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This section includes 7 InterviewSolutions, each offering curated multiple-choice questions to sharpen your Current Affairs knowledge and support exam preparation. Choose a topic below to get started.
| 1. |
22 [० raoudioan o A £ puw 5 jo wms gy 2piaiqy Ofl |
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Answer» sum of 7/10+3/5= 35+30/50= 65/50reciprocal of 11/20= 20/1165/50*20/11=2.36 |
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| 2. |
llap e la |
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| 3. |
11. Add: P(-9), 249,-4) ond uld-) |
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| 4. |
12. Vile the positive TUUL Uld13. If a, 2n-3find S2Ibofia radicali |
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| 5. |
XERCISE 3.3rice.I, CP=60, profit = 10%3, CP= 96, loss= 500B. Find the cost price.1, SP 270, loss-10003, SP56, profit -500Solve these word problems.A bookseller buys perat 110 each. Find hA sofa that cost9100 was sol |
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| 6. |
Wateh50 per ream. At what price per quire should he sell it so as to gain 20%?6. A bookseller buys paper at[Hint. 1 ream 20 quires]i aaingd at what nrice should they have been sold |
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Answer» CP per ream= Rs 50Profit%= 20%Profit= 50×20/100= Rs 10SP= CP+ PROFITSP= Rs50+ Rs 10Selling Price= Rs 60 |
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| 7. |
If the sum of measures T WUother.(2) In âłABC, LA = 76", LB = 48", then find measure of LC.NAVNEET PRACTICE PAPERS: STD. X |
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Answer» Given,In triangle Angle A = 76°, Angle B = 48°, Angle C =? In triangle sum of all angles = 180 Angle A + Angle B + Angle C = 180 76 + 48 + Angle C = 180124 + Angle C = 180Angle C = 180 - 124 = 56 |
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| 8. |
7. A bookseller buys a dictionary for 158 and sells itat 181.70. He also sells a set of encyclopaedias for72827.20 which he had bought for 2480. In whichsale was his profit percentage higher and by howmuch? |
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| 9. |
The cost of some books is 60. Cost of every book is the same. If the booksellerdecreases the cost of the book by 1, one gets 5 books more for the same amountWhat is the cost of each book and how many books are purchased? |
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| 10. |
(1) The cost of some books is60. Cost of every book is the same. If the booksellerdecreases the cost of the book by ? 1, one gets 5 books more for the same amount.What is the cost of each book and how many books are purchased? |
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Answer» Let the number of books = nTotal cost of books = 60 Then,Cost of each book = 60/n If price of each book decreased by Rs 1Then, Number of books = n + 5 Cost of each book will be = 60/(n + 5) Thus,60/(n+5) = 60/n - 160(1/n - 1/n+5) = 160(5) = n(n + 5)n^2 + 5n - 300 = 0n^2 + 20n - 15n - 300 = 0n(n + 20) - 15(n + 20) = 0(n - 15)(n + 20) = 0n = 15, - 20 As negative value not possible Therefore,Total number of books = 15Cost of each book = 60/15= 4 Rs |
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| 11. |
Learn tables from 2 to 15.e la expenditure done during the trip.Using number from 5 to 13 complete the magic square so that the sum of each row, eachcolumn and along each diagonal is 27. |
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| 12. |
(1) The cost of some books is60. Cost of every book is the same. If the booksellerdecreases the cost of the book by1, one gets 5 books more for the same amount.What is the cost of each book and how many books are purchased? |
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Answer» Let number of books = nCost of n books = 60Then,Cost of one book = 60/n If cost decrease by 1 rupees Number of books = n + 5Thus cost of each book will be = 60/(n + 5) 60/n - 1 = 60/(n + 5)(60-n)/n = 60/(n + 5)(60-n)(n + 5) = 60n60n + 300 - n^2 - 5n = 60nn^2 + 5n - 300 = 0n^2 + 20n - 15n - 300 = 0n(n + 20) - 15(n + 20) = 0(n - 15)(n + 20) = 0n = 15, - 20 Number of books = 15Cost of each book = 60/15 = Rs 4 |
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| 13. |
wms Pax aaow, that la\left| \begin{array}{lll}{x} & {a} & {a} \\ {a} & {x} & {a} \\ {a} & {a} & {x}\end{array}\right|=(x-a)^{2}(x+2 a) |
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| 14. |
DULU.1Form the pair of linear equations in the following problems, and find their solutionsgraphically.) 10 students of Class X took part in a Mathematics quiz. If the number of girls is 4more th in the number of boys, find the number of boys and girls who took part inthe quiz.(i) 5 pencils and 7 pens together cost * 50, whereas 7 pencils and 5 pens togethercost * 46. Find the cost of one pencil and that of one pen. |
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| 15. |
If the sum of two numbers bemultiplied by each numberseparately, the products soobtained are 247 and 114. Thesum of the numbers is: |
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| 16. |
