1.

]+SinA'V1-SinA

Answer»

on rationalizing it with √1+sinA

= √(1+sinA)*√(1+sinA)/√(1-sinA)(1+sinA)= √(1+sinA)²/√cos²A= (1+sinA)/cosA= 1/cosA +sinA/cosA= secA + tanA



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