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cos 10 cos 50 cos 70= (1/2) [ 2 cos 50 cos 70 ] cos 10= (1/2) [ cos 20 + cos 120 ] cos 10= (1/2) [ cos 20 -- 1 / 2 ] cos 10= (1/2) cos 20 cos 10 -- [ 1 / 4 ] cos 10= (1/4) [ 2 cos 20 cos 10 ] -- [ 1 / 4] cos 10= (1/4) [ cos 30 + cos 10 ] -- (1/4) cos 10= (1/4) cos 30= (1/4) sqrt(3)/2= sqrt(3) / 8

maa ki kasam like karo please like

correct answer is C=12like......

like........like........

12 is the correct answer

your correct answer is 12

12 is the correct answer of the given question

X and H and O is the answer to that question

(c) 24

5 × 4 × 2 = 403 × 5 × 3 = 456 × 4 × 1 = 24

c24 is the write ans

the answer is 24 because in it all triangle's answer comes after multiply together.

the answer is 24. 6×4×1

The right answer of this question is 24 .proof:- given that 4 ,6 and 1 so we are multiple of these number for example consider A=4,B=6,C=1 so we multiple A×B×C 4×6×1=24×1=24So the right answer is (C)24.

24 is my answer because 5

(c) 24

5×4×2=403×5×3=456×4×1=24

option c is the right answer.

my answers is 24 because 5 multiply 4=20 20 multiple by 2 =40 and 3 multiple by 5=15 and 15 multiple by 3 =45 and 6 multiple by 4=24and 24 multiple by 1=24

(c) is the right answer

Now don't send many answers this question answer is knowing all the students

5×4×2=४०३×५×३=४५६×४×१=२४

this is correct answer (c) 24 6(1)(4)=24.

5*2*4=405*3*3=45than 6*4*1=24

(c) 24

5 x 4 x 2=403 x 5 x 3=456 x 4 x 1=24

24 is right answer now

Option C is the correct answer.

5 × 2 × 4 = 403 × 5 × 3 = 454 × 6 ×1 = 24

c = 24 Ans.

24 option c is correct

thx bro

As 49 gives 7*7 & 343 gives 7*7*7 so in multiply power will add when base are same so it gives 7*7*7*7*7 so 2x+1=5 by solving the equation we get x=2

X= 2 is the correct answer of the given question

x=2 is the correct answer

Let a be the first term and d be the common difference of the given AP.Sum of the first n terms is given bySn = n/2 {2a + (n - 1)d}Putting n = 10, we getS₁₀ = 10/2 {2a + (10 - 1)d}210 = 5 (2a + 9d)2a + 9d = 210/52a + 9d = 42 ...............(1)Sum of the last 15 terms is 2565⇒ Sum of the first 50 terms - sum of the first 35 terms = 2565S₅₀ - S₃₅ = 2565⇒ 50/2 {2a + (50 - 1)d} - 35/2 {2a + (35 - 1)d} = 256525 (2a + 49d) - 35/2 (2a + 34d) = 2565⇒ 5 (2a + 49d) - 7/2 (2a + 34d) = 513⇒ 10a + 245d - 7a + 119d = 513⇒ 3a + 126d = 513⇒ a + 42d = 171 ........(2)Multiply the equation (2) with 2, we get2a + 84d = 342 .........(3)Subtracting (1) from (3) 2a + 84d = 342 2a + 9d = 42- - -_______________ 75d = 300_______________d= 4Now, substituting the value of d in equation (1)2a + 9d = 422a + 9*4 = 422a = 42 - 362a = 6a = 3So, the required AP is 3, 7, 11, 15, 19, 23, 27, 31, 35, 39 ......

1) 243 must be multiplied by 3 to obtain 729 which of perfect cube of 92) 256 should be multiplied by 2 to obtain 512 which is perfect cube of 83) 72 must be multiplied by 3 to obtain 216 which is perfect cube of 64) 675 must be multiplied by 5 to get 3375 which is perfect cube of 15 5) 100 must be multiplied by 10 to obtain 1000 which is perfect cube of 10.

1- 243 must be multiplied by 3 to obtain 729 which is perfect cube of 9

7/10 and 2/3is the correct answer

3 / 5 + 5 / 4 = 3 / 4

-2/3 and 1/4-2*4/3*4 =-8/12and 3/12-7/12,-6/12 are two rational numbers

sin67° + cos 75°

= cos 23° + sin 15°

This is according to the formula,

sin(90-∅) = cos∅ andcos (90-∅) = sinФ

2m 10cm + 5m 67cm=2.10m + 5.67m=7.77m=7m 77cm

angles are in 3:5:9:13 so 3x,5x,9x,13xso 3x+5x+9x+13x=36030x=360so x=12so angles are 36,60,108,156

thank you

c) is the right answer of the following

option (A) is the right answer

(B) is the correct answer

d is the correct answer

c) is the right answer of the following

option c is the right answer

To find this add both57 for tomatoes +65 for onions =122 rupees

12a^2-27ab+24ac+16ab-36b^2+32bc-24ac+54bc-48c^2=12a^2-11ab-36b^2+86bc-48c^2

(-11)^3=(-11×-11×-11)=-1331

the cubes of (-11) =-11×-11×-11=-1331

The first four multiple of 10 are10,20,30 and 40

Given points are (1,7),(4,2),(-1,-1),(-4,4)Let the points are A,B,C,D.Distance formula =√(x₂-x₁)²+(y₂-y₁)² AB =√(4-1)²+(2-7)² =√9+25 =√34 BC =√(-1-4)²+(-1-2)² =√25+9 = √34 CD =√(-4-(-1))²+(4-(-1))² =√9+25 = √34 DA =√(1-(-4))²+(7-4)² =√25+9 =√34We know that the all sides of the square are equal.Here by the distance formula, we got the for sides equal .So,from this we can say that these points are the vertices of a square.

