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This section includes 7 InterviewSolutions, each offering curated multiple-choice questions to sharpen your Current Affairs knowledge and support exam preparation. Choose a topic below to get started.
| 1. |
A chord of length 16 cm is drawn in a circle of radius 10 cm. Find the distance of the chord from the centre of the circle. |
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| 2. |
1. A chord of length 16 cm is drawn in a circle of radius 10 cm. Find thedistance of the chord from the centre of the circle. |
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| 3. |
EXERCISE 131 A chord of length 16 cm is drawn in a circle of radius 10 cm. Calculate the distance of thechord from the centre of the circle.of radius R |
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| 4. |
The population of a town increases by 10.5% every year if its present population is 795600, what wasit a year ago? |
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| 5. |
1Z0D One year ago, a man was 8 times as old as his son. Now, his age is equalhoursto the square of his son's age. Find their present ages |
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| 6. |
day, I asked the son of my close friend about his age. The child repliedHe said,8.ay He said. "One year ago. my dad was 8 times as old as me and now his age (in yearsin a differentequal to the square of my age." Represent the above situation in the form of a quadraicequation.CESE 2014) |
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Answer» Let the present age of son be x and age of father be yATQy= 8(x-1)y= x^2 then putting eqn 1 in 28x - 7 = x^2x^2-8x+8=0x= 4 |
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| 7. |
the 2 year ago 2 year ago father was three times as old as his son and two years hence twice his age will be equal to five times that of his son find the present age |
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| 8. |
The population of a town increases by 6% every year. If the present population is 15900 find its poa year ago.13 |
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Answer» Population increases =6% x + 6x/100 = 15900 106x/100 = 15900 x = 15900*100/106 x = 15000 |
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| 9. |
0.025 in terms of rate percent is ? |
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Answer» 0.025*1002.5 percentage is the answer to that question |
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| 10. |
If P-108, T- 2.5years, I- 90 then the rate percent is |
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Answer» 90=(108×R×2.5)/100so R=(90×100)/(108×2.5)=33.33% |
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| 11. |
29. Which of the following is equal to 1 ?(A) sin-45°+ cos 45。(B) sin0s coso(C) cos'60(D) sin 30°cos 30° |
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Answer» other options are not having the Value of 1 |
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| 12. |
Find the area of triangle having base 6 cm and altitude 8 cm. |
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| 13. |
Two adjacent sides of a parallelogram ABCD are 16 cm and 11 cmrespectively. If the altitude corresponding to side BC of the parallelogrambe 8 cm, find the length of other altitude AE |
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| 14. |
+| x2ーー! +to oo and xy = 2, then calculate the values of x and y with thcondition that X <1 |
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| 15. |
18. If sin afind the values of tan x, sec x and cosec xth a |
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| 16. |
“कहा 2. ःष्हस्थ o Lice \n‘d—A\’\ |
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Answer» If you like the solution, Please give it a 👍 👍👍 Thankyou |
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| 17. |
9. If Q(0, 1) is equidistant from P(5,-3) and R(x, 6), find the values of x. Also fdistances QR and PR.find10. Find a relation betweenand x such thnt th |
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| 18. |
The average of 6 numbers is 30. If one number isexcluded, the average of the remaining numbers is29. The excluded number isa) 29b) 30c) 35d) 45 |
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Answer» thank you very much |
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| 19. |
Q5. How many triangles are there in(A) 29(C) 45(B) 32(D) of these |
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| 20. |
Q5. How many triangles are there in the given figure?(A) 29(B) 32(C)45(D) of these |
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Answer» none of these is the answer to this question |
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| 21. |
Co ordinate geometryProve that the distarre of the point ("os α,sin α) tron, the ongn is independen of α |
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| 22. |
