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8. Ahemisphencal bowl is made ofbrass, 0.25 ăthickness.The innerradius ofthe bowlis 5 cm. Find the ratio of outer surface area to inner surface area. |
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Answer» Inner radius of hemispherical bowl = 5 cm Thickness of the bowl = 0.25 cm ∴ Outer radius (r) of hemispherical bowl = (5 + 0.25) cm = 5.25 cm Outer CSA of hemispherical bowl = 2πr2 = 2 x 22/7 x (5.25 cm)2= 173.25 cm2 Therefore, the outer curved surface area of the bowl is 173.25 cm2. please like the solution 👍 ✔️👍 |
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