4) The students of a class in a school were taken to theslavground. Hall of the students were pilavinaHalf of the remaining students were playing on wOne third of the remaining students were riding mego-round and remaining 10 students were doing theirhomework. Find the total number of students in theplayground |
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| 17. |
en indcosa |
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| 18. |
CANADA :DOLLAR::GERMANY :0) YEN2) DOLLAR(3) DEUTSCHE MARK(4) RIYAL |
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Answer» Answer is 3)DEUTSCHE MARK In Canada , Canadian dollar is the currency .In Germany Deutsche mark is the currency But remember one thing , German currency was replaced by the EURO on 28,Feb 2002. |
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| 19. |
ctzor, adollar-medi- |
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Answer» 9% of 30 9/100 × 30 270/100 = 2.7 % |
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| 20. |
35 studĂŠnts of Class X took part in a Mathematics quiz. If thenumber of girls is 8 less than the number of boys. Write twolinear equations for the above. |
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Answer» x+y-8= 35y+x-8= 35these are two equation |
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| 21. |
1 Sudents of Class X took part in a Mathematics quiz. If the number of girls is 4more than the number of boys, fnd the number of boys and gifls who took pairthe quiz. |
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Answer» Total number of students = 10Let number of boys = nThen number of girls = n + 4 Therefore,n + n + 4 = 102n + 4 = 102n = 6n = 6/2 = 3 Number of boys = 3Number of girls = 7 |
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| 22. |
The height of the cone is 15 cm. If its volume is 1570 cm^3. Find the radius of the base |
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Answer» radius is 10cm.V=πr^2 h/3 tq tq tq tq Volume of cone = (πr²h)/3So given volume is 15701570 = (22 × r² × 15 )/21r² = (1570×21)/15×22r² = 99.09r = 9.99 cm |
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| 23. |
uighlordm.Ifitsvolumeis 1570 cm^3, find the radius of the base.(Use π=3.14)fthe volume of a right circular cone ocheit i |
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| 24. |
®एक शंकु की ऊँचाई 15 cm है। यदि इसका आयतन 1570 cm है, तो इसके आधार कत्रिज्या ज्ञात कीजिए। ( = 3.14 प्रयोग कीजिए)) |
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Answer» शंकु का आयतन=1/3pie×r²×h 1570=(1/3)×(3.14)×r²×15 r²=(1570×3)/(3.14×15) r²=100 r²=10² r=10अतः शंकु की त्रिज्या 10cm. होगी। sankuu 10 centimeter ka hoga |
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| 25. |
3. The height of a cone is 15 cm. If its volume is 1570 cm2, find the radius of the base.(Use π = 3.14) |
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Answer» thnk u |
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| 26. |
Click any question from belowand learn how Scholr worksQ1. A vessel is in the form of a hollow hemisphere mounted by a hollowcylinder. The diameter of the hemisphere is 14 cm and the totalheight of the vessel is 13 cm. Find the inner surface area of the vessel.Q2 A vertical pole of length 6 m casts a shadow 4 m long on the groundand at the same time a tower casts a shadow 28 m long, Find theheight of the tower |
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Answer» 1)part a) |
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| 27. |
lalearnow Scholr WuQ1. A vessel is in the form of a hollow hemisphe cm and themounted by a hollowcylinder The diameter of the hemisphereheight of the vessel is 13 cm. Find the inner suis 14 em and the totalsurface area of the vessel |
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| 28. |
1. All the letters of the word 'EAMCET' are arranged inall possible ways. The number of such arrangementsin which two vowels are not adjacent to each otheris(a) 360(c) 72(b) 114(d) 54 |
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| 29. |
A solid piece of iron of dimensions 49 cm x 33 cm x 24 cm is moulded into a sphere.The radius of sphere is : (use π =-) |
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| 30. |
The height of a cone is 15 cm. If its volume is 1570 cm, find the radius of the base.(Use π-314) |
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| 31. |
Draw a rcompasses and a ruler only.raw a rectangle whose two adjacent sides are 5 cm and 3.5 cm. Make use dh of uhoce sides is 5 cm. Use a pair of compasses and a nun7. |
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| 32. |
The height of a cone is 15 cm. If its volume is 1570 cm', find the radius of the base.(Use 3.14) |
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| 33. |
Nine articles are to be placed in nine boxes onnumber of possible arrangements.e in each box. Five of them are too big for the three of the boxes. Find the |
