1.

day, I asked the son of my close friend about his age. The child repliedHe said,8.ay He said. "One year ago. my dad was 8 times as old as me and now his age (in yearsin a differentequal to the square of my age." Represent the above situation in the form of a quadraicequation.CESE 2014)

Answer»

Let the present age of son be x and age of father be yATQy= 8(x-1)y= x^2

then putting eqn 1 in 28x - 7 = x^2x^2-8x+8=0x= 4



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