CH-7 (CO-ORDINATE GEOMETRY)2A) İs R(2,-3), the mid-point of the line segment joining the point P(a,b-2) &0(then the value of a &b will be?& lo.a). Find the values of p&q if the |
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Answer» Acoordinate geometryis a branch ofgeometrywhere the position of the points on the plane is defined with the help of an ordered pair of numbers also known ascoordinates. see answer |
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| 23. |
3.5 cm(iv)cnFig 7.244. In Fig 7.25, AB and CD bisect each otherG) State the three pairs of equal parts in(ii) Which of the following statements aretriangles AOC and BODtrue?Fig 7.25A Gam |
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| 24. |
co ordinate geometry formulas |
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| 25. |
रावली.2. ABCforB-24cmCami|..7 |
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Answer» correct answer is AC = 25 |
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| 26. |
For points A (1, -2) and B(-2, -3), find (Ordinate of B - Ordinate of A). |
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| 27. |
9. Find the altitude of a trapezium whose areais 105 cm2 and whose bases are 14 cm and7 cm. |
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| 28. |
8. In the given figure, line mis parallel to line n and line lis transversal. The value of xis(3r+ 35)(2x+15)O(a) 113째O (b) 67째O(c) 64째O (d) 26째 |
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Answer» 3x+35+2x+15=1803x+2x+15+35=1805x+50=1805x=180-505x=130x=130\5x=26 3x+35+2x+15=1803x+2x+15+35=1805x+50=1805x=180-505x=130x=130/5x26 the answer of the question is 113 degree 113 degree is the answer 3x+35+2x+15=1805x+50=1805x=180-505x=130x=130/5x=26 2x+15+3x+35=1805x+50=180x=(180-50)/5x=130/5x=26 answer= the value of x is x= 26 3x+35+2x+15=1803x+2x+15+35=1805x+50=1805x=180-505x=130x=130/5x=26 ans,3x+35+2x+15=180x=26 and. of the question is(3x+35)+(2x+15)=180x=26. 3x+35+2x+15=1803x+2x+15+35=1805x+50=1805x=180-505x=130x=130\5x=26Ans. x = 26° eisaka answer (b) 67 eiska (answer) jabab 26 hai option a is weight 113 answer of this question is D 26 3x+35+2x15=1803x+2x+15+35=1805x+50=1805x=180-505x=130x=130/5x=26 the value of x is 26 The Question is 113 Deigree ans of the question is 26 The answer to this question is = (d) 26° this is the right answer of c d iska right answer hoga the answer is the value of x=26 x=26degree(d) answer hoga the value of x =26 ........................ 3x+35+2x+15=1803x+2x+15+35=1805x+50=1805x=180-505x=130x=130/5x=26 3x+35+2x+15=1805x=180-505x=130x=26 question answer 26° a 113°correct answer option D is correct answer This question 3x+35°+2x+15°=180°5×+50°=180°5×=130°×=130/5×=26° is the right answer 26° 26 is correct answer 3x+35+2x+15=1805x=180-50x=26 is the correct answer. 26° is right answer this question & answer=(2x+15)+(3x+35) step-3x+35+2x+15=180$step=5x+50=180 180-50==130÷5==26x x ka value 26° hai (d) 26° 3×+35+2×+15 =1803×+2× +35+15=1805×+50=1805×=180-505×=130×=130/5×=26My answer is 26 3×+35+2×+15=1803×+2×+35+15=1805× +50=1805×=180-505×=130×=130/5×=26My answer is 26My option is (D) 3×+35+2×+15=1805×+50=1805×=180_505×=130×=26 b 67° ho ga ans ha ok |
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| 29. |
ind the area of the trapezium whose:a) bases 15 cm and 20 cm and altitude 8 cmb) bases 10 cm and 12 cm and altitude-5 cm |
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| 30. |
Find the sum of the lengths of the bases of a trapeziumwhose area is 4.2m2 and whose height is 280cm. |
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| 31. |
Find the sum of the lengths of the bases of a trapeziumwhose area is 4.2 m and whose height is 280 cm. |
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| 32. |
Einl thvalues a aah22.Ou |
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Answer» Given equations2x + 3y = 72ax + (a + b)y = 28 Have infinitely many solutions Then,2/2a = 3/(a + b) = 7/28 2/2a = 7/28a = 28/7= 4 3/(a + b) = 7/28 = 1/43*4 = (a + b)4 + b = 12b = 12 - 4 = 8 Therefore, value of a = 4, b = 8 |
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| 33. |
u1sing the formula. find the amount and compound interest on:6000 for 2 years at 9% per annum compounded annually. |
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| 34. |
Example 17 If "C, = "C,, find CX |
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| 35. |
areaofarhombusis238cm*andoffetdtaguttal1d10 The11. Find thearea of a rhombus each side of which measures 30cm, and one of whose diagonals is 48cm.oris 64cm Find its height. |
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| 36. |
) Mr. Satish Sharma gets Rs 6,455 at the end of one year at the rate of 14% per annum ina recurring deposit account. Find the monthly instalment. |
