| 5. |
LIn an isosceles triangle ABC, with AB = AC, the bisectors ofeach other at O. Join A to O. Show that:B and L C intersect(i)OB = OC(ii) AO bisectsA |
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| 6. |
16)Show thatنے 23 |
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Answer» the question is wrong give the correct question and then ask |
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| 7. |
xem| | V1 + a"X1, then find ě |
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| 8. |
\log _{8}\left[\log _{2}\left\{\log _{3}\left(4^{x}+17\right)\right\}\right]=\frac{1}{3} |
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| 9. |
3 log, 71- 3 log, 71-3 log 2 |
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| 10. |
\left. \begin{array} { l } { 2 \operatorname { log } _ { 2 } \operatorname { log } _ { 2 } x + \operatorname { log } _ { 1 / 2 } \operatorname { log } _ { 2 } ( 2 \sqrt { 2 } x ) = 1 } \\ { \operatorname { log } _ { 3 / 4 } \operatorname { log } _ { 8 } ( x ^ { 2 } + 7 ) + \operatorname { log } _ { 1 / 2 } \operatorname { log } _ { 1 / 4 } ( x ^ { 2 } + 7 ) ^ { - 1 } = - 2 } \end{array} \right. |
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Answer» it's an integer type question so what is the final answer |
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| 11. |
1. In quadrilateral ACBDAC AD and AB bisects A(seeFig. 7.16). Show that Δ ABCa Δ ABDWhat can you say about BC and BD? |
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| 12. |
In quadrilateral ACBD,AC = AD and AB bisects <A(see Fig. 7.16), Show that A ABCEA ABD.1.What can you say about BC and BD? |
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| 13. |
EXERCISE 7.11. In quadrilateral ACBD,AC AD and AB bisects L A(see Fig. 7.16). Show that AABCAABDWhat can you say about BC and BD2 |
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| 14. |
Find the volume of the right circular cone with(i) radius 6 cm, height 7 cm(i) radius 3.5 cm, height 12 cm |
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| 15. |
In the given figure, AB is a chord oflength 9.6 cm of a circle with centre Oand radius 6 cm. The tangents at Aand B intersect at P. Find the lengthPof PA.GIVEN A circle with centre O andradius 6 cm. AB is a chord of16 cm[CBSE 2009c] |
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| 16. |
volume of the right circular cone withd theradius 6 cm, height 7 cm(ii) radius 3.5 cm, h |
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| 17. |
\frac{\sec \theta+\tan \theta}{\sec \theta-\tan \theta}=2 \frac{51}{79} |
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| 18. |
x ^ { 2 } + \frac { 1 } { x ^ { 2 } } = 51 , \text { find the value of } ( x - \frac { 1 } { x } ) |
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| 19. |
-1o) JdxV1-x2 |
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| 20. |
ABCD is a rectangle in which diagonal AC bisects A as welu)ABCD is a square (n) diagonai BD bisects B as well as 4 Das 4C |
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Answer» what is your profession |
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| 21. |
EXERCISE 7.1n quadnilateral ACBDAC AD and AB bisects 2Asee Fig. 7.16). Show that A ABCEA ABD.What can you say about BC and BD? |
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| 22. |
32. V1+ sinA.1-sin A.2 = (sec A-tan A) |
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| 23. |
2)IfV1 22=1+what is the value of x ? |
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Answer» Squaring both sideshence1+27/169=1+x^2/169+2x/1327/169=13x^2+338x/169*1327=13x^2+338x/13351=13x^2+338xhence27=x^2+26xx^2+26x-27=0x=-26+-√676+108/2x=-26+-√784/2x=-26+-28/2x=1,27 |
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| 24. |
3.Differentiate\left(x^{2}+6\right)^{10}w.rt."X". |
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| 25. |
हिजाहरण 5. शेढ़ी उ, 5, 7, ..... 51 में कुल किले पद BT |
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Answer» a= 3d=5Tn=a+(n-1)d=513+(n-1)2=512n=50n=25 |
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| 26. |
\left. \begin{array} { l } { ( i ) \operatorname { tan } ^ { 2 } A - \operatorname { tan } ^ { 2 } B } \\ { = \frac { \operatorname { cos } ^ { 2 } B - \operatorname { cos } ^ { 2 } A } { \operatorname { cos } ^ { 2 } B \operatorname { cos } ^ { 2 } A } = \frac { \operatorname { sin } ^ { 2 } A - \operatorname { sin } ^ { 2 } B } { \operatorname { cos } ^ { 2 } A \operatorname { cos } ^ { 2 } B } } \end{array} \right. |
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| 27. |
51+5 |
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Answer» Ans :- 51 + 5 = 56 |
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| 28. |
\frac{\cos ^{2} \alpha-\cos ^{2} \beta}{\cos ^{2} \alpha \cdot \cos ^{2} \beta}=\tan ^{2} \beta-\tan ^{2} \alpha |
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| 29. |
