The common factors are:1, 2, 7, 14, 49, 98

The Greatest Common Factor:GCF = 98Therefore,themaximum capacity of bag so that wheat can be packed in exact no. of bags is 98 kg

the wheat is packed in 2 bags

To find the maximum capacity of the bag to pack all the weight in exact number of bags, we need to find the HCF of these weights490=2*5*7*7588=2*2*3*7*7882=2*3*3*7*7common factors are-2 and 7(occurring twice)so HCF=7*7*2=98so the capacity of the bag is 98 kg

wheat is packed in 2 bags

let common factor 1,2,3,7,14,49,98

common factor gcfis 98

Required no of bags = hcf of 490, 588, 882 = 98

Max no of bags = hcf of 490, 882 and 588 = 98

HCF of 490, 588, 882 is 95so correct answer is 98

L.C.M of 490,588and 882 is 98hence, the maximum capacity of bag so wheat can be packed in exact no. of bags is 98 kg

maximum capacity of bag is 98 kgs

there are maximum capacity of bag so that wheat can be packed in exact no.of bag is 98kg

there are maximum capacity of bag so that wheat can be packed in exact no of bag is 98 kg

HCF of 490 ,588, 882 is490=2*5*7*7588=2*2*3*7*7882=2*3*3*7*7so HCF =2*7*7=98so the capacity of bag is 98

Maximum capacity of the bag is 98kg

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the common factors are 1,2,7,14,49 and 98the greatest common factor is 98therefore the maximum capacity of bag so that the wheat can be packed in exact number of bags is 98 kg

98 is the answer for this question

this solution We will take the heights comman factorfor these numbersand all numbers have heights comman factor is 98 and answer will be 98 kg. bag

here we need maximum capacity bag so first find highest common factor of these no that is 98. mean 98kg capacity bag should be needed for packing .you can check all there no should be divisible by 98 so 98 is correct answer.(always remember for max find hcf for min lcm)

The maximum capacity of each bag= 78Kg

no. of bag is 98, kg

do hcf of 490 . 588. and 882. and 98 is yoir answers

h. c. f of 490,588,882 is 98 so answer will be 98

The answer will be 98

a is must be better answer for this question

exact number of bags is 98

98kg is the right answer

Three farmers have 490 kg, 588 kg and 882 kg of wheat respectively. Find the maximum capacity of a bag so that the wheat can be packed in exact number of bags. (i) 98 kg (ii) 290 kg (iii) 200 (iv) 350 kg​

Three farmers have 490 kg, 588 kg and 882 kg of wheat respectively. Find the maximum capacity of a bag so that the wheat can be packed in exact number of bags. (i) 98 kg (ii) 290 kg (iii) 200 (iv) 350 kg​

98kg is the capacity of a bag

HCF OF 498,588,882 IS 98 so that we can be packed in extra number of bags is 98 kg

First find the Hcf of all three numbers that is 98 and that is the maximum capacity and then find the Lcm that is 8820 and divide by 98. The answer is 90.

98 kgs because the greatest common factor is 98

number of bags - hcf of 490 ,588,882 is 98

we hve to find the hcf that iz equal to 98

taking HCF we get 98.Hence maximum capacity of a bag be 98kg

the answer get by taking hcf is 98

98 is correct answer bcz greatest common factor is 98

98kg is the maximum capacity of a bag is required.

the HCF of 490,588,and 882is 98

882 is answer this is a farmer wheat

the common factor are 1,2,7,14,49,98 so max number is 98

to find the maximum capacity of the bag to pack all the weight in exact number of bags , we need to find the h.c.f of these weights 490 = 2*5*7*7588 =2*2*3*7*7882 =2*3*3*7*7common factors are - 2 and 7(occurring twiceso,h.c.f = 7*7 *2 =98so,the capacity of these bags will be 98