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Answer» First off all select 5 boxes out 6 boxes in which 5 big ball can fit then arrange these ball in theae 5 boxes and then put remaining 4 ball in any remaining box. So Ans is [(6C5)5!](4!) = 6!4! = 17280. 17280 is the ans basically take 5 box out of 6 so keep 5 big ball in 5 box and then Piet renaming 4 balls in remanig box |
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| 34. |
the line whvee intercepts on the ness areand thoa show that 1/p^2=1/a^2+1/b^2 |
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| 35. |
9. Write seven consecutive composite numbers less than 100 having no prime numberbetween them. |
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| 36. |
. Find two consecutive composite numbers less than 10, such that there is no primenumber between them. |
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Answer» 9,8 as there is no prime number between them |
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| 37. |
0.1 In the given figure, x-30The value of y is(a) 10(b) 40(c) 36(d) 45°3y2x |
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Answer» 3y+2x=180( they form a linear pair) replacing value of x we get3y+2(30)=1803y+ 60 =1803y = 180-603y = 120y= 120/3y = 40 answer b 40 x=30° then,2×30=60so,2x=60 now we know that angle made on straigt line is always of 180° so,3y+2x=180° 3y+60=180° 3y=180-60=120 3y=120 y=120÷3=40 so,the value of y =40 |
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| 38. |
Divide 26244 by the smallest number so that the quotient is a perfect cube. Also, find the cube root othe quotient. |
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Answer» 26244 = 2×2×3×3×3×3×3×3×3×3. So, 2x2x 3x 3 = 36 is the smallest number by which 26244 must be divided so that the quotient is a perfect cube.So, dividing 26244 by 36 will give us the required quotient = 729. Therefore, the cube root of the quotient = ³√729= 9. please answer on copy |
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| 39. |
List the composite numbers between 60 and 80 |
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Answer» 62, 63, 64, 65, 66, 68, 69, 70, 72, 74, 75, 76, 77 and 78. composite number=62, 64, 65, 66, 68, 69, 70,72, 74, 75, 76, 77, 78 |
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| 40. |
6. The difference between two rational numbers is . If the smaller rational number is gthen find the larger rational number. |
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| 41. |
(७१६ 1% ९0 09 ()है DU Lok ) |
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| 42. |
||DU46. जब -1 को -1 से 100 बार गुणा किया जाए, तोगुणनफल है।) 1(B) -1 |
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Answer» गुरणफल 1 होगा क्योंकि -1*-1=1thnx |
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| 43. |
Sunt of theirre come under preted mutual fu.e last nine mont1+ sin 2011. Prove that 11-sin 20(1+tan(1-tan)ULU Investo |
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| 44. |
20. In the given figure, O is a point in the interior of a triangle ABC, OD 1 BC, OE 1 AC andOFAB. Show thatOR0 |
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Answer» thank you |
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| 45. |
lution to the given equation(c) 7n 5 19 (n 2)(f) 4p_3= 13 (p=0)d:racted from y is 8.umber h divided by 5 gives 6 |
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Answer» 7multiplied by 2 +5 = 18 When you have 7n you plug in 2 for (n) then you multiply 7 by 2 which equals 14. Then you add 5 which equals 19. So the correct answer is (c) |
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| 46. |
umber when divided by 6 is diminished by 40. Find the number.hor hy 10. Find |
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| 47. |
8. Ahemisphencal bowl is made ofbrass, 0.25 ăthickness.The innerradius ofthe bowlis 5 cm. Find the ratio of outer surface area to inner surface area. |
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Answer» Inner radius of hemispherical bowl = 5 cm Thickness of the bowl = 0.25 cm ∴ Outer radius (r) of hemispherical bowl = (5 + 0.25) cm = 5.25 cm Outer CSA of hemispherical bowl = 2πr2 = 2 x 22/7 x (5.25 cm)2= 173.25 cm2 Therefore, the outer curved surface area of the bowl is 173.25 cm2. please like the solution 👍 ✔️👍 |
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| 48. |
A hemispherical bowl is made up of brass with 0.25cm thickness. the inner radius is 5cm .find ratio of outer surface area and inner surface area |
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Answer» tq |
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| 49. |
7 ă1 Linear symmetry of the lettof the English alphabet |
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Answer» Thoseletterscannot be folded in half in any way with the parts matching up. The rest of theletters, A, B, C, D, and E all have only 1lineofsymmetry. Notice that the A has a verticallineofsymmetry, while the B, C, D, and E have a horizontallineofsymmetry |
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| 50. |
A hemispherical bowl is made of brass, 0.25 cm. thickness. The inner radius of the bowlis 5s.cm. Find the ratio of outer surface area to inner surface area. |
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