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Answer» For recurring depositMaturity value= (1 + (n+1)R/2400)nP Where Maturity value = 6455, R = 14, n = 12, P = monthly installment 6455 = (1 + (12+1)*14/2400)*12*P6455 = (1 + 13*14/2400)*12P6455 =[ (2400 + 182)/200]PP = (6455*200)/2582 = (12910/2582)*100 = 5*100 = 500 Monthly Installment is Rs 500 |
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| 37. |
2016)10 Mr. R.K. Nair gets?6455 at the end of one year at the rate of 14% per annum in arecurring deposit account. Find the monthly instalment.(2005) |
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| 38. |
a. 163b. 32v3c. 64V381. The difference between the circumference and diameter of a circles24cm. Find the radius of the circle |
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| 39. |
Find the value of x in the given figure :24cm |
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Answer» ??? didn't understand |
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| 40. |
3. The maturity value of a R.D. Account is16,176. If the monthly instalment is 400and the rate of interest is 8%; find the time(period) of this R.D. Account. |
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Answer» Installment per month (P) = Rs. 400 Number of months (n) = n Let rate of interest (r) = 8 % p.a.SI = P x n(n+1)/2*12 * r/100 = 400 * n(n + 1)/24 * 8/100 = 4n(n + 1)/3 Given maturity value = Rs. 16,176 Then,(400*n) + SI = 16176400n + 4n(n + 1)/3 = 161761200n + 4n^2 + 4n = 48528n^2 + 301n - 12132 = 0(n + 337)(n - 36) = 0n = - 337, 36 Therefore, Number of months = 36 months = 3 years. |
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| 41. |
3 The maturity value of a R.D. Accountis16,176. If the monthly instalment is 400and the rate of interest is 8%; find the time(period) of this R.D. Account. |
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| 42. |
9(2014)Mohan has a recurring deposit account in a bank for 2 years at 6 % pa. simple interest.If he gets 1200 as interest at the time of maturity, find:(i) the monthly instalment(ii) the amount of maturity.(2016) |
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Answer» SI=P*R*T/100120000=P×2×6120000=12PSO P= 120000÷12=10000RS. AMT=INTEREST + MONTHLY INSTALMENT=RS 1200+RS 10000=RS 11200 |
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| 43. |
4Flite LUIT5. The area of a room is 216 mand its breadth is 12 m. Find the lengurfradius 7 cm. Take 22 |
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Answer» area of room =216m^L×B=216or, L×12=216L=216/12L=18mso correct answer is 18m correct answer is 18 m. length= 216/12length=18 length= area /breadthlength = 216/12length = 18m Length=area/breadthLength=216/12Length=18mSo correct answer is length of room is 18m area = length × breath breath = 12 m then length = area / breath = 216/ 12 = 18 18 m is the length of the roon Yes,,, all answer is right |
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| 44. |
iiu the rate of20149 ) Mohan has a recurring deposit account in a bank for 2 years at 6% pa, siIf he gets t 1200 as interest at the time of maturity, find(0 the monthly instalment(i) the amount of maturity |
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Answer» SI=P*R*T/100120000=P×2×6120000=12PSO P= 120000÷12=10000RS. AMT=INTEREST + MONTHLY INSTALMENT=RS 1200+RS 10000=RS 11200 I=P×n×n+1÷2×12×r÷1001200=x×24×25×6÷100x=₹800 (monthly ins) M.V=P×n+I =800×24+1200 =₹ 20400 😎😎😎 you are intillengent do your self |
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| 45. |
U. A racetrack is in the form of a ring whose inner circumference is 528 m and thecircumference is 616 m. Find the width of the track.o.The inner circumfo |
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| 46. |
u TaluUIS per sag. m.wire of length 10 m is bent to form a rectangle of length 4 m. Find the widthA squareWhich has more area -the square or the rectangle? |
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Answer» Please hit the like button if this helped you |
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| 47. |
Factorise the expressions.ax + bx7p21q |
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| 48. |
The perimeter of a rhombus is 52cm.If one diagonal is 24cm ,Find. 1. the length of its other diagonal2. it's area. |
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Answer» thq 😊 |
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| 49. |
find the maximum length of the rod that can be kept in a cubical box of side 30cm,24cm and 18 cm |
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Answer» Find its diagonal. You will get your answer it's formula is √l^2+b^2+h^2where l = length, b = breadth and h = height so it's answer will be 30√2 cm |
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| 50. |
The lengths of the diagonals of a rhombus are 24cm and 18cm respectively. Find the length ofeach side of the rhombus. |
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Answer» given diagonals=24,18area of rhoumbus=1/2×d1×d2=1/2×24×18=24×9216 |
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