\frac{\sin A+\cos A}{A-\cos A}+\frac{\sin A-\cos A}{\sin A+\cos A}=\frac{2}{\operatorname{atm}^{2} A-\cos ^{2} A}=\frac{2}{1-2 \cos ^{2} A} |
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| 30. |
\frac 5 2 = \frac n 2 51 |
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Answer» 44/20=x/544×5=20×x220=20xx=220/20x=11 |
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| 31. |
\begin{array} { c } { \text { 12. In } \Delta A B C , \text { show that } } \\ { \frac { \cos ^ { 2 } B - \cos ^ { 2 } C } { b + c } + \frac { \cos ^ { 2 } C - \cos ^ { 2 } A } { c + a } = \frac { \cos ^ { 2 } B - \cos ^ { 2 } A } { a + b } } \end{array} |
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| 32. |
\cos ^{2} 5+\cos ^{2} 10^{\circ}+\cos ^{2} 15^{\circ}+\ldots+\cos ^{2} 360^{\circ}= |
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Answer» Cos²5° + cos²10° + cos²15° + ......+ cos²90°= cos²5° + cos²10° + cos²15° +......+ cos²75° + cos²80° + cos²85° + cos²90° we know, cos(90-∅) = sin∅ use this here, = cos²5° + cos²10° + cos²15° +.....+ cos²(90-15) + cos²(90-10) + cos²(90-5)+ cos²90° = cos²5° + cos²10° + cos²15° + ......+ sin²15° + sin²10° + sin²5° + 0 [ cos90° = 0 ] = (cos²5° + sin²5°) + (cos²10°+sin²10°)+(cos²15°+ sin²15°) + ..... ( cos²40° + sin²40°) + cos²45° = 1 + 1 + 1 +.... +1 + ( 1/√2)² [ use here sin²∅+cos²∅ = 1] = 8 + 1/2 = 17/2 |
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| 33. |
6. In the given figure, ABCD is a quadrilateralin which AB- AD and BC DC. Prove that(i) AC bisects ZA and ZC, (ii) BE DE,(ii) ZABC- LADC. |
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| 34. |
and E are points on sides AB and AC respectively of Δ ABC such thatC)ar (ERC). Prove that DE II BC. |
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| 35. |
In the given figure, ABCD is a quadrilateralin which AB AD and BC- DC. Prove that(i) AC bisects LA and LC, (ii) BE= DE,(ii) ZABC ZADC. |
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| 36. |
D and E are points on sides AB and AC respectively of Δ ABC such thatar (DBC)-ar (EBC). Prove that DE II BC. |
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| 37. |
bisects BDn the given figure, ABCD is a quadrilateralin which AB AD and BC-DC. Prove that(6) AC bisects ZA and ZC, (ii) BE DE,(ii) ZABC LADC |
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| 38. |
differentiate6) tan' CasaItsins |
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| 39. |
4.Construct a triangle XYZ in which ZY = 30°, <Z = 90° and XY + YZ+2Xe l l cm. |
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| 40. |
The Waweol a casa deisus only00% IP the horsent value of the cand thesarr, what will be ile Tolu s 2 |
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| 41. |
L+h9 THAE c+Ay ¢+hg |
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| 42. |
Section A1. 5 b77. Represent this situation inooks andthe form of linear equation in two variables.pens together cost79, w here as 7 books and 5 pens together cost1cm and PA is a tangent drawn to the |
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| 43. |
uplalt with one example?trodesWhat is directive influence? Explain with examples |
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Answer» Enzyme catalysisis the increase in the rate of a chemical reaction by the active site of a protein. The proteincatalyst(enzyme) may be part of a multi-subunit complex, and/or may transiently or permanently associate with a Cofactor (e.g. adenosine triphosphate). |
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| 44. |
14 t-(2t +5)-51-2t)2(3+4t)-3( 4) |
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Answer» t - (2t + 5) - 5( 1 - 2t) = 2 ( 3 + 4t) - 3 ( t - 4)=> t - 2t - 5 - 5 + 10t = 6 + 8t - 3t + 12=> 9t - 10 = 5t + 18=> 4t = 28=> t = 7 PLEASE HIT THE LIKE BUTTON |
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| 45. |
62)P— T — Dजि जा oA29 zची किंमतकिती? (दोन अचूक पर्याय निवड़ा)2)3 3) 3143 |
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Answer» P/19 = 1/57 P = 19/57 P = 1/3 3) 1/3 is correct option |
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| 46. |
t-(2t+5)-5(1-2t)=2(3+4t)-3(t-4) |
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| 47. |
9. 3 रा. खालील उपप्रश्न सोडवा. (प्रत्येक 3 गुण)i) एका अंकगणितीय श्रेढीचे 7 बे पद 32 g 1.अंकगणितीय श्रेढ़ी लिहा-द 62 आहे तर ती |
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| 48. |
8. In the figure given alongside, x : y = 2 : 3 and LACD-130°. Findthe values of x, y and z.Hint. Let x-2t and y 3t. Then, 2t +3t 130t 26ye130 |
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| 49. |
ABCD is a rectangle in which, diagonal AC bisects <A as well as <C. Show that(i) ABCD is a squareIS(i) diagonal BD bisects B as well as D |
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| 50. |
t-(2t + 5)-5(1-2t) = 2 (3 + 4t)-3(t-4) |
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