Let a be any positive integer

a=6q+r where 0< or equal to r <6

put r=1: a=6q+1 =odd integer

r=3: a=6q+3=odd integer

r=5: a=6q+5=odd integer

therefore,any positive odd integer is of the form 6q+1,6q+3 or 6q+5,where q is some integerLike if you find it useful

thanx

we know thatAn isosceles triangle has two equal sides and two equal anglesThe equilateral triangle has the three equal sides and the three equal anglessoIf a triangle is isosceles cannot be equilateraltherefore the statement is False

First we have to convert the given

word problem into algebraic

equation.

Let the number = x

Four times of its reciprocal = 4/ x

According to the problem,

x - 4 / x = 3

( x ^2 - 4 )/ x = 3

x ^2 - 4 = 3x

x ^2 - 3x - 4 = 0

Spilt the middle term

x ^2 + x - 4x - 4 = 0

x ( x + 1 ) - 4 ( x + 1 ) = 0

( x + 1 ) ( x - 4 ) = 0

x + 1 = 0 or x - 4 = 0

x = -1 or x = 4

The common factors are:1, 2, 7, 14, 49, 98

The Greatest Common Factor:GCF = 98Therefore,themaximum capacity of bag so that wheat can be packed in exact no. of bags is 98 kg

the wheat is packed in 2 bags

To find the maximum capacity of the bag to pack all the weight in exact number of bags, we need to find the HCF of these weights490=2*5*7*7588=2*2*3*7*7882=2*3*3*7*7common factors are-2 and 7(occurring twice)so HCF=7*7*2=98so the capacity of the bag is 98 kg

wheat is packed in 2 bags

let common factor 1,2,3,7,14,49,98

common factor gcfis 98

Required no of bags = hcf of 490, 588, 882 = 98

Max no of bags = hcf of 490, 882 and 588 = 98

HCF of 490, 588, 882 is 95so correct answer is 98

L.C.M of 490,588and 882 is 98hence, the maximum capacity of bag so wheat can be packed in exact no. of bags is 98 kg

maximum capacity of bag is 98 kgs

there are maximum capacity of bag so that wheat can be packed in exact no.of bag is 98kg

there are maximum capacity of bag so that wheat can be packed in exact no of bag is 98 kg

HCF of 490 ,588, 882 is490=2*5*7*7588=2*2*3*7*7882=2*3*3*7*7so HCF =2*7*7=98so the capacity of bag is 98

Maximum capacity of the bag is 98kg

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the common factors are 1,2,7,14,49 and 98the greatest common factor is 98therefore the maximum capacity of bag so that the wheat can be packed in exact number of bags is 98 kg

98 is the answer for this question

this solution We will take the heights comman factorfor these numbersand all numbers have heights comman factor is 98 and answer will be 98 kg. bag

here we need maximum capacity bag so first find highest common factor of these no that is 98. mean 98kg capacity bag should be needed for packing .you can check all there no should be divisible by 98 so 98 is correct answer.(always remember for max find hcf for min lcm)

The maximum capacity of each bag= 78Kg

no. of bag is 98, kg

do hcf of 490 . 588. and 882. and 98 is yoir answers

h. c. f of 490,588,882 is 98 so answer will be 98

The answer will be 98

a is must be better answer for this question

exact number of bags is 98

98kg is the right answer

Three farmers have 490 kg, 588 kg and 882 kg of wheat respectively. Find the maximum capacity of a bag so that the wheat can be packed in exact number of bags. (i) 98 kg (ii) 290 kg (iii) 200 (iv) 350 kg​

Three farmers have 490 kg, 588 kg and 882 kg of wheat respectively. Find the maximum capacity of a bag so that the wheat can be packed in exact number of bags. (i) 98 kg (ii) 290 kg (iii) 200 (iv) 350 kg​

98kg is the capacity of a bag

HCF OF 498,588,882 IS 98 so that we can be packed in extra number of bags is 98 kg

First find the Hcf of all three numbers that is 98 and that is the maximum capacity and then find the Lcm that is 8820 and divide by 98. The answer is 90.

98 kgs because the greatest common factor is 98

number of bags - hcf of 490 ,588,882 is 98

we hve to find the hcf that iz equal to 98

taking HCF we get 98.Hence maximum capacity of a bag be 98kg

the answer get by taking hcf is 98

98 is correct answer bcz greatest common factor is 98

98kg is the maximum capacity of a bag is required.

the HCF of 490,588,and 882is 98

882 is answer this is a farmer wheat

the common factor are 1,2,7,14,49,98 so max number is 98

to find the maximum capacity of the bag to pack all the weight in exact number of bags , we need to find the h.c.f of these weights 490 = 2*5*7*7588 =2*2*3*7*7882 =2*3*3*7*7common factors are - 2 and 7(occurring twiceso,h.c.f = 7*7 *2 =98so,the capacity of these bags will be 98

As ABC is congruent then angle ABC = ACBin BDC angle BDC= angle DCDadding them we get angle ABD= angle ACD

Let a be the positive odd integer which when divided by 6 gives q as quotient and r as remainder.

according to Euclid's division lemmaa=bq+ra=6q+rwhere , a=0,1,2,3,4,5then,a=6qora=6q+1ora=6q+2ora=6q+3ora=6q+4ora=6q+5

but here,a=6q+1 & a=6q+3 & a=6q+5 are odd.

option B

Sorry I got my answer from somewhere else and the answer is 60. Its 210=5*6*7120=4*5*660=3*4*524=2*3*46=1*2*30=0*1*2So the answer in series is 60.Thanks for giving advice!

0,-1,1,( minus 1/2